Calculate duration in HH:MM:SS format using difference in start and end time.
# Time Arithmetic
TIME1="00:30:20"
TIME2="00:30:50"
# Convert the times to seconds from the Epoch
SEC1=`date -j -f '%T' $TIME1 "+%s"`
#echo $SEC1
SEC2=`date -j -f '%T' $TIME2 "+%s"`
#echo $SEC2
# Use expr to do the math, let's say TIME1 was the start and TIME2 was the finish
DIFFSEC=`expr ${SEC2} - ${SEC1}`
#echo $DIFFSEC
echo Start ${TIME1}
echo Finish ${TIME2}
echo Took ${DIFFSEC} seconds.
# And use date to convert the seconds back to something more meaningful
result=`date -r $DIFFSEC "+%T"`
echo Result ${result}
Expected : Result 00:30:30 00:00:30(corrected)
Actual : Result 05:30:30
EDIT Actual TIME1 and TIME2 will be coming as params, and intension here is not to calculate time elapsed. It is a sample code i have used to demonstrate the issue. Strangely when TIME1=05:30:20 and TIME2=05:30:50 then also Result is : 05:30:30
Corrected Subject.
I finally settled with below, thanks anyways.
result=$(printf '%02d:%02d:%02d' $(($DIFFSEC/3600)) $(($DIFFSEC%3600/60)) $(($DIFFSEC%60)))
Related
I need difference between two dates in seconds. I input datetime in format "YYYY-MM-DD HH:MM" and then calculate difference in seconds, but the run_time is in UTC timezone and current_time is calculated from system timezone.
#!/bin/bash
run_time=$1
run_time=$(date -d "$run_time" +"%s")
current_time="$(date +"%s")"
echo $run_time
echo $current_time
echo "$(($run_time-$current_time))"
How to retrieve absolute value of seconds between current datetime and another one?
Edit: actually that script has worked after restart of computer. No clue why previously it showed up different results. I have not changed anything in settings, nor computer time.
Right #Jetchisel, based on your comment a sample script could look like:
#!/bin/bash
STARTTIME_UTC=$1
STARTTIME_UTC=$(date -u -d "${STARTTIME_UTC}" +"%s")
echo "CURRENT DATE: $(date)"
CURRENTTIME="$(date +"%s")"
echo
echo "STARTTIME_UTC: ${STARTTIME_UTC} sec since"
echo "CURRENTIME: ${CURRENTTIME} sec since"
echo
echo "RUNTIME: $((${CURRENTTIME}-${STARTTIME_UTC})) sec"
As per original question
I input datetime in format "YYYY-MM-DD HH:MM"
the value of input time seconds in ${STARTTIME_UTC} will be set to zero (:00) whereby the value of current time seconds in ${CURRENTIME} will be set to what the clock provides. I.e., if it is 18 seconds before the next minute and the runtime would be almost zero, the script will report a difference of 42 seconds.
I have a bash script that creates a file with a timestamp as the name. Once some time passes, it is supposed to pick up that file and do something with it. I want it to pick it up after two hours, but for some reason, it is picking it up after 57 minutes (and 6 seconds). Can anyone point me to an error in my logic or assumptions?
Here are the details:
I have a variable set to 2 hours (7200 seconds):
SERVICE_DURATION=${SERVICE_DURATION:-7200} # seconds
I am setting the filename equal to the Unix timestamp concatenated with nanoseconds:
active_name=`date +%s%N`
echo "${1}" >> ${ACTIVE_DIR}/${active_name}
I then loop forever until the time is right:
while true
do
for fa in ${ACTIVE_DIR}/*
do
if [ $(basename ${fa}) -le $(($(date +%s%N) - ${SERVICE_DURATION} * 1000000000)) ]
then
exec 6< "${fa}"
read old_port <&6
read old_host <&6
read old_config <&6
exec 6<&-
logger -p daemon.info "Recycling port ${old_port}."
start_remote_service "${old_port}"
stop_remote_service "${old_port}" "${old_host}" "${old_config}" "${fa}"
sleep 2
fi
done
sleep 30
done
I can't see what is wrong with this. The filename ($(basename ${fa})) shouldn't be less than the current time minus the specified duration in nanoseconds ($(($(date +%s%N) - ${SERVICE_DURATION} * 1000000000))) until the duration has passed.
In order to keep the script from constantly checking, there is a sleep 30 at the end of the loop, so it could be that the time is somewhere between 56:36 and 57:06.
Any help would be appreciated. Thanks.
I need help using time in the c-shell
I want to know how much time it took to execute a script,so i want to do in the following way
1.set start_time=time
2 script part
3.set end_time=time
4. set diff=end_time-start_time
5.echo "It took $diff seconds"
but i couldn't get the time value using any command.
could any one suggest a command to read the time value in c-shell
I think you want the "date" command, with the format to give you raw seconds:
# start_time = `date +%s`
script part
# end_time = `date +%s`
# diff = $end_time - $start_time
echo "It took $diff seconds"
First of all: sorry for using c shell, blame my company not me. I hate the damn thing as much as most of you do now (at first I was like, hey this ain't so bad).
I am trying to subtract large numbers obtained from time stamps. Here is what I am trying:
set curTime = `date +%s%N`
#... some stuff
#curTime = `date +%s%N` - $curTime #get the diff
echo "time taken: $curTime"
However I guess the numbers are too big - before I tried with just seconds and it worked fine. Here's what I see in the log:
#curMilli = 1349996279792995000 - 1349996279170458000
#curMilli: Command not found.
As I said I do the exact same thing with date +%s and it's fine, so I'm assuming it's something about the largeness of the numbers.
How can I do this? Thanks a lot.
The article http://en.wikipedia.org/wiki/Bc_programming_language has a short section "Using bc in shell scripts". A test:
set curTime = `/bin/date +%s%N`
/bin/sleep 2
set prevTime = $curTime
set curTime = `/bin/date +%s%N`
set diff = `echo "$curTime - $prevTime;" | /usr/bin/bc`
echo $diff
will give (with the digits after the initial 20 variable):
2016204108
P.s: I wish I could vote you up twice for "I hate the damn thing as much as most of you do now (at first I was like, hey this ain't so bad)."
I run my own script to dump databases into files on a nightly basis.
I wanted to count time (in seconds) it takes to dump each database, so I was trying to write some functions to help me achieve it, but I'm running into problems.
I am no expert in scripting in bash, so if I'm doing it plain wrong, just say so and ideally suggest alternative, please.
Here's the script:
#!/bin/bash
declare -i time_start
function get_timestamp {
declare -i time_curr=`date -j -f "%a %b %d %T %Z %Y" "\`date\`" "+%s"`
echo "get_timestamp:" $time_curr
return $time_curr
}
function timer_start {
get_timestamp
time_start=$?
echo "timer_start:" $time_start
}
function timer_stop {
get_timestamp
declare -i time_curr=$?
echo "timer_stop:" $time_curr
declare -i time_diff=$time_curr-$time_start
return $time_diff
}
timer_start
sleep 3
timer_stop
echo $?
The code should really be quite self-explanatory. echo commands are only for debugging.
I expect the output to be something like this:
$ bash timer.sh
get_timestamp: 1285945972
timer_start: 1285945972
get_timestamp: 1285945975
timer_stop: 1285945975
3
Now this is not the case unfortunately. What I get is:
$ bash timer.sh
get_timestamp: 1285945972
timer_start: 116
get_timestamp: 1285945975
timer_stop: 119
3
As you can see, the value that local var time_curr gets from the command is a valid timestamp, but returning this value causes it to be changed to an integer between 0 and 255.
Can someone please explain to me why this is happening?
PS. This obviously is just my timer test script without any other logic.
UPDATE
Just to be perfectly clear, I want this to be part of a bash script very similar to this one, where I want to measure each loop cycle.
Unless of course I can do it with time, then please suggest a solution.
You don't need to do all this. Just run time <yourscript> in the shell.
$? is used to hold the exit status of a command and can only hold a value between 0 and 255. If you pass an exit code outside this range (say, in a C program calling exit(-1)), the shell will still receive a value in that range and set $? accordingly.
As a workaround, you could just set a different value in your bash function:
function get_timestamp {
declare -i time_curr=`date -j -f "%a %b %d %T %Z %Y" "\`date\`" "+%s"`
echo "get_timestamp:" $time_curr
get_timestamp_return_value=$time_curr
}
function timer_start {
get_timestamp
#time_start=$?
time_start=$get_timestamp_return_value
echo "timer_start:" $time_start
}
...
I believe you should be able to use the existing "time" function.
After Update to the question:
This was the bit of script from your link which was doing a for loop.
# dump each database in turn
for db in $databases; do
echo $db
$MYSQLDUMP --force --opt --user=$USER --password=$PASSWORD
--databases $db > "$OUTPUTDIR/$db.bak"
done
You could extract the inner portion of the loop into a new script (call it dump_one_db.sh)
and do this inside the loop:
# dump each database in turn
for db in $databases; do
time dump_one_db.sh $db
done
Make sure to write the output of the time against the db name into some file.
This is happening because return codes need to be between 0-255. You can't return an arbitrary number. If you continue to refuse to use the builtin time function and roll your own, change your functions to echo their stamp and use a process expansion ($()) to grab the value.