I’m trying to use a Java, Serenity-BDD project with gradle version 4.8+, but the application is not pulling the CLI arguments of -Denvironment and -Dservicebranches. I have these properties as blank values in my local.properties file, and they’re not getting assigned when my app runs.
./gradlew --build-cache build -Dwebdriver.remote.url=${SELENIUM_REMOTE_URL} -Denvironment=${ENVIRONMENT} -Dservicebranches=${SERVICE_BRANCHES} -Dtags=${TAGS}
I have a local.properties file with properties that are being successfully dependency injected into the project (through Serenity-Spring). I'm hoping that these CLI arguments will override these values:
servicebranches=
environment=local
But right now, anything specified in the CLI arguments are not being passed into the project. Either through DI, or through explicitly grabbing the environment variables in the build.gradle, which what I've tried hasn't been working.
Here's a few things which I have tried in the build.gradle:
//task integrationTests() {
// doFirst
// {
// def environment = System.getProperty('environment')
// def servicebranches = System.getProperty('servicebranches')
// }
// tasks.build.execute()
//}
//integrationTests.dependsOn(build)
//build.doFirst{
// systemProperties System.properties
// def environment = System.properties['environment']
// environment = environment //This actually flags with 'Silly assignment'
//}
build.doFirst{
def environment = System.getProperty('environment')
def servicebranches = System.getProperty('servicebranches')
}
The latest one seems to still be missing a step, because the program is still working, but the args are still not getting through. I've even tried -Denvironment=potato, and no errors have come up because I do not have a property or properties file named that.
I've also tried using the -P tag instead of -D tag, but that doesn't seem to be working either.
All I’m trying to do is use build.gradle to use System.getProperty(‘environment’) and System.getProperty(‘servicebranches’) before I use the already created ‘build’ task that comes with Serenity. How would I do this? Do I build a whole new task, where I use these getProperties, and then call the build task? Do I have to specify the assignment of these same named variables in the local.properties file?
-D is for system properties in Gradle. Try with -P instead (https://docs.gradle.org/current/userguide/build_environment.html#sec:project_properties)
I know this is a very old question but here's what I did to solve my problem, I got the idea from here: https://github.com/serenity-bdd/serenity-documentation/pull/120/files
Serenity was not pulling the environment from gradle to use EnvironmentSpecificProperties, it kept saying "undefined property for environment 'null" when I removed the default environment. I had to add this to my Gradle file:
test {
systemProperty 'environment', System.properties['environment']
}
I have a KotlinJs only project which I use official kotlin2js gradle to build, and no problems there.
How to setup the output folder, currently, the building of subproject will result in a build which locates inside the subproject folder, how to set it to somewhere else? I tried:
sourceSets {
main {
kotlin.outputDir = new File(‘./out/‘)
}
}
and
sourceSets {
main.kotlin.outputDir = new File(‘./out/’)
}
No luck.
What I want is to no matter how many subprojects are there, the output folder should be in some path like ./build/projectA and ./build/projectB, rather than all in their own folder. How to do this?
Currently, it's done through the task configuration, namely setting its kotlinOptions.outputFile:
compileKotlin2Js.kotlinOptions.outputFile = "out/output.js"
It's briefly mentioned in the tutorial: Getting Started with Kotlin and JavaScript with Gradle
In an attempt to follow the doc, I added a task like this to my build.gradle file:
task createStartScripts(type: CreateStartScripts) {
applicationName = 'dc-coverage-calculator'
}
I then executed
./gradlew clean installDist
at which point I expected to find a file at build/install/dc-coverage-calculator/bin/dc-coverage-calculator, but no files with dc-coverage-calculator were created anywhere the build folder. Instead, gradle continued to use the default application name, based on the mainClassName.
I also tried removing the hyphens from the app name.
Unfortunately it doesn't work this way. You've added a new task whereas yo need to modify the existing one, which will be done this way:
startScripts {
applicationName = 'dc-coverage-calculator'
}
Grab a demo here.
I haven't done anything with Gradle for a while, so it appears I've forgotten how configuration resolution works.
I'm trying to use the gretty plugin (instead of core, deprecated jetty), but I cannot seem to create a custom configuration.
I've boiled it down to a very short, simple script (using Gradle 3.4):
buildscript {
repositories {
maven {
url 'https://plugins.gradle.org/m2/'
}
}
dependencies {
classpath 'org.akhikhl.gretty:gretty:1.4.0'
}
}
plugins {
id 'org.akhikhl.gretty' version '1.4.0'
}
configurations {
fooTest
}
configurations.fooTest.each {
println it.toString()
}
It seems to not like me iterating over the fooTest configuration.
Assuming I need to know the dependencies for that configuration (I stripped that part from the code above)
What am I doing wrong here?
The script above gives me this:
org.gradle.api.InvalidUserDataException: Cannot change strategy of configuration ':fooTest' after it has been resolved.
The key point here was that I needed an unresolved configuration to loop over. Admittedly this information was neglected in the initial description as I didn't know it was critical information. We needed to loop over the files in the dependency and copy/unzip them into certain locations.
However, we cannot do that with a resolved configuration. That said, we can copy the configuration into a unresolved one, and loop over that instead:
configurations.fooTest.copy().each {
println it.toString()
}
This will successfully print out the files involved in the dependency (or unzip them, as my case needs).
I'm using Gradle spring-boot plugin and I need to select a spring active profile for the test run.
How do I pass spring.profiles.active system property to the bootRun plugin's task?
What has already failed:
task bootRunLocal {
systemProperty "spring.profiles.active", "local"
System.setProperty("spring.profiles.active", "local")
tasks.bootRun.execute() // I suspect that this task is executed in a separate JVM
}
and some command line magic also fails:
./gradle -Dspring.profiles.active=local bootRun
Could someone kindly help me solve my troubles?
Update from the answers and comments:
I'm able to set the systemProperty and pass it to the spring container by doing :
run {
systemProperty "spring.profiles.active", "local"
}
However, when I do this, the local profile is being set for both bootRun task and bootRunLocal task. I need a way to set this property for bootRunLocal task and call booRun task from bootRunLocal.
That might sound very simple, but I come with peace from the structured world of Maven.
I know I'm late here... but I recently faced this exact issue. I was trying to launch bootRun with spring.profiles.active and spring.config.location set as system properties on the command line.
So, to get your command line "magic" to work, simply add this to your build.gradle
bootRun {
systemProperties System.properties
}
Then running from the command line...
gradle -Dspring.profiles.active=local bootRun
Will set local as the active profile, without needing to define a separate task simply to add the env variable.
task local {
run { systemProperty "spring.profiles.active", "local" }
}
bootRun.mustRunAfter local
Then run gradle command as:
gradle bootRun local
There is no generic way to pass system properties to a task. In a nutshell, it's only supported for tasks that fork a separate JVM.
The bootRunLocal task (as defined above) will not execute in a separate JVM, and calling execute() on a task isn't supported (and would have to happen in the execution phase in any case). Tests, on the other hand, are always executed in a separate JVM (if executed by a Test task). To set system properties for test execution, you need to configure the corresponding Test task(s). For example:
test {
systemProperty "spring.profiles.active", "local"
}
For more information, see Test in the Gradle Build Language Reference.
SPRING_PROFILES_ACTIVE=local gradle clean bootRun
This is according to this and this and it works.
According to the spring-boot-gradle-plugin documentation you should be able to pass arguments like this
./gradlew bootRun --args='--spring.profiles.active=dev'
Seems like this is a new gradle feature since 4.9. I used it in my project and it worked out of the box.
For gradle 2.14 below example works.
I have added as below.
When System.properties['spring.profiles.active'] is null then default profile is set.
bootRun {
systemProperty 'spring.profiles.active', System.properties['spring.profiles.active']
}
command line example
gradle bootRun -Dspring.profiles.active=dev
Just for reference if anyone will have this issue:
Vlad answer didn't quite worked for me but this one works great with 2.4,
task local <<{
bootRun { systemProperty "spring.profiles.active", "local" }
}
local.finalizedBy bootRun
then gradle local
Responding to OP's exact request here ...
How do I pass spring.profiles.active system property to the bootRun plugin's task?
And assuming by "pass" the OP meant "pass from commandline" or "pass from IDE invocation" ... This is how I like to do it.
Add this to build.gradle:
/**
* Task from spring-boot-gradle-plugin, configured for easier development
*/
bootRun {
/* Lets you pick Spring Boot profile by system properties, e.g. gradle bootRun -Dspring.profiles.active=dev */
systemProperties = System.properties
}
Then when you invoke it, use the familiar Java flag for setting a system property
gradle bootRun -Dspring.profiles.active=local
There is one main advantage of sticking to system properties, over the environment variables option (SPRING_PROFILES_ACTIVE=local gradle bootRun) ... and that's easy portability between Linux/OS X (bash, etc.) and Windows (cmd.exe anyway).
I learned this way from this blog post.
(UPDATE: Ah somehow I had missed #Erich's response with same recommendation. Oops! I'm leaving my answer, because of the additional details about portability, etc.)
You can create a new task (in discussed case with name bootRunLocal), that would extend org.springframework.boot.gradle.run.BootRunTask and setup properties before task execution. You can create such a task with following code:
task bootRunLocal(type: org.springframework.boot.gradle.run.BootRunTask) {
doFirst() {
main = project.mainClassName
classpath = sourceSets.main.runtimeClasspath
systemProperty "spring.profiles.active", "local"
}
}
More details can be found here:
https://karolkalinski.github.io/gradle-task-that-runs-spring-boot-aplication-with-profile-activated/
Starting from SpringBoot 2.0.0-M5 setSystemProperties() is no longer a method of the task bootRun.
The build.gradle needs to be updated to
bootRun {
execSpec {
// System.properties["spring.profiles.active"]
systemProperties System.properties
}
}
This is as springBoot's run task uses org.gradle.process.JavaExecSpec
This works for me using Gradle 4.2
This works:
SPRING_PROFILES_ACTIVE=production ./gradlew app-service:bootRun
with run command you can add to build file run { systemProperties = System.properties } and start with gradle run -Dspring.profiles.active=local
Another way which doesn't require any support from the gradle task: Set the JAVA_TOOL_OPTIONS environment variable:
JAVA_TOOL_OPTIONS='-Dfoo=bar' gradle ...
Or if the variable might already contain anything useful:
JAVA_TOOL_OPTIONS="$JAVA_TOOL_OPTIONS -Dfoo=bar" gradle ...
// defualt value
def profiles = 'dev'
bootRun {
args = ["--spring.profiles.active=" + profiles]
}
Then you can simply pick a specific version when starting a gradle task, like
./gradlew bootRun -P dev
"dev" is gonna to take place "prod"