I'm preparing IT blog with admin panel. Posts have categories like databases, operation systems etc. Every category has own site. How should I create a logic to display, route and manage(CRUD)?
I think it can be in one controller, which have parameter $category, which will be use to show specific posts. Something like this(between post-category is one-to-many-invert relation):
public function index()
{
$posts=Post::where('category_id',$category)->get();
}
EDIT:
Categories:
programming, databases, other
Target URL:
blog/programming
blog/databases
blog/other
Above sites should have all posts from specific category.
I think, if I've understood the question, that you're looking for a simple Category controller.
class CategoryController extends Controller {
public function view($categorySlug)
{
$posts = Post::whereHas(['category' => function ($query) use($categorySlug) {
$query->where('slug', '=', $categorySlug);
}])->paginate(2);
return view('my.view', compact('posts');
}
}
The next question comes from the structure of the posts slug. For example, lets say that you have my.blog/category-slug that points to the above. Are your posts my.blog/category-slug/post-slug or are they my.blog/post-slug or my.blog/year/month/day/post-slug?
Related
I'm searching for a fine and neat solution to filter my Eloquent collection with the data in the related pivot table. I actually found a solution to my problem already though it feels like my solution is somehow bad. Here is, what I got:
Two models Video and User where every user can track separately the progress on a video. For this I need to save the progress for every video in the ratings table related to the user. When you want to search for just the progress you can do that besides some other filters (category, full text search). What I find a bit quirky is that I have to double "where()" the part where I'm checking the video progress for the logged in user.
Video.php
class Video extends Model
{
use SearchableTrait;
use Taggable;
[...]
public function videocreator(){
return $this->belongsTo('App\User', 'create_user_id');
}
public function users(){
return $this->belongsToMany('App\User', 'progress', 'video_id', 'user_id')
->withPivot('progress_index')
->withTimestamps();
}
[...]
}
User.php
class User extends Authenticatable
{
use Notifiable;
[...]
public function videoscreated(){
return $this->hasMany('App\Video');
}
public function videos(){
return $this->belongsToMany('App\Video', 'progress', 'user_id', 'video_id')
->withPivot('progress_index')
->withTimestamps();;
}
}
VideoController.php
class VideoController extends Controller
{
public function index(Request $request)
{
[...]
$videos = Video::with('videocreator')->with(['users' => function ($query) {
$query->where('users.id', '=', auth()->user()->id);
}])->latest();
if($request->filled('progress') && $request['progress'] !== 'all'){
$videos = $videos->whereHas('users', function($query) use($selectedProgress) {
$query->where('progress_index', $selectedProgress)->where('users.id', '=', auth()->user()->id);
});
}
$videos = $videos->get();
[...]
}
As you can see this part where('users.id', '=', auth()->user()->id) is duplicated. A friend of mine from the Ruby on Rails Faction proposed to come from the User Model first and then fetch the Videos (that's how you would do it there). Though this way you would limit the videos to the user from the progress table. This is not what you want. The App shall track only the per user progress per video, meaning, all the users can see all the videos (just not the progress which is not their own.
Another approach would be to put the part where you filter for the user into the relationship. A method like: myProgress() or something similar.
What is your opinion to that? Is there a more 'eloquent' way to solve that?
Thanks in advance for reading this post!
I would do something like this :
// Get an instance of the videos relationship of the current authenticated user
// Eager load the videocreator relationship
$videoQuery = request()->user()->videos()->with('videocreator');
if ($request->filled('progress') && $request->input('progress') !== "all") {
// Constrain the query : only get the videos with rated_index equal to $selectedProgress
$videoQuery = $videoQuery->wherePivot('rated_index', $selectedProgress);
}
// Finally, run the query against the database
$videos = $videoQuery->latest()->get();
I am a couple of weeks in to learning Laravel and have come across a problem which I can not find the answer to by myself, or online.
I am building a directory website with urls structured like:
directory.co.uk/parks
directory.co.uk/parks/{county-name}
directory.co.uk/parks/{county-name}/{park-name}
As {park-name} is not unique, I am struggling to return the page for an individual park. The controller needs to look up the county.id using the county.slug and then the park.id using the park.county_id and the park.slug.
I have routes in the web.php file such as:
Route::get('/parks','ParksController#index')->name('parks');
Route::get('/parks/{county}/{park}','ParksController#show')->name('park');
I have Parks and Counties models and (belongsTo and hasMany relationships set up between the two).
I have this is in both models:
public function getRouteKeyName()
{
return 'seo_url';
}
Then in my ParksController, I am at a loss. I currently have:
public function show(Counties $county, Parks $park)
{
//return $park;
//dd($park);
return view('parks.park', ['park'=>$park]);
}
I have also tried the non-Eloquent way:
public function show($county_slug,$park_slug)
{
$county = DB::table('counties')->where('seo_url',$county_slug)->get();
$county_id = $county->pluck('id');
$park = DB::table('parks')->where('county_id', $county_id)->where('seo_url', $park_slug)->get();
//dd($county_id);
//return $park;
return view('parks.park', ['park'=>$park]);
}
This returns a 404 error. Any help would be much appreciated. (I have done a lot of reading on Route model binding, but can not see any examples like mine.)
Laravel has an undocumented feature in its explicit model binding, where the callback can be given the current Route the binding is for. This can allow you to access the other parameters and use them to add conditionals.
Router::bind('park', static function ($value, Route $route) {
$query = Parks::where('seo_url', '=', $value);
if ($route->hasParameter('county')) {
$county = $route->parameter('county');
$query->where('county_id', '=', $county instanceof Counties ? $county->id : $county);
}
return $query->first() ?? abort(404);
});
I Have multiple models that have many to many relationship
Here are the models
News Section
Categories
Sub Categories
Approved News
Pending News
Each News Section can have multiple Categories.
Each Category can have multiple Sub Categories.
Each Sub Category can has multiple Approved News and Pending News.
I want to have News with Categories, Sub Categories and Pending / Approve news
and stuff like
Categories with Sub Categories and Approve news
I tried with pivot tables but not able to get results
Models are as follow
News Section
class NewsSection extends Model
{
public function categories()
{
return $this->belongsToMany(Category::class);
}
}
Category
class Category extends Model
{
public function subcats(){
return $this->belongsToMany(SubCategory::class);
}
public function newssections(){
return $this->belongsToMany(NewsSection::class);
}
}
SubCategory
class SubCategory extends Model
{
public function category(){
return $this->belongsTo(Category::class);
}
public function approvednews(){
return $this->belongsToMany(ApprovedNews::class);
}
public function pendingnews(){
return $this->belongsToMany(PendingNews::class);
}
}
ApprovedNews
class ApprovedNews extends Model
{
public function subcategories (){
return $this->belongsToMany(SubCategory::class);
}
}
PendingdNews
class PendingdNewsextends Model
{
public function subcategories (){
return $this->belongsToMany(SubCategory::class);
}
}
Update
This what I have done so far
$news =Category::with('subcats.approvednews')->where('id',1)->get();
I got all the approved news with subcategories and categories
how can i modify this to get specific subcats and approved news per category, if i do this
$news =Category::with('subcats.approvednews')->where('subcats.id',1)->get();
I get an error like id ambiguous
Is it possible to pick and chose items from relation for instance return just 2 subcats and 3 approved news for each subcat of selected category
or
get count of approved news and pending news per subcat and category
Thanks in advance
The error "error like id ambiguous" means that you need to specify the table in your where('id', 1) like where('table.id', 1) so that MySQL knows which id column in which table you mean.
You can constrain the models returned by with like this:
Category::with(['subcats' => function(Builder $query) {
$query->where('id', '=', 1);
}]);
Also you can count relations:
$subcat = SubCategory::withCount(['approvednews']);
$subcat->approvednews_count;
Limiting eager loaded relations is not possible per the docs.
A workaround may be to go the other way round starting from ApprovedNews:
ApprovedNews::whereHas(['subcategories' => function(Builder $query) {
$query->where('id', '=', 1);
}])->limit(10);
I have a few suggestions of how you can get this to work. In your comments, you say you are getting an issue doing the following:
$items=Category::with('subcategory')->where('id',1)->get();
Where is 'subcategory' coming from? By the looks of your model, your relationship between Category and Subcategory is called subcats. So you would need to change it to:
$items=Category::with('subcats')->where('id',1)->get();
And if you dump that out, you should see that you will get the category where the ID is 1, and the subcategories loaded in. A way to test that your relationships are working would be something like this:
$category = Category::find(1);
$subCats = $category->subcats()->get();
dd($subCats);
In your relationships, instead of using SubCategory::class I would suggest trying return $this->belongsToMany('App\SubCategory'); so that the models are definitely connected.
Once you have tested that your relationships between one another work, you can get started on testing that you can go from a->b->c etc.
May be using "Nested Eager Loading" and "scope", you can do something like
$pendings = NewSection::with('categories.subCategories')->pending()->get()
$approved = NewSection::with('categories.subCategories')->approved()->get()
not tested it, but you can try, may be with some modification, you can reach to your goal.
if you want return one collection, you may like to merge it
$approved->merge($pendings);
but, you should avoid it.
I'm using Laravel 5.8 to build a babysitting site. I have 4 tables with different relationships as below:
please see this image
The relationships are:
Babysitter->hasMany(session)
Sessions->hasOne(Review)
Sessions->hasOne(Kids)
Sessions->hasOne(Babysitter)
Sessions->hasOne(Parent)
I want to achieve 2 things:
First one
I want to show this result when listing all babysitters. I'm showing this information for each babysitter:
plsease see this image
See here what I couldn't achieve
plsease see this image
This is my code
Sitters::where('Status', 'active')->where('Verified', 1)->get();
Second one
Also, I've tried to show kids name with parent review as shown here:
plsease see this image
This is what i'm using
Sessions::select('Reviews.*', 'Sessions.Parent_id')->join('Reviews', 'Reviews.Session_id', '=', 'Sessions.id')->with('owner')->where('Trainer_id', session('user')->Id)->where('Status', '=', 'complete')->with('owner')->orderBy('Sessions.id', 'DESC')->get();
Here is Session.php Model
public function owner(){
return $this->belongsTo('App\Models\Parents', 'Parent_id');
}
As discussed change the relations:
Babysitter->hasMany(sesstion)
Sessions->hasOne(Review)
Sessions->belongsTo(Kids)
Sessions->belongsTo(Babysitter)
Sessions->belongsTo(Parent)
First one
in Babysitter.php declare the following attributes
class Babysitter extends Model
{
public function reviews()
{
$this->hasManyThrough(Review::class, Session::class);
}
public function getAverageReviewAttribute()
{
return $this->reviews()->avg('Rating');
}
}
Then you just need to call it on the model instance.
$babysitter = Babysitter::first();
return $babysitter->average_review;
Second one
Just use the relation
$babysitter = BabySitter::with(['sessions' => public function ($session) {
$session->with(['review','parent','kids']);
})->where('trainer_id', '=', session('user')->Id) //did not understand this condition
->first();
This assumes you have parent, kids and review relation declared on Session::class. (change the names if needed)
After a few days of searching & testing, this is what worked for me:
Inside (Sitters) Model, put this relation
public function sessions()
{
return $this->hasMany(Sessions::class, 'sitter_id')
->withCount('reviews')
->withCount(['reviews as review_avg' => function($query){
$query->select(DB::raw('AVG(Rating)'));
}]);
}
Also, inside (Sessions) Model, put this relation
public function reviews()
{
return $this->hasOne(Reviews::class, 'Session_id');
}
Now you query like this
return $sitters = Sitters::with('sessions')->get();
I hope this can help someone :)
I have the following code which works but doesn't seem to follow the laravel eloquent way:
Article::left_join('images', 'articles.id', '=', 'images.article_id')
->join('article_category', 'articles.id', '=', 'article_category.article_id')
->where('article_category.category_id', '=', $category_id)
->get();
I have 4 tables; articles and categories which have a many to many relationship with each other, a pivot table article_category table which holds the article id and category id and an image table which has one to one relationship with an article.
I setup my models as:
class Category extends Eloquent {
public static function get_articles($category_id) {
return static::find($category_id)->has_many_and_belongs_to('Article');
}
class Article extends Eloquent {
public function categories() {
return $this->has_many_and_belongs_to('Category');
}
public function image() {
return $this->has_one('Image');
}
However I can't seem to get all three bits of info together. I can do:
Category::get_articles($current_category)->get();
To get all articles in a given category but I can't seem to get the image for the article, there seems to be nothing I can chain onto? Unless I'm doing it incorrectly? Is there a trick I'm missing?
I even tried the stripped down version from the docs:
foreach (Article::with('image')->get() as $article) {
echo $article->image->foo;
}
However I get an error: Trying to get property of non-object, even though var_dump shows $article->image is an object! Weird.
Thanks
If you have not setup a model for the image table, do that. The ORM needs the model there so it knows what 'Image' refers to.
Can you get the category information using the ::with method or is that troublesome too?