Configure swagger in gradle build script with kotlin dsl - gradle

Question

I'm trying to switch my simple project from Groovy to Kotlin in build scripts.
I'm using this plugin:
https://github.com/gigaSproule/swagger-gradle-plugin
I have this configuration in my build script:
swagger{
apiSource {
springmvc = false
locations = ['my.location']
schemes = ['https']
host = 'test.com:8080'
info {
title = 'My Service'
version = 'v1'
}
swaggerDirectory = "$buildDir/swagger"
}
To where shall I refer to in this situations?
Shall I do something like?
task( "swagger" ) {
...
}
It is not quite familiar for me.
Thanks.

Answer 1

In case anyone is still looking for this information, this is how you would do it using Gradle Kotlin DSL:
import com.benjaminsproule.swagger.gradleplugin.model.*
plugins {
id("com.benjaminsproule.swagger") version "1.0.0"
}
swagger {
apiSource(closureOf<ApiSourceExtension> {
springmvc = false
schemes = mutableListOf("https")
host = "test.com:8080"
info(closureOf<InfoExtension> {
title = "My Service"
version = "v1"
description = "My Service Description"
termsOfService = "http://www.example.com/termsOfService"
contact(closureOf<ContactExtension> {
email = "email#internet.com"
name = "A Developer"
url = "http://www.internet.com"
})
license(closureOf<LicenseExtension> {
url = "http://www.apache.org/licenses/LICENSE-2.0.html"
name = "Apache 2.0"
})
})
locations = mutableListOf("com.foo.fighting")
swaggerDirectory = "$buildDir/swagger"
})
}
I've tested it using Gradle v4.6.