How can I make this command run on files only?
du -h * | sort -h -r | head -n 5
Now I am using * which runs on all files and directories but I want to change that.
you need to use the find utility to pinpoint only the files:
find . -type f -exec du -h {} + | sort -n -r | head -n 5
also you have a typo, it's sort -n -r not sort -h -r
Maybe it helps
for i in $(ls -d */ | sort -h -r | head -n 5); do du -h $i; done
Related
As an exercise, I should find all .c files starting from my home directory, count the lines of each file and store the sorted output in sorted_statistics.txt, using find, wc, cut ad sort.
I found this command to work
find /home/user/ -type f -name "*.c" 2> /dev/null -exec wc -l {} \; | cut -f 1 -d " " | sort -n -o sorted_statistics.txt
but I can't understand why
find /home/user/ -type f -name "*.c" 2> /dev/null -exec wc -l {} \; | cut -f 1 -d " " >> sorted_statistics.txt | sort -n sorted_statistics.txt
stops just before the sort command.
Just out of curiosity, why is that?
You were appending everything to sorted_statistics.txt ( consuming all the output ) and then trying to use that none existing output in a pipe for sort. I have corrected your code so it works now.
find /home/user/ -type f -name "*.c" 2> /dev/null -exec wc -l {} \; | cut -f 1 -d " " >> tmp.txt && sort -n tmp.txt > sorted_statistics.txt
Regards!
This part of the command makes no sense:
cut -f 1 -d " " >> sorted_statistics.txt | sort ...
because the output of cut is appended to the file sorted_statistics.txt and no output at all goes to the sort command. You will probably want to use tee:
cut -f 1 -d " " | tee -a sorted_statistics.txt | sort ...
The tee command sends its input to a file and also to the standard output. It is like a Tee junction in a pipeline.
I want to pipe the output of ls into head and pipe it into mv.
I used the following command on terminal but it isn't working properly.
ls -t Downloads/ | head -7 | xargs -i mv {} ~/cso/
Please do rectify the error. Thanks in advance!
It is well documented that parsing ls output is not recommended. You can use this safe approach using find + sort + cut + head + xargs pipeline:
find . -maxdepth 1 -type f -printf '%T#\t%p\0' |
sort -z -rnk1 |
cut -z -f2 |
head -z -n 7 |
xargs -0 -I {} mv {} ~/cso/
Use -I like here :
ls -t Downloads/* | head -7 | xargs -I '{}' mv '{}' ~/cso/
I have an alias in my bashrc file that outputs current folder contents and system available storage, updated continuously by the watch function.
alias wtch='watch -n 0 -t "du -sch * -B 1000000 2>/dev/null | sort -h && df -h -B 1000000| head -2 | awk '{print \$4}'"'
The string worked fine until I put in the awk part. I know I need to escape the single quotation marks, while still staying in the double quotation marks and the $4 but I haven't been able to get it to work. What am I doing wrong?
This is the error I get
-bash: alias: $4}": not found
Since the quoting for the alias is making it tough, you could just make it a function instead:
wtch() {
watch -n 0 -t "du -sch * -B 1000000 2>/dev/null | sort -h && df -h -B 1000000| head -2 | awk '{print $4}'"
}
This is a lot like issue 2 in the BashFAQ/050
Also, a minor thing but you can skip the head process at the end and just have awk do it, even exiting after the second row like
wtch() {
watch -n 0 -t "du -sch * -B 1000000 2>/dev/null | sort -h && df -h -B 1000000| awk '{print $4} NR >= 3 {exit}'"
}
In this case you can use cut instead of awk. And you'll have the same effect.
alias wtch="watch -n 0 -t 'du -sch * -B 1000000 2>/dev/null | sort -h && df -h -B 1000000| head -2 | cut -d\ -f4'"
Explaining cut:
-d option defines a delimiter
-d\ means that my delimiter is space
-f selects a column
-f4 gives you the fourth column
So my objective here is to print a small graph, followed by the file size and the path for the 15 largest files. However, I'm running into issues trying to call the create_graph function on each line. Here's what isn't working
find $path -type f | sort -nr | head -$n | while read line; do
size=$(stat -c '%s' $line)
create_graph $largest $size 50
echo "$size $line"
done
My problem is that it isn't sorting the files, and the files aren't the n largest files. So it appears my "while read line" is messing it all up.
Any suggestions?
The first command,
find $path -type f
just prints out file names. So it can't sort them by size. If you want to sort them by size, you need to make it print out the size. Try this:
find $path -type f -exec du -b {} \; | sort -nr | cut -f 2 | head -$n | ...
Update:
Actually, only the first part of that seems to do everything you want from it:
find $path -type f -exec du -b {} \; | sort -nr | head -$n
will print out a table with size and filename, sorted by file size, and limited to $n rows.
Of course I don't know what the create_graph does.
Explanation:
find $path -type f -exec du -b {} \;
Find all files (not directories or links) in ${path} or its subdirectories, and execute the command du -b <file> on each.
du -b <file>
will output the size of the file (disk usage). See man du for details.
This will produce something like this:
8880 ./line_too_long/line.o
4470 ./line_too_long/line.f
934 ./random/rand.f
9080 ./random/rand
23602 ./random/monte
7774 ./random/monte.f90
13610 ./format/form
288 ./format/form.f90
411 ./delme.f90
872 ./delme_mod.mod
9029 ./delme
So for each file, it prints the size (-b for 'in bytes').
Then you can do a numerical sort on that.
$ find . -type f -exec du -b {} \; | sort -nr
23602 ./random/monte
13610 ./format/form
9080 ./random/rand
9029 ./delme
8880 ./line_too_long/line.o
7774 ./random/monte.f90
4470 ./line_too_long/line.f
934 ./random/rand.f
872 ./delme_mod.mod
411 ./delme.f90
288 ./format/form.f90
And if you then cut it off after the first, say five entries:
$ find . -type f -exec du -b {} \; | sort -nr | head -5
23602 ./random/monte
13610 ./format/form
9080 ./random/rand
9029 ./delme
8880 ./line_too_long/line.o
Some idea to put that back together:
find . -type f -exec du -b {} \; | sort -nr | head -$n | while read line; do
size=$(cut -d ' ' -f 1 <<< $line)
file=$(cut -d ' ' -f 2 <<< $line)
create_graph $largest $size 50
echo $line
done
Note that I have no idea what create_graph is or what $largest contains. I took that straight out of your script.
My linux 'watch' command is quite old and doesn't support '--color' option. How can I have same output like it does? because in my script the loop gives output one after another(of course). But i need it to replace the previous. Is there any tricks with terminal output?
#!/bin/bash
while true
do
/usr/sbin/asterisk -rx "show queue My_Compain" \
| grep Agent \
| grep -v \(Unavailable\) \
| sort -t"(" -k 2 \
| GREP_COLOR='01;31' egrep -i --color=always '^.*[0-9] \(Not in use.*$|$' \
| GREP_COLOR='01;36' egrep -i --color=always '^.*\(Busy*$|$'
sleep 2
done
You can use clear to clear the screen before dumping your output to give the appearance of in-place updates.
To reduce blinking, you can use the age old technique of double buffering:
#!/bin/bash
while true
do
buffer=$(
clear
/usr/sbin/asterisk -rx "show queue My_Compain" \
| grep Agent \
| grep -v \(Unavailable\) \
| sort -t"(" -k 2 \
| GREP_COLOR='01;31' egrep -i --color=always '^.*[0-9] \(Not in use.*$|$' \
| GREP_COLOR='01;36' egrep -i --color=always '^.*\(Busy*$|$'
)
echo "$buffer"
sleep 2
done