I am using bash scripting to check whether two specific directories are containing some specific number of files. lets assume 20. Is it possible to check it in a line inside a if statement?
#!/bin/bash
if [ [ls /path/to/dir1 | wc -l ] != 20 || [ ls /path/to/dir2 | wc -l ] != 50 ]; then
echo "do this!"
elif
echo "do that!"
fi
The syntax is incorrect:
if [[ $(ls /path/to/dir1 | wc -l) != 20 || $(ls /path/to/dir2 | wc -l) != 50 ]]
then
echo "do this!"
else
echo "do that!"
fi
(I move the position of the then for readability)
With two square brackets [[ you can use || for "or" instead of -o, which is closer to conventional languages. Strictly speaking the [[ does pattern matching, so although the code above will work, an arithmetic test should really use ((:
if (( $(ls /path/to/dir1 | wc -l) != 20 || $(ls /path/to/dir2 | wc -l) != 50 ))
then
echo "do this!"
else
echo "do that!"
fi
The $( ) runs a subshell and captures the output.
Correct if syntax:
if [ $(ls /path/to/dir1 | wc -l) -ne 20 -o $(ls /path/to/dir2 | wc -l) -ne 50 ]
But in your example you shouldn't use just elif. Use either else, or specify condition for elif, exmpl:
if [ $(ls /path/to/dir1 | wc -l) -ne 20 -o $(ls /path/to/dir2 | wc -l) -ne 50 ]
then
echo "Do smth"
elif [ $(ls /path/to/dir3 | wc -l) -ne 100 ]
then
echo "Do anything else"
fi
Related
I have function
function contain() {
if [[ $(echo "$1" | grep "$2" | wc -c) -gt 0 ]]; then
return 0
else
return 1
fi
}
when I write instead
if [[ $(md5sum -c tool | grep -v "OK$" | wc -c) -gt 0 ]]; then
this
if contain "$(md5sum -c tool)" "OK$"
wants not work
#!/bin/bash
a=2
b=2
COUNTER=0
sam="abcd"
sam1="xyz"
sam2="mno"
for x in ls | grep .rpm
do
`C=rpm -qpR $x | grep -v CompressedFileNames | grep -v PayloadFilesHavePrefix | wc -l`
if [ "sam2"!="$sam1" ]
then
echo "${sam1}"
echo "${sam2}"
if [ $C -eq $a ]
then
COUNTER=$((COUNTER+1))
echo "${x}"
eval sam=$x
#eval sam1=sam | cut -d '-' -f 1
sam1=`echo "${sam}"| cut -d '-' -f 1`
if [ $COUNTER -eq $b ]
then
break
fi
fi
fi
sam2=`echo "${x}"| cut -d '-' -f 1`
done
This is the output I am getting:
xyz
mno
comps-4ES-0.20050107.x86_64.rpm
comps
comps
comps-4ES-0.20050525.x86_64.rpm
My question is: why is the if condition returning true despite sam1 and sam2 being equal? I have checked for non-equality.
Response is the same even if I use
if [ $C -eq $a ] && [ "$sam2" != " $sam1" ]
As Ansgar Wiechers pointed out, you're missing a "$" in front of the sam2 variable. That way, you're comparing the literal string "sam2" with the string value of $sam1 (which initially is set to "xyz"). What you want to do is compare the string values of both variables:
if [ "$sam2" != "$sam1" ]
Regarding $C, you should only include the commands to be evaluated inside backticks, not the evaluation itself. This is called a command substitution - a subshell is created in which the commands are executed, and the backtick expression is substituted by the computed value. The line should look like this:
C=`rpm -qpR $x | grep -v CompressedFileNames | grep -v PayloadFilesHavePrefix | wc -l`
Your for loop also needs a command substitution: for x in ls | grep .rpm makes it look as if you're piping the output of a for command into grep. What you want to do is iterate over the ls | grep part, which you can do with the following command substitution:
for x in `ls | grep .rpm`
Hi Guys Got the solution:
#!/bin/bash
read -p "enter dep number" a
read -p "enter no of rpms" b
COUNTER=0
sam="abcd"
sam1="xyz"
sam2="mno"
for x in `ls | grep .rpm`
do
C=`rpm -qpR $x |grep -v CompressedFileNames | grep -v PayloadFilesHavePrefix | wc -l`
# echo "${C}:c"
if [ $C -eq $a ] && [ "$sam2" != "$sam1" ]
then
COUNTER=$((COUNTER+1))
# echo "${COUNTER}:counter"
# echo "${x}"
eval sam=$x
#eval sam1=sam | cut -d '-' -f 1
sam1=`echo "${sam}"| cut -d '-' -f 1`
if [ $COUNTER -eq $b ]
then
break
fi
fi
sam2=`echo "${x}"| cut -d '-' -f 1`
#echo "${sam2}"
#echo "${sam1}"
done
I have five different files and all are in different directory, I want to check matching files and find out the unique files as well.
I am not sure how should I handle this.
You can look to the output of
chksum "path1/file1" "path2/f2" "p3/f3" "p4/f4" "p5/f5" | sort
You can also make a script looping through the files with
files=("path1/file1" "path2/f2" "p3/f3" "p4/f4" "p5/f5")
for i in {0..4}; do
((j=$i+1))
while [ $j -le 4 ]; do
diff "${files[i]}" "${files[j]}" >/dev/null
if [ $? -eq 0 ]; then
echo "${files[i]} and ${files[j]} are the same."
else
echo "${files[i]} and ${files[j]} are different."
fi
((j++))
done
done
You can use cksum ou md5sum to detect identical files :
find . -type f | while read f; do md5sum "$f"; done > tmp.txt
cat tmp.txt | cut -d" " -f1 | while read c
do n=`grep $c tmp.txt | wc -l`
if [ "$n" != "1" ]; then
grep $c tmp.txt
fi
done | sort -u
I am trying to extract all files with a line count greater than x using the following code.
for i in massive*;
do
if [ wc -l $i | cut -d ' ' -f 1 > 50 ]; then
mv $i subset_massive_subcluster_num_gt50/;
fi;
done
However I am getting the following error everytime it goes through the loop:
cut: ]: No such file or directory
-bash: [: missing `]'
Any ideas?
Change this:
for i in massive*;
do
if [ wc -l $i | cut -d ' ' -f 1 > 50 ]; then
mv $i subset_massive_subcluster_num_gt50/;
fi;
done
To this:
for i in massive*;
do
if [ "$(wc -l "$i" | cut -d ' ' -f 1)" -gt 50 ]; then
mv "$i" subset_massive_subcluster_num_gt50/;
fi;
done
Maybe you can try:
for file in massive*
do
[[ $(grep -c '' "$file") > 50 ]] && echo mv "$file" subset_massive_subcluster_num_gt50/
done
the grep -c '' is nicer (and safer) than wc -l | cut
The above is for "dry run". Remove the echo if satisfied.
I am trying to do something like this:
if [ $(wc -l $f) -lt 2 ]
where $f is a file. When I run this, I get the error message:
[: too many arguments
Does anybody know how to fix this line in my command?
The full script is:
for f in *.csv
do
if [ $(wc -l $f) -lt 2 ]
then
echo $f
fi
done
at least in my case wc -l filename does output 32 filename being 32 the number of lines. so you must strip of the filename after the line count.
You could change your code from
if [ $(wc -l $f) -lt 2 ]
to
if [ $(wc -l $f | cut -f1 -d' ') -lt 2 ]
or
if [ $(wc -l < $f) -lt 2 ]
If does not solve your problem please add the output of wc -l filename to your question or as a comment.
Try this :
if (( $(wc -l < "$f") < 2 ))
or if you want to keep your syntax :
if [ $(wc -l < "$f") -lt 2 ]
Note
((...)) is an arithmetic command, which returns an exit status of 0 if the expression is nonzero, or 1 if the expression is zero. Also used as a synonym for "let", if side effects (assignments) are needed. See http://mywiki.wooledge.org/ArithmeticExpression
What you need is probably
if [ `cat $f | wc -l` -lt 2 ]
instead of
if [ $(wc -l $f) -lt 2 ]