I'm trying to write a Bash script that, when it receives a SIGINT signal, creates a copy of itself before exiting. So, when a user tries to kill this script using a SIGINT signal a copy of the process reapppears.
trap "echo Exiting...?; ./ghoul.sh; exit 1" SIGINT
while :
do
echo Process Number $$, with PPID $PPID!
sleep 1
done
However, whenever I suspend the process and check ps -f, there are multiple processes of the script (children and children of children). The exit command never seems to run since it's waiting for the children to exit. I want to find a way to run the script in the trap statement and exit afterward while maintaining the resulting child process. Is there any way to do this besides creating the child as a background process?
I find it much simpler to put exit code into a function. For example, your unquoted echo contains a bare ? which is a glob (file expansion) character. To avoid the parent killing the child you can use disown, and yes, you need to run it in background.
Try this:
f_exit() {
echo 'Exiting...?'
./ghoul.sh &
disown -h %1
exit 1
}
trap "f_exit" SIGINT
while :
do
echo "Process Number $$, with PPID $PPID!"
sleep 1
done
Related
Context:
Users provide me their custom scripts to run. These scripts can be of any sort like scripts to start multiple GUI programs, backend services. I have no control over how the scripts are written. These scripts can be of blocking type i.e. execution waits till all the child processes (programs that are run sequentially) exit
#exaple of blocking script
echo "START"
first_program
second_program
echo "DONE"
or non blocking type i.e. ones that fork child process in the background and exit something like
#example of non-blocking script
echo "START"
first_program &
second_program &
echo "DONE"
What am I trying to achieve?
User provided scripts can be of any of the above two types or mix of both. My job is to run the script and wait till all the processes started by it exit and then shutdown the node. If its of blocking type, case is plain simple i.e. get the PID of script execution process and wait till ps -ef|grep -ef PID has no more entries. Non-blocking scripts are the ones giving me trouble
Is there a way I can get list of PIDs of all the child process spawned by execution of a script? Any pointers or hints will be highly appreciated
You can use wait to wait for all the background processes started by userscript to complete. Since wait only works on children of the current shell, you'll need to source their script instead of running it as a separate process.
( source userscript; wait )
Sourcing the script in an explicit subshell should simulate starting a new process closely enough. If not, you can also background the subshell, which forces a new process to be started, then wait for it to complete.
( source userscript; wait ) & wait
ps --ppid $PID will list all child processes of the process with $PID.
You can open a file descriptor that gets inherited by other processes, and then wait until it's no longer in use. This is a low overhead method that usually works fine, though it's possible for processes to work around it if they want:
foo=$(mktemp)
( flock -x 5000; theirscript; ) 5000> "$foo"
flock -x 0 < "$foo"
rm "$foo"
echo "The script and its subprocesses are done"
You can follow all invoked processes using ptrace, such as with strace. This is easier, but has some associated overhead and may not work when scripts invoke suid binaries:
strace -f -e none theirscript
You can use pgrep -P <parent_pid> to get a list of child processes. Example:
IFS=$'\n' read -ra CHILD_PROCS -d '' < <(exec pgrep -P "$1")
And to get the grand-children, simply do the same procedure on each child process.
Check out my blog Bash functions to list and kill or send signals to process trees.
You can use one of those function to properly list all processes spawned under one process. Each has their own method or order of sending signals to process.
The only limitation by those is that process still have to be connected and not orphaned. If you could somehow find a way to group your processes, then that might be your solution.
To simply answer the question that was asked. You could store the process ID of each script you're calling into the same variable:
echo "START"
first_program &
child_process_ids+="$! "
second_program &
child_process_ids+="$! "
echo $child_process_ids
echo "DONE"
$child_process_ids would just be a space delimited string of process Ids. Now, this answers the question asked, however, what I would do would be a bit different. I would call each script from a for loop, store its process ID, then wait on each one in another for loop to finish and inspect each exit code individually. Using the same example, here's what it would look like.
echo "START"
scripts="first_program second_program"
for script in $scripts; do
#Call script and send to background
./$script &
#Store the script's processID that was just sent to the background
child_process_ids+="$! "
done
for child_process_id in $child_process_ids; do
#Pass each processId into the wait command to retrieve its exit
#code and store it in $rc
wait $child_process_id
rc=$?
#Inspect each processes exit code
if [ $rc -ne 0 ]; then
echo "$child_process_id failed with an exit code of $rc"
else
echo "$child_process_id was successful"
fi
done
#!/usr/bin/env bash
for i in $(seq 1 $1);
do
./extended&
done
wait
This is my bash script and I execute the extended binary as many times as specified in command line argument. When I kill the bash script using SIGINT the child processes also killed. I've called wait in the bash script I couldn't figure how the child processes are killed. I know that wait will make the parent to wait till child terminates.
bash sends a SIGHUP (hang-up signal) to all children on exit by default. If you don't want this behaviour use disown -h
From man bash:
To prevent the shell from sending the signal to a particular job, it should be removed from the jobs table with the disown builtin or marked to not receive SIGHUP
using disown -h.
How can a KornShell (ksh) script exit/kill all the processes started from another ksh script?
If scriptA.ksh calls scriptB.ksh then the following code works good enough, but is there a better solution for this?:
scriptA.ksh:
#call scriptBSnippet
scriptBSnippet.ksh ${a}
scriptB.ksh:
#if error: exit this script (scriptB) and calling script (scriptA)#
kill ${PPID}
exit 1
To add complexity what if scriptA calls scriptB which calls scriptC, then how to exit out of all three scripts if there is an error in scriptC?
scriptA.ksh:
#call scriptBSnippet
scriptBSnippet.ksh ${a}
scriptB.ksh:
#if error: exit this script (scriptB) and calling script (scriptA)#
kill ${PPID}
exit 1
scriptC.ksh:
#if error: exit this script (scriptC) and calling scripts (scriptA, scriptB)#
#kill ${PPID}
#exit 1
Thanks in advance.
Killing all processes started by the same script is a bit of a brute force method.
It would be best to have some method of communication between the processes that would allow them to gracefully shutdown.
However, if all processes are in the same process group, you can send a signal to the entire process group:
kill -${Signal:?} -${Pgid:?}
Note that two arguments are required in this case. A single argument starting with - is always interpreted as a signal.
Run some tests to see which processes get included in the process group.
parent.sh:
Shell=ksh
($Shell -c :) || exit
$Shell child1.sh & pid1=$!
$Shell child2.sh & pid2=$!
$Shell child3.sh & pid3=$!
ps -o pid,sid,pgid,tty,cmd $PPID $$ $pid1 $pid2 $pid3
exit
child.sh:
sleep 50
If you run parent.sh from a terminal - it will become the process leader.
granny.sh:
Shell=ksh
($Shell -c :) || exit
$Shell parent.sh &
wait
exit
If you run parent.sh from another script granny.sh, then that will be the process group leader, and will be included when you use the kill -SIG -PGID method.
See also this answer to:
What are “session leaders” in ps? for some background on sessions and process groups.
Context:
Users provide me their custom scripts to run. These scripts can be of any sort like scripts to start multiple GUI programs, backend services. I have no control over how the scripts are written. These scripts can be of blocking type i.e. execution waits till all the child processes (programs that are run sequentially) exit
#exaple of blocking script
echo "START"
first_program
second_program
echo "DONE"
or non blocking type i.e. ones that fork child process in the background and exit something like
#example of non-blocking script
echo "START"
first_program &
second_program &
echo "DONE"
What am I trying to achieve?
User provided scripts can be of any of the above two types or mix of both. My job is to run the script and wait till all the processes started by it exit and then shutdown the node. If its of blocking type, case is plain simple i.e. get the PID of script execution process and wait till ps -ef|grep -ef PID has no more entries. Non-blocking scripts are the ones giving me trouble
Is there a way I can get list of PIDs of all the child process spawned by execution of a script? Any pointers or hints will be highly appreciated
You can use wait to wait for all the background processes started by userscript to complete. Since wait only works on children of the current shell, you'll need to source their script instead of running it as a separate process.
( source userscript; wait )
Sourcing the script in an explicit subshell should simulate starting a new process closely enough. If not, you can also background the subshell, which forces a new process to be started, then wait for it to complete.
( source userscript; wait ) & wait
ps --ppid $PID will list all child processes of the process with $PID.
You can open a file descriptor that gets inherited by other processes, and then wait until it's no longer in use. This is a low overhead method that usually works fine, though it's possible for processes to work around it if they want:
foo=$(mktemp)
( flock -x 5000; theirscript; ) 5000> "$foo"
flock -x 0 < "$foo"
rm "$foo"
echo "The script and its subprocesses are done"
You can follow all invoked processes using ptrace, such as with strace. This is easier, but has some associated overhead and may not work when scripts invoke suid binaries:
strace -f -e none theirscript
You can use pgrep -P <parent_pid> to get a list of child processes. Example:
IFS=$'\n' read -ra CHILD_PROCS -d '' < <(exec pgrep -P "$1")
And to get the grand-children, simply do the same procedure on each child process.
Check out my blog Bash functions to list and kill or send signals to process trees.
You can use one of those function to properly list all processes spawned under one process. Each has their own method or order of sending signals to process.
The only limitation by those is that process still have to be connected and not orphaned. If you could somehow find a way to group your processes, then that might be your solution.
To simply answer the question that was asked. You could store the process ID of each script you're calling into the same variable:
echo "START"
first_program &
child_process_ids+="$! "
second_program &
child_process_ids+="$! "
echo $child_process_ids
echo "DONE"
$child_process_ids would just be a space delimited string of process Ids. Now, this answers the question asked, however, what I would do would be a bit different. I would call each script from a for loop, store its process ID, then wait on each one in another for loop to finish and inspect each exit code individually. Using the same example, here's what it would look like.
echo "START"
scripts="first_program second_program"
for script in $scripts; do
#Call script and send to background
./$script &
#Store the script's processID that was just sent to the background
child_process_ids+="$! "
done
for child_process_id in $child_process_ids; do
#Pass each processId into the wait command to retrieve its exit
#code and store it in $rc
wait $child_process_id
rc=$?
#Inspect each processes exit code
if [ $rc -ne 0 ]; then
echo "$child_process_id failed with an exit code of $rc"
else
echo "$child_process_id was successful"
fi
done
This question already has answers here:
What's the best way to send a signal to all members of a process group?
(34 answers)
Closed 6 years ago.
For testing purposes I have this shell script
#!/bin/bash
echo $$
find / >/dev/null 2>&1
Running this from an interactive terminal, ctrl+c will terminate bash, and the find command.
$ ./test-k.sh
13227
<Ctrl+C>
$ ps -ef |grep find
$
Running it in the background, and killing the shell only will orphan the commands running in the script.
$ ./test-k.sh &
[1] 13231
13231
$ kill 13231
$ ps -ef |grep find
nos 13232 1 3 17:09 pts/5 00:00:00 find /
$
I want this shell script to terminate all its child processes when it exits regardless of how it's called. It'll eventually be started from a python and java application - and some form of cleanup is needed when the script exits - any options I should look into or any way to rewrite the script to clean itself up on exit?
I would do something like this:
#!/bin/bash
trap : SIGTERM SIGINT
echo $$
find / >/dev/null 2>&1 &
FIND_PID=$!
wait $FIND_PID
if [[ $? -gt 128 ]]
then
kill $FIND_PID
fi
Some explanation is in order, I guess. Out the gate, we need to change some of the default signal handling. : is a no-op command, since passing an empty string causes the shell to ignore the signal instead of doing something about it (the opposite of what we want to do).
Then, the find command is run in the background (from the script's perspective) and we call the wait builtin for it to finish. Since we gave a real command to trap above, when a signal is handled, wait will exit with a status greater than 128. If the process waited for completes, wait will return the exit status of that process.
Last, if the wait returns that error status, we want to kill the child process. Luckily we saved its PID. The advantage of this approach is that you can log some error message or otherwise identify that a signal caused the script to exit.
As others have mentioned, putting kill -- -$$ as your argument to trap is another option if you don't care about leaving any information around post-exit.
For trap to work the way you want, you do need to pair it up with wait - the bash man page says "If bash is waiting for a command to complete and receives a signal for which a trap has been set, the trap will not be executed until the command completes." wait is the way around this hiccup.
You can extend it to more child processes if you want, as well. I didn't really exhaustively test this one out, but it seems to work here.
$ ./test-k.sh &
[1] 12810
12810
$ kill 12810
$ ps -ef | grep find
$
Was looking for an elegant solution to this issue and found the following solution elsewhere.
trap 'kill -HUP 0' EXIT
My own man pages say nothing about what 0 means, but from digging around, it seems to mean the current process group. Since the script get's it's own process group, this ends up sending SIGHUP to all the script's children, foreground and background.
Send a signal to the group.
So instead of kill 13231 do:
kill -- -13231
If you're starting from python then have a look at:
http://www.pixelbeat.org/libs/subProcess.py
which shows how to mimic the shell in starting
and killing a group
#Patrick's answer almost did the trick, but it doesn't work if the parent process of your current shell is in the same group (it kills the parent too).
I found this to be better:
trap 'pkill -P $$' EXIT
See here for more info.
Just add a line like this to your script:
trap "kill $$" SIGINT
You might need to change 'SIGINT' to 'INT' on your setup, but this will basically kill your process and all child processes when you hit Ctrl-C.
The thing you would need to do is trap the kill signal, kill the find command and exit.