I have a query sequence in Vertica below:
drop table [table_name];
create [table_name] as select ...;
drop table [table_name];
create [table_name] as select ...;
select ...;
My resulting file looks like
DROP TABLE
CREATE TABLE
DROP TABLE
CREATE TABLE
column1 | column2 | column3 |
Does Vertica have a configuration parameter that can eliminate the 'DROP' and 'CREATE' table and retains only the SELECT output?
Related
I'm new in Hive. I have three tables like this:
table1:
id;value
1;val1
2;val2
3;val3
table2
num;desc;refVal
1;desc;0
2;descd;0
3;desc;0
I want to create a new table3 that contains:
num;desc;refVal
1;desc;3
2;descd;3
3;desc;3
Where num and desc are columns from table2 and refVal is the max value of column id in table1
Can someone guide me to solve this?
First, you have to create an table to hold this.
CREATE TABLE my_new_table;
After that, you have to insert into this table, as showed here
INSERT INTO TABLE my_new_table
[PARTITION (partcol1=val1, partcol2=val2 ...)]
select_statement1;
In the select_statement1 you can use the same select you would normally use to join and select the columns you need.
For more informations, you can check here
SQL> create table justlike(customerid varchar(19),first_name varchar(40),last_name varchar(100),Address varchar(50),city varchar(30),pincode varchar(10),state varchar(20));
Just use:
desc <table_name>;
This will print the description of your table columns
in your case:
desc justlike;
You can always check the table definition, in case you are using Oracle, by running below query -
SELECT * FROM USER_TAB_COLS
WHERE TABLE_NAME = 'JUSTLIKE';
OR you can write a select on table itself -
SELECT * FROM JUSTLIKE;
I am having an issue creating a table in Hue after I do a bunch of temp. table commands. A very high-level example is below.. I am trying to create a table after the many temporary tables are created.
I am basically trying to create a table of the last select statement but I am running into errors both with the create table line and also determining what the last select * table is called..
With TABLEA as (Select * from TEST1.FILEA),
TableB as (Select * from tableA)
Select * from tableB
where TableB.Curr = 'TYPEE'
CREATE TABLE TEST
row format delimited
fields terminated by '|'
STORED AS RCFile
as Select * from TableB
In your query please follow the syntax and examples as below
create table as <your_with_clause_select_query>
Example:
create table test as
with tableA as ( select * from test1.fileA)
select * from tableA;
You can also use nested select statements with CTAS.
CREATE TABLE TEST AS
select * from (
select
*
from
test1.fileA
) b
row format delimited fields terminated by '|'
STORED AS RCFile
I have orc table in hive I want to drop column from this table
ALTER TABLE table_name drop col_name;
but I am getting the following exception
Error occurred executing hive query: OK FAILED: ParseException line 1:35 mismatched input 'user_id1' expecting PARTITION near 'drop' in drop partition statement
Can any one help me or provide any idea to do this? Note, I am using hive 0.14
You cannot drop column directly from a table using command ALTER TABLE table_name drop col_name;
The only way to drop column is using replace command. Lets say, I have a table emp with id, name and dept column. I want to drop id column of table emp. So provide all those columns which you want to be the part of table in replace columns clause. Below command will drop id column from emp table.
ALTER TABLE emp REPLACE COLUMNS( name string, dept string);
There is also a "dumb" way of achieving the end goal, is to create a new table without the column(s) not wanted. Using Hive's regex matching will make this rather easy.
Here is what I would do:
-- make a copy of the old table
ALTER TABLE table RENAME TO table_to_dump;
-- make the new table without the columns to be deleted
CREATE TABLE table AS
SELECT `(col_to_remove_1|col_to_remove_2)?+.+`
FROM table_to_dump;
-- dump the table
DROP TABLE table_to_dump;
If the table in question is not too big, this should work just well.
suppose you have an external table viz. organization.employee as: (not including TBLPROPERTIES)
hive> show create table organization.employee;
OK
CREATE EXTERNAL TABLE `organization.employee`(
`employee_id` bigint,
`employee_name` string,
`updated_by` string,
`updated_date` timestamp)
ROW FORMAT SERDE
'org.apache.hadoop.hive.ql.io.orc.OrcSerde'
STORED AS INPUTFORMAT
'org.apache.hadoop.hive.ql.io.orc.OrcInputFormat'
OUTPUTFORMAT
'org.apache.hadoop.hive.ql.io.orc.OrcOutputFormat'
LOCATION
'hdfs://getnamenode/apps/hive/warehouse/organization.db/employee'
You want to remove updated_by, updated_date columns from the table. Follow these steps:
create a temp table replica of organization.employee as:
hive> create table organization.employee_temp as select * from organization.employee;
drop the main table organization.employee.
hive> drop table organization.employee;
remove the underlying data from HDFS (need to come out of hive shell)
[nameet#ip-80-108-1-111 myfile]$ hadoop fs -rm hdfs://getnamenode/apps/hive/warehouse/organization.db/employee/*
create the table with removed columns as required:
hive> CREATE EXTERNAL TABLE `organization.employee`(
`employee_id` bigint,
`employee_name` string)
ROW FORMAT SERDE
'org.apache.hadoop.hive.ql.io.orc.OrcSerde'
STORED AS INPUTFORMAT
'org.apache.hadoop.hive.ql.io.orc.OrcInputFormat'
OUTPUTFORMAT
'org.apache.hadoop.hive.ql.io.orc.OrcOutputFormat'
LOCATION
'hdfs://getnamenode/apps/hive/warehouse/organization.db/employee'
insert the original records back into original table.
hive> insert into organization.employee
select employee_id, employee_name from organization.employee_temp;
finally drop the temp table created
hive> drop table organization.employee_temp;
ALTER TABLE emp REPLACE COLUMNS( name string, dept string);
Above statement can only change the schema of a table, not data.
A solution of this problem to copy data in a new table.
Insert <New Table> Select <selective columns> from <Old Table>
ALTER TABLE is not yet supported for non-native tables; i.e. what you get with CREATE TABLE when a STORED BY clause is specified.
check this https://cwiki.apache.org/confluence/display/Hive/StorageHandlers
After a lot of mistakes, in addition to above explanations, I would add simpler answers.
Case 1: Add new column named new_column
ALTER TABLE schema.table_name
ADD new_column INT COMMENT 'new number column');
Case 2: Rename a column new_column to no_of_days
ALTER TABLE schema.table_name
CHANGE new_column no_of_days INT;
Note that in renaming, both columns should be of same datatype like above as INT
For external table its simple and easy.
Just drop the table schema then edit create table schema , at last again create table with new schema.
example table: aparup_test.tbl_schema_change and will drop column id
steps:-
------------- show create table to fetch schema ------------------
spark.sql("""
show create table aparup_test.tbl_schema_change
""").show(100,False)
o/p:
CREATE EXTERNAL TABLE aparup_test.tbl_schema_change(name STRING, time_details TIMESTAMP, id BIGINT)
ROW FORMAT SERDE 'org.apache.hadoop.hive.ql.io.parquet.serde.ParquetHiveSerDe'
WITH SERDEPROPERTIES (
'serialization.format' = '1'
)
STORED AS
INPUTFORMAT 'org.apache.hadoop.hive.ql.io.parquet.MapredParquetInputFormat'
OUTPUTFORMAT 'org.apache.hadoop.hive.ql.io.parquet.MapredParquetOutputFormat'
LOCATION 'gs://aparup_test/tbl_schema_change'
TBLPROPERTIES (
'parquet.compress' = 'snappy'
)
""")
------------- drop table --------------------------------
spark.sql("""
drop table aparup_test.tbl_schema_change
""").show(100,False)
------------- edit create table schema by dropping column "id"------------------
CREATE EXTERNAL TABLE aparup_test.tbl_schema_change(name STRING, time_details TIMESTAMP)
ROW FORMAT SERDE 'org.apache.hadoop.hive.ql.io.parquet.serde.ParquetHiveSerDe'
WITH SERDEPROPERTIES (
'serialization.format' = '1'
)
STORED AS
INPUTFORMAT 'org.apache.hadoop.hive.ql.io.parquet.MapredParquetInputFormat'
OUTPUTFORMAT 'org.apache.hadoop.hive.ql.io.parquet.MapredParquetOutputFormat'
LOCATION 'gs://aparup_test/tbl_schema_change'
TBLPROPERTIES (
'parquet.compress' = 'snappy'
)
""")
------------- sync up table schema with parquet files ------------------
spark.sql("""
msck repair table aparup_test.tbl_schema_change
""").show(100,False)
==================== DONE =====================================
Even below query is working for me.
Alter table tbl_name drop col_name
I read this code from "Hadoop the Definitive Guide":
SELECT a.ad_id, a.campaign_id, a.account_id, b.user_id
FROM dim_ads a JOIN impression_logs b ON (b.ad_id = a.ad_id)
WHERE b.dateid = '2008-12-01') x
INSERT OVERWRITE DIRECTORY 'results_gby_adid'
SELECT x.ad_id, count(1), count(DISTINCT x.user_id) GROUP BY x.ad_id
INSERT OVERWRITE DIRECTORY 'results_gby_campaignid'
SELECT x.campaign_id, count(1), count(DISTINCT x.user_id) GROUP BY x.campaign_id
INSERT OVERWRITE DIRECTORY 'results_gby_accountid'
SELECT x.account_id, count(1), count(DISTINCT x.user_id) GROUP BY x.account_id;
but as my test, using several DISTINCT cannot get right results.
my hiveql as below:
CREATE TABLE IF NOT EXISTS a (logindate int, id int);
then
load local file to this table...
CREATE TABLE IF NOT EXISTS user (id INT) PARTITIONED BY (logindate INT) ROW FORMAT DELIMITED FIELDS TERMINATED BY '\t' STORED AS TEXTFILE;
then
if inserting table separately:
INSERT OVERWRITE TABLE user PARTITION(logindate=20130120) SELECT DISTINCT(id) FROM a WHERE logindate=20130120;
INSERT OVERWRITE TABLE user PARTITION(logindate=20130121) SELECT DISTINCT(id) FROM a WHERE logindate=20130121;
the results are correct;
but if choosing the next multiple insert hql:
FROM a
INSERT OVERWRITE TABLE user PARTITION(logindate=20130120) SELECT DISTINCT(id) WHERE logindate=20130120
INSERT OVERWRITE TABLE user PARTITION(logindate=20130121) SELECT DISTINCT(id) WHERE logindate=20130121;
the results are not correct, both partitions have the same number of records, seems like select from DISTINCT(id) WHERE logindate=20130120 OR logindate=20130121
so is it a bug or did I write some wrong syntax?
DISTINCT has a bit of an odd history in the code as an alias to group by.
If there is a bug, then the version of hive you are using would be important to know since bugs are addressed in each release.
This might work:
FROM a
INSERT OVERWRITE TABLE user PARTITION(logindate=20130120) SELECT id WHERE logindate=20130120 GROUP BY id
INSERT OVERWRITE TABLE user PARTITION(logindate=20130121) SELECT id WHERE logindate=20130121 GROUP BY id;
if that doesn't work, this will definitely work...even though it isn't the approach you were attempting to use...
FROM (select distinct id, logindate from a where logindate in ('20130120','20130121')) subq_a
INSERT OVERWRITE TABLE user PARTITION(logindate=20130120) SELECT id WHERE logindate=20130120
INSERT OVERWRITE TABLE user PARTITION(logindate=20130120) SELECT id WHERE logindate=20130121;