I have following table:
CREATE TABLE logins (
type_id BIGINT NOT NULL,
created_date TIMESTAMP(0) WITHOUT TIME ZONE DEFAULT now() NOT NULL);
INSERT INTO logins VALUES
(5, '1/26/2018 5:00:00 PM'),
(5 ,'1/26/2018 3:45:44 PM'),
(5, '1/26/2018 3:45:44 PM')
When I run this code separately:
SELECT l.type_id , l.created_date FROM logins l
WHERE
l.type_id = 5 AND
l.created_date BETWEEN ((CAST('1/26/2018' AS DATE) - 1) + TIME ' 17:00:00') AND
(CAST('1/26/2018' AS DATE) + TIME ' 17:00:00')
ORDER BY l.created_date DESC
It orders the dates the way I want but when I run following code:
WITH results as (SELECT l.type_id , l.created_date FROM logins l
WHERE
l.type_id = 5 AND
l.created_date BETWEEN ((CAST('1/26/2018' AS DATE) - 1) + TIME ' 17:00:00') AND
(CAST('1/26/2018' AS DATE) + TIME ' 17:00:00')
ORDER BY l.created_date DESC)
SELECT * FROM results
UNION
SELECT 0, NULL
WHERE NOT EXISTS (SELECT * FROM results )
The order by doesn't work at all. I'd like to know the reason.
Put the order by at the end of the sql. Also, UNION removes duplicates while UNION ALL do not remove duplicates. Try this and you will get the same result as previous. Thanks.
WITH results as (SELECT l.type_id , l.created_date FROM logins l
WHERE
l.type_id = 5 AND
l.created_date BETWEEN ((CAST('1/26/2018' AS DATE) - 1) + TIME ' 17:00:00') AND
(CAST('1/26/2018' AS DATE) + TIME ' 17:00:00')
)
SELECT * FROM results
UNION
SELECT 0, NULL
WHERE NOT EXISTS (SELECT * FROM results )
ORDER BY created_date DESC
Related
I have the following recursive CTE which splits each element coming from base per month:
with
base (id, start_date, end_date) as (
select 1, date '2022-01-15', date '2022-03-15' from dual
union
select 2, date '2022-09-15', date '2022-12-31' from dual
union
select 3, date '2023-09-15', date '2023-09-25' from dual
),
split (id, start_date, end_date) as (
select base.id, base.start_date, least(last_day(base.start_date), base.end_date) from base
union all
select base.id, split.end_date + 1, least(last_day(split.end_date + 1), base.end_date) from base join split on base.id = split.id and split.end_date < base.end_date
)
select * from split order by id, start_date, end_date;
It works on Oracle and gives the following result:
id
start_date
end_date
1
2022-01-15
2022-01-31
1
2022-02-01
2022-02-28
1
2022-03-01
2022-03-15
2
2022-09-15
2022-09-30
2
2022-10-01
2022-10-31
2
2022-11-01
2022-11-30
2
2022-12-01
2022-12-31
3
2023-09-15
2023-09-25
The two following stop conditions work correctly:
... from base join split on base.id = split.id and split.end_date < base.end_date
... from base, split where base.id = split.id and split.end_date < base.end_date
The following one fails with the message ORA-32044: cycle detected while executing recursive WITH query:
... from base join split on base.id = split.id where split.end_date < base.end_date
I fail to understand how the last one is different from the two others.
It looks like a bug as all your queries should result in identical explain plans.
However, you can rewrite the recursive sub-query without the join (and using a SEARCH clause so you may not have to re-order the query later):
WITH split (id, start_date, month_end, end_date) AS (
SELECT id,
start_date,
LEAST(
ADD_MONTHS(TRUNC(start_date, 'MM'), 1) - INTERVAL '1' SECOND,
end_date
),
end_date
FROM base
UNION ALL
SELECT id,
month_end + INTERVAL '1' SECOND,
LEAST(
ADD_MONTHS(month_end, 1),
end_date
),
end_date
FROM split
WHERE month_end < end_date
) SEARCH DEPTH FIRST BY id, start_date SET order_id
SELECT id,
start_date,
month_end AS end_date
FROM split;
Note: if you want to just use values at midnight rather than the entire month then use INTERVAL '1' DAY rather than 1 second.
Which, for the sample data:
CREATE TABLE base (id, start_date, end_date) as
select 1, date '2022-01-15', date '2022-04-15' from dual union all
select 2, date '2022-09-15', date '2022-12-31' from dual union all
select 3, date '2023-09-15', date '2023-09-25' from dual;
Outputs:
ID
START_DATE
END_DATE
1
2022-01-15T00:00:00Z
2022-01-31T23:59:59Z
1
2022-02-01T00:00:00Z
2022-02-28T23:59:59Z
1
2022-03-01T00:00:00Z
2022-03-31T23:59:59Z
1
2022-04-01T00:00:00Z
2022-04-15T00:00:00Z
2
2022-09-15T00:00:00Z
2022-09-30T23:59:59Z
2
2022-10-01T00:00:00Z
2022-10-31T23:59:59Z
2
2022-11-01T00:00:00Z
2022-11-30T23:59:59Z
2
2022-12-01T00:00:00Z
2022-12-31T00:00:00Z
3
2023-09-15T00:00:00Z
2023-09-25T00:00:00Z
fiddle
It's because WHERE and ON conditions are not evaluated at the same level:
when the condition is in the ON clause it's limiting the rows concerned by the JOIN, where it's in the WHERE it's filtering the results after the JOIN has been applied, and since a recursive CTE see all rows selected up to now...
So I have this working SQL script that take a date and returns the age from current time to the given date excluding dates defined in a table called exclude dates
SELECT
COUNT(*)
FROM
(
SELECT
ROWNUM rnum
FROM
all_objects
WHERE
ROWNUM <= CAST(current_timestamp AS DATE) - to_date('&2') + 1
)
WHERE
to_char(to_date('&2') + rnum - 1, 'DY') NOT IN ( 'SAT', 'SUN' )
AND NOT EXISTS (
SELECT
NULL
FROM
exclude_dates
WHERE
no_work = trunc(to_date('&2') + rnum - 1)
);
I have a table called
TICKETS
that contains columns named
ID, UPDATED_AT
I want to create a view that uses the above script to return
ID, AGE
where age is the output of the script above.
You code has a few weaknesses.
There is no need for CAST(current_timestamp AS DATE).
If you need the current DATE then simply use TRUNC(SYSDATE)
You don't need to select from all_objects. Better use hierarchical query
SELECT LEVEL as rnum FROM dual CONNECT BY LEVEL <= ...
Using to_date('&2') without a format is usually bad. Either your input value is a string, then you should include the format, e.g. to_date('&2', 'YYYY-MM-DD') or your input value is a DATE, then simply use &2 - never use TO_DATE() on a value which is already a DATE!
Final query could be this one - assuming input parameter is a DATE value:
WITH t AS (
SELECT LEVEL as d
FROM dual
CONNECT BY LEVEL <= TRUNC(SYSDATE) - the_day)
SELECT COUNT(*) AS buisiness_days
FROM t
WHERE TO_CHAR(the_day + d - 1, 'DY', 'NLS_DATE_LANGUAGE = american') NOT IN ('SAT', 'SUN')
AND NOT EXISTS (
SELECT 'x'
FROM exclude_dates
WHERE no_work = TRUNC(the_day + d - 1)
)
However, for me it is not clear how you want to provide this as a view! You would need to create a separate view for each input date, or at least create a new view every day.
I would suggest to create a function:
CREATE OR REPLACE FUNCTION buisiness_days(the_date IN DATE) RETURN INTEGER AS
ret INTEGER;
BEGIN
WITH t AS (
SELECT LEVEL as d
FROM dual
CONNECT BY LEVEL <= TRUNC(SYSDATE) - the_date)
SELECT COUNT(*) AS buisiness_days
INTO ret
FROM t
WHERE TO_CHAR(the_date + d - 1, 'DY', 'NLS_DATE_LANGUAGE = american') NOT IN ('SAT', 'SUN')
AND NOT EXISTS (
SELECT 'x'
FROM exclude_dates
WHERE no_work = TRUNC(the_date + d - 1)
);
RETURN ret;
END;
The function will return a list of dates between the date range you provide so the dates don't have to be stored in a table.
CREATE OR REPLACE TYPE nt_date IS TABLE OF DATE;
/
CREATE OR REPLACE FUNCTION generate_dates_pipelined(
p_from IN DATE,
p_to IN DATE
)
RETURN nt_date PIPELINED DETERMINISTIC
IS
v_start DATE := TRUNC(LEAST(p_from, p_to));
v_end DATE := TRUNC(GREATEST(p_from, p_to));
BEGIN
LOOP
PIPE ROW (v_start);
EXIT WHEN v_start >= v_end;
v_start := v_start + INTERVAL '1' DAY;
END LOOP;
RETURN;
END generate_dates_pipelined;
/
To exclude holidays you need to know what dates they fall on so there needs to be a holiday table.
create table holidays(
holiday_date DATE not null,
holiday_name VARCHAR2(20),
constraint holidays_pk primary key (holiday_date),
constraint is_midnight check ( holiday_date = trunc ( holiday_date ) )
);
INSERT into holidays (HOLIDAY_DATE,HOLIDAY_NAME)
WITH dts as (
select to_date('25-NOV-2021 00:00:00','DD-MON-YYYY HH24:MI:SS'), 'Thanksgiving 2021' from dual union all
select to_date('29-NOV-2021 00:00:00','DD-MON-YYYY HH24:MI:SS'), 'Hanukkah 2021' from dual
)
SELECT * from dts;
This query will provide the count of days between the range, number of working days and number of holidays in the range.
SELECT COUNT (*) AS total_days
, COUNT ( CASE
WHEN h.holiday_date IS NULL
AND d.column_value - TRUNC (d.column_value, 'IW') < 5
THEN 'Business Day'
END
) AS business_days
, COUNT (h.holiday_date) AS holidays
FROM generate_dates_pipelined (DATE '2021-11-01', DATE '2021-11-30') d
LEFT JOIN holidays h ON h.holiday_date = d.column_value;
This query will provide a list of dates excluding sat, sun and holidays that fall between the range.
SELECT
COLUMN_VALUE
FROM
TABLE(generate_dates_pipelined(DATE '2021-11-01',
DATE '2021-11-30')) c
where
to_char(COLUMN_VALUE, 'DY') NOT IN ('SAT', 'SUN')
AND NOT EXISTS (
SELECT 1
FROM holidays h
WHERE c.COLUMN_VALUE = h.holiday_date
);
You don't need a function or to use a row generator function and can calculate the number of business days:
CREATE VIEW business_day_ages (ID, AGE) AS
SELECT id,
( TRUNC( SYSDATE, 'IW' ) - TRUNC( updated_at, 'IW' ) ) * 5 / 7
-- Number of full weeks.
+ LEAST( SYSDATE - TRUNC( SYSDATE, 'IW' ), 5 )
-- Add part weeks at the end.
- LEAST( updated_at - TRUNC( updated_at, 'IW' ), 5 )
-- Subtract part weeks at the start.
- COALESCE(
( SELECT SUM(
LEAST(no_work + INTERVAL '1' DAY, SYSDATE)
- GREATEST(no_work, updated_at)
)
FROM exclude_dates
WHERE no_work BETWEEN TRUNC(updated_at) AND SYSDATE
),
0
)
-- Subtract the holiday days.
FROM tickets;
Or, if you are not calculating using part days then you can simplify it to:
CREATE OR REPLACE VIEW business_day_ages (ID, AGE) AS
SELECT id,
( TRUNC( SYSDATE, 'IW' ) - TRUNC( updated_at, 'IW' ) ) * 5 / 7
-- Number of full weeks.
+ LEAST( TRUNC(SYSDATE) - TRUNC( SYSDATE, 'IW' ), 5 )
-- Add part weeks at the end.
- LEAST( updated_at - TRUNC( updated_at, 'IW' ), 5 )
-- Subtract part weeks at the start.
- COALESCE(
( SELECT 1
FROM exclude_dates
WHERE no_work BETWEEN TRUNC(updated_at) AND TRUNC(SYSDATE)
),
0
)
-- Subtract the holiday days.
FROM tickets;
db<>fiddle here
I have a table with 3 columns:
resid type date
The table is used to track steps in a workflow and a specific resid can exist multiple with different type id(numbers) and datestamps.
I want to calculate the time used between two typeshift - i.e, 1 and 17 on a specific resid
I have tried with a sql-plus syntax like this
and also tried to use aliases:
Any suggestions?
select resid, date - date
from tablename
where resid, date in
(select resid, date from tablename
where type='1')
and
where resid, date in
(select resid, date from tablename
where type='17')
and tablename.resid=tablename.resid
Your attempted query is missing parentheses around the column list before the in - so should be where (resid, date in) - but also has and where which isn't valid, and probably other issues. Mostly it doesn't do what you want, not least because both date values are coming from the same row (for type 1) so subtracting them will always give zero.
You could use conditional aggregation:
select resid,
min(case when type_id = 17 then date_stamp end)
- min(case when type_id = 1 then date_stamp end) as diff
from tablename
where type_id in (1, 17) -- optional
and resid = :some_value
group by resid;
The case gives either null or the date stamp for each matching row; the aggregation then gives you a single value from those (favouring not-null ones).
If only one of the type IDs exists then the difference will be null.
You might want to change the min() for 17 to max() if there may be multiples - depends what you really need.
Quick demo:
with tablename(resid, type_id, date_stamp) as (
select 1, 1, sysdate - 10 from dual
union all select 1, 17, sysdate - 7 from dual
union all select 2, 1, sysdate - 5 from dual
union all select 2, 17, sysdate - 3 from dual
union all select 3, 1, sysdate - 10 from dual
)
select resid,
min(case when type_id = 17 then date_stamp end)
- min(case when type_id = 1 then date_stamp end) as diff
from tablename
where type_id in (1, 17) -- optional
--and resid = 2
group by resid;
RESID DIFF
---------- ----------
1 3
2 2
3
SELECT a.resid, a."type" type1, a."date" date1, b."type" type17, b."date" date17, b."date" - a."date" AS date_diff
FROM tablename a JOIN tablename b ON a.resid = b.resid AND b."type" = '17'
WHERE a."type" = '1' AND a.resid = :resid
Please do not use oracle reserved words as column names.
When (resid, type) is unique you can do:
SELECT :resid resid,
(select "date" FROM tablename WHERE resid = :resid AND "type" = '17') -
(select "date" FROM tablename WHERE resid = :resid AND "type" = '1') date_diff
FROM DUAL
I want to calculate average values in Oracle tables
CREATE TABLE AGENT_HISTORY(
EVENT_ID INTEGER NOT NULL,
AGENTID INTEGER NOT NULL,
EVENT_DATE DATE NOT NULL
)
/
CREATE TABLE CPU_HISTORY(
CPU_HISTORY_ID INTEGER NOT NULL,
EVENT_ID INTEGER NOT NULL,
CPU_NAME VARCHAR2(50 ) NOT NULL,
CPU_VALUE NUMBER NOT NULL
)
/
I use this SQL query:
----- FOR 24 HOURS CPU
CURSOR LAST_24_CPU_CURSOR IS
--SELECT EVENT_DATE, CPU FROM AGENT_HISTORY WHERE NAME = NAMEIN AND EVENT_DATE >= SYSDATE-(60*24)/1440;
SELECT START_DATE, NVL(AVG(CH.CPU_VALUE),0)
FROM (SELECT START_DATE - (LVL+1)/24 START_DATE, START_DATE - LVL/24 END_DATE
FROM (SELECT SYSDATE START_DATE, LEVEL LVL FROM DUAL CONNECT BY LEVEL <= 24))
LEFT JOIN AGENT_HISTORY AH ON EVENT_DATE BETWEEN START_DATE AND END_DATE
LEFT JOIN CPU_HISTORY CH ON AH.EVENT_ID = CH.EVENT_ID
JOIN AGENT AG ON AH.AGENTID = AG.ID
WHERE AG.NAME = NAMEIN
GROUP BY START_DATE
ORDER BY 1;
This query prints only one average value. I would like to modify it to print 24 values for every hour average value. Can you help me to modify the query?
I guess your input contains data only for one of the given intervals; since you're using an INNER JOIN with AGENT which in turn is filtered by AGENT_HISTORY, you're effectively converting all your LEFT JOINs to inner ones.
I suggest you use a CROSS JOIN between AGENT and the timeslots instead:
with agent_history(event_date, agentid, event_id) as (
select timestamp '2015-11-18 09:00:07', 1, 1001 from dual
),
agent(id, name) as (
select 1, 'myAgent' from dual
),
cpu_history(event_id, cpu_value) as (
select 1001, 75.2 from dual
),
time_slots(start_date, end_date) as (
SELECT START_DATE - (LVL + 1) / 24 START_DATE,
START_DATE - LVL / 24 END_DATE
FROM (SELECT SYSDATE START_DATE,
LEVEL LVL
FROM DUAL
CONNECT BY LEVEL <= 24)
)
SELECT START_DATE,
NVL(AVG(CH.CPU_VALUE),
0)
FROM time_slots ts
CROSS JOIN AGENT AG
LEFT JOIN AGENT_HISTORY AH
ON AH.AGENTID = AG.ID
AND EVENT_DATE BETWEEN START_DATE AND END_DATE
LEFT JOIN CPU_HISTORY CH
ON AH.EVENT_ID = CH.EVENT_ID
WHERE AG.NAME = 'myAgent'
GROUP BY START_DATE
ORDER BY 1;
This ensures you get the full 24 rows (one for each timeslot).
Change start_date to to_char(start_date, 'hh24:mi') both in select and group by clauses.
I have a table 'Holiday' which lists a set of holiday details.If i specify a date,I should obtain a result date after 5 days of specified date.If there is holiday in between it should exclude them and display the non holiday date.I have table named holiday which includes holiday date,holiday type|(weekly off,local holiday).Now i have used nested decode for continuous holiday checking.Tell me how this can be changed in case function.
DECODE
(date,
holidaydate, DECODE
(date + 1,
holidaydate + 1, DECODE
(date + 2,
holidaydate + 2, DECODE
(date + 3,holidaydate+3,date+4,date+3),date+2),date+1),date);
This can be achieved with a simple subquery which counts the number of holiday dates between a specified date and date+5. The following will return a date that is five non-holiday days in the future:
testdate+(select 5+count(1)
from holiday
where holidaydate between testdate
and testdate + 5)
Simply change both "5"s so another number to change the evaluation period.
SQLFiddle here
Edit - based on comment below, my code doesn't evaluate any days after the fifth day. This would probably be much easier with a function, but the following cte-based code will work also:
with cte as ( (select alldate,holidaydate
from (select to_date('20130101','yyyymmdd')+level alldate
from dual
connect by level < 10000 -- adjust for period to evaluate
) alldates
left join holiday on alldate=holidaydate) )
select
testdate,test_plus_five
from (
select
alldate test_plus_five,testdate,
sum(case when holidaydate is null
then 1
else 0 end) over (partition by testdate order by alldate) lastday
from
cte,
testdates
where
alldate >= testdate
group by
alldate,holidaydate,testdate)
where
lastday = 6
This script builds a calendar table so it can evaluate each day (holiday or non-holiday); then we get a running count of non-holiday days, and use the sixth one.
SQLFiddle here
AFAIK, You can use CASE alternative to DECODE in Oracle
CASE [ expression ]
WHEN condition_1 THEN result_1
WHEN condition_2 THEN result_2
...
WHEN condition_n THEN result_n
ELSE result
END
Finally i found the optimal solution.Thanks for ur response guys. SELECT dt FROM
(SELECT dt FROM (SELECT TO_DATE('15-AUG-2013','dd-mon-yyyy')+LEVEL dt FROM DUAL
CONNECT BY LEVEL < 30)
WHERE
(SELECT COUNT (*) FROM mst_holiday WHERE holidaydate = dt) = 0 )
where rownum=1