Dynamic allowed length in kendoMaskedTextBox - kendo-ui

I need to use kendoMaskedTextBox to allow user type 3-4 numbers and prevent to type more. And I don't want to get spaces in value.
When user enters 123, I need to get 123. I don't want to get 123_.
I need to get it as value, because I'm using Knockout with Kendo controls, there is no way how to use raw function to strip mask.
So I need to set mask like 000_ but get rid of space in value.
Is it possible?

Related

how to distinguish between value zero and blank cells in conditional formatting

The Title explains everything
=$N4=0 < using this custom formula to conditional format a range but the cells that are empty also gets formatted
what can we do for this.
use:
=($N4=0)*($N4<>"")
not sure what the specifics are but within the Format Rules you could also directly use 'is equals to' instead of opting for 'custom formula'

transformer Fill mask bad_words_ids

In the documentation on text generation (https://huggingface.co/transformers/main_classes/model.html#generative-models) there is the option to put
bad_words_ids (List[int], optional) – List of token ids that are not allowed to be generated. In order to get the tokens of the words that should not appear in the generated text, use tokenizer.encode(bad_word, add_prefix_space=True).
Is there a way to use this bad_words_ids but in a Fill mask model?
Thanks

c++11 Using regex for input validation

I have been looking forever how I can use Regex to validate input for c++ 11. What I basically would like is a piece of code that validates a number input within a specific range (for this example lets say 0-9). It should only allow numbers that I want the user to enter within the range. How can I do this?

How do I concatenate string in Pentaho spoon?

I am a newbie to Pentaho (installed today). I was able to do basic transformation in Spoon. Now I need to do some stuff, which I can't figure out how.
my input looks like
2012-09-17|garima|fbhjgjhgj87687jghgj88jgjj|garima#1347868164626|::ffff:120.56.132.137
3rd field is an ID, for which I need to get some information from a REST API
http://api.app.com/app/api/v1/feature/fbhjgjhgj87687jghgj88jgjj
What do I need to do in Spoon to get this done?
Also, data return will be in json format. how do I parse that?
You should first get your input with a CSV File Input using | as delimiter. Then you can get the 3rd field as a string.
Next you probably need to remove all spaces from this string with a String operations step. Look at the Remove special character column, and select space.
Then you need to concatenate it with your http address http://api.app.com/app/api/v1/feature/. For this you'll use a Calculator step. At this step first create a new temporary field tmpAddr, with operation Define a constant value for ... (or something like this, sorry my spoon is in portuguese). At the Field A column you'll write your http address. It's a good practice, after you make this work, to set your address as a system variable so if it changes you don't need to replace it everywhere on your transformations (look at menu Edit -> System Variables).
Now on the same Calculator step create another field, let's say MyAddress, with operation A+B. Choose for Field A the field tmpAddr you just created, and for Field B the 3rd field from your input.
Now on your stream you should have the full address as a field MyAddress. Connect a REST client step. Mark Accept URL from field and choose field MyAddress as URL Field Name. Set Application Type to JSON. Set Result Fieldname as MyResult.
If you need further JSON parsing you can add a Json input step. Set Source is defined in a field and select field MyResult as Get Source from field.
An alternate approach is to use the "Replace in String" step to append the string.
Set 'use RegEx' to Y
Set 'Search' to (.*)
Set 'Replace with' to http://api.app.com/app/api/v1/feature/$1
Set 'Whole Word' to Y
The parentheses in the regex set up a capture group that you can then insert into your replacement string with the $X syntax

Local Currency String conversion

I am maintaining an app for a client that is used in two locations. One in England and one in Poland.
The database is stored in England and uses the format £1000.00 for currency, but the information is being gathered locally in Poland where 1000,00 is the format.
My question is, in VB6 is there a function that takes a currency string in a local format and converts to another, or will I just have to parse the string and replace , or . ?
BTW I have looked at CCur, but not sure if that will do what I want.
The data is not actually stored as the string "£1000.00"; it's stored in some numeric format.
Sidebar: Usually databases are set up to store money amounts using either the decimal data type (also called money in some DBs), or as a floating point number (also called double).
The difference is that when it's stored as decimal certain numbers like 0.01 are represented exactly whereas in double those numbers can only be stored approximately, causing rounding errors.
The database appears to be storing the number as "£1000.00" because something is formatting it for display. In VB6, there's a function FormatCurrency which would take a number like 1000 and return a string like "£1000.00".
You'll notice that the FormatCurrency function does not take an argument specifying what type of currency to use. That's because it, along with all the other locale-specific functions in VB, figures out the currency from the current locale of the system (from the Windows Control Panel).
That means that on my system,
Debug.Print FormatCurrency(1000)
will print $1,000.00, but if I run that same program on a Windows computer set to the UK locale, it will probably print £1,000.00, which, of course, is something completely different.
Similarly, you've got some code, somewhere, I can't tell where, in Poland, it seems, that is responsible for parsing the user's string and converting it to a number. And if that code is in Visual Basic, again, it's relying on the control panel to decide whether "." or "," is the thousands separator and whether "," or "." is the decimal point.
The function CDbl converts its argument to a number. So for example on my system in the US
Debug.Print CDbl("1.200")
produces the number one point two, on a system with the Control Panel set to European formatting, it would produce the number one thousand, two hundred.
It's possible that the problem is that you have someone sitting a computer with the regional control panel set to use "." as the decimal separator, but they're typing "," as the decimal separator.
What database are you using? And what data type is the amount stored in?
As long as you are always converting from one format to another, you do not need to do any parsing, just replace "." with "," or the other way around. You may need to remove the "£"-sign as well if that is stored in your string.
There's probably a correct answer dealing with culture objects and such, but the easiest way would be to taken the input from the polish input, and replace the , with a ., and then store it in your database as type "money" or "decimal". If you know they (possibly configurable per user) are always entering numbers in either Polish or English, you could have a function that you run all the input numbers through to convert the string to a proper "decimal" typed variable. Also, for display purposes you could run it through another similar function to ensure that the user always sees the number format they are comfortable with. The key here is to switch it to a decimal as soon as you get it from the user, and only switch it back to a string at the last step before sending it out to the user.
#KiwiBastard yes i would think so. Are you storing your amount in an "(n)varchar" field or are you using a currency/decimal type field? If the latter is the case, the currency-symbols and separators are added by your client, and there would be no need to replace anything in the database.

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