How to process (iterate through) a large JSON file on a hadoop/Spark cluster? - hadoop

I've been looking now for some time, and finding a lot of broken examples and links from the past, but I have a 2 GB file of json data that I need to process line by line, run a significant amount of code on each line, and save out reformatted data to the cluster.
I've been trying to do this in Spark 2.0/PySpark, but am not having much luck. I can do it on a smaller file, but on my actual file my director runs out of heap memory.
When I try and break up the file, I get the error listed here (Spark __getnewargs__ error) but for obviously different reasons, as I'm not referencing columns.
I'm on CentOS6 with Hortonworks, single machine cluster for now. I'm actually looking more for "what I should be doing" than just how to do it. I know that Spark can do this, but if there's a better way, then I'm happy to explore that as well.

You can define a Hive table on top of your JSON file using JSON serde and then can do analysis using Hive or Spark.

Related

Effectively merge big parquet files

I'm using parquet-tools to merge parquet files. But it seems that parquet-tools needs an amount of memory as big as the merged file. Do we have other ways or configurable options in parquet-tools to use memory more effectively? Cause I run the merge job in as a map job on hadoop env. And the container gets killed every time cause it used more memory than it is provided.
Thank you.
I wouldn't recommend using parquet-tools merge, since it just places row groups one after the another, so you will still have small groups, just packed together in a single file. The resulting file will typically not have noticably better performance, and under certain circumstances it may even perform worse than separate files. See PARQUET-1115 for details.
Currently the only proper way to merge Parquet files is to read all data from them and write it to a new Parquet file. You can do it with a MapReduce job (requires writing custom code for this purpose) or using Spark, Hive or Impala.

Data format and database choices Spark/hadoop

I am working on structured data (one value per field, the same fields for each row) that I have to put in a NoSql environment with Spark (as analysing tool) and Hadoop. Though, I am wondering what format to use. i was thinking about json or csv but I'm not sure. What do you think and why? I don't have enough experience in this field to properly decide.
2nd question : I have to analyse these data (stored in an HDFS). So, as far as I know I have two possibilities to query them (before the analysis):
direct reading and filtering. i mean that it can be done with Spark, for exemple:
data = sqlCtxt.read.json(path_data)
Use Hbase/Hive to properly make a query and then process the data.
So, I don't know what is the standard way of doing all this and above all, what will be the fastest.
Thank you by advance!
Use Parquet. I'm not sure about CSV but definitely don't use JSON. My personal experience using JSON with spark was extremely, extremely slow to read from storage, after switching to Parquet my read times were much faster (e.g. some small files took minutes to load in compressed JSON, now they take less than a second to load in compressed Parquet).
On top of improving read speeds, compressed parquet can be partitioned by spark when reading, whereas compressed JSON cannot. What this means is that Parquet can be loaded onto multiple cluster workers, whereas JSON will just be read onto a single node with 1 partition. This isn't a good idea if your files are large and you'll get Out Of Memory Exceptions. It also won't parallelise your computations, so you'll be executing on one node. This isn't the 'Sparky' way of doing things.
Final point: you can use SparkSQL to execute queries on stored parquet files, without having to read them into dataframes first. Very handy.
Hope this helps :)

Can HBase Access Text Documents and CSV Documents Just as Hadoop?

In Hadoop, I can easily create Map/Reduce apps which access and process data in huge text files and csv files. My question is can Hbase do the same and access such huge files, or HBase has other uses?
Hbase runs queries just as relational databases; so, I kind of have a hard time to understand the advantage of HBase, unless it can access huge text and csv files just as Hadoop does.
First of all Hbase is just a store. And a store never accesses anything. Rather you access the store to fetch or put the data. Like any other datastore Hbase has only one job to do, store your data and make it available to you whenever you need it. You can write MapReduce jobs or sequential Java programs etc etc to put data into Hbase or fetch data from it. It's totally upto you which path you prefer.
Coming to the second part of your question, Hbase never ever works like traditional relational databases. Everything, starting from storing the data to accessing the data, is totally different. The advantage of using Hbase is that you can store really really huge amount of data into it and have random read/write access. The data can be of any type viz. text, csv, tsv, binary etc etc. But, before going ahead, you must think well whether Hbase is a suitable choice for you or not, as one size doesn't fit all.
HTH

replace text in input file with hadoop MR

I am a newbie on the MR and Hadoop front.
I wrote an MR for finding missing's in csv file and it is working fine.
now I have an usecase where i need to parse a csv file and code it with the regarding category.
ex: "11,abc,xyz,51,61,78","11,adc,ryz,41,71,38",.............
now this has to be replaced as "1,abc,xyz,5,6,7","1,adc,ryz,4,7,3",.............
here i am doing a mod of 10 but there will be different cases of mod's.
data size is in gb's.
I want to know how to replace the content in-place for the input. Is this achievable with MR?
Basically i have not seen any file handling or writing based hadoop examples any where.
At this point i do not want to go to HBase or other db tools.
You can not replace data in place, since HDFS files are append only, and can not be edited.
I think simplest way to achiece your goal is to register your data in the Hive as external table, and write your trnasformation in HQL.
Hive is a system sitting aside of hadoop and translating your queries to MR Jobs.
Its usage is not serious infrastructure decision as HBASE usage

Running a MR Job on a portion of the HDFS file

Imagine you have a big file stored in hdtf which contains structured data. Now the goal is to process only a portion of data in the file like all the lines in the file where second column value is between so and so. Is it possible to launch the MR job such that hdfs only stream the relevant portion of the file versus streaming everything to the mappers.
The reason is that I want to expedite the job speed by only working on the portion that I need. Probably one approach is to run a MR job to get create a new file but I am wondering if one can avoid that?
Please note that the goal is to keep the data in HDFS and I do not want to read and write from database.
HDFS stores files as a bunch of bytes in blocks, and there is no indexing, and therefore no way to only read in a portion of your file (at least at the time of this writing). Furthermore, any given mapper may get the first block of the file or the 400th, and you don't get control over that.
That said, the whole point of MapReduce is to distribute the load over many machines. In our cluster, we run up to 28 mappers at a time (7 per node on 4 nodes), so if my input file is 1TB, each map slot may only end up reading 3% of the total file, or about 30GB. You just perform the filter that you want in the mapper, and only process the rows you are interested in.
If you really need filtered access, you might want to look at storing your data in HBase. It can act as a native source for MapReduce jobs, provides filtered reads, and stores its data on HDFS, so you are still in the distributed world.
One answer is looking at the way that hive solves this problem. The data is in "tables" which are really just meta data about files on disk. Hive allows you to set columns on which a table is partitioned. This creates a separate folder for each partition so if you were partitioning a file by date you would have:
/mytable/2011-12-01
/mytable/2011-12-02
Inside of the date directory would be you actual files. So if you then ran a query like:
SELECT * FROM mytable WHERE dt ='2011-12-01'
Only files in /mytable/2011-12-01 would be fed into the job.
Tho bottom line is that if you want functionality like this you either want to move to a higher level language (hive/pig) or you need to roll your own solutions.
Big part of the processing cost - is data parsing to produce Key-Values to the Mapper. We create there (usually) one java object per value + some container. It is costly both in terms of CPU and garbage collector pressure
I would suggest the solution "in the middle". You can write input format which will read the input stream and skip non-relevant data in the early stage (for example by looking into few first bytes of the string). As a result you will read all data, but actually parse and pass to the Mapper - only portion of it.
Another approach I would consider - is to use RCFile format (or other columnar format), and take care that relevant and non relevant data will sit in the different columns.
If the files that you want to process have some unique attribute about their filename (like extension or partial filename match), you can also use the setInputPathFilter method of FileInputFormat to ignore all but the ones you want for your MR job. Hadoop by default ignores all ".xxx" and _xxx" files/dirs, but you can extend with setInputPathFilter.
As others have noted above, you will likely get sub-optimal performance out of your cluster doing something like this which breaks the "one block per mapper" paradigm, but sometimes this is acceptable. Can sometimes take more to "do it right", esp if you're dealing with a small amount of data & the time to re-architect and/or re-dump into HBase would eclipse the extra time required to run your job sub-optimally.

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