I am having multiple products and each of them are having there own Product table and Value table. Now I have to create a generic screen to validate those product and I don't want to create validated table for each Product. I want to create a generic table which will have all the Products details and one extra column called ProductIdentifier. but the problem is that here in this generic table I may end up putting millions of records and while fetching the data it will take time.
Is there any other better solution???
"Millions of records" sounds like a VLDB problem. I'd put the data into a partitioned table:
CREATE TABLE myproducts (
productIdentifier NUMBER,
value1 VARCHAR2(30),
value2 DATE
) PARTITION BY LIST (productIdentifier)
( PARTITION p1 VALUES (1),
PARTITION p2 VALUES (2),
PARTITION p5to9 VALUES (5,6,7,8,9)
);
For queries that are dealing with only one product, specify the partition:
SELECT * FROM myproducts PARTITION FOR (9);
For your general report, just omit the partition and you get all numbers:
SELECT * FROM myproducts;
Documentation is here:
https://docs.oracle.com/en/database/oracle/oracle-database/12.2/vldbg/toc.htm
Related
There's total of three tables involved. one header base table, one material
base table, one staging table.
I have created the staging table with 4 columns, the values will be
updated from csv uploaded, column 1 is batch_no, column 2 is for
attribute.
>header base table(h) has batch_no and batch_id
>material base table(m) has batch_id, attr_m (empty, to be updated)
>staging table(s) has batch_no and attr_s
create table he (BATCH_ID number, BATCH_NO varchar2(30));
create table me (a6 varchar2(30), BATCH_id number);
create table s (batch_no varchar2(30), att varchar2(30));
I want to take values from attr_s and update attr_m against batch_no. How do I do that?
Here's my code, please help me fix this code, it doesn't work
update me
set a6 = (select att
from s where batch_no = (select he.batch_no
from he, s
where he.batch_no=s.batch_no))
error received:
single row subquery return multiple rows.
single row subquery return multiple rows
The update statement is applied to each individual row in ME. Therefore the assignment operation requires one scalar value to be returned from the subquery. Your subquery is returning multiple values, hence the error.
To fix this you need to further restrict the subquery so it returns one row for each row in ME. From your data model the only way to do this is with the BATCH_ID, like so:
update me
set a6 = (select att
from s where batch_no = (select he.batch_no
from he, s
where he.batch_no=s.batch_no
and he.batch_id = me.batch_id))
Such a solution will work providing that there is only one record in S which matches a given permutation of (batch_no, batch_id). As you have provided any sample data I can't verify that the above statement will actually solve your problem.
I'm trying to copy data from a table called accounts into an empty table called accounts_by_area_code. I have the following fields in accounts_by_area_code: acct_num INT, first_name STRING, last_name STRING, phone_number STRING. The table is partitioned by areacode (the first 3 digits of phone_number.
I need to use a SELECT statement to extract the area code into an INSERT INTO TABLE command to copy the speciļ¬ed columns to the new table, dynamically partitioning by area code.
This is my last attempt:
impala-shell -q "INSERT INTO TABLE accounts_by_areacode (acct_num, first_name, last_name, phone_number, areacode) PARTITION (areacode) SELECT STRLEFT (phone_number,3) AS areacode FROM accounts;"
This generates ERROR: AnalysisException: Column permutation and PARTITION clause mention more columns (5) than the SELECT / VALUES clause and PARTITION clause return (1). I'm not convinced I have even the basic syntax correct so any help would be great as I'm new to Impala.
Impala creates partitions dynamically based on data. So not sure why you want to create an empty table with partitions because it will be auto created while inserting new data.
Still, I think you can create empty table with partitions like this-
impala-shell -q "INSERT INTO TABLE accounts_by_areacode (acct_num) PARTITION (areacode)
SELECT CAST(NULL as STRING), STRLEFT (phone_number,3) AS areacode FROM accounts;"
For example, I have a table name Emp and it has empname, designation, salary as columns. I would like this table to have 2 partitions, like list of employees who are managers in one partition and rest(engineer, peon, clerk) in one partition.
can someone help on how to create it
In this case you will have to use LIST based partition. Create a pertition where ROLE = MANAGER and create another partition which is default. Here is an example which will help you.
Exclude values from oracle partition
Example
CREATE TABLE EMPLOYEE (EMP_ID VARCHAR2(25),
EMP_NAME VARCHAR2(250),
ROLE VARCHAR2(100)
)
PARTITION BY LIST (ROLE)
(
PARTITION part_managers
VALUES ('MANAGER'),
PARTITION part_others
VALUES (DEFAULT)
);
Please refer the following URL and example:
For example, the following SQL statement splits the sales_Q4_2007 partition of the partitioned by range table sales splits into five partitions corresponding to the quarters of the next year. In this example, the partition sales_Q4_2008 implicitly becomes the high bound of the split partition.
ALTER TABLE sales SPLIT PARTITION sales_Q4_2007 INTO
( PARTITION sales_Q4_2007 VALUES LESS THAN (TO_DATE('01-JAN-2008','dd-MON-yyyy')),
PARTITION sales_Q1_2008 VALUES LESS THAN (TO_DATE('01-APR-2008','dd-MON-yyyy')),
PARTITION sales_Q2_2008 VALUES LESS THAN (TO_DATE('01-JUL-2008','dd-MON-yyyy')),
PARTITION sales_Q3_2008 VALUES LESS THAN (TO_DATE('01-OCT-2008','dd-MON-yyyy')),
PARTITION sales_Q4_2008);
For the sample table customers partitioned by list, the following statement splits the partition Europe into three partitions.
ALTER TABLE list_customers SPLIT PARTITION Europe INTO
(PARTITION western-europe VALUES ('GERMANY', 'FRANCE'),
PARTITION southern-europe VALUES ('ITALY'),
PARTITION rest-europe);
https://docs.oracle.com/database/121/VLDBG/GUID-01C14320-0D7B-48BE-A5AD-003DDA761277.htm
You will get some idea about this.
I have a table with several employees. They have the following columns empid,datecolumn1,is_valid.
Very few employees have a more than one record in the table. If an employee has more than one record in the table I would like to 'invalidate' one of the records on the following condition:
1. If a employee has more than one record in the table then the record with no value in the datecolumn1 is valid (update is_valid to 1) and the record with value in datecolumn1 is not valid (update is_valid to 0).
How do I accomplish this?
As Ben points out, you've stated that if datecolumn1 is NULL you want the is_valid column to be set to both 0 and 1. Assuming you fix that, you may need to adjust this CASE statement depending on which way you decide is correct.
UPDATE employees
SET is_valid = (CASE WHEN datecolumn1 IS NULL
THEN 1
ELSE 0
END)
WHERE empid IN (SELECT e.empid
FROM employees e
GROUP BY emempid
HAVING COUNT(*) > 1)
create a staging table, and fill it by a SELECT on the original table with a GROUP BY employee Id (or whatever your unique identifier is). Create a second staging table and fill it by SELECTING on the original table and excluding all rows that match rows in your grouped table. Now you have a table that contains only those people with multiple rows. From your original table, set is_valid to 0 on all rows that match employee id with the second staging table and also have no datecolumn1 (or perhaps that also have a datecolumn1 - your question as of this writing is a bit unclear.) and is_valid to 1 on the others. Once done with that, delete the staging tables, and you should have what you need.
You could also do this with a single more complicated multiselect call, but I find it helpful to use staging tables when things get complicated.
I have two tables:
create table Number( num number(5));
create table Entry(id number(3), name varchar(50));
How can I increment the num field of Number table in Oracle whenever I insert something in the Entry table?
You should use a SEQUENCE instead. The "Number" table is an inherently bad idea, because when two sessions are inserting rows concurrently, each session only sees the uncommited value in the Number table.
This is what you should do instead:
create sequence entrySeq;
create table Entry(id number(3), name varchar(50));
create trigger tr_entry before insert on Entry for each row
begin
select entrySeq.nextval into :new.number from dual;
end;
/
Do you want number.num to continually represent the number of rows iin the Entry table? If so you could just define it as a view:
create view number_view
as
select count(*) from Entry
create sequence entrySeq;
create table Entry(id number(3), name varchar(50));
insert into Entry value (entrySeq.nextval, 'MyName');
(You don't need a trigger).
A sequence returns a unique and increasing number value but Oracle doesn't guarantuee that it is gapless. When sometimes transactions are rollbacked the values of column id will contain gaps.