There's a public streaming Meetup API that streams JSON events: http://stream.meetup.com/2/rsvps
In a single line from the command line, I'd like to be able to redirect that stream such that each JSON object is POSTed to another API.
I've tried lots of permutations of cURL but thus far have been unable to make it work. My current attempt looks something like:
curl -s http://stream.meetup.com/2/rsvps | curl -H "Content-Type: application/json" -X POST -d #- 'http://my-api-url-here'
This produces nothing as far as I can see. The requests are not streamed to the destination API and nothing is sent to standard out. As a bonus, I'd like to see the standard output but the core requirement is streaming the JSON records to the target API.
If I try redirecting the stream to a file like:
curl -s http://stream.meetup.com/2/rsvps > output.txt
This works as expected. The challenge seems to be getting the output from the initial cURL stream to POST as data to the second.
This could work for let's say, 10 events at a time
curl -H "Content-Type: application/json" -X POST -d "[$(curl -s http://stream.meetup.com/2/rsvps | sed -n '1{p; :loop n; p; 10q; b loop}' | sed -re '1,9 s/[}]$/},/')]" 'http://my-api-url-here'
As suggested by meetup docs, the number of events may be limited using since_count and since_mtime.
Related
I need to make a POST request via cURL from the command line. Data for this request is located in a file. I know that via PUT this could be done with the --upload-file option.
curl host:port/post-file -H "Content-Type: text/xml" --data "contents_of_file"
You're looking for the --data-binary argument:
curl -i -X POST host:port/post-file \
-H "Content-Type: text/xml" \
--data-binary "#path/to/file"
In the example above, -i prints out all the headers so that you can see what's going on, and -X POST makes it explicit that this is a post. Both of these can be safely omitted without changing the behaviour on the wire. The path to the file needs to be preceded by an # symbol, so curl knows to read from a file.
I need to make a POST request via Curl from the command line. Data for this request is located in a file...
All you need to do is have the --data argument start with a #:
curl -H "Content-Type: text/xml" --data "#path_of_file" host:port/post-file-path
For example, if you have the data in a file called stuff.xml then you would do something like:
curl -H "Content-Type: text/xml" --data "#stuff.xml" host:port/post-file-path
The stuff.xml filename can be replaced with a relative or full path to the file: #../xml/stuff.xml, #/var/tmp/stuff.xml, ...
If you are using form data to upload file,in which a parameter name must be specified , you can use:
curl -X POST -i -F "parametername=#filename" -F "additional_parm=param2" host:port/xxx
Most of answers are perfect here, but when I landed here for my particular problem, I have to upload binary file (XLSX spread sheet) using POST method, I see one thing missing, i.e. usually its not just file you load, you may have more form data elements, like comment to file or tags to file etc as was my case. Hence, I would like to add it here as it was my use case, so that it could help others.
curl -POST -F comment=mycomment -F file_type=XLSX -F file_data=#/your/path/to/file.XLSX http://yourhost.example.com/api/example_url
I was having a similar issue in passing the file as a param. Using -F allowed the file to be passed as form data, but the content type of the file was application/octet-stream. My endpoint was expecting text/csv.
You are able to set the MIME type of the file with the following syntax:
-F 'file=#path/to/file;type=<MIME_TYPE>
So the full cURL command would look like this for a CSV file:
curl -X POST -F 'file=#path/to/file.csv;type=text/csv' https://test.com
There is good documentation on this and other options here: https://catonmat.net/cookbooks/curl/make-post-request#post-form-data
I had to use a HTTP connection, because on HTTPS there is default file size limit.
https://techcommunity.microsoft.com/t5/IIS-Support-Blog/Solution-for-Request-Entity-Too-Large-error/ba-p/501134
curl -i -X 'POST' -F 'file=#/home/testeincremental.xlsx' 'http://example.com/upload.aspx?user=example&password=example123&type=XLSX'
I wrote a curl script to pull data from my api url into my unix terminal. But when I run the script below, I get a blank space as my output, rather than data from the api url. I don't get any standard error message, just a blank space followed by $ to enter a new command.
#!/bin/bash
INSTANCE_NAME="https://servicenow.com/ServiceNowData/tickets?ticks=4320000"
DATA_OUTPUT=$(curl -s -k -X GET -H "accept: application/json" $INSTANCE_NAME)
echo $DATA_OUTPUT
Page 404. And -H "Accept-Encoding: application/json"
I 'd like to post directly a json object from a url(json) to another url
so the command goes as follows:
curl "<resource_link>.json" -o sample.json
curl -X POST "<my_link>" "Content-type: application/json" -d #sample.json
I 'd like to avoid this, so what is the solution? Is it something like that?
curl -X POST "<my_link>" "Content-type: application/json" -d "curl <resource_link>.json"
But it does not work? Also, this one post Stream cURL response to another cURL command posting the result
does not explain thouroughly and it is not working
Yes,
curl
manual explains the '#' but it does not explain about using another curl
Alternatievely, if I could save somewhere temporarily the 1st cURL response and use it in the other command(but not in a file)
You don't want -x POST in there so let's start with dropping that.
Send the results from the first transfer to stdout by not using -o, or telling -o to use stdout with -o-, and
Make sure your second transfer accepts the data to send on stdin, by using -d#-.
curl "<link>.json" | curl "<link2>" -H "Content-type: application/json" -d #-
With curl 7.82.0 and later
Starting with curl 7.82.0 you can do it even easier with the new --json option:
curl "<link>.json" | curl "<link2>" --json #-
I would like to create a curl output live in a single shell command, to log a output from an Ansible job in realtime filling a log file.
I've tried this command:
curl -f -k -N -H 'Content-Type: application/json' -XPOST \
--user admin:awxsecret \
http://192.168.42.100/api/v2/jobs/1620/
...but it only returns the output generated thus far, not waiting for newly-generated content.
As #charles-duffy said: "AWX does support websockets" I will work with this solution.
I'm using curl to create several classifications. I have written the json for the many classifications and they are in one folder. I would like to create all the classifications in one go. But using curl I can only create them one at a time. How could I make them in one request?
curl -u admin:admin -H "Content-Type: application/json" -X POST -d #pii.json http://127.0.0.1:21000/api/atlas/v2/types/typedefs
The curl manual for -d says 'Multiple files can also be specified'. How can I do this? All my attempts have failed.
Do I need a bash script instead? If so, could you help me - I'm not a coder and I'm struggling without an example!
Thanks in advance.
You probably don't want to use multiple -d with JSON data since curl concatenates multiple ones with a & in between. As described in the man page for -d/--data:
If any of these options is used more than once on the same command
line, the data pieces specified will be merged together with a
separating &-symbol. Thus, using '-d name=daniel -d skill=lousy' would
generate a post chunk that looks like 'name=daniel&skill=lousy'.
You can however easily and conveniently pass several files on stdin to let curl use them all in one go:
cat a.json b.json c.json | curl -d#- -u admin:admin -H "Content-Type: application/json" http://127.0.0.1:21000/api/atlas/v2/types/typedefs
(please note that -X POST has no place on a command line that uses -d)
I found the following to work in the end:
<fileToUpload.dat xargs -I % curl -X POST -T "{%}" -u admin:admin -H "Content-Type: application/json" http://127.0.0.1:21000/api/atlas/v2/types/typedefs
Where fileToUpload.dat contained a list of the .json files.
This seemed to work over Daniel's answer, probably due to the contents of the files. Hopefully this is useful to others if Daniel's solution doesn't work for them.
I needed to upload all the *.json files from a folder via curl and I made this little script.
nfiles=*.json
echo "Enter user:"
read user
echo "Enter password:"
read -s password
for file in $nfiles
do
echo -e "\n----$file----"
curl --user $user:$password -i -X POST "https://foo.bar/foo/bar" -H "Content-Type: application/json" -d "#$file"
done
Maybe fits your needs.