Create a json file using jq and multiple variables - arguments

Question

I have a json file like this:
{
"name": "Job",
"type": "xdb",
"typeLogoUrl": "public/app/plugins/logo.svg",
"access": "proxy",
"url": "http://xdb:80",
"password": {},
"user": "xx",
"database": "Job",
"basicAuth": true,
"basicAuthUser": "xx",
"basicAuthPassword": {},
"withCredentials": true,
"isDefault": false,
"jsonData": {},
"secureJsonFields": null
}
Now all I want is to pass environment variables to key password and basicAuthPassword and to generate new json file as below:
{
"name": "Job",
"type": "xdb",
"typeLogoUrl": "public/app/plugins/logo.svg",
"access": "proxy",
"url": "http://xdb:80",
"password": "password" ,
"user": "xx",
"database": "Job",
"basicAuth": true,
"basicAuthUser": "xx",
"basicAuthPassword": "password",
"withCredentials": true,
"isDefault": false,
"jsonData": {},
"secureJsonFields": null
}
I have tried like below to replace at least one key and it's giving me null.
/usr/local/bin/jq -n --arg "password" '.password = $arg' < input.json
Can anyone suggest me how to achieve this?

Answer 1

Security wise, it's a bad idea to pass password in command line, but I hope you know what you're doing.
Assuming that, you need to modify your jq command like this:
jq --arg p "password" '.password = $p | .basicAuthPassword = $p' < input.json

Answer 2

If the password is already an environment variable (which may not be such a good idea though), then to avoid exposing it on the command-line, you could use the env builtin, along the lines of:
.password = env.password
etc.
An alternative to consider would be putting the password into a temporary file, and then using the --argfile command-line option, for example. Or if your shell supports it, --argfile pw <(echo "\"$password\"")