Covert MySql query to Laravel - laravel-5

Question

Can you please help me out to write the Laravel Raw Query for below Mysql query.
SELECT
SUM(IF(d.business_email_template_10_open = "Yes", 1,0)) AS `business_email_template_10_open`,
SUM(IF(d.business_email_template_11_open = "Yes", 1,0)) AS `business_email_template_11_open`
FROM dummy_email_track d
join recommend_email_send_by_cron r on d.user_id = r.user_id
join user_form_submission u on r.user_id = u.id'
where d.business_id = $businessId

Answer 1

If you can't use stored procedure, ignore my answer.
I think you can't use Laravel QueryBuilder cause something reason(I have a similar situation). How about using SP(stored procedure)?
Mysql SP
CREATE DEFINER=`your_mysql_id`#`%` PROCEDURE `get_usage_business_email_template`()
__SP:BEGIN
BEGIN
SELECT
SUM(IF(d.business_email_template_10_open = "Yes", 1,0)) AS `business_email_template_10_open`,
SUM(IF(d.business_email_template_11_open = "Yes", 1,0)) AS `business_email_template_11_open`
FROM dummy_email_track d
join recommend_email_send_by_cron r on d.user_id = r.user_id
join user_form_submission u on r.user_id = u.id'
WHERE d.business_id = $businessId
END;
END
And, Laravel call this SP like below
$result = DB::select('CALL get_usage_business_email_template()');
I hope you will save your time becasue my answer...

Answer 2

This should give you a headstart!
https://laravel.com/docs/5.6/database#running-queries
$results = DB::select('select * from users where id = :id', ['id' => 1]);
Make sure you give right id to your where clause. So in you case it would something like this:
(where d.business_id = :businessId, ['businessId' => 1])
Goodluck!

Answer 3

Please try this :
$data = DB::table('dummy_email_track as d')
->select('d.*','r.*','u.*')
->selectRaw('SUM(IF(d.business_email_template_10_open = "Yes", 1,0)) AS business_email_template_10_open')
->selectRaw('SUM(IF(d.business_email_template_11_open = "Yes", 1,0)) AS `business_email_template_11_open`')
->leftJoin('recommend_email_send_by_cron as r','d.user_id', '=', 'r.user_id')
->leftJoin('user_form_submission as u', 'r.user_id', '=', 'u.id')
->where('d.business_id','=', $businessId)
->get();