Zip directory without header [duplicate] - go

Question

I want to zip some directory inside content into zip file
e.g. assume i’ve this directory structure
dir1
file1.html
file2.go
Now I want to zip it to dir1.zip which is working
when I extract it I got the same structure...
I want to zip the content inside that when I unzip it I get the files inside without the `dir1' folder as root after extracting it
file1.html
file2.go
I try to play with the path’s with this code and it doesn’t work,
Any idea what I miss here ?
i've tryied
func Zipit(source, target string) error {
zipfile, err := os.Create(target)
if err != nil {
return err
}
defer zipfile.Close()
archive := zip.NewWriter(zipfile)
defer archive.Close()
info, err := os.Stat(source)
if err != nil {
return nil
}
var baseDir string
if info.IsDir() {
baseDir = filepath.Base(source)
}
filepath.Walk(source, func(path string, info os.FileInfo, err error) error {
if err != nil {
return err
}
header, err := zip.FileInfoHeader(info)
if err != nil {
return err
}
if baseDir != "" {
header.Name = filepath.Join(baseDir, strings.TrimPrefix(path, source))
}
if info.IsDir() {
header.Name += "/"
} else {
header.Method = zip.Deflate
}
writer, err := archive.CreateHeader(header)
if err != nil {
return err
}
if info.IsDir() {
return nil
}
file, err := os.Open(path)
if err != nil {
return err
}
defer file.Close()
_, err = io.Copy(writer, file)
return err
})
return err
}
dir.Zipit("path/dir1" +"/", "test"+".zip")
Or maybe there is simpler way in GO to achieve this?

Answer 1

Assuming you are calling your function as follows:
Zipit("dir1/", "dir1.zip")
All you need to do is remove the baseDir that is being added to the filename inside the archive.
You currently have the following code:
if baseDir != "" {
header.Name = filepath.Join(baseDir, strings.TrimPrefix(path, source))
}
baseDir here is dir1.
Simply omit the baseDir (but to keep trimming the prefix):
header.Name = strings.TrimPrefix(path, source)
This is very similar to Unzip artifacts with different name where all you need to do is modify header.Name as you see fit. It sounds like you need to examine the various filepath functions to see how they can help you.