I am using spring boot and I have a file in resources folder. I am using digital ocean machine and when i run the application using java -jar mywebapp.war, I am unable to access the file from classpath. I am accessing it using following standard syntax:
File file = new ClassPathResource("mfile").getFile();
I am getting error that class path resource cannot be resolved to absolute path. The problem I see is that it is showing the path with ! marks as follows:
/home/u/webapp/target/mywebapp.war!/WEB-INF/classess!/mfile
What am I doing wrong here?
Since you're running it with java -jar you should build it as a JAR file instead of WAR.
Read more: https://docs.spring.io/spring-boot/docs/current/reference/html/deployment-install.html
Get file does not work while running as jar.you should get it as a resource Stream.
ClassLoader classLoader = getClass().getClassLoader();
InputStream inputStream = classLoader.getResourceAsStream("/file.xsd") ;
File file = File.createTempFile("file", ".xsd");
try {
FileUtils.copyInputStreamToFile(inputStream, file);
} finally {
IOUtils.closeQuietly(inputStream);
it gets you a file. if the requirement is to get as a file.
Related
In spring boot application how do I give an external windows path using #Value Spring annotation and Resource
The below example works fine that look into resources folder but I want to give the path outside of application like c:\data\sample2.csv
#Value("classPath:/sample2.csv")
private Resource inputResource;
...
#Bean
public FlatFileItemReader<Employee> reader() {
FlatFileItemReader<Employee> itemReader = new FlatFileItemReader<Employee>();
itemReader.setLineMapper(lineMapper());
itemReader.setLinesToSkip(1);
itemReader.setResource(inputResource);
and if I want to get the value from properties file in annotaion, whats the format to put the path in windows?
i tried these, none of them worked:
in code
#Value("${inputfile}")
in properties file:
inputfile="C:\Users\termine\dev\sample2.csv"
inputfile="\\C:\\Users\\termine\\dev\\sample2.csv"
inputfile="C:/Users/termine/dev/sample2.csv"
inputfile="file:\\C:\Users\termine\dev\sample2.csv"
inputfile="file://C://Users//termine///dev//sample2.csv"
When you use classpath spring will try to search with the classpath even if you provide the outside file path.
so instead of using classpath: you can use file:
Ex.
#Value("file:/sample2.csv") //provide full file path if any
Use the key spring.config.location in properties to set the config location. Spring-boot will by default load properties from the locations, with precedence like below :
A /config subdir of the current directory.
The current directory
A classpath /config package
The classpath root
and apart from this when you start the jar or in application.properties you can provide the location of the config file like :
$ java -jar myproject.jar --spring.config.location=classpath:/default.properties,classpath:/override.properties
You can serve static files from the local disk, by making the resource(s) "sample2.csv" as a static resource. An easy way to do this is by adding spring.resources.static-locations configuration to your applicaiton.properties file. Example:
spring.resources.static-locations=file:///C:/Temp/whatever/path/sample2.csv",classpath:/static-files, classpath:/more-static-resource
When I did this in one of the projects, I was able to access the file form the browser using localhost:8080/sample2.csv.
I'm trying to give resource folder for Freemarker template below is my bean config
Configuration freeMarkerConfig() throws IOException {
Configuration cfg = new Configuration(Configuration.VERSION_2_3_29);
cfg.setDirectoryForTemplateLoading(new ClassPathResource("ftl").getFile());
return cfg;
}
and I have ftl folder in the resources folder
-- java
-- resources
-- ftl
-- template.ftl
while deploying it works fine in my local machine but fails in my docker container with exception
java.io.FileNotFoundException: class path resource [ftl] cannot be resolved to absolute file
path because it does not reside in the file system: jar:file:!/BOOT-INF/classes!/ftl
I need to keep ftl in the resources folder and give the directory path to configuration. I don't know how to debug further.
Property spring.freemarker.template-loader-path is available.
spring.freemarker.template-loader-path=classpath:/ftl/
Or, use setTemplateLoaderPath("classpath:/ftl/") instead of setDirectoryForTemplateLoading().
I found the issue after repeated searching. Issue is because of this
Classpath resource not found when running as jar
My Spring Boot project contains an XML file within the src/main/resources folder, which is the common location for such a file.
Running locally and also on Pivotal CloudFoundary, I am able to locate the file and read it in, but on Beanstalk the process results in an empty file.
Code to locate and read file:
URL url = getClass().getResource("/myFile.xml");
LOG.info("File location: " + url.toString());
Resulting log entry:
File location: jar:file:/var/app/current/application.jar!/WEB-INF/classes!/myFile.xml
When I SSH into EC2 instance, I can find the jar in the specified directory.
Do I need to configure Maven to move this file somewhere?
UPDATE
I've since realized that I need to treat this file as in InputStream as it's packaged within the jar.
I'm now using the following code which results in the follow errors:
FileUtils.copyInputStreamToFile(new ClassPathResource("myFile.xml").getInputStream(), myFile);
java.lang.NullPointerException: null
at org.apache.commons.io.FileUtils.openOutputStream(FileUtils.java:345) ~[commons-io-2.5.jar:2.5]
and
FileUtils.copyInputStreamToFile(new ClassPathResource("classpath:myFile.xml").getInputStream(), myFile);
java.io.FileNotFoundException: class path resource [classpath:myFile.xml] cannot be opened because it does not exist
Thanks!
How does your pom.xml look like? Maybe there is a resource-filter active?
In a spring application you could use File file = ResourceUtils.getFile("classpath:myFile.xml"); to read a resource file.
Could you check the result by using ResourceUtils?
Here the link to the api-documentation:
https://docs.spring.io/spring/docs/current/javadoc-api/org/springframework/util/ResourceUtils.html#getFile-java.lang.String-
I have a Spring Boot application, the code need to access a file under resources/templates folder.
here is my application.properties file:
pont.email.template.location=templates/mailTemplate.html
This is the java file where I use the variable:
#Value("${pont.email.template.location}")
private String templateLocation;
----------------
BufferedReader reader = new BufferedReader(new FileReader(templateLocation));
The problem is not get the varibale, it returns correctly, The problem is that the application do not found any file for this path.
I always get
java.io.FileNotFoundException: templates/mailTemplate.html (No such file or directory)
I have checked that the file is in the path..
what is wrong in my code?
Help please, thanks.
You cannot read a File from inside a JAR. This fails due to the fact that the File has to point to an actual file resource on the file system and not something inside a JAR.
Let Spring do the heavy lifting and use the Resource abstraction to hide the nasty internals. So instead of using a String use a Resource and prefix the value of the property with classpath: to make sure it is loaded from the classpath. Then use an InputStreamReader instead of FileReader to obtain the information you need.
#Value("${pont.email.template.location}")
private Resource templateLocation;
----------------
BufferedReader reader = new BufferedReader(new InputStreamReader(templateLocation.getInputStream()));
In your application.properties prefix with classpath:.
pont.email.template.location=classpath:templates/mailTemplate.html
Now it should work regardless of the environment you are running in.
I want to set my relative file path in a properties file so my SaxReader can pick it up when it runs on Tomcat server. I know this should be easy but I've forgotten forgive me :)
I know Spring Boot has application.properties file but I don't see a way to hook in here.
Is there a way to set the relative path in a properties file that will get picked up by Spring Boot and the SaxReader will see it?
As it is I'm hard coding just the filename and putting the file in the resources folder that serves up the templates and static content such as css and js files. The filePath system.out gives: org.dom4j.DocumentException C:sts-bundle\sts-3.7.2.RELEASE\myFileName the toolsuite root location??? weird!!
Please tell me how to specify the relative path in a properties file.
Thanks!!
You can set the file path like any other string property in Spring Boot properties file and access it from inside the path.
E.g. I have the following set in my application.properties file:
download.directory=temp
and it is used as follows in java class:
#Value("${download.directory}")
private String downloadDirectory;
It is used to download the files, now, if I start the application with jar file present in let's say G:/applications folder then the files will be downloaded into G:/applications/temp.