I have an application that uses the jQuery Datatable and I want to click on a row, pick up the id, and then bring up a view that allows for editing of that view and updating the underlying database.
Ajax gets me to the controller-action that for the edit view but I can't get the view itself to display. Instead, the controller action just returns to ajax. I've tried numerous tactics with no joy. Here is a simple example based upon a standard CORE template:
#section scripts{
<script>
$(document).on('click', 'button.number', function () {
alert($(this).val());
$.ajax({
method: 'GET',
url: '#Url.Action("About", "Home")'
});
});
</script>
}
<h3>Home Page</h3>
<div>
<button href="#" type="button" class="number" id="one" value="1">1</button>
<button href="#" type="button" class="number" id="two" value="2">2</button>
</div>
Running the debugger shows that About action is called OK but the view isn't rendered - it just returns to ajax. I've tried all sorts of redirection but any "return" just goes back to ajax.
Is there away around this or perhaps a better way to get from the JS to the controller-action? Thanks
EDIT:
Batuhan gets the credit for his solution but I'm re-posting it to clean up a little syntax and add the parameter passing that was my initial goal.
$(document).on('click', 'button.number', function () {
var id = $(this).val();
alert(id);
$.ajax
({
method: 'GET',
url: '#Url.Action("About", "Home")',
}).success(function (result) {
window.location.href = '/home/about/' + id;
});
});
And here is Home Controller for the About Action:
public IActionResult About(int id)
{
string parm2 = id.ToString();
ViewBag.msg = parm2;
return View();
}
And the About page:
#{
ViewData["Title"] = "About";
}
<p>
<h1> #ViewBag.msg </h1>
</p>
All works as initially hoped for!
$(document).on('click', 'button.number', function () {
alert($(this).val());
$.ajax({
method: 'GET',
url: '#Url.Action("About", "Home")'
}).success: function(result){
///this line
window.href='redirect url';
}});;
});
this is a solution cause you cant redirect from ajax call. it returns The view in html form So if you want to postback you needto use window.href="url";
Related
I have looked through all the similar posts out there but nothing seems to help. This is what I have
HTML:
<section>
<form id="contact-form" action="" method="post">
<fieldset>
<input id="name" name="name" placeholder="Name" type="text" />
<input id="email" name="email" placeholder="Email" type="text" />
<textarea id="comments" name="comments" placeholder="Message"></textarea>
<div class="12u">
Send Message
Clear Form
</div>
<ul id="response"></ul>
</fieldset>
</form>
</section>
JavaScript/jQuery:
function sendForm() {
var name = $('input#name').val();
var email = $('input#email').val();
var comments = $('textarea#comments').val();
var formData = 'name=' + name + '&email=' + email + '&comments=' + comments;
$.ajax({
type: 'post',
url: 'js/sendEmail.php',
data: formData,
success: function(results) {
$('ul#response').html(results);
}
}); // end ajax
}
What I am unable to do is prevent the page refresh when the #form-button-submit is pressed. I tried return false; I tried preventDefault() and every combination including return false; inside the onClick. I also tried using input type="button" and type="submit" instead and same result. I can't solve this and it is driving be nuts. If at all possible I would rather use the hyperlink due to some design things.
I would really appreciate your help on this.
Modify the function like this:
function sendForm(e){
e.preventDefault();
}
And as comment mentions, pass the event:
onclick = sendForm(event);
Update 2:
$('#form-button-submit').on('click', function(e){
e.preventDefault();
var name = $('input#name').val(),
email = $('input#email').val(),
comments = $('textarea#comments').val(),
formData = 'name=' + name + '&email=' + email + '&comments=' + comments;
$.ajax({
type: 'post',
url: 'js/sendEmail.php',
data: formData,
success: function(results) {
$('ul#response').html(results);
}
});
});
function sendForm(){
// all your code
return false;
}
I was also bit engaged in finding solution to this problem, and so far the best working method I found was this-
Try using XHR to send request to any url, instead of $.ajax()...I know it sounds bit weird but try it out!
Example-
<form method="POST" enctype="multipart/form-data" id="test-form">
var testForm = document.getElementById('test-form');
testForm.onsubmit = function(event) {
event.preventDefault();
var request = new XMLHttpRequest();
// POST to any url
request.open('POST', some_url, false);
var formData = new FormData(document.getElementById('test-form'));
request.send(formData);
This would send your data successfully ...without page reload.
Have you tried using
function sendForm(event){
event.preventDefault();
}
Simple and Complete working code
<script>
$(document).ready(function() {
$("#contact-form").submit(function() {
$("#loading").show().fadeIn('slow');
$("#response").hide().fadeOut('slow');
var frm = $('#contact-form');
$.ajax({
type: frm.attr('method'),
url: 'url.php',
data: frm.serialize(),
success: function (data) {
$('#response').html(data);
$("#loading").hide().fadeOut('slow');
$("#response").slideDown();
}, error: function(jqXHR, textStatus, errorThrown){
console.log(" The following error occured: "+ textStatus, errorThrown );
} });
return false;
});
});
</script>
#loading could be an image or something to be shown when the form is processing, to use the code simply create a form with ID contact-form
Another way to avoid the form from being submitted is to place the button outside of the form. I had existing code that was working and created a new page based on the working code and wrote the html like this:
<form id="getPatientsForm">
Enter URL for patient server
<br/><br/>
<input name="forwardToUrl" type="hidden" value="/WEB-INF/jsp/patient/patientList.jsp" />
<input name="patientRootUrl" size="100"></input>
<br/><br/>
<button onclick="javascript:postGetPatientsForm();">Connect to Server</button>
</form>
This form cause the undesirable redirect described above. Changing the html to what is shown below fixed the problem.
<form id="getPatientsForm">
Enter URL for patient server
<br/><br/>
<input name="forwardToUrl" type="hidden" value="/WEB-INF/jsp/patient/patientList.jsp" />
<input name="patientRootUrl" size="100"></input>
<br/><br/>
</form>
<button onclick="javascript:postGetPatientsForm();">Connect to Server</button>
I expect anyone to understand my idea very well as it's a very simple idea.
give your required form itself an id or you can get it by any other way you prefer.
in the form input "submit" call an onclick method from your javascript file.
in this method make a variable refer to your from id the addEventListener on it and make a preventDefault method on "submit" not on "click".
To clarify that see this:
// element refers to the form DOM after you got it in a variable called element for example:
element.addEventListener('submit', (e) => {
e.preventDefault();
// rest of your code goes here
});
The idea in brief is to deal with the form by submit event after dealing with submit button by click event.
Whatever is your needs inside this method, it will work now without refresh :)
Just be sure to deal with ajax in the right way and you will be done.
Of course it will work only with forms.
The way I approached this: I removed the entire form tag and placed all the form elements such as input, textarea tags inside a div and used one button to call a javascript function. Like this:
<div id="myform">
<textarea name="textarea" class="form-control">Hello World</textarea>
<button type="submit" class="btn btn-primary"
onclick="javascript:sendRequest()">Save
changes</button>
<div>
Javascript:
function sendRequest() {
$.ajax({
type: "POST",
url: "/some/url/edit/",
data: {
data: $("#myform textarea").val()
},
success: function (data, status, jqXHR) {
console.log(data);
if (data == 'success') {
$(`#mymodal`).modal('hide');
}
}
});
return true;
}
I thought why use a form when we are sending the actual request using AJAX. This approach may need extra effort to do things like resetting the form elements but it works for me.
Note:
The above answers are more elegant than this but my use case was a little different. My webpage had many forms and I didn't think registering event listeners to every submit button was a good way to go. So, I made each submit button call the sendRequest() function.
I am trying to bind my parameter of a custom knockout component into the viewmodel with a value provided by an ajax call. However it appears the binding is taking place before the ajax call completes. Is there anyway to make sure the ajax call completes before the binding occurs? Thanks.
The view with the custom component is something like this
<section>
<mycustomcomponent params="item: item"> </mycustomcomponent>
</section>
Here are the relevant parts of the viewmodel
define(function (require) {
var Item = require('models/item');
var item;
return {
activate: function () {
var ajaxCall = $.ajax({
method: 'get',
url: 'myapicall',
success: function (data) {
item = new Item(data);
}
});
return ajaxCall;
},
item: item,
};
});
You could try wrapping the component in an if binding so that it doesn't render until item contains something valid.
<section data-bind="if: item">
<mycustomcomponent params="item: item"> </mycustomcomponent>
</section>
So I want to do something almost exactly like you find here:
http://www.makeitspendit.com/calling-asp-mvc-controllers-from-jquery-ajax/
It will do exactly what I want it to do, but having the same script written out for all 4 buttons is not very DRY. (Well, not DRY at all)
I would like to have one script to call the correct view based on the ID of the button, so that code would only have to be on my page once.
I tried passing this.id into the function call, and using concatenation in the "url:" property of the ajax call but that doesn't work.
EXAMPLE:
<div id="projectDiv">
<button onclick="loadProject(this.id)" id="_Project1">Project 1</button>
<button onclick="loadProject(this.id)" id="_Project2">Project 2</button>
<script>
function loadProject(projectID) {
$.ajax({
url: ("/Projects/Project/"+projectID),
datatype: "text",
type: "POST",
success: function (data) {
$('#projectDiv').html(data);
},
});
});
</script>
And in the controller:
[HttpPost]
public ActionResult Project(string id)
{
return View(id);
}
I've searched all over for this and found similar things (but not similar enough to derive what I need) but couldn't find this scenario -- which I would've assumed was common enough to have more information.
The example code illustrates how I would LIKE it to work, but I can't seem to pass the variable into the url property like that. While I am admittedly pretty new to ASP.NET MVC, this seems like it should be pretty basic and yet I've been stuck on this for a minute.
I realize this post is over a year old at this point, but I wanted to add a more complete answer based off the comments made on the original question, in case others like me stumble across it.
In my /Views/Shared/ folder I have _YourPartialName.cshtml
In my HomeController.cs I have:
[HttpPost]
public PartialViewResult AddPartialToView(string id)
{
return PartialView(id);
}
In my MainView.cshtml I have:
...
<div id="placeHolderDiv">
</div>
<div class="form-group">
<button class="btn" type="button" onclick="replaceContentsOfDiv(this.id)" id="_YourPartialName">Add A Partial View Above This</button>
</div>
...
<script>
function replaceContentsOfDiv(partialViewToInsert) {
$.ajax({
url: '#Url.Action("AddPartialToView", "Home")',
data: { id: partialViewToInsert},
type: "POST",
success: function(data) {
$('#placeHolderDiv').html(data);
}
});
}
</script>
This will result in:
<div id="placeHolderDiv">
<whatever class="you had in your partial">
</whatever>
</div>
Hope this helps.
I am using MVC3, Razor, C#, JQuery and AJAX.
I am using an Ajax call to postback a form to the server. I get all the form element values being passed back to the controller in:
[HttpPost]
public ActionResult Edit(Product myProduct, string actionType)
if (actionType == "Save")
save....
And in the View I have:
#using (Html.BeginForm("Edit", "RA", FormMethod.Post, new { #class = "editForm", #id = "frmEdit" }))
Form Elements:
<td>
#Html.HiddenFor(p=>p.Id)
<button type="submit" name="actionType" value="Save" >Save</button>
</td>
<td>#Html.EditFor(p=>p.Name)</td>
Some Ajax:
$('.editForm').on('submit', function () {
$.ajax({
url: this.action,
type: this.method,
data: $('#frmEdit').serialize(),
context: $('button', this).closest('tr'),
success: function (result) {
$(this).html(result);
}
});
return false;
});
Now I think the problem line is since I have seen quite a few posts about problem with JQuery and submitting button values:
data: $('#frmEdit').serialize(),
But I cannot get the button to submit an actionType of "Save". I just get null.
Thoughts greatly appreciated.
Thanks.
UPDATE:
My code seems to interfere with my JQuery listener ?? My code is:
<input type="submit" id="btn" name="btn" value="Save" onclick="document.getElementById('actionType').value = 'Save';"/>
From the documentation:
No submit button value is serialized since the form was not submitted using a button.
However you can add it by hand:
data: $('#frmEdit').serialize() + '&actionType=Save',
or
data: $('#frmEdit').serialize()
+ '&'
+ encodeURIComponent(button.name)
+ '='
+ encodeURIComponent(button.value),
where button is the <button> DOM element.
Is there anyway to submit a form but have it remain on the page?
Right now I'm displaying a table of objects, but each row has an editable value with each row in its own Ajax form but when I click the update button it goes to the method alright but the whole page changes.
Is there anyway to submit a form but have it remain on the page?
Of course, you could use AJAX:
#using (Html.BeginForm())
{
... some form input fields
<input type="submit" value="Go" />
}
and then unobtrusively AJAXify this form in a separate file:
$(function() {
$('form').submit(function() {
$.ajax({
url: this.action,
type: this.method,
data: $(this).serialize(),
success: function(result) {
// TODO: handle the results of the AJAX call
}
});
return false;
});
});
and to avoid writing all this javascript code you may take a look at the excellent jquery.form plugin:
$(function() {
$('form').ajaxForm(function(result) {
// TODO: handle the results of the AJAX call
});
});
Another alternative is to use the ASP.NET MVC 3 Ajax.BeginForm helper:
#using (Ajax.BeginForm(new AjaxOptions { OnSuccess = "success" }))
{
... some form input fields
<input type="submit" value="Go" />
}
and then have a success handler in javascript:
function success(result) {
// TODO: handle the results of the AJAX call
}
you will also need to include the jquery.unobtrusive-ajax.js script in addition to jquery to your page if you want to use the Ajax.* helpers.