Create a Logout Link in Html Page - spring-boot

Question

I have working login and logout forms with using Spring Security Basic Authentication and thymeleaf.
my problem is my logout link is display as a button. but I want to include it in a <a href=""> tag. but when I include my logout link in the <a href=""> tag it isn't working. here is my code.
Logout Controller - Spring Boot
#RequestMapping(value = {"/logout"}, method = RequestMethod.POST)
public String logoutDo(HttpServletRequest request,HttpServletResponse response){
HttpSession session= request.getSession(false);
SecurityContextHolder.clearContext();
session= request.getSession(false);
if(session != null) {
session.invalidate();
}
for(Cookie cookie : request.getCookies()) {
cookie.setMaxAge(0);
}
return "redirect:/login?logout";
}
Logout form - Front End
<form th:action="#{/logout}" method="POST">
<input type="submit" value="Logout"/>
</form>
Security Configurations
#Override
protected void configure(HttpSecurity http) throws Exception {
http
.requestMatchers()
.antMatchers("/login", "/", "/customer/**", "/registration", "/admin/**")
.and()
.authorizeRequests()
.antMatchers("/admin/**").hasAuthority("ADMIN").antMatchers("/customer/**").hasAuthority("CUSTOMER")
.antMatchers("/login", "/registration", "/").permitAll()
.anyRequest().authenticated()
.and()
.httpBasic().and().csrf().disable()
.formLogin() //login configuration
.loginPage("/login")
.loginProcessingUrl("/login")
.usernameParameter("email")
.passwordParameter("password")
.defaultSuccessUrl("/customer/home")
.and().logout() //logout configuration
.logoutUrl("/logout")
.logoutSuccessUrl("/login")
.and().exceptionHandling() //exception handling configuration
.accessDeniedPage("/error");
}

Answer 1

A workaround is to submit a 'hidden' form:
<a href="javascript: document.logoutForm.submit()" > Logout Link </a>
<form name="logoutForm" th:action="#{/logout}" method="post" th:hidden="true">
<input hidden type="submit" value="Logout"/>
</form>