I have an endpoint streamed as in the sample code block. When streaming, I call an async method through streamHelper.getStreamSuspendCount(). I am stopping this async method in changing state. But I can not access this async method when the browser is closed and the session is terminated. I am stopping the async method in session scope when changing state. But I can not access this async method when the browser is closed and the session is terminated. How can I access this scope when Session is closed?
#RequestMapping(value = "/stream/{columnId}/suspendCount", produces = MediaType.TEXT_EVENT_STREAM_VALUE)
#ResponseBody
public Flux<Integer> suspendCount(#PathVariable String columnId) {
ColumnObject columnObject = streamHelper.findColumnObjectInListById(columnId);
return streamHelper.getStreamSuspendCount(columnObject);
}
getStreamSuspendCount(ColumnObject columnObject) {
...
//async flux
Flux<?> newFlux = beSubscribeFlow.get(i);
Disposable disposable = newFlux.subscribe();
beDisposeFlow.add(disposable); // my session scope variable. if change state, i will kill disposable (dispose()).
...
return Flux.fromStream(Stream.generate(() -> columnObject.getPendingObject().size())).distinctUntilChanged()
.doOnNext(i -> {
System.out.println(i);
}));
}
I think part of the problem is that you are attempting to get a Disposable that you want to call at the end of the session. But in doing so, you are subscribing to the sequence yourself. Spring Framework will also subscribe to the Flux returned by getStreamSuspendCount, and it is THAT subscription that needs to be cancelled for the SSE client to get notified.
Now how to achieve this? What you need is a sort of "valve" that will cancel its source upon receiving an external signal. This is what takeUntilOther(Publisher<?>) does.
So now you need a Publisher<?> that you can tie to the session lifecycle (more specifically the session close event): as soon as it emits, takeUntilOther will cancel its source.
2 options there:
the session close event is exposed in a listener-like API: use Mono.create
you really need to manually trigger the cancel: use MonoProcessor.create() and when the time comes, push any value through it
Here are simplified examples with made up APIs to clarify:
Create
return theFluxForSSE.takeUntilOther(Mono.create(sink ->
sessionEvent.registerListenerForClose(closeEvent -> sink.success(closeEvent))
));
MonoProcessor
MonoProcessor<String> processor = MonoProcessor.create();
beDisposeFlow.add(processor); // make it available to your session scope?
return theFluxForSSE.takeUntilOther(processor); //Spring will subscribe to this
Let's simulate the session close with a scheduled task:
Executors.newSingleThreadScheduledExecutor().schedule(() ->
processor.onNext("STOP") // that's the key part: manually sending data through the processor to signal takeUntilOther
, 2, TimeUnit.SECONDS);
Here is a simulated unit test example that you can run to better understand what happens:
#Test
public void simulation() {
Flux<Long> theFluxForSSE = Flux.interval(Duration.ofMillis(100));
MonoProcessor<String> processor = MonoProcessor.create();
Executors.newSingleThreadScheduledExecutor().schedule(() -> processor.onNext("STOP"), 2, TimeUnit.SECONDS);
theFluxForSSE.takeUntilOther(processor.log())
.log()
.blockLast();
}
Related
I have two data sources, each returning a Mono:
class CacheCustomerClient {
Mono<Entity> createCustomer(Customer customer)
}
class MasterCustomerClient {
Mono<Entity> createCustomer(Customer customer)
}
Callers to my application are hitting a Spring WebFlux controller:
#PostMapping
#ResponseStatus(HttpStatus.CREATED)
public Flux<Entity> createCustomer(#RequestBody Customer customer) {
return customerService.createNewCustomer(entity);
}
As long as either data source successfully completes its create operation, I want to immediately return a success response to the caller, however, I still want my service to continue processing the result of the other Mono stream, in the event that an error was encountered, so it can be logged.
The problem seems to be that as soon as a value is returned to the controller, a cancel signal is propagated back through the stream by Spring WebFlux and, thus, no information is logged about a failure.
Here's one attempt:
public Flux<Entity> createCustomer(final Customer customer) {
var cacheCreate = cacheClient
.createCustomer(customer)
.doOnError(WebClientResponseException.class,
err -> log.error("Customer creation failed in cache"));
var masterCreate = masterClient
.createCustomer(customer)
.doOnError(WebClientResponseException.class,
err -> log.error("Customer creation failed in master"));
return Flux.firstWithValue(cacheCreate, masterCreate)
.onErrorMap((err) -> new Exception("Customer creation failed in cache and master"));
}
Flux.firstWithValue() is great for emitting the first non-error value, but then whichever source is lagging behind is cancelled, meaning that any error is never logged out. I've also tried scheduling these two sources on their own Schedulers and that didn't seem to help either.
How can I perform these two calls asynchronously, and emit the first value to the caller, while continuing to listen for emissions on the slower source?
You can achieve that by transforming you operators to "hot" publishers using share() operator:
First subscriber launch the upstream operator, and additional subscribers get back result cached from the first subscriber:
Further Subscriber will share [...] the same result.
Once a second subscription has been done, the publisher is not cancellable:
It's worth noting this is an un-cancellable Subscription.
So, to achieve your requirement:
Apply share() on each of your operators
Launch a subscription on shared publishers to trigger processing
Use shared operators in your pipeline (here firstWithValue).
Sample example:
import java.time.Duration;
import reactor.core.publisher.Mono;
public class TestUncancellableMono {
// Mock a mono successing quickly
static Mono<String> quickSuccess() {
return Mono.delay(Duration.ofMillis(200)).thenReturn("SUCCESS !");
}
// Mock a mono taking more time and ending in error.
static Mono<String> longError() {
return Mono.delay(Duration.ofSeconds(1))
.<String>then(Mono.error(new Exception("ERROR !")))
.doOnCancel(() -> System.out.println("CANCELLED"))
.doOnError(err -> System.out.println(err.getMessage()));
}
public static void main(String[] args) throws Exception {
// Transform to hot publisher
var sharedQuick = quickSuccess().share();
var sharedLong = longError().share();
// Trigger launch
sharedQuick.subscribe();
sharedLong.subscribe();
// Subscribe back to get the cached result
Mono
.firstWithValue(sharedQuick, sharedLong)
.subscribe(System.out::println, err -> System.out.println(err.getMessage()));
// Wait for subscription to end.
Thread.sleep(2000);
}
}
The output of the sample is:
SUCCESS !
ERROR !
We can see that error message has been propagated properly, and that upstream publisher has not been cancelled.
Problem:
I would like to unblock my KTOR response from portions of the code that take longer and can be executed in async manner after the fact.
The core business logic for REST response should not wait for the async tasks such as sending email, kafka event etc..
What I have tried:
I get the desired results with this code example. I can see that the rest response is returned immediately and does not wait on the delayed tasks (email and Kafka message).
I am unclear at this point if I need to keep these lines inside the runBlocking code
val patient = PatientService.addPatient()
//Return REST response
call.respond(patient)
Question
If I keep it out of the runblocking code, the entire rest response is blocked until the email and kafka event code is complete.
Is this the right approach to offload certain delayed code execution
logic from the main REST API response in KTOR?
fun Route.patientRoute(){
route("/patient") {
post (""){
runBlocking {
val patient = PatientService.addPatient() //..Business logic to add a new patient
launch { //unblock the REST response from certain async. tasks
sendKafkaEvent()
sendEmail()
}
call.respond(patient) //Return REST response
}
}
}
}
suspend fun sendEmail() {
delay(5000L) //Mock some delay in the operation
}
suspend fun sendKafkaMessage() {
delay(5000L) //Mock some delay in the operation
}
I would firstly run asynchronous tasks and then call to PatientService.addPatient() to pass its returned value for call.respond.
Additionally, you can specify a different dispatcher for your tasks.
post("") {
launch(Dispatchers.IO) {
sendEmail()
}
launch(Dispatchers.IO) {
sendKafkaEvent()
}
call.respond(PatientService.addPatient())
}
I'm developing an application which uses reactor libraries to connect with Google pubsub. So I have a Flux of messages. I want it to always consume from the queue, no matter what happens: this means handling all errors in order not to terminate the flux. I was thinking about the (very unlikely) event the connection to pubsub may be lost or whatever may cause the just created Flux to signal an error. I came up with this solution:
private final PubSubReactiveFactory pubSubReactiveFactory;
private final String requestSubscription;
private final Long requestPollTime;
private final Flux<AcknowledgeablePubsubMessage> requestFlux;
#Autowired
public FluxContainer(/* Field args...*/) {
// init stuff...
this.requestFlux = initRequestFlux();
}
private Flux<AcknowledgeablePubsubMessage> initRequestFlux() {
return pubSubReactiveFactory.poll(requestSubscription, requestPollTime);
.doOnError(e -> log.error("FATAL ERROR: could not retrieve message from queue. Resetting flux", e))
.onErrorResume(e -> initRequestFlux());
}
#EventListener(ApplicationReadyEvent.class)
public void configureFluxAndSubscribe() {
log.info("Setting up requestFlux...");
this.requestFlux
.doOnNext(AcknowledgeablePubsubMessage::ack)
// ...many more concatenated calls handling flux
}
Does it makes sense? I'm concerned about memory allocation (I'm relying on the gc to clean stuff). Any comment is welcome.
What I think you're looking for is basically a Flux that restarts itself when it is terminated for any situation except for the subscription being disposed. In my case I have a source that would generate infinite events from Docker daemon which can disconnect "successfully"
Let sourceFlux be the flux providing your data and would be something you'd want to restart on error or complete, but stop on subscription disposal.
create a recovery function
Function<Throwable, Publisher<Integer>> recoverFromThrow =
throwable -> sourceFlux
create a new flux that would recover from throw
var recoveringFromThrowFlux =
sourceFlux.onErrorResume(recoverFromThrow);
create a Flux generator that generates the flux that would recover from a throw. (Note the generic coercion is needed)
var foreverFlux =
Flux.<Flux<Integer>>generate((sink) -> sink.next(recoveringFromThrowFlux))
.flatMap(flux -> flux);
foreverFlux is the flux that does self recovery.
Is it possible to allow emitting values from a Flux conditionally based on a global boolean variable?
I'm working with Flux delayUntil(...) but not able to fully grasp the functionality or my assumptions are wrong.
I have a global AtomicBoolean that represents the availability of a downstream connection and only want the upstream Flux to emit if the downstream is ready to process.
To represent the scenario, created a (not working) test sample
//Randomly generates a boolean value every 5 seconds
private Flux<Boolean> signalGenerator() {
return Flux.range(1, Integer.MAX_VALUE)
.delayElements(Duration.ofMillis(5000))
.map(integer -> new Random().nextBoolean());
}
and
Flux.range(1, Integer.MAX_VALUE)
.delayElements(Duration.ofMillis(1000))
.delayUntil(evt -> signalGenerator()) // ?? Only proceed when signalGenerator returns true
.subscribe(System.out::println);
I have another scenario where a downstream process can accept only x messages a second. In the current non-reactive implementation we have a Semaphore of x permits and the thread is blocked if no more permits are available, with Semaphore permits resetting every second.
In both scenarios I want upstream Flux to emit only when there is a demand from the downstream process, and I do not want to Buffer.
You might consider using Mono.fromRunnable() as an input to delayUntil() like below;
Helper class;
public class FluxCondition {
CountDownLatch latch = new CountDownLatch(10); // it depends, might be managed somehow
Runnable r = () -> { latch.await(); }
public void lock() { Mono.fromRunnable(r) };
public void release() { latch.countDown(); }
}
Usage;
FluxCondition delayCondition = new FluxCondition();
Flux.range(1, 10).delayUntil(o -> delayCondition.lock()).subscribe();
.....
delayCondition.release(); // shall call this for each element
I guess there might be a better solution by using sink.emitNext but this might also require a condition variable for controlling Flux flow.
According my understanding, in reactive programming, your data should be considered in every operator step. So it might be better for you to design your consumer as a reactive processor. In my case I had no chance and followed the way as I described above
I'm using a spring flux to send parallel requests to a service, this is very simplified version of it:
Flux.fromIterable(customers)
.flatMap { customer ->
client.call(customer)
} ...
I was wondering how I could cancel this flux, as in, grab a reference to the flux somehow and tell it to shut down.
As you probably know, with reactive objects, all operators are lazy. This means execution of the pipeline is delayed until the moment you subscribe to the reactive stream.
So, in your example, there is nothing to cancel yet because nothing is happening at that point.
But supposing your example was extended to:
Disposable disp = Flux.fromIterable(customers)
.flatMap { customer ->
client.call(customer)
}
.subscribe();
Then, as you can see, your subscription returns a Disposable object that you can use to cancel the entire thing if you want, e.g.
disp.dispose()
Documentation of dispose says:
Cancel or dispose the underlying task or resource.
There’s another section of the documentation that says the following:
These variants [of operators] return a reference to the subscription
that you can use to cancel the subscription when no more data is
needed. Upon cancellation, the source should stop producing values and
clean up any resources it created. This cancel and clean-up behavior
is represented in Reactor by the general-purpose Disposable interface.
Therefore canceling the execution of stream is not free from complications on the reactive object side, because you want to make sure to leave the world in a consistent state if you cancel the stream in the middle of its processing. For example, if you were in the process of building something, you may want to discard resources, destroy any partial aggregation results, close files, channels, release memory or any other resources you have, potentially undoing changes or compensating for them.
You may want to read the documentation on cleanup about this, such that you also consider what you can do on the reactive object side.
Flux<String> bridge = Flux.create(sink -> {
sink.onRequest(n -> channel.poll(n))
.onCancel(() -> channel.cancel())
.onDispose(() -> channel.close())
});
Answer from #Edwin is precise. As long as you don't call subscribe, there is nothing to cancel, because no code will be executed.
Just wanted to add an example to make it clear.
public static void main(String[] args) throws InterruptedException {
List<String> lists = Lists.newArrayList("abc", "def", "ghi");
Disposable disposable = Flux.fromIterable(lists)
.delayElements(Duration.ofSeconds(3))
.map(String::toLowerCase)
.subscribe(System.out::println);
Thread.sleep(5000); //Sleeping so that some elements in the flux gets printed
disposable.dispose();
Thread.sleep(10000); // Sleeping so that we can prove even waiting for some time nothing gets printed after cancelling the flux
}
But I would say a much cleaner way (functional way) is to make use of functions like takeUntil or take. For instance I can stop the stream in the above example like this as well.
List<String> lists = Lists.newArrayList("abc", "def", "End", "ghi");
Flux.fromIterable(lists).takeUntil(s -> s.equalsIgnoreCase("End"))
.delayElements(Duration.ofSeconds(3))
.map(String::toLowerCase)
.subscribe(System.out::println);
or
List<String> lists = Lists.newArrayList("abc", "def", "ghi");
Flux.fromIterable(lists).take(2)
.delayElements(Duration.ofSeconds(2))
.map(String::toLowerCase)
.subscribe(System.out::println);
Another subscribe to my flux then calling a dispose did it for me:
// Setup flux and populate
Flux<String> myFlux = controller.get(json);
// Subscribe
FlowSubscriber<String> sub = new FlowSubscriber<String>();
myFlux.subscribe(sub);
// Work on elements in the subscription
String myString = sub.consumedElements.get(0);
... do work ...
// Cancel
myFlux.subscribe().dispose();