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How can I manipulate text in bash using either awk, grep, perl or sed?
Input:
ted foo,bar,zoo
john ket,ben
Expected Output:
foo,ted
bar,ted
zoo,ted
ket,john
ben,john
With awk:
awk 'BEGIN{FS="[ ,]"; OFS=","} {for (i=2; i<=NF; i++) print $i,$1}' file
Output:
foo,ted
bar,ted
zoo,ted
ket,john
ben,john
See: 8 Powerful Awk Built-in Variables – FS, OFS, RS, ORS, NR, NF, FILENAME, FNR
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I am trying to concatenate the output of three cut functions with - in a shell script in a single line. I tried as below, but wont work. How do I do this ?
echo "$(cut -d',' -f2 FILE.csv)-$(cut -d',' -f1 FILE.csv)-$(cut -d',' -f3 FILE.csv)"
Using awk to change the delimiter:
awk -F, '{ print $2, $1, $3 }' OFS='-' FILE.csv
Or with csvkit commands (Especially useful if your file has more complex CSV with things like commas in quoted fields or multi-line fields that a naive split on comma can't handle correctly):
csvcut --columns 2,1,3 FILE.csv | csvformat -D'-'
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Exactly what the title says: what is the bash command for printing out the longest word in a text file that appears at least 10 times.
Try this Denis:
tr -s " " "\n" < file | while read -r l; do echo "${#l} $l"; done | sort -n | awk '$1 >= 10 ' | awk '{print $2}' | tail -n1
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the text file contains
from:sender#gmail.com
to:receiver#gmail.com
subject:
attachment:asdfg.xlsx
all arguments should be handled in shell script
I tried but if subject contains space then it gives problem
from=$(echo $1|cut -d ":" -f 2 <<< "$1")
to=$(echo $2|cut -d ":" -f 2 <<< "$2")
subject="$3"
attachment=$(echo $4|cut -d ":" -f 2 <<< "$4")
When you could read the Input_file then passing it as a variable will not be a good option IMHO, so create variables inside script by reading Input_file, opting OP's method of creating variables but enhancing code to awk.
from=$(awk -F':' '/from/{print $NF}' Input_file)
to=$(awk -F':' '/^to/{print $NF}' Input_file)
subject=$(awk -F':' '/^subject/{if($NF){print $NF} else {print "NULL subject"}}' Input_file)
attachment=$(awk -F':' '/^attachment/{print $NF}' Input_file)
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I'm supposed to filter records from multiple files. Files are delimited by |. On the 24th field, I will filter the records by "9120". How am I supposed to filter the files by using bash script?
20|09328833007|0|0|9222193385|0|GS|515051032704315|0|*HOME||20140311|101640|0|0|||12|18|0|0|1||3100|00886FC0||0|0|| |||N|N|||N||||N|||||| 301131301|||||||||||11|0||00|FF|11|FF|140311101640|352912058113130000||CEBS1|MSH15
The more concise way using awk:
awk '$24=="9120"' FS='|' file*
Using variable input:
awk -v col=24 -v value="9120" '$col==value' FS='|' file*
awk is useful to processing files like this. You set the FIELD SEPARATOR to |:
To print the 24th field:
$ awk -F '|' '{ print $24 }' sample.txt
3100
To print lines where the 24th field is the value you specified:
awk -F '|' '$24=="9120" { print; }' sample.txt
Try this:
cat file* | awk -F"|" '$24=="9120" {print $0}'
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I have a shell script that creates a CSV output file like below (on separate lines) :
aaa,111
bbb,222
ccc,999
I want to have a record number as the first column in the above output such as,
dm1,aaa,111
dm2,bbb,222
dm3,ccc,999
How do I create a variable for dm within my shell script?
Use awk:
awk '{print "dm" NR "," $0}' input.csv >output.csv
or
... | awk '{print "dm" NR "," $0}' >output.csv
You can use a var and expr to do some maths like
dm=`expr $dm + 1`
echo "dm$dm,...rest of output..."
Pipe your output to awk
yourcommand | awk -F, -v prefix="dm" '{printf "%s%d,%s\n", prefix, NR, $0}'
we set -F, to set the input field separator, and the -v to set a prefix. You can replace "dm" with a shell variable, if you want.