ls -l | grep "Feb 22" | grep -l "good" *
This is the command i am using . i have 4 files among which one file contains the world good . I want to list that file . And that file creation is the current date . based on both the criteria i want to list that file
Try this :
find . -type f -newermt 2018-02-21 ! -newermt 2018-02-22 -exec grep -l good {} \;
or
find . -type f -newermt 2018-02-21 ! -newermt 2018-02-22 | xargs grep -l good
And please, don't parse ls output
Hi Try with below command. How it works? Here find command with parameter -mtime -1 will search for files with current date in current directory as well as its sub directories. Each file found will be pass to grep command one at a time. grep command will check for the string in that file (means each file passes to it)
find . -mtime -1 -type f | xargs grep -i "good"
In the above command it will list all the file with current date. To list a files of specific kind you below command. Here I am listing only txt files.
find . -name "*.txt" -mtime -1 -type f | xargs grep -i "good"
find . is for running it from current directory (dot means current directory). To run it from a specific directory path modify like below:-
find /yourpath/ -name "*.txt" -mtime -1 -type f | xargs grep -i "good"
Also grep -i means "ignore case". For a specific case just use grep "good"
Related
The below command will show how many characters contains in every file in current directory.
find -name '*.*' |xargs wc -c
I want to write the standout into a file.
find -name '*.*' |xargs wc -c > /tmp/record.txt
It encounter an issue:
wc: .: Is a directory
How to write all the standard output into a file?
Why -name '*.*'? That will not find every file and will find directories. You need to use -type f, and better than piping the result to xargs is using -exec:
find . -type f -maxdepth 1 -exec wc -c {} + > /tmp/record.txt
-maxdepth 1 guarantees that the search won't dive in subdirectories.
I think you maybe meant find |xargs wc -c?
find -name '.' just returns .
Filter only files, if you want only files.
find -type f
it should display only the file names without the.sh
Example
$>./file.sh | cat -e
you can do :
find . -maxdepth 1 -type f -name \*.sh | sed 's|.sh$||'
remove the maxdepth 1 option if you want to find all the files recursively
You can just do ls | grep -v .sh to find in the current directory.
-v, --invert-match
Invert the sense of matching, to select non-matching lines.
If you need system-wide search, you'll need find:
find / -type f ! -name "*\.sh"
/ means root folder
type f = file
! -name = not sending with .sh
I tried to list the zipped files in sort order and transfer this to new file, but it does not work properly in shell script. Why my script is not working?
ls |grep gz|sort -t '.' -k 2,2n >filename;
I did not find any problem with your commands. But they do not seem the right way to do this, at least to me. These two ways I'm pasting I think are better. Try them out.
With only names :
find . -type f -name '*.html' 2>/dev/null -exec basename {} \; | sort > filename.txt
With full paths :
find . -type f -name '*.html' 2>/dev/null | sort > filename.txt
You can also add the "-maxdepth 1" flag to search only on the current directory where you are running this, and not recursively within nested dirs :
find . -type f -maxdepth 1 -name '*.html' 2>/dev/null | sort > filename.txt
Hope this helps you :)
I have a bash script:
for entry in "/home/pictures"/*
do
echo "ls -larth $entry"
done
I want to list also the files in subfolders and include their path
I want to sort the results by date
It must be a bash script, because some other software (Jenkins) will call it .
Try find.
find /home/pictures -type f -exec ls -l --full-time {} \; | sort -k 6
If there are no newlines in file names use:
find /home/pictures -type f -printf '%T# %p\n'|sort -n
If you can not tolerate timestamps in output, use:
find /home/pictures -type f -printf '%28T# %p\n' | sort -n | cut -c30-
If there is possibility of newlines in file name, and, if you can make the program that consumes the output accept null terminated records, you can use:
find /home/pictures -type f -printf '%T#,%p\0' | sort -nz
For no timestamps in output, use:
find /home/pictures -type f -printf '%28T# %p\0' | sort -nz | cut -zc30-
P.S.
I have assumed that you want to sort by last modification time.
I found out the solution for my question:
find . -name * -exec ls -larth {} +
I have a script that I'm running from the home directory to search for all files called "script.sh" that contain the string "watermelon". It's not finding anything but I can clearly see these scripts in the subdirectories. Could someone please suggest a change to the command I'm using:
find . -name script.sh | grep watermelon
You need to use xargs:
find . -name script.sh | xargs grep watermelon
xargs will modify the behavior to search within the files, rather than just search within the names of the files.
find returns the filename it finds by default. If you want it to search within the files then you need to pipe it to xargs or use the -exec and -print predicates:
find . -name script.sh -exec grep -q watermelon {} \; -print
use -type f to indicate file
find . -type f -name "script.sh" -exec grep "watermelon" "{}" +;
or if you have bash 4
shopt -s globstar
grep -Rl "watermelon" **/script.sh