Curl Multiline on Command Windows 10 - windows

How i can send multiline via curl on Windows 10 ?
This is my CURL command :
curl -X POST \
-H "Accept: application/json" \
-H "X-Access-Token: ZmQ780ODRmNDlkMjMzYjA0OTA1Y54545jY5ODQ3MjM0YmNjYjM5ODA1OWU5NTE1YjEwNTdjMjcxMzQ3ZDdjMzMxNDA0ZA==" \
-H "Cache-Control: no-cache" \
-d '{
"frames": [
{
"text": "USDCHF",
"icon": "i34",
"index": 0
}
]
}' \
https://developer.myurl.com/api/v1/dev/widget/update/com.myurl.7a9c72294c097a37f0f0a3337f5ad444598f21/1
PS: Line by line work perfectly
Thanks

Related

GET CURL doesn't escape some of the characters [duplicate]

This question already has answers here:
Escaping characters in bash (for JSON)
(13 answers)
Parsing JSON with Unix tools
(45 answers)
Closed 10 days ago.
I have the following GET CURL from which I get an xml.
curl -X 'GET' \
'http://local/something/something2' \
-H 'accept: application/json' \
-H 'authorization: auth'
Now I want to use the previous xml received above within this POST CURL:
curl -X 'POST' \
'http://something/something2' \
-H 'accept: application/json' \
-H 'authorization: auth' \
-H 'Content-Type: application/json' \
-d '{
"components": [
{
"locator": "sample",
"config": xml file from above
}
]
}'
How can I make the second CURL with POST?
See this post to see how to capture the output of the first command into a variable. Use it like this:
output=$(curl -X 'GET' \
'http://local/something/something2' \
-H 'accept: application/json' \
-H 'authorization: auth')
# Assuming the $output variable is a JSON object, with a property
# called 'result', use 'jq' to extract the value of that property
result=$(jq -r '.result' <<< "$output")
# As noted above, escape the double quotes with backslashes
curl -X 'POST' \
'http://something/something2' \
-H 'accept: application/json' \
-H 'authorization: auth' \
-H 'Content-Type: application/json' \
-d "{
\"components\": [
{
\"locator\": \"sample\",
\"config\": \"$result\"
}
]
}"
Note the double quotes - double quotes must be there so $output variable can be used. As a result, the double quotes in the JSON need to be escaped.

Use CURL POST using a CURL GET output in bash [duplicate]

This question already has answers here:
Escaping characters in bash (for JSON)
(13 answers)
Parsing JSON with Unix tools
(45 answers)
Closed 10 days ago.
I have the following GET CURL from which I get an xml.
curl -X 'GET' \
'http://local/something/something2' \
-H 'accept: application/json' \
-H 'authorization: auth'
Now I want to use the previous xml received above within this POST CURL:
curl -X 'POST' \
'http://something/something2' \
-H 'accept: application/json' \
-H 'authorization: auth' \
-H 'Content-Type: application/json' \
-d '{
"components": [
{
"locator": "sample",
"config": xml file from above
}
]
}'
How can I make the second CURL with POST?
See this post to see how to capture the output of the first command into a variable. Use it like this:
output=$(curl -X 'GET' \
'http://local/something/something2' \
-H 'accept: application/json' \
-H 'authorization: auth')
# Assuming the $output variable is a JSON object, with a property
# called 'result', use 'jq' to extract the value of that property
result=$(jq -r '.result' <<< "$output")
# As noted above, escape the double quotes with backslashes
curl -X 'POST' \
'http://something/something2' \
-H 'accept: application/json' \
-H 'authorization: auth' \
-H 'Content-Type: application/json' \
-d "{
\"components\": [
{
\"locator\": \"sample\",
\"config\": \"$result\"
}
]
}"
Note the double quotes - double quotes must be there so $output variable can be used. As a result, the double quotes in the JSON need to be escaped.

Can you use an if else statement with Curl command in bash script

I have command I am running with works for one enviornment in a bash script e.g.
so for example
ZONE_ID=prod
#!/bin/bash
curl -X DELETE "https://api.cloudflare.com/client/v4/zones/$ZONE_ID/purge_cache" \
-H "X-Auth-Email: EMAIL" \
-H "X-Auth-Key: AUTH_KEY" \
-H "Content-Type: application/json" \
--data '{"purge_everything":true}'
What i would like to do is change the data item if possible for a different environment depending on the zone_id
ZONE_ID=prod
ZONE_ID=UAT
for example UAT would be
curl -X DELETE "https://api.cloudflare.com/client/v4/zones/$ZONE_ID/purge_cache" \
-H "X-Auth-Email: EMAIL" \
-H "X-Auth-Key: AUTH_KEY" \
-H "Content-Type: application/json" \
--data '{"files":["http://www.example.com/css/styles.css",{"url":"http://www.example.com/cat_picture.jpg","headers":{"Origin":"https://www.cloudflare.com","CF-IPCountry":"US","CF-Device-Type":"desktop"}}]}'
So what I kind of want to do is the following, but this doesnt work
#!/bin/bash
curl -X DELETE "https://api.cloudflare.com/client/v4/zones/$ZONE_ID/purge_cache" \
-H "X-Auth-Email: EMAIL" \
-H "X-Auth-Key: AUTH_KEY" \
-H "Content-Type: application/json" \
if [$ZONE_ID -q prod]; then
--data '{"purge_everything":true}'
else
--data '{"files":["http://www.example.com/css/styles.css",{"url":"http://www.example.com/cat_picture.jpg","headers":{"Origin":"https://www.cloudflare.com","CF-IPCountry":"US","CF-Device-Type":"desktop"}}]}'
One possible way to do it is:
#! /bin/bash
curl -X DELETE "https://api.cloudflare.com/client/v4/zones/$ZONE_ID/purge_cache" \
-H "X-Auth-Email: EMAIL" \
-H "X-Auth-Key: AUTH_KEY" \
-H "Content-Type: application/json" \
--data "$(if [[ $ZONE_ID == prod ]]; then
echo '{"purge_everything":true}'
else
echo '{"files":["http://www.example.com/css/styles.css",{"url":"http://www.example.com/cat_picture.jpg","headers":{"Origin":"https://www.cloudflare.com","CF-IPCountry":"US","CF-Device-Type":"desktop"}}]}'
fi)"
However, a much better option (for clarity and maintainability) is to put the --data argument in a variable.
I would recommend set variable before use it in curl command
example as follow
DATA=""
if [ "$ZONE_ID" = "prod" ]; then
DATA='{"purge_everything":true}'
else
DATA='{"files":["http://www.example.com/css/styles.css",{"url":"http://www.examp
le.com/cat_picture.jpg","headers":{"Origin":"https://www.cloudflare.com","CF-IPC
ountry":"US","CF-Device-Type":"desktop"}}]}'
fi
curl -X DELETE "https://api.cloudflare.com/client/v4/zones/$ZONE_ID/purge_cache"
\
-H "X-Auth-Email: EMAIL" \
-H "X-Auth-Key: AUTH_KEY" \
-H "Content-Type: application/json" \
--data $DATA

How to make a valid curl request in shell script? [duplicate]

Goal:
I'm using a bash CURL script to connect to the Cloudflare APIv4. The goal is to update an A-record. My script:
# Get current public IP
current_ip=curl --silent ipecho.net/plain; echo
# Update A record
curl -X PUT "https://api.cloudflare.com/client/v4/zones/ZONEIDHERE/dns_records/DNSRECORDHERE" \
-H "X-Auth-Email: EMAILHERE" \
-H "X-Auth-Key: AUTHKEYHERE" \
-H "Content-Type: application/json" \
--data '{"id":"ZONEIDHERE","type":"A","name":"example.com","content":"'"${current_ip}"'","zone_name":"example.com"}'
Problem:
The current_ip variable is not printed when I call it in my script. The output will be "content" : "" and not "content" : "1.2.3.4".
I used other stackoverflow posts and I'm trying to follow their examples but I think I'm still doing something wrong, just can't figure out what. :(
Using jq for this, as Charles Duffy's answer suggests, is a very good idea. However, if you can't or do not want to install jq here is what you can do with plain POSIX shell.
#!/bin/sh
set -e
current_ip="$(curl --silent --show-error --fail ipecho.net/plain)"
echo "IP: $current_ip"
# Update A record
curl -X PUT "https://api.cloudflare.com/client/v4/zones/ZONEIDHERE/dns_records/DNSRECORDHERE" \
-H "X-Auth-Email: EMAILHERE" \
-H "X-Auth-Key: AUTHKEYHERE" \
-H "Content-Type: application/json" \
--data #- <<END;
{
"id": "ZONEIDHERE",
"type": "A",
"name": "example.com",
"content": "$current_ip",
"zone_name": "example.com"
}
END
The reliable way to edit JSON from shell scripts is to use jq:
# set shell variables with your contents
email="yourEmail"
authKey="yourAuthKey"
zoneid="yourZoneId"
dnsrecord="yourDnsRecord"
# make sure we show errors; --silent without --show-error can mask problems.
current_ip=$(curl --fail -sS ipecho.net/plain) || exit
# optional: template w/ JSON content that won't change
json_template='{"type": "A", "name": "example.com"}'
# build JSON with content that *can* change with jq
json_data=$(jq --arg zoneid "$zoneid" \
--arg current_ip "$current_ip" \
'.id=$zoneid | .content=$current_ip' \
<<<"$json_template")
# ...and submit
curl -X PUT "https://api.cloudflare.com/client/v4/zones/$zoneid/dns_records/$dnsrecord" \
-H "X-Auth-Email: $email" \
-H "X-Auth-Key: $authKey" \
-H "Content-Type: application/json" \
--data "$json_data"

How to use a variable in a CURL request with bash?

Goal:
I'm using a bash CURL script to connect to the Cloudflare APIv4. The goal is to update an A-record. My script:
# Get current public IP
current_ip=curl --silent ipecho.net/plain; echo
# Update A record
curl -X PUT "https://api.cloudflare.com/client/v4/zones/ZONEIDHERE/dns_records/DNSRECORDHERE" \
-H "X-Auth-Email: EMAILHERE" \
-H "X-Auth-Key: AUTHKEYHERE" \
-H "Content-Type: application/json" \
--data '{"id":"ZONEIDHERE","type":"A","name":"example.com","content":"'"${current_ip}"'","zone_name":"example.com"}'
Problem:
The current_ip variable is not printed when I call it in my script. The output will be "content" : "" and not "content" : "1.2.3.4".
I used other stackoverflow posts and I'm trying to follow their examples but I think I'm still doing something wrong, just can't figure out what. :(
Using jq for this, as Charles Duffy's answer suggests, is a very good idea. However, if you can't or do not want to install jq here is what you can do with plain POSIX shell.
#!/bin/sh
set -e
current_ip="$(curl --silent --show-error --fail ipecho.net/plain)"
echo "IP: $current_ip"
# Update A record
curl -X PUT "https://api.cloudflare.com/client/v4/zones/ZONEIDHERE/dns_records/DNSRECORDHERE" \
-H "X-Auth-Email: EMAILHERE" \
-H "X-Auth-Key: AUTHKEYHERE" \
-H "Content-Type: application/json" \
--data #- <<END;
{
"id": "ZONEIDHERE",
"type": "A",
"name": "example.com",
"content": "$current_ip",
"zone_name": "example.com"
}
END
The reliable way to edit JSON from shell scripts is to use jq:
# set shell variables with your contents
email="yourEmail"
authKey="yourAuthKey"
zoneid="yourZoneId"
dnsrecord="yourDnsRecord"
# make sure we show errors; --silent without --show-error can mask problems.
current_ip=$(curl --fail -sS ipecho.net/plain) || exit
# optional: template w/ JSON content that won't change
json_template='{"type": "A", "name": "example.com"}'
# build JSON with content that *can* change with jq
json_data=$(jq --arg zoneid "$zoneid" \
--arg current_ip "$current_ip" \
'.id=$zoneid | .content=$current_ip' \
<<<"$json_template")
# ...and submit
curl -X PUT "https://api.cloudflare.com/client/v4/zones/$zoneid/dns_records/$dnsrecord" \
-H "X-Auth-Email: $email" \
-H "X-Auth-Key: $authKey" \
-H "Content-Type: application/json" \
--data "$json_data"

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