Goal: In a batch file, append or concatenate the text in Var_1 with the string JpgListand add the extension .txt to the output file
In the batch this works
Dir *.Jpg > JpgList.txt
In the batch, I have already retrieved a Variable %Var_1%
Problem is: concatenating the Var with the literal string JpgList and appending .txt as the output filename.
Here are code examples of what I have tried along with pseudo code that fails, (Some produce a .txt file with no name, some produce nothing and some produce a file with the Var_1 name, but no content in file).
dir *.jpg Var_1 + jpgList.txtdir > %label_% >>".txt"dir > %%label_%% >>".txt"
I have tried every which way but upside down to put this together, and
appreciate any tips or syntax for making the code work.
Because you haven't provided your batch file, we have no idea of the possible content of %Var_1% or %label_% so answers currently need to speculate.
The following should work, as long as the content of %Var_1% does not include problematic/disallowed characters or a non-existent/inaccessble location.
Dir /B/A-D-L *.jpg>"%Var_1%JpgList.txt"
Related
i need a script which will rename large amount of files. I got a folder with a lot of files. Every file is named by ID. Then i have a CSV file like this:
oldID;newID
oldID;newID
etc...
Every old and new id is specific and original. I'd like to ask what should be the best way to do it or little help in bash/batch.
The solution for batch is very similar to e0k's solution for bash; you read the file in one line at a time, split the line on semicolons, and rename the file accordingly.
for /f "tokens=1,2 delims=;" %%A in (ids.csv) do ren "%%A" "%%B"
This assumes that your IDs are in a file called ids.csv
If you are using bash (the shell used in world of Linux, UNIX, etc.), you can use the following short script based on this internal field separator answer. This assumes that you are using a semicolon (;) as the delimiter of your "CSV" file and that there is only one such delimiter.
#!/bin/bash
while IFS=';' read -ra names; do
mv "${names[0]}" "${names[1]}";
done < translation.csv
where translation.csv is your file containing the name translations with an oldname;newname format.
If you are instead asking for a batch file (i.e. for Windows, DOS, etc.) then that is a different animal in a different world.
Given that your OS is some unix (like linux), and given that the use of csv files has been your own choice, there might be an easier way to go: mmv can rename many files in one go, using patterns to match original files, and allowing to use the matched strings in the target file names. See http://ss64.com/bash/mmv.html.
I am trying to concatenate a set of .txt files using windows command line, into a csv file.
so i use
type *.txt > me_new_file.csv
but a the fields of a given row, which is tab delimited, ends up in one column. How do I take advantage of tab separation in the original text file to create a csv file such that fields are aligned in columns correctly, using one or more command lines? I am thinking there might be something like...
type *.txt > me_new_file.csv delim= ' '
but haven't been able to find anything yet.
Thank You for your help. Would also appreciate if someone could direct me to a related answer.
From the command line you'd have a fairly complicated time of it. The Windows cmd.exe command processor is much, much simpler than dash, ash, or bash, et.al.
Best thing would be to concatenate all of your files into the .csv file, open it in a text editor, and do a global find and replace replacing with ,
Be careful that your other data doesn't have any commas in it.
If the source files are tab delimited, then the output file is also tab delimited. Depending on the software you are using, you should be able load the tab delimited data properly.
Suppose you are using Excel. If the output file has a .csv extension, then Excel will default to comma delimited columns when it opens the file. Of course that does not work for you. But if you rename the file to have some other extension like .txt, then when you open it with Excel, it will open a series of dialog boxes where you can specify the format, including tab delimited.
If you want to keep the .csv extension and have Excel automatically open it properly, then you need to transform the data. This can be done very easily with JREPL.BAT - a hybrid JScript/batch utility that performs a regular expression search and replace on text data. JREPL.BAT is pure script that runs natively on any Windows machine from XP onward.
The following encloses each value in quotes, just in case a value contains a comma literal.
type *.txt 2>nul | jrepl "\t" "\q,\q" /x /jendln "$txt='\x22'+$txt+'\x22'" /o output.csv
Beware: Your use of type *.txt will fail if the last line in any of your source .txt files does not end with a newline. In such a case, the first line of the next file will be appended to the last line of the previous file. Not good.
You can solve that problem by processing each file individually in a FOR loop.
(for %F in (*.txt) do jrepl "\t" "\q,\q" /x /jendln "$txt='\x22'+$txt+'\x22'" /f "%F") >output.csv
The above is designed to run on the command line. If used in a batch script, then a few changes are needed:
(for %%F in (*.txt) do call jrepl "\t" "\q,\q" /x /jendln "$txt='\x22'+$txt+'\x22'" /f "%%F") >output.csv
Note: My answer assumes none of the source files contain quotes. If they do contain quotes, then a more complicated search and replace is required. But it still can be done efficiently with JREPL.
I do not know much bash scripting, but I know the task I would like to do would be greatly simplified by it. I would like to test a program against expected output using many test input files.
For example, I have files named "input1.txt, input2.txt, input3.text..." and expected output in files "output1.txt, output2.txt, output3.txt...". I would like to run my program with each of the input files and output a corresponding "test1.txt, test2.txt, test3.txt...". Then I would do a "cmp output1.txt test1.txt" for each file.
So I think it would start like this.. roughly..
for i in input*;
do
./myprog.py < "$i" > someoutputthing;
done
One question I have is: how would I match the numbers in the filename? Thanks for your help.
If the input file name pattern is inputX.txt, you need to remove input from the beginning. You do not have to remove the extension, as you want to use the same for output:
output=output${i#input}
See Parameter Expansion in man bash.
I have two text files that I want to combine ..I am using the below code to do that ..the issue is at the start of the second file this code is inserting some weird characters like spaces..Is there a way to insert a new line instead of using writeline.
Set txsOutput = FSO.CreateTextFile(strOutputPath)
Set txsInput = FSO.OpenTextFile(strInputPath,1)
txsOutput.Writeline txsInput.ReadAll
Thanks
.ReadAll() reads the trailing EOL(s) of the file. .Writeline will add a further EOL. Use .Write instead to get an exact copy of the first input file as the head of the output file.
If the "weird characters like spaces" are - unwanted - parts of the first file, you'll have to use string ops (Instr, Left, Replace, ...) or a RegExp to clean the data.
If they come from the second file (assuming you used .ReadAll for that too), you should check the encoding of that file and/or clean the data using the methods above.
I'm trying to use the following batch script to concatenate some files together:
copy NUL bin\translate.js
for %%f in (source\Libraries\sprintf.js, source\translate-namespace.js, source\util.js, source\translator.js, source\translate.js) do (
type %%f >> bin\translate.js
echo. >> bin\translate.js
)
However, when I do this, an extra character seems to be printed at the end of each file. When I view the file in ASCII, it is interpreted as these three characters:

Why is this happening? What can I do to fix it?
The  looks like a unicode byte order mark. Is it possible to start with files that are stored without the byte mark? I am not aware of any command line commands that can remove the mark.
The DOS copy command works like the UNIX cat command. That is, you can list multiple source files and one destination file, seperated with + signs.
copy source\Libraries\sprintf.js+source\translate-namespace.js bin\translate.js