I have the following models: Merchant, Product and Store:
Merchant:
class Merchant extends Model
{
public function products() {
return $this->hasMany('App\Product');
}
}
Product:
class Product extends Model
{
public function merchants() {
return $this->belongsTo('App\Merchant');
}
public function stores() {
return $this->belongsTo('App\Store');
}
}
Store:
class Store extends Model
{
public function products() {
return $this->hasMany('App\Product');
}
}
In my MerchantController, I have the following method show():
public function show() {
$merchants = Merchant::selectRaw('merchants.*, REPLACE(abstract, \'[[name]]\', name) AS abstract')
->with('products')
->where('active', 'yes')
->Paginate(10);
dd($merchants);
//return view('merchants', compact('merchants'));
}
How can I access the stores, the several products are in? I tried ->with(['products', 'stores']) and got an error:
Call to undefined relationship [stores] on model [App\Merchant].
What can I do to solve my problem?
Use laravel's hasManyThrough relationship
in your Merchant model
add this relationship
public function stores()
{
return $this->hasManyThrough(Store::class, Product::class);
}
Related
I have 5 tables User, Profile, Address,State,City .Need to create relationship between tables.Address has State id , City id and Profile id in the table.Profile has User Id in the table.City has State Id in the table. How to write relationship between table
class City extends Model
{
public function state() {
return $this->belongsTo('App\State');
}
public function addresses() {
return $this->hasMany('App\Address');
}
}
class State extends Model
{
public function cities() {
return $this->hasMany('App\City');
}
public function addresses() {
return $this->hasMany('App\Address');
}
}
class Profile extends Model
{
public function address() {
return $this->belongsTo('App\Address');
}
public function user() {
return $this->belongsTo('App\User');
}
}
class Address extends Model
{
public function profile() {
return $this->belongsTo('App\Profile');
}
public function city() {
return $this->belongsTo('App\City');
}
public function state() {
return $this->belongsTo('App\State');
}
}
// users table
public function profile(){
return $this->hasOne('App\Profile');
}
Generally your model design is true, i have edited a few parts. Try the codes below.
class City extends Model
{
public function state()
{
return $this->belongsTo('App\State');
}
public function addresses()
{
return $this->hasMany('App\Address');
}
}
class State extends Model
{
public function cities()
{
return $this->hasMany('App\City');
}
public function addresses()
{
return $this->hasMany('App\Address');
}
}
class Profile extends Model
{
public function addresses()
{
return $this->hasMany('App\Address');
}
public function user()
{
return $this->belongsTo('App\User');
}
}
class Address extends Model
{
public function profile()
{
return $this->belongsTo('App\Profile');
}
public function city()
{
return $this->belongsTo('App\City');
}
public function state()
{
return $this->belongsTo('App\State');
}
}
class User extends Model
{
public function profile()
{
return $this->hasOne('App\Profile');
}
}
By the way, Laravel relationships add default keys according to your method names. If you have problem about it you can find info from official documents. For example:
$this->belongsTo('App\Model', 'foreign_key', 'other_key');
as #mustafa.akcoban says...
When you use belongsTo Eloquent will work as follow
$this->belongsTo('App\City', 'foreign_key', 'other_key');
// foreign_key = is the primary key in the related model, by default 'id' for Eloquent
// other_key = is the field in the current model that contains the id of the other model, by default othermodelname_id for Eloquent
// For eg. 'App\City', 'id', 'city_id'
When you use hasMany Eloquent works as follow
$this->hasMany('App\Model', 'currentmodel_id', 'primary_key');
// currentmodel_id = is the field that contains the current model primary key in the related model
// primary_key = is the current primary key model that will be in the other model, by default id for Eloquent
// For eg. 'App\City', 'state_id', 'id'
Remember you can or can't use second and third parameter, if something is wrong Laravel dump will tell you what column was not found in the table, and you will can fix.
Please try and practice this, and let me know how it works :)
I'm working on a complex shopping cart project. I have relationships like this
CategoryGroup model
// App\CategoryGroup
class CategoryGroup extend Model
{
public function categories()
{
return $this->hasMany(Category::class);
}
}
Category model
// App\Category
class Inventory extend Model
{
public function categoryGroup()
{
return $this->belongsTo(CategoryGroup::class);
}
public function products()
{
return $this->belongsToMany(Product::class);
}
public function listings()
{
return $this->belongsToMany(
Inventory::class,
'category_product',
null,
'product_id',
null,
'product_id'
);
}
}
Product model
// App\Product
class Product extend Model
{
public function categories()
{
return $this->belongsToMany(Category::class);
}
public function listings()
{
return $this->hasMany(Inventory::class);
}
}
Inventory model
// App\Inventory
class Inventory extend Model
{
public function products()
{
return $this->belongsTo(Product::class);
}
}
Now I'm stuck on the situation where I need to create a relationship between The CategoryGroups and the Inventory model like this:
// App\CategoryGroup
class CategoryGroup extend Model
{
public function categories()
{
return $this->hasMany(Category::class);
}
public function listings()
{
// Can't figured out the way
// A belongsToMany like the App\Category would be great
}
}
Is there a good way to achieve this kind of relationship?
Laravel has no native support for a direct relationship.
I created a package for cases like this: https://github.com/staudenmeir/eloquent-has-many-deep
You can use it like this:
class CategoryGroup extends Model {
use \Staudenmeir\EloquentHasManyDeep\HasRelationships;
public function inventories() {
return $this->hasManyDeep(
Inventory::class,
[Category::class, 'category_product', Product::class]
);
}
}
I created a relationship like this:
Type.City.Street.House.Apartment
In this relation, the apartment must depend on the House and on the Type at the same time, so result sql query must be like this:
select * from `apartments` where `apartments`.`house_id` in ('1', '2', '3') and `type_id` = '777'
The problem is that the HasManyThrough relationship only looks at a two of levels and it's not possible to get to the very first model with it.
Please, advise how this can be done?
My models definations:
class Type extends Model {
public function city() {
return $this->hasMany('App\City');
}
}
class City extends Model {
public function street() {
return $this->hasMany('App\Street');
}
}
class Street extends Model {
public function house() {
return $this->hasMany('App\House');
}
}
class House extends Model {
public function Apartment() {
return $this->hasMany('App\Apartment');
//->where('type_id', '=' type.id) ?????
}
}
class Apartment extends Model {
public $fillable = ['house_id', 'type_id']
}
I would add a mapping for house_id in Apartment model and sets bidirectional mappings among your models
class Apartment extends Model {
public $fillable = ['house_id', 'type_id'];
public function house() {
return $this->belongsTo('App\House', 'house_id');
}
}
class Type extends Model {
public function city() {
return $this->hasMany('App\City');
}
}
class City extends Model {
public function type() {
return $this->belongsTo('App\Type', 'type_id');
}
public function street() {
return $this->hasMany('App\Street');
}
}
class Street extends Model {
public function city() {
return $this->belongsTo('App\City', 'city_id');
}
public function house() {
return $this->hasMany('App\House');
}
}
class House extends Model {
public function street() {
return $this->belongsTo('App\Street', 'street_id');
}
public function Apartment() {
return $this->hasMany('App\Apartment');
//->where('type_id', '=' type.id) ?????
}
}
then you can query apartments as per your criteria like
Apartments::whereHas('house.street.city.type', function ($query) use ($type_id) {
$query->where('id', '=', $type_id);
})
->whereHas('house', function ($query) use ($house_ids) {
$query->whereIn('id', $house_ids);
});
And i guess there is no need for type_id in Apartments model
I created a HasManyThrough relationship with unlimited levels: Repository on GitHub
After the installation, you can use it like this:
class Type extends Model {
use \Staudenmeir\EloquentHasManyDeep\HasRelationships;
public function Apartment() {
return $this->hasManyDeep(Apartment::class, [City::class, Street::class, House::class])
->where('apartments.type_id', $this->id);
}
}
Unfortunately, this doesn't work with eager loading.
I have a recently started learning Laravel 5.4, I am having trouble with my 3 way table relationship, I've looked at a few articles online regarding many to many, but this relationship is just a "hasOne" on both sides.
Could anyone give me a helpful hint as to how to structure my table relationship, here is the PK/FK relationship:
Users table (id)
Listings table (id, user_id)
Insights table (id, listing_id) - one insight row per listing only.
And the models below:
Users Model
class User extends Model
{
public function listing()
{
return $this->belongsTo('App\Listing');
}
}
Listing Model
class Listing extends Model
{
public function insight()
{
return $this->hasOne('App\Insight');
}
}
Insight Model
class Insight extends Model
{
public function listing()
{
return $this->hasOne('App\Listing');
}
}
And what I am trying to achieve is to query the users own listings, with each listings current insights.
Thanks a bunch.
Simon.
User model
class User extends Model
{
public function listing()
{
return $this->hasOne('App\Listing');
}
}
Listing Model
class Listing extends Model
{
public function insight()
{
return $this->hasOne('App\Insight');
}
public function user()
{
return $this->belongsTo('App\User');
}
}
Insight Model
class Insight extends Model
{
public function listing()
{
return $this->belongsTo('App\Listing');
}
}
And if you want query users with Listing and Insight
$users = User::with(['listing', 'listing.insight'])->get();
foreach($users as $user) {
$user->listing->insight;
}
class User extends Model
{
public function listing()
{
return $this->hasMany(Listing::class);
}
}
class Listing extends Model
{
public function insight()
{
return $this->hasOne(Insight::class);
}
public function user()
{
return $this->belongsTo(User::class);
}
}
class Insight extends Model
{
public function listing()
{
return $this->belongsTo(Listing::class);
}
}
$users = User::with('listing.insight')->get();
foreach($users as $user) {
$user->listing->insight;
}
In my Laravel application I have the following classes:
class Product extends Model
{
public function extended()
{
return $this->morphTo();
}
public function users {
return $this->belongsToMany('App\User', 'products_users', 'product_id');
}
}
class Foo extends Model
{
public function product()
{
return $this->morphOne('App\Product', 'extended');
}
public function bars()
{
return $this->hasMany('App\Bar');
}
}
class Bar extends Model
{
public function product()
{
return $this->morphOne('App\Product', 'extended');
}
public function foo()
{
return $this->belongsTo('App\Foo');
}
}
class User extends Model
{
public function products()
{
return $this->belongsToMany('App\Product', 'products_users', 'user_id');
}
}
I can easily get users of a bar object using Bar::find(1)->product->users and I can also get the bars of a user with User::find(1)->products.
How can I get the users of all bars belonging to a specific foo? That is, Foo::find(1)->users should return all users that have the bars belonging to Foo with id 1. It's basically hasManyThrough with polymorphic and many-to-many relations.
Try something like this:
public function users()
{
$Foo = static::with(['bars', 'bars.products', 'bars.product.users'])->get();
return collect(array_flatten(array_pluck($Foo, 'bars.*.product.users')));
}
This should work for you (code has been tested, but not against the exact same structure as your setup). The first line will return all the users deeply nested through the relationships. The second line will pull out the users, flatten them into an array, then transform the array into a collection.
I created a HasManyThrough relationship for cases like this: Repository on GitHub
After the installation, you can use it like this:
class Foo extends Model {
use \Staudenmeir\EloquentHasManyDeep\HasRelationships;
public function users() {
return $this->hasManyDeep(
User::class,
[Bar::class, Product::class, 'products_users'],
[null, ['extended_type', 'extended_id']]
);
}
}