if folders exist - by using wildcard [duplicate] - bash

Question

This question already has answers here:
Test whether a glob has any matches in Bash
(22 answers)
Closed 4 years ago.
or "How to handle prefixed folder names?"
Inside a folder I have two (or more) foo_* folders
foo_0
foo_1
What I'm trying to achieve is to
perform an action if there's 1 or more foo_* folders
Use a wildcard *
Currently I'm doing it this way (going directly to check if directory foo_0 exists):
prefix=foo_
if [ -d "./${prefix}0/" ]; then
printf "foo_0 folder found!"
# delete all foo_* folders
fi
Having directories 0-to-N so the above works, but i'm not sure I'll always have a foo_0 folder...
I'd like to do use a wildcard:
prefix=foo_
if [ -d "./${prefix}*/" ]; then # By using wildcard...
printf "One or more foo_* folders found!" # this never prints
# delete all foo_* folders
fi
I've read that a wildcard * inside quotes loses its powers, but placing it outside quotes throws :
if [ -d "./${prefix}"* ] <<< ERROR: binary operator expected
Or is it possible to use some sort of regex like? ./foo_\d+ ?
The only solution I don't (arguably) like, is by using set
set -- foo_*
if [ -d $1 ]; then
printf "foo_* found!"
fi
but it wipes program arguments.
Is there any other nice solution to this I'm missing?

Answer 1

I think a nice solution for pretty much all such cases is to use ls in the test, in that it often works quite simply:
if [ -n "$(ls -d foo_*)" ]; then ... If you want to do more regexp-like matching you can shopt -s extglob and then match with ls foo_+([0-9]).
There's also an all-bash solution using several shell options, but it's not as easy to remember, so I'll leave that to another poster ;-)
EDIT: As #PesaThe pointed out, using ls foo_* would fail if there's only one empty matching directory, as just the empty contents of that directory would get listed and ls foo_* would not only match directories, so it's preferable to use -d.