my working tree is like this:
/opt/go/src/tb-to-composer/
├── apis
│ └── rtb.go
├── config.yaml
├── jsondef
│ └── structures.go
├── LICENSE.md
├── README.md
├── tb-to-composer
└── thingsToComposer.go
when I do go build inside /opt/go/src/tb-to-composer/ the build doesn't recompile rtb.go and structures.go even though there was changes in them. In order to achieve build I need to run go build -a every time I do a change to rtb.go or structures.go, is that the expected behavior from go build? How to I recompile only custom libs inside my package folder without recompile the whole /opt/go/src tree?
You can try the -i flag, or (this does not work, sorry) specify the files in the directories explicitly as arguments to go build, i.e. go build thingsToComposer.go apis/rtb.go jsondef/structures.go
Related
I'm using Gradle with the wrapper, and the folder structure by default is like so:
.
├── settings.gradle
├── build.gradle
├── gradle.properties
├── gradle
│ └── wrapper
│ ├── gradle-wrapper.jar
│ └── gradle-wrapper.properties
├── gradlew
└── gradlew.bat
However, I would like to change it to so:
.
├── gradle
| ├── build.gradle
│ ├── settings.gradle
│ ├── gradle.properties
│ └── wrapper
│ ├── gradlew
│ ├── gradlew.bat
│ ├── gradle-wrapper.jar
│ └── gradle-wrapper.properties
└── src
├── main
└── test
Other than the fact that I don't know how to tell IntelliJ about the folder structure, I don't know how to change it for Gradle since the Environment Options related with changing the folder structure are deprecated:
-b, --build-file (deprecated)
Specifies the build file. For example: gradle --build-file=foo.gradle. The default is build.gradle, then build.gradle.kts.
-c, --settings-file (deprecated)
Specifies the settings file. For example: gradle --settings-file=somewhere/else/settings.gradle
You can't tell Gradle and Intellij IDEA that you use a non-standard Gradle build layout. And in all honesty, you shouldn't even consider that unless you have strong reasons to do so. There are mainly two reasons for that:
Developers familiar with one Gradle project feel immediately at home when starting with your Gradle project.
A non-standard build file and directory layout requires additional logic in IDE's (which is not present) and requires to provide extra parameters when building on the command line.
To put things into context, please have look at Gradle issue #16402.
Deprecate command-line options that describe the build layout
The -b and -c command-line options are effectively used to describe a non-standard build layout to Gradle. This is problematic because it means that a specific combination of options must be used whenever Gradle is used on that build, for example whenever invoked from the IDE, CI, command-line or some other tool. These command-line options also have some potentially surprising behaviours, such as running a settings script present in the target directory.
We don't think there are any use cases that are strong enough to justify keeping these options, and we should remove them (via deprecation). If we discover there are some use cases, we might consider replacing the options with more self-describing contracts, for example conventions for build script names.
I encountered a problem with gradle project structure. I have a task that needs to be realized and some tests are meant to be executed to check whether my project structure is correct and the tasks in gradle execute correctly. However I think I misunderstood instruction a bit and I'm wondering whether I can do something with my current folders structure or If I will have to rewrite the whole project. My current project structure looks like this:
main-repo-folder/
├── docker-related-file
├── rootProject
│ ├── sub-project-1
│ ├── build(output from tasks is created here)
│ ├── build.gradle
│ ├── sub-project-2
│ ├── gradle
│ ├── gradlew
│ ├── gradlew.bat
│ ├── settings.gradle
│ └── src
As you can see, the root project is a directory inside a repo. In order for my tests to execute I think the repo itself must be a root folder (or act as one) because the tests seem to be trying executing there. And here is my question, is it possible to add f.e settings.gradle file in main-repo-folder (at the same level as rootProject folder) to "point" gradle to build from rootProject and treat that folder as the root?(I mean f.e if I call gradle clean build task_name in main-repo-folder I want to make gradle execute it as I would be in rootProject folder)
I've tried to find some information but I'm at the path of learning gradle and I don't know if it is even possible :/ .
Rename main-repo-folder/rootProject to main-repo-folder.
I am creating a script.sh file that creates a Test.swift file and adds it into a Xcode project. However, I would like to know if there is a way to add this file to Xcode (in the project.pbxproj file) from this script? Instead of doing it manually in Xcode (Add files to Project...).
Thank you
3/05 Update
I tried #Johnykutty answer, here is my current Xcode project before executing the ruby script:
I have already generated a A folder with a Sample.swift file located in test, but these files are not linked to my Xcode project yet:
Now here is the script that I'm executing:
require 'xcodeproj'
project_path = '../TestCodeProjTest.xcodeproj'
project = Xcodeproj::Project.open(project_path)
file_group = project["TestCodeProjTest"]["test"]
file_group.new_file("#{project.project_dir}/TestCodeProjTest/test/A")
project.save()
This almost works fine, except that it creates a folder reference instead of a group, and it doesn't link it to my target:
Hence the content of Sample.swift is unreachable.
Its hard to achieve by bash. But really easy if you use Ruby and xcodeproj gem from Cocoapods
Consider you have file structure like
├── GeneratedFiles
│ └── Sample1.swift
├── MyProject
│ ├── AppDelegate.swift
│ ├── ... all other files
│ ├── SceneDelegate.swift
│ └── ViewController.swift
├── MyProject.xcodeproj
│ ├── project.pbxproj
│ ├── .....
└── add_file.rb
Then you can add files like
require 'xcodeproj'
project_path = 'MyProject.xcodeproj'
project = Xcodeproj::Project.open(project_path)
file_group = project["MyProject"]
file_group.new_file("../GeneratedFiles/Sample1.swift")
project.save()
UPDATE:
project["MyProject"] returns a file group which is a group named MyProject in the root of the project, you can select another group inside MyProject by file_group = project["MyProject"]["MyGroup"]
Then the generated file path should be either related to that group like file_group.new_file("../../GeneratedFiles/Sample1.swift") or full path like file_group.new_file("#{project.project_dir}/GeneratedFiles/Sample1.swift")
More details about Xcodeproj here
I'm new to go modules, and am taking them for a spin in a new project which I'm trying to model after the structure described here
Here is an example of my directory structure:
.
├── cmd
│ └── app_name
│ └── main.go
├── go.mod
├── go.sum
├── internal
│ └── bot
│ └── bot.go
└── pkg
├── website_name
│ ├── client.go
│ ├── client.options.go
│ ├── server.go
│ └── server.options.go
└── lib
└── lib.go
Is this idiomatically correct? I know there's not a whole lot of consensus out there, but I'd like to follow best practices.
When I run go build I get 'unexpected module path "github.com/ragurney/app_name/cmd/app_name"', but when I run go build ./... it works. Why?
When I move main.go to the top level everything works as expected. Should I just not use the /cmd pattern with modules?
To answer your first question, its completely opinionated and whatever you like best that is also easy to understand for others you should go with (I think it's fine).
To answer your second question the reason go build ./... works as opposed to go build from the root directory is because ./... starts in the current directory (the root) and searches for all program entry-points and builds them. When you move main.go to the root directory, with this new information, go build working then makes sense, as its only looking in the current directory.
You can explicitly say go build ./cmd/app_name which would also work.
Your application structure works perfectly fine with modules, as I use something very similar to it (https://www.ardanlabs.com/blog/2017/02/package-oriented-design.html) and modules work very well for me.
from what i can tell there is nothing wrong with your project structure. What has worked for me is to run the go build/run command from the project root
eg.
go run github.com/username/project/cmd/somecommand
go build -o somebinary github.com/username/project/cmd/somecommand
I prefer to add the specific file to build, there are some projects with more than one executable
go build -o app ./cmd/server/main.go
I’ve tried to add a package to Buildroot that uses Qt and Boost. The package uses qmake to generate a Makefile, this part seems to be working, however I get an error when I build saying:
Could not find qmake configuration file qws/linux-arm-g++.
Error processing project file: MsgDisplay.pro
The contents of my package is laid out like this:
DummyPgm
├── main.cpp
├── MsgDisplay.pri
├── MsgDisplay.pro
├── MsgDisplay.pro.user
├── MsgHandler.cpp
├── MsgHandler.h
├── MsgServer.cpp
├── MsgServer.h
├── Tcp
│ ├── TcpAddrPort.cpp
│ ├── TcpAddrPort.h
│ ├── TcpServer.cpp
│ ├── TcpServer.h
│ ├── TcpSocket.cpp
│ └── TcpSocket.h
└── Tools
├── Banner.cpp
├── Banner.h
├── IoExt.h
├── SeparateArgumentList.cpp
├── SeparateArgumentList.h
└── SysTypes.h
2 directories, 20 files
I have added a package directory, dummypgm, which contains Config.in and dummypgm.mk files. The contents of the files are:
Config.in:
config BR2_PACKAGE_DUMMYPGM
bool "dummypgm"
help
Foo Software.
http://www.foo.com
dummypgm.mk:
DUMMYPGM_VERSION = 0.1.0
DUMMYPGM_SOURCE = DummyPgm-$(DUMMYPGM_VERSION).tar.gz
define DUMMYPGM_CONFIGURE_CMDS
(cd $(#D); $(QT_QMAKE) MsgDisplay.pro)
endef
define DUMMYPGM_BUILD_CMDS
$(MAKE) -C $(#D)
endef
$(eval $(generic-package))
Since the package is hosted locally, I’ve simply put the DummyPgm-0.1.0.tar.gz in the dl directory.
I’ve also added the following to package/Config.in:
source "package/dummypgm/Config.in"
I’m a little lost as to why this doesn’t work, if anyone could help me I would be very grateful. Also, is there any way to call $(eval $(qmake-package)) or something?
Are you using Qt4 or Qt5 ? Your package/dummypgm/Config.in should have a depends on on one of them, and your dummypgm.mk should have a DUMMYPGM_DEPENDENCIES = qt or DUMMYPGM_DEPENDENCIES = qt5base.
My intuition is that you are using Qt5. In this case, you shouldn't call $(QT_QMAKE), but $(QT5_QMAKE).
Have a look at http://git.buildroot.net/buildroot/tree/package/qextserialport/qextserialport.mk for an example. Note that this example supports both Qt4 and Qt5, probably in your case you only need one of the two.
Also, you should really subscribe to the Buildroot mailing list, you would get a lot more answers than here.