Return multiple strings from AJAX - ajax

Question

With AJAX post i'm sending a data and on other page, according to this data i'm retrieving two different column values of mysql database by query. And i need to get back these two different values as a result of AJAX and show in two different inputs.
var mus_barkod = document.getElementById('mus_barkod').value;
var dataString = "mus_barkod="+mus_barkod;
$.ajax({
type: "POST",
url: "musteri_indir.php",
data: dataString,
success: function(result){
$("#indirim").val(result.mus_indirim);
$("#mus_isim").val(result.mus_isim);
This is the part of AJAX and below the (OLD) query for fetching data:
$mus_barkod = $_REQUEST['mus_barkod'];
$mus_cek = mysql_query("SELECT * FROM musteriler WHERE mus_barkod =
'".$mus_barkod."' AND sub_id = '".$per_sube."' ");
while ($mus_al=mysql_fetch_array($mus_cek)){
$mus_isim = $mus_al['mus_isim'];
$mus_indirim= $mus_al['mus_indirim'];
}
$mus_isim1 = 'Kayıtlı Müşteri Değil';
$mus_indirim1 = '0.00';
if($mus_barkod == '10' || $mus_barkod == '100090'|| $mus_barkod ==
'100237')
{
echo
$mus_indirim,$mus_isim;
}else{
echo
$mus_indirim1,$mus_isim1;
}
So how can i get back mus_indirim and mus_isim seperately and show in different inputs?
NOTE: Don't mind mysql_, this is an old system. PDO Forever :)

Answer 1

Fixed it by checking my codes more carefully. Here is the result for those need the same solution:
var mus_barkod = document.getElementById('mus_barkod').value;
var dataString = "mus_barkod="+mus_barkod;
$.ajax({
type: "POST",
url: "musteri_indir.php",
data: dataString,
dataType: "json", => the little thing i forgot to write :)
success: function(result){
$("#indirim").val(result.mus_indirim);
$("#mus_isim").val(result.mus_isim);
The Old PHP:
$mus_barkod = $_REQUEST['mus_barkod'];
$mus_cek = mysql_query("SELECT * FROM musteriler WHERE mus_barkod =
'".$mus_barkod."' AND sub_id = '".$per_sube."' ");
while ($mus_al=mysql_fetch_array($mus_cek)){
$mus_isim = $mus_al['mus_isim'];
$mus_indirim= $mus_al['mus_indirim'];
}
if($mus_barkod == '10' || $mus_barkod == '100090'|| $mus_barkod ==
'100237')
{
echo json_encode(array("mus_indirim" => $mus_indirim, "mus_isim" =>
$mus_isim));
}else{
echo json_encode(array("mus_indirim" => '0.00', "mus_isim" => 'Kayıtlı
Müşteri Değil'));
}