I'm very new to both three.js & to js in general.
1st I select a polyHedron geometry with a dat.gui checkbox
which renders say a tetrahedron. these selections work.
I also have a dat.gui checkbox to either phongfill or wireframe render.
I initially wanted just a wireframe type mesh but not with all of the internal triangles. I found the edgesgeometry() function which draws pretty much what I want(hard edges only). there is however a known issue with linewidth not working in windows anymore. all lines drawn as strokeweight/width 1.
I'd like to use tubeGeometry() to draw tubes of whatever radius as opposed to 1weight lines. I know I'll have to draw something such as a sphere at/over the connection vertices for it to not look ridiculous.
geo = new THREE.TetrahedronBufferGeometry(controls0.Radius,controls0.Detail);
...
egeo = new THREE.EdgesGeometry( geo );
lmat = new THREE.LineBasicMaterial({ color: 0x0099ff, linewidth: 4 });
ph = new THREE.LineSegments( egeo, lmat );
scene.add(ph);
....
playing around in the console I found some geometry/bufferGeomery arrays that are likely the vertices/indices of my selected X-hedron as their sizes change with type(tetra/icosa etc) selection & detail increase/decrease:
//p = dome.geometry.attributes.uv.array;
p = egeo.attributes.position.array
//p = geo.attributes.uv.array
...
var path = new THREE.Curve();
path.getPoint = function (t) {
// trace the arc as t ranges from 0 to 1
var segment = (0 - Math.PI*2) *t;
return new THREE.Vector3( Math.cos(segment), Math.sin(segment), 0);
};
var geomet = new THREE.TubeBufferGeometry( path, 10, 0.2, 12, false );
var mesh = new THREE.Mesh( geomet, mat );
scene.add( mesh );
from above the tubeGeometry() draws fine separately as well but with the "path" made by that curve example. How can I use the vertices from my tetrahedron for example to create that "path" to pass to tubegeometry() ?
maybe a function that creates "segment vectors" from the vertices ?
I think it needs other properties of curve/path as well ?
I'm quite stuck at this point.
ANY Help, suggestions or examples would be greatly appreciated !
thanks.
You can try to create a TubeGeometry for each edge. Generate a LineCurve3 as the input path. Use the vertices of the edge as the start and end vector for the line.
Consider to use something like "triangulated lines" as an alternative in order to visualize the wireframe of a mesh with a linewidth greater than 1. With the next release of three.js(R91) there are new line primitives for this. Demo:
https://rawgit.com/mrdoob/three.js/dev/examples/webgl_lines_fat.html
This approach is much more performant than drawing a bunch of meshes with a TubeGeometry.
Related
I want to create a plane and set the x,y,z locations for the plane individually. So, in three.js it would be something like this ...
var plane = new THREE.PlaneGeometry(planeSize, planeSize, planeDefinition, planeDefinition);
var plane = new THREE.Mesh(plane, new THREE.MeshBasicMaterial({
color: meshColor,
wireframe: true
}));
for (var i = 0; i < plane.vertices.length; i++) {
plane.vertices[i].z += Math.random() * vertexHeight - vertexHeight;
plane.vertices[i]._myZ = plane.vertices[i].z
}
I don't need to update these vertices locations, so I don't need to use a hook of any kind. Is there a parameter to feed vertices locations directly into the react component? Is there a better way to do this? I tried creating the vertices and then feeding them into the vertices parameter with a primitive, but that requires you to make the faces as well and I could not get that to work.
Thanks
You can't feed vertices directly to the component, you'd have to set that imperatively like in Three.js. You could either get a ref to the geometry component and modify it in useLayoutEffect, or create the geometry inside of something like useMemo or useState and assign it to the geometry prop of the <mesh>. Note that PlaneGeometry is now a BufferGeometry in Three.js r125 so you can't set vertices like you've shown anymore.
I'm doing something like this, How to create a custom square in a-frame but with custom shapes (i.e. drawing around an image to make a hotspot to make part of that image interactive)
I've got the line working and I'm now trying to convert this into a fill.
this._mesh = make('a-plane', {
geometry:"buffer: false"
}, this.el)
this._mesh.addEventListener('loaded', e => {
this._mesh.getObject3D('mesh').geometry.vertices = this._points
this._mesh.getObject3D('mesh').geometry.computeFaceNormals()
this._mesh.getObject3D('mesh').geometry.computeVertexNormals()
})
I'm getting close but it's only showing one triangle i.e. something like this
How do i get the shape to fill the whole area? I have done this before with a ConvexGeometry and Quick hull but it seems cumbersome.
I got the idea for updating the vertices of a plane from the above post.
If you create an array with Vector2 objects representing the contour of your shape in CCW order, you can use an instance of Shape and ShapeBufferGeometry to achieve the intended result. Just pass the array of points to the ctor of Shape. The following official three.js example demonstrates this approach:
https://threejs.org/examples/webgl_geometry_shapes
BTW: Instead of defining the contour by an array of points, you can also use the API of Shape to define shapes. A simple triangle would look like so:
var triangleShape = new THREE.Shape()
.moveTo( 80, 20 )
.lineTo( 40, 80 )
.lineTo( 120, 80 )
.lineTo( 80, 20 );
var geometry = new THREE.ShapeBufferGeometry( shape );
var mesh = new THREE.Mesh( geometry, material );
three.js R113
I'm working on an app where I visualize ATV trails in a 3d perspective (NAIP imagery draped over elevation data). I am using three.js for the rendering engine.
In the above image, the white line you see is just a THREE.Line instance, where I convert a trails gps coordinates into threejs coordinates. I'd like to add more of 3d perspective to this line. I tried implementing a THREE.TubeGeometry where the path was a THREE.CatmullRomCurve3 using the same Vector3 points as how I built the line you see in the image above. That did not produce a desirable result...
From the many, many THREE examples I have looked at, I really think an extruded geometry would achieve the look I am after... But I cant for the life of me figure out how to extrude a geometry for the line. Any suggestions/thoughts?
UPDATE 1:
Here is my desired look (same trail - no imagery). This image was produced in QGIS using the Q2Threejs plugin
UPDATE 2: Here is a code of how I have attempted to create a tubegeometry. Maybe I am messing something up in there...
// trailVectors are an array of Vector3 - same as ones used to create line
var trailCurve = new THREE.CatmullRomCurve3(trailVectors);
var tubeGeometry = new THREE.TubeGeometry(trailCurve,80,1,15,false);
var material = new THREE.MeshBasicMaterial({color:0x00ff00});
var tubeMesh = new THREE.Mesh(tubeGeometry,material);
var wireframeMaterial = new THREE.LineBasicMaterial({color:0xffffff,lineWidth:2});
var wireframe = new THREE.Mesh(tubeGeometry,wireframeMaterial);
tubeMesh.add(wireframe);
scene.add(tubeMesh);
UPDATE 3
THREE.TubeGeometry(trailCurve,80,4,2,false) per mzartman request
I think that you should be able to achieve what you want with a TubeGeometry. I think the big thing is that your example (from the picture shown) has more than 2 radius segments. That gives it the tubular shape and makes it look sort of like a blob. If you set the radial segment count to 2 (as it's shown below) then I think it would look a lot better.
tubeGeometry = new THREE.TubeBufferGeometry(
[YOUR_PATH_HERE],
params.extrusionSegments, // <--- Edit this for higher resolution on the spline
3, // <--- This defines the height
2, // <--- This 2 keeps 2D (i.e. not a tube!!!!)
true );
var mesh = new THREE.Mesh( geometry, material );
var wireframe = new THREE.Mesh( geometry, wireframeMaterial );
mesh.add( wireframe );
scene.add( mesh );
Update:
I think that you might do better with a material that shows some shadow like the MeshPhong. Also, to do the wireframe you want to add it as an option in the material initialization. Give it a show with the following:
var tubeGeometry = new THREE.TubeGeometry(curve,80,1,2,false);
var material = new THREE.MeshPhongMaterial({color:0x00ff00, wireframe: true});
var tubeMesh = new THREE.Mesh(tubeGeometry,material);
scene.add(tubeMesh);
I want to use a texture on the surface of my extruded geometry. I have been researching custom UVgenerators for a while now, and have found these related questions:
1.) How to apply a texture to THREE.ExtrudeGeometry?
2.) Loaded texture appears blurred, or like a single color. How to make the texture crisp and sharp
However, the method proposed to divide my geometry points by 1000 and to mesh.scale.set(1000,1000,1) doesn't work because my geometry is no longer in the correct place. I would prefer to specify the UV Mapping. One answer says to implement a custom uvgenerator based on the source code, but I am stuck & can't figure out what to do.
This is my geometry creation, the material is 512x512px, how can I map a texture onto the top?:
pointList=[[0,0,0],
[0,1000,0],
[750,1000,0],
[750,750,0],
[1000,750,0],
[1000,0,0]]
for (i=0;i < pointList.length; i++) {
point = pointList[i];
x = point[0];
y = point[1];
myPoints.push( new THREE.Vector2 (x,y) );
}
myShape = new THREE.Shape( myPoints );
extrusionSettings = {
amount:height
};
myGeometry = new THREE.ExtrudeGeometry( myShape, extrusionSettings );
resultshape = new THREE.Mesh( myGeometry, material );
You can specify custom UVs for your ExtrudeGeometry by specifying your own UVGenerator, one of the properties of extrusionSettings.
To specify your custom UV generator, you can use as a template THREE.ExtrudeGeometry.WorldUVGenerator, which can be found in src/extras/geometries/ExtrudeGeometry.js.
There is a simpler solution that may work for you, however.
Instead of a custom UV generator, you can take advantage of the offset and repeat properties of your texture. Use the following pattern:
texture.wrapS = texture.wrapT = THREE.RepeatWrapping;
texture.repeat.set( 1 / 500, 1 / 500 );
texture.offset.set( 0.1, 0.5 );
three.js r.68
I have some code similar to the following...
this.texture = new THREE.ImageUtils.loadTexture( 'spritesheet.png' );
this.material = new THREE.MeshBasicMaterial( { map: this.texture, side:THREE.DoubleSide } );
this.geometry = new THREE.PlaneGeometry(32, 32, 1, 1);
this.sprite = new THREE.Mesh( this.geometry, this.material );
game.scene.add( this.sprite );
I've also tried along the lines of...
this.material = new THREE.SpriteMaterial( {
map: image,
useScreenCoordinates: true,
alignment: THREE.SpriteAlignment.center
} );
this.sprite = new THREE.Sprite( this.material );
These display the full spritesheet (sort of), as I would expect without further settings.
How do I align the sprite so it only displays say 32x32px starting at offset 50,60 for example ? The three.js documentation doesn't seem have much information, and the examples I've seen tend to use one image per sprite (which may be preferable, or only way possible ?)
Edit: I've spotted a material uvOffset and uvScale that I suspect is related to alignment in a Sprite object if anyone knows how these work. Will dig further.
Well, there is a "uvOffset" and "uvScale" parameter in spriteMaterial , i think you could use those but I cannot present any source code to you.
What you can of course do is using PlaneGeometry and calculate UV Coordinates for the 2 triangles (the plane). For example top-left is your offset and bottom right is calculated from a given offset and size (32x32) but using the whole image size in pixels to get the UV coordinates between 0 and 1
for example topleft is (50/imageSize, 60/imagesize) and bottom right is ( (50+32)/imgSize, (60+32)/imgSize). I think this should work, although i am not quite sure if you would get the result you want as OpenGL treats images "up side down". But you can try and go on from here. Hope this helps.