Get number first and second and third from text line - vbscript

Question

I have the following format in my txt file:
1 1,30705856804525E-7 2,64163961816166E-8
1,12201845645905 1,24157281788939E-7 2,45690063849224E-8
1,25892543792725 1,18248813407718E-7 2,29960868125545E-8
1,41253757476807 1,13006606738963E-7 2,16654658657944E-8
1,58489322662354 1,0842624220686E-7 2,05472137082552E-8
1,77827942371368 1,04479198625995E-7 1,96135836461053E-8
1,99526226520538 1,01119816520168E-7 1,8839035220708E-8
2,23872113227844 9,82917924829962E-8 1,82003176973922E-8
2,51188635826111 9,59338279926669E-8 1,76765304615856E-8
2,81838297843933 9,39840489877497E-8 1,72491425587395E-8
3,16227769851685 9,23831819932275E-8 1,69019571671924E-8
3,54813385009766 9,10766573269939E-8 1,66210121221866E-8
3,98107171058655 9,00157104410937E-8 1,63944182673958E-8
4,46683597564697 8,91577514039454E-8 1,62121711611007E-8
5,01187229156494 8,8466336478632E-8 1,60659361370108E-8
5,6234130859375 8,7910699164695E-8 1,59488209305891E-8
6,30957365036011 8,74651959748007E-8 1,58551749507296E-8
7,07945775985718 8,71086527354237E-8 1,57803938805046E-8
7,94328212738037 8,68237393092386E-8 1,57207402651238E-8
8,91250896453857 8,65963372120859E-8 1,56731942979604E-8
10 8,64150138113473E-8 1,56353241465013E-8
11,2201843261719 8,62705391568852E-8 1,5605175818223E-8
I need to get only value for integers on left and right value so in this example I need to get:
1
2,64163961816166E-8
10
1,56353241465013E-8
This is what I've tried:
' Check Noise Spectral Density.txt exists
Set fso = CreateObject("Scripting.FileSystemObject")
If (fso.FileExists(fso.GetParentFolderName(WScript.ScriptFullName) + "\Projects\Noise Spectral Density.txt")) Then
' Open the file for input.
Set NoiseSpectralDensity = fso.OpenTextFile(fso.GetParentFolderName(WScript.ScriptFullName) + "\Projects\Noise Spectral Density.txt", 1)
' Noise Variables
Dim Noise
' Read from the file and display the results.
Do While NoiseSpectralDensity.AtEndOfStream <> True
' Read Line By Line
TextLine = NoiseSpectralDensity.ReadLine
' Check If Number
'If (IsNumeric(Left(TextLine, 5))) Then
' Get Noise
' Noise # 1kHz
Noise = Right(TextLine, InStr(Mid(TextLine, 2), InStr(TextLine, " ")-1))
x = MsgBox("SNR: " & Split(Left(TextLine, 5), " ")(0) & " NOISE: " & Noise & "",0, "Noise Spectral Density")
'End If
Loop
' Close the file for input.
NoiseSpectralDensity.Close
Else
x = MsgBox("Noise Spectral Density.txt NOT Found!" & vbCrLf & "Wave->Save As Text...", 0, "Noise Spectral Density")
End If
But I could not get left and right numbers in VBScript using Split(TextLine, " ")(0).

Answer 1

Your data seems to be tab-separated, so you could do something like this:
arr = Split(TextLine, vbTab)
If Not (InStr(arr(0), ",") > 0) Then
'first number doesn't have decimals
snr = arr(0)
noise = arr(2)
End If

Answer 2

Though the solution provided by #AnsgarWiechers should work but in case, if it doesn't, you can make use of regular expressions(Replace the whole Do-while loop with the following):
Set objReg = New RegExp
objReg.Pattern = "^(\d+)(?=\s).*\s+([\d,Ee-]+)$" 'See the explanation below
Do While NoiseSpectralDensity.AtEndOfStream <> True
'Read Line By Line
TextLine = NoiseSpectralDensity.ReadLine
' Check If Number
Set objMatches = objReg.Execute(TextLine)
For Each objMatch In objMatches
SNR = objMatch.submatches.item(0)
Noise = objMatch.submatches.item(1)
MsgBox "SNR: "&SNR&"; Noise: "&Noise
Next
Loop
Click for Regex Demo
Regex Explanation:
^ - asserts the start of the string
(\d+) - matches 1+ occurrences of a digit and captures it in Group 1
(?=\s) - positive lookahead to find the position immediately preceded by a white-space. So the digits in the step 2 will be matched until a whitespace(spaces,tabs etc.) is encountered
.* - matches 0+ occurrences of any character except a newline
\s+ - matches 1+ occurrences of a whitespace
([\d,Ee-]+) - matches 1+ occurrences of a digit or , or - or the letter E or e and capture it in group 2
$ - asserts the end of the string