Bash Script will not recognize function [duplicate] - bash

Question

This question already has answers here:
Calling custom function in bash results in "Command not found" [duplicate]
(1 answer)
Having problems calling function within bash script
(1 answer)
Closed 4 years ago.
I'm trying to create a bash script that will allow you to specify an AWS account that you want to perform some actions in.
I have a variable I need to pass that refers to a file that the script will cycle through.
But the function that performs the actions isn't recognized by the script.
This is the error I get :
./delete_snapshots.sh
What AWS Account:
12345678910
Delete Snapshots in account: AWS Lab
./delete_snapshots.sh: line 14: delete_snapshots: command not found
This is the script :
#!/bin/bash
echo "What AWS Account: ";
read accountnumber
declare -a arr=("12345678910" "109876543212")
for i in "${arr[#]}"
do
if [ "$i" -eq 12345678910 ]; then
aws_account="AWS Lab"
aws_key="lab"
aws_file="aws_lab_snapshots.txt"
echo "Delete Snapshots in account: $aws_account"
delete_snapshots
break
elif [ "$i" -eq 109876543212 ]; then
aws_account="AWS Billing"
aws_key="bill"
aws_file="aws_bill_snapshots.txt"
echo "You are currently in account: $aws_account"
delete_snapshots
break
else
echo "Unkown account"
fi
done
delete_snapshots(){
for i in $(cat $aws_file)
do
echo "*****************************************************************"
echo "deleting snapshot: $i"
aws ec2 delete-snapshot --snapshot-id=$i --profile=lab 2>&1 | sed -e 's/^An error occurred.*when calling the DeleteSnapshot operation: //'
echo "*****************************************************************"
echo; echo; echo; echo; echo
sleep 5
echo "*****************************************************************"
echo "Verify that snapshot: $i is gone:"
aws ec2 describe-snapshots --snapshot-ids=$i --profile=lab 2>&1 | sed -e 's/^An error occurred.*when calling the DescribeSnapshots operation: //g'
echo "*****************************************************************"
echo; echo; echo; echo; echo
done
}
The script works now thanks for some helpful suggestions. Here's the working form of the script:
#!/bin/bash
delete_snapshots(){
for i in $(cat $aws_file)
do
echo "*****************************************************************"
echo "deleting snapshot: $i"
aws ec2 delete-snapshot --snapshot-id=$i --profile=$aws_key 2>&1 | sed -e 's/^An error occurred.*when calling the DeleteSnapshot operation: //'
echo "*****************************************************************"
echo; echo; echo; echo; echo
sleep 5
echo "*****************************************************************"
echo "Verify that snapshot: $i is gone:"
aws ec2 describe-snapshots --snapshot-ids=$i --profile=$aws_key 2>&1 | sed -e 's/^An error occurred.*when calling the DescribeSnapshots operation: //g'
echo "*****************************************************************"
echo; echo; echo; echo; echo
done
}
echo "What AWS Account: ";
read accountnumber
declare -a arr=("123456789101" "109876543212")
for i in "${arr[#]}"
do
if [ "$i" -eq 123456789101 ]; then
aws_account="AWS Lab"
aws_key="lab"
aws_file="source_files/aws_lab_snapshots.txt"
echo "Delete Snapshots in account: $aws_account"
delete_snapshots
break
elif [ "$i" -eq 109876543212 ]; then
aws_account="AWS Billing"
aws_key="bill"
aws_file="source_files/aws_bill_snapshots.txt"
echo "You are currently in account: $aws_account"
delete_snapshots
break
else
echo "Unkown account"
fi
done