combineLatest deprecated in favor of static combineLatest - rxjs

Question

After running the rxjs migration tool using
rxjs-5-to-6-migrate -p src/tsconfig.app.json
I'm now getting a linting error:
combineLatest is deprecated: Deprecated in favor of static
combineLatest.
Here is my code before running the migration command:
this.store.combineLatest(
this.store.select(lang.getCurrent),
this.store.select(lang.getCurrentLocale)
).subscribe(([state, currentLang, locale]) => {
this._language = session.language === currentLang ? '' : currentLang;
this._locale = session.locale === locale ? '' : locale;
});
My code after running the migration command: (currently presenting a linting error)
import {map, combineLatest} from 'rxjs/operators';
this.store.combineLatest(
this.store.select(lang.getCurrent),
this.store.select(lang.getCurrentLocale)
).subscribe(([state, currentLang, locale]) => {
this._language = session.language === currentLang ? '' : currentLang;
this._locale = session.locale === locale ? '' : locale;
});
The question was asked in this stackoverflow questions, but it was not specific enough: Angular 6 ng lint duplicate errors and warnings, combineLatest is deprecated
.

Answer 1

In rxjs 6.5+
import { combineLatest } from 'rxjs';
combineLatest([a$, b$, c$]);
And for most applications it's helpful to map the array of observables to a new value as well:
combineLatest([a$, b$, c$]).pipe(
map(([a$, b$, c$]) => ({
a: a$,
b: b$,
c: c$
}))
);
Also see: https://www.learnrxjs.io/learn-rxjs/operators/combination/combinelatest

Answer 2

Deprecated!
Please refer to ofir fridman's answer for the correct syntaxs as of RxJs 6.5
I found an answer in this article titled: RxJS 6: What's new and what has changed? ( which comes from official docs):
The solution is to convert:
import { combineLatest } from 'rxjs/operators';
a$.pipe(combineLatest(b$, c$));
into:
import { combineLatest } from 'rxjs';
combineLatest([a$, b$, c$]);

Answer 3

rxjs version 6.4.0
You should import map operator from RxJs operators for it to work
combineLatest(a$, b$, c$).pipe(map([a, b, c]) => treat(a, b, c))

Answer 4

Seems combineLatest has been deprecated and passing an array as suggested in the various answers still throws the error in rxjs v.7.0.0 Deprecation Notice
Replaced with combineLatestWith. Will be removed in v8.
For those using rxjs v.7.0.0 and above you will need to use combineLatestwith
input1Changes$.pipe(
combineLatestWith(input2Changes$)
)

Answer 5

import { combineLatest } from 'rxjs';
combineLatest([
this.store.select(lang.getCurrent),
this.store.select(lang.getCurrentLocale)
]).subscribe(([state, currentLang, locale]) => {
this._language = session.language === currentLang ? '' : currentLang;
this._locale = session.locale === locale ? '' : locale;
});

Answer 6

combineLatest with a list of subscribers:
combineLatest([aSubscriber, bSubscriber]).pipe(map((aRes, bRes)=>{
// your business logic
}));