How can I run this function as a shell script? - bash

Question

I am working on a shell script, and I wish to do the following as part of a shell script without declaring a function. Basically, I would like to convert the following code into a shell script simply without declaring a function.
#!/bin/bash
function json2keyvalue {
cat<<EOF | jq -r 'to_entries|map("\(.key)\t\(.value|tostring)")[]'
{
"hello1": "world1",
"testk": "testv"
}
EOF
}
while IFS=$'\t' read -r key value
do
export "$key"="$value"
done < <(json2keyvalue)
into a shell script. I did the following,
values='{"hello1":"world1","hello1.world1.abc1":"hello2.world2.abc2","testk":"testv"}'
while IFS=$'\t' read -r key value
do
export "$key"="$value"
done < < (echo $values | jq -r 'to_entries|map("\(.key)\t\(.value|tostring)")[]')
But this doesn't seem to work. When I run the shell script, it gives the error as follows, where file name is abc.sh.
./abc.sh: line 6: syntax error near unexpected token `<'
./abc.sh: line 6: `done < < (jq -r 'to_entries|map("\(.key)\t\(.value|tostring)")[]' <<<"$values")'
The script takes a JSON like the following, and converts the key-values into environment variables.
{
"hello1": "world1",
"testk": "testv"
}

Answer 1

I suggest:
#!/bin/bash
shopt -s lastpipe
cat <<EOF | jq -r 'to_entries|map("\(.key)\t\(.value|tostring)")[]' | while IFS=$'\t' read -r key value; do export "$key"="$value"; done
{
"hello1": "world1",
"testk": "testv"
}
EOF
lastpipe: If set, and job control is not active, the shell runs the last command of a pipeline not executed in the background in the current shell environment.
Update:
If variable $values contains valid json code, this should work:
#!/bin/bash
shopt -s lastpipe
values='place valid json code here'
echo "$values" | jq -r 'to_entries|map("\(.key)\t\(.value|tostring)")[]' | while IFS=$'\t' read -r key value; do export "$key"="$value"; done