I'm trying to achieve something like the following:
"SELECT * FROM lists WHERE school_name LIKE '%" . $search . "%'"
Eloquent and Query builder
Thanks in advance.
$results = List::where('school_name', 'like', '%' . $search . '%')->get();
This assumes that you have a model called 'List' and a database table called 'lists'. If you do not have a model directly coupled, you could use the following query:
$results = DB::table('lists')->where('school_name', 'like', '%' . $search . '%')->get();
You can also only get the first result by using first() instead of get()
Here is the documentation describing the query builder:
https://laravel.com/docs/5.6/queries
Related
I have a little problem to make a query in my laravel application :
I have a table which displays all the customers of my shop.
We are many administrators, and each one have his own shop and his own customers.
The user table has a field 'shop_id' to filter that and the table will only displays the customers who have the same 'shop_id' as the authentified admin.
So I have this query :
$customers = Customer::where('shop_id', Auth::user()->shop_id)->paginate(12);
But we have a lot of customers, so I want to filter those customers. I use a livewire component to make this filter dynamic with a public $search.
So my new query is :
$customers = Customer::where('shop_id', Auth::user()->shop_id)->where('name', 'like', '%' . $this->search . '%')->paginate(12);
Everything's ok if I don't want to add some additionnal filters. But I need to filter by name, by reference_client, and by society name, everything in the same search input.
I thought the next query were correct :
$customers = Customer::where('shop_id', Auth::user()->shop_id)->where('name', 'like', '%' . $this->search . '%')->orWhere('society', 'like', '%' . $this->search . '%')->orWhere('reference', 'like', '%' . $this->search . '%')->paginate(12);
But the orWhere clauses cancel the first where clause (relative to shop_id) : the table displays all the customers, not only the customers who have the good 'shop_id'.
I imagine that I have to combine the 'search' queries in a function, but I have some problem to realize that.
I hope someone could help me, it would be great :)
Thanks in advance
I think I found the solution, a function a the where clause as i thought : $customers = Customer::where('shop_id', Auth::user()->shop_id)->where(function($q) { $query->where('name', 'like', '%'.$this->search.'%')->orWhere('company', 'like', '%'.$this->search.'%')->orWhere('reference', 'like', '%'.$this->search.'%'); })->paginate(12)
I have models: Student, Tutor, Country.
Main model is Student with code:
public function studentTutors()
{
return $this->morphedByMany(Tutor::class, 'studentable')
->with('tutorAddresses');
}
Then relations.
Tutor:
public function tutorAddresses()
{
return $this->hasMany(TutorAddress::class, 'tutor_id', 'id')
->with('tutorCountry');
}
TutorAddress:
public function tutorCountry()
{
return $this->hasOne(Country::class, 'country_id', 'country_id')
->where('user_lang', 'en');
}
How do I use it:
$paginator = $student->studentFavouriteTutors()
->getQuery() //for paginate
->where(function ($query) use ($searchPhraze) {
if (strlen(trim($searchPhraze))) {
return $query
->where('username', 'like', '%' . $searchPhraze . '%')
->orWhere('firstname', 'like', '%' . $searchPhraze . '%')
->orWhere('lastname', 'like', '%' . $searchPhraze . '%');
}
})
->paginate($pages, $columns, $pageName, $page);
Question:
I am searching in tutors table (Tutor) for user/first/last names.
Is there are way to search for country name from countries table (Country: tutorCountry)? Lets say, table has 'name' column with country names.
If yes, how should $paginator code look like, to get data from countries table?
Same question goes for relation tutorAddresses. Lets say, table has 'city' column with city names.
Is this possible?
Now, I do not use relations for search, and just do joins.
BTW: I tried hasManyThrough relation, but it does not seem to pass data from that 'through' table, so this is not going to work for me. Also, my 'through' relations go a bit too deep for it (unless I do not understand something as far as this relation is concerned).
EDIT:
Answer by jedrzej.kurylo is perfect!
I just want to add, for all these, who look for a way to search within relation of a relation, like in my case:
studentTutors / tutorAddresses / tutorCountry
... where within model Student, I also want to look for country name inside of Country model, that is deeper in chain of relations and is not directly related to Tutor, but to TutorAddress, which is related to Tutor.
It is just a question of nesting queries:
$searchPhraze = 'France';
$res = $student->studentFavouriteTutors()
//first relation level
->whereHas('tutorAddresses', function($query) use ($searchPhraze) {
//deeper relation
$query->whereHas('tutorCountry', function($query) use ($searchPhraze) {
$query->where('country', 'like', '%' . $searchPhraze . '%');
});
})->get();
Or you can even combine of searches of parent and child relations:
$searchPhraze = 'Hodkiewiczville';
$res = $student->studentFavouriteTutors()
//first relation level
->whereHas('tutorAddresses', function($query) use ($searchPhraze) {
$query
//first level relation search
->where('city', 'like', '%' . $searchPhraze . '%')
//deeper relation
->orWhereHas('tutorCountry', function($query) use ($searchPhraze) {
$query->where('country_label', 'like', '%' . $searchPhraze . '%'));
});
})->get();
Above code found related datasets as expected.
Thou, I am not sure as to benchmark of this.
You can search data in related tables using whereHas() function, e.g.:
$student->studentFavouriteTutors()
->whereHas('tutorAddresses', function($query) use ($searchPhraze) {
$query->where('city', 'like', '%' . $searchPhraze . '%');
})->get();
This will get you all student's favourite tutors that have an address where city column contains given phrase.
I have this search query for Post model in Laravel:
return $q ->where('title', 'like', '%'.$keyword.'%')
Which works totally fine. In my Post model I also have a relation database categories. This is available as an object in my returned post object.
Is there a way I can query the category -> name?
I have tried:
return $q ->where('category->name', 'like', '%'.$keyword.'%')
I believe what you are looking for can be found here: https://laravel.com/docs/5.6/eloquent-relationships#querying-relations
For your use case you need to make sure you have the relationship established in your Post model. If that is set your query should look similar to the following:
return $q->where('title', 'like', '%'.$keyword.'%')->whereHas('category',
function ($query) use ($keyword) {
$query->where('name', 'like', '%'.$keyword.'%');
})->get();
Hope this helps!
If you're db is well structured - then will want to use Laravel's ORM for this stuff.
https://laravel.com/docs/5.6/eloquent#introduction
I assume that you have Models:
Post
Category
Also that you have category_id as a foreign key in Post model.
This is basic structure.
I assume that you want to search Posts and Categories same time so you can do something like this:
return Post::leftJoin('categories', 'posts.category_id', '=', 'categories.id)
->where('categories.name', 'like', '%' . $keyword . '%')
->orWhere('posts.title', 'like', '%' . $keyword . '%')
->get();
I have this SQL query:
SELECT * FROM books WHERE id IN
(SELECT book_id FROM `author_book` WHERE author_book.author_id IN
(SELECT id FROM authors WHERE self_name like "%ори%" OR father_name LIKE "%ори%" OR family_name LIKE "%ори%"))
It works, but I need convert to Laravel eloquent.
I try this:
DB::select("SELECT * FROM books WHERE id IN "
. "(SELECT book_id FROM `author_book` WHERE author_book.author_id IN "
. "(SELECT id FROM authors WHERE self_name like '%" . $attributes['search'] . "%' "
. "OR father_name LIKE '%" . $attributes['search'] . "%' "
. "OR family_name LIKE '%" . $attributes['search'] . "%'))");
And this works, but can't use pagination. Does anyone have any idea?
If you want Eloquent solution, use the whereHas() method:
Book::whereHas('authors', function($q) use($search) {
$q->where('self_name', 'like', '%' . $search . '%')
->orWhere('father_name', 'like', '%' . $search . '%')
->orWhere('family_name', 'like', '%' . $search . '%')
})->get();
This will work if you properly defined relationships. In the Book model:
public function authors()
{
return $this->belongsToMany(Author::class);
}
And in the Author model:
public function books()
{
return $this->belongsToMany(Book::class);
}
I have a table that I am running a search on. Foo. I want to check if the search term is like a bunch of different fields in the table. But I want the results to be forced to be "active".
I am using Laravel 5.0
$foos = DB::table('foo')
->where('name', 'LIKE', '%' . $query . '%')
->orWhere('description', 'LIKE', '%' . $query . '%')
->orWhere('address_city', 'LIKE', '%' . $query . '%')
->orWhere('short_description', 'LIKE', '%' . $query . '%')
->orWhere('interview', 'LIKE', '%' . $query . '%')
->get();
$foos = $foos->where('active', true)->get();
Collection has a where method similar to query builder.
$activeFoos = $foos->where('active', true);
https://laravel.com/docs/5.4/collections#method-where
Edit :
I understand what you need from the comments now. Try the code below, and also note that i changed your original $query to $find. So keep that in mind.
$foos = DB::table('foo')
->where('active', true)
->where(function ($query) use ($find) {
$query->where('name', 'LIKE', "%{$find}%")
->orWhere('description', 'LIKE', "%{$find}%")
->orWhere('address_city', 'LIKE', "%{$find}%")
->orWhere('short_description', 'LIKE', "%{$find}%")
->orWhere('interview', 'LIKE', "%{$find}%");
})
->get();
Is the value of active actually true or just truthy (such as an integer of 1)?
For loose comparisons then you'll need to use whereLoose('active', true), otherwise Laravel's method where() on Collections will perform strict type comparisons.
Like Sandeesh said, you'll need to remove the get() since get() is a query builder method, Collections where() methods return a new collection not a builder instance.