I am trying to run a report for next day by using getdate()+1 but I want to exclude weekends and holidays. To exclude weekends, I included the following in my where statement but it doesn't work. Ideally it should show Monday's results if I am running on Friday. But instead I am getting no results.
Below is my query:
select * from table
where CONVERT(DATE, [Appointment_DateTime]) = CONVERT(DATE, getdate()+1)
and DATEPART(w,CONVERT(DATE, [Appointment_DateTime])) NOT IN (1,7)
I am using not in (1,7) since sunday is the first day of the server so I am excluding sunday and Saturday.
If you want to show Monday data on Friday, you should add three days if it's Friday today:
select *
from table
where CONVERT(DATE, [Appointment_DateTime]) = CONVERT(DATE, getdate() + IIF(DATEPART(w,CONVERT(DATE, [Appointment_DateTime])) = 6, 3, 1))
and DATEPART(w,CONVERT(DATE, [Appointment_DateTime])) NOT IN (1,7)
another approach is to use different conditions for Mon-Thu and Fri:
select *
from table
where CONVERT(DATE, [Appointment_DateTime]) = CONVERT(DATE, GETDATE() + 1)
and DATEPART(weekday,CONVERT(DATE, [Appointment_DateTime])) in (2,3,4,5)
union all
select *
from table
where CONVERT(DATE, [Appointment_DateTime]) = CONVERT(DATE, GETDATE() + 3)
and DATEPART(weekday,CONVERT(DATE, [Appointment_DateTime])) = 6
first part of union will yield rows for Mon-Thu, second one for Fridays
Related
i'm trying to get sysdate year and month into number or char.
I'd want something like this:
202107
or last month
202106
i tried this code:
select trunc(add_months(sysdate, -1), 'MM') from dual;
please help, thanks
Convert it to a string and then to a number:
SELECT TO_NUMBER(TO_CHAR(ADD_MONTHS(SYSDATE,-1), 'YYYYMM'))
FROM DUAL;
Or, you can use extract and wrap it in a sub-query so you do not need to repeat adding the months:
SELECT EXTRACT(YEAR FROM dt) * 100 + EXTRACT(MONTH FROM dt)
FROM (
SELECT ADD_MONTHS(SYSDATE, -1) AS dt
FROM DUAL
)
Like
SELECT EXTRACT(year from sysdate) * 100 + EXTRACT(month from sysdate)
If you want to scroll around, manipulate the date before you extract from it, rather than minusing after you extract (gets tricky to e.g. go back a month if the date is in jan)
--will work for jan 2021
SELECT EXTRACT(year from ADD_MONTHS(somedate, -1)) * 100 + EXTRACT(month from ADD_MONTHS(somedate, -1))
--won't work for jan 2021
SELECT EXTRACT(year from somedate) * 100 + (EXTRACT(month from somedate) - 1)
TRUNC is a device that "rounds" a date to a particular interval, such as "trimming the time off a datetime" or "making any day of the week back to the date that was the start of the week" - very useful for all sorts of stuff like "total sales by month - SUM(sale) GROUP BY TRUNC(saledate, 'mm')" but it keeps all the components of the date (the day, the hour, the minute etc) so it isn't what you want.
how can i return records sales from todays + 6 months.
Example:
Today´s month: May-2018.
Today´s month + 6: Nov-2018
So, i want a function to retrieve records from Table_Date, from November (1 to 30).
Thanks.
Use the TRUNC and ADD_MONTHS functions:
SELECT *
FROM sales
WHERE SalesDate >= ADD_MONTHS( TRUNC( SYSDATE, 'MM' ), 6 )
AND SalesDate < ADD_MONTHS( TRUNC( SYSDATE, 'MM' ), 7 );
You have SQL server and oracle, it cant be both.
This is for SQL Server (though logic would work in ORACLE, but syntax may not)
This is to get 6 months from today
SELECT DATEADD(MM, 6, GETDATE())
Added extra code here for more details after looking at question more:
I am using variables to do the calculations to make it easier to understand but you could do it all inline (but harder to read).
This script gets a date 6 months from now, takes that month and finds the first day of that month, and then the last day of that month so you can use those 2 dates in a where clause logic.
DECLARE #NewMonth AS VARCHAR(10)
DECLARE #NewYear AS VARCHAR(10) -- in case adding months goes to next year
SELECT #NewMonth = DATEPART(MONTH, DATEADD(MM, 6, GETDATE())),
#NewYear = DATEPART(YEAR, DATEADD(MM, 6, GETDATE()))
DECLARE #FirstOfMonth AS DATE = #NewMonth + '/1/' + #NewYear
-- for start of month check we can just hard code one in it, for end of month we cant because we dont know how many days are in it
SELECT #FirstOfMonth, DATEADD(DAY, -1, DATEADD(MONTH, 1, #FirstOfMonth)) AS LastDayOfMontbh
In this query I found the weeks of month, for example november begin 1th Wednesday and ends sunday 5.
These are the first week on november.
SELECT * FROM (
WITH days AS
(SELECT to_date('01012017','ddmmyyyy') + level-1 date_in
FROM dual
CONNECT BY level < 32)
SELECT date_in,
TO_CHAR(date_in,'IW') - TO_CHAR(TRUNC(date_in,'MM'),'IW') + 1 week_number
FROM days) where week_number = 1;
The week_number can change depending of the weeks of the month, but in January is not working.
Your requirement is not clear for me but perhaps you are looking for this:
SELECT TRUNC (next_day(TRUNC(TO_DATE('20022017','ddmmyyyy'), 'mm'),'monday') - 1), 'IW') AS first_week
FROM dual;
I'm still a bit unclear as to what you're looking for, but perhaps the following query will help you on your way:
WITH YEAR_START AS (SELECT TO_DATE('01012017', 'DDMMYYYY') AS FIRST_DAY_OF_YEAR
FROM DUAL),
MONTH_START AS (SELECT FIRST_DAY_OF_YEAR AS FIRST_DAY_OF_MONTH
FROM YEAR_START
UNION ALL
SELECT ADD_MONTHS(FIRST_DAY_OF_YEAR, LEVEL) AS FIRST_DAY_OF_MONTH
FROM YEAR_START
CONNECT BY LEVEL <= 11),
MONTH_START_AND_END AS (SELECT FIRST_DAY_OF_MONTH,
ADD_MONTHS(FIRST_DAY_OF_MONTH, 1) - INTERVAL '1' DAY AS LAST_DAY_OF_MONTH
FROM MONTH_START),
ABS_MONTH_WEEKS AS (SELECT FIRST_DAY_OF_MONTH,
LAST_DAY_OF_MONTH,
TO_NUMBER(TO_CHAR(FIRST_DAY_OF_MONTH, 'IW')) AS ABS_FIRST_WEEK_OF_MONTH,
TO_NUMBER(TO_CHAR(LAST_DAY_OF_MONTH, 'IW')) AS ABS_LAST_WEEK_OF_MONTH
FROM MONTH_START_AND_END),
REL_MONTH_WEEKS AS (SELECT a.*,
1 AS REL_FIRST_WEEK_OF_MONTH,
ABS_LAST_WEEK_OF_MONTH - CASE
WHEN ABS_FIRST_WEEK_OF_MONTH > ABS_LAST_WEEK_OF_MONTH THEN 0
ELSE ABS_FIRST_WEEK_OF_MONTH-1
END AS REL_LAST_WEEK_OF_MONTH
FROM ABS_MONTH_WEEKS a)
SELECT *
FROM REL_MONTH_WEEKS;
Best of luck.
does anyone know the query to get data from first day of the month until yesterday? I Try using query below but the problem is when today is the first day of the month, so the value become between 20170201 and 20170131
select * from a where to_char(DATE,'yyyymmdd') BETWEEN to_char(sysdate,'yyyymm')||'01' and to_char(sysdate-1,'yyyymmdd')
Ex: if today is 01-02-2017 i want to select the data from 01-01-2017 until 31-01-2017, but if today is 13-02-2017 i want to select the data from 01-02-2017 until 12-02-2017, thank's before
This question has been updated with your new logic. The query below will retain records under the following conditions:
someDate falls between the first day and yesterday of the current month, or
someDate, when today is the first of the month, falls anywhere in the previous month
SELECT *
FROM yourTable
WHERE someDate BETWEEN CASE WHEN EXTRACT(DAY FROM SYSDATE) = 1
THEN TRUNC(SYSDATE-1, 'MONTH')
ELSE TRUNC(SYSDATE, 'MONTH') END AND
CASE WHEN EXTRACT(DAY FROM SYSDATE) = 1
THEN TRUNC(SYSDATE, 'MONTH') - 1
ELSE TRUNC(SYSDATE - 1) END
This query assumes that you have a DATE column called someDate.
I have a table 'Holiday' which lists a set of holiday details.If i specify a date,I should obtain a result date after 5 days of specified date.If there is holiday in between it should exclude them and display the non holiday date.I have table named holiday which includes holiday date,holiday type|(weekly off,local holiday).Now i have used nested decode for continuous holiday checking.Tell me how this can be changed in case function.
DECODE
(date,
holidaydate, DECODE
(date + 1,
holidaydate + 1, DECODE
(date + 2,
holidaydate + 2, DECODE
(date + 3,holidaydate+3,date+4,date+3),date+2),date+1),date);
This can be achieved with a simple subquery which counts the number of holiday dates between a specified date and date+5. The following will return a date that is five non-holiday days in the future:
testdate+(select 5+count(1)
from holiday
where holidaydate between testdate
and testdate + 5)
Simply change both "5"s so another number to change the evaluation period.
SQLFiddle here
Edit - based on comment below, my code doesn't evaluate any days after the fifth day. This would probably be much easier with a function, but the following cte-based code will work also:
with cte as ( (select alldate,holidaydate
from (select to_date('20130101','yyyymmdd')+level alldate
from dual
connect by level < 10000 -- adjust for period to evaluate
) alldates
left join holiday on alldate=holidaydate) )
select
testdate,test_plus_five
from (
select
alldate test_plus_five,testdate,
sum(case when holidaydate is null
then 1
else 0 end) over (partition by testdate order by alldate) lastday
from
cte,
testdates
where
alldate >= testdate
group by
alldate,holidaydate,testdate)
where
lastday = 6
This script builds a calendar table so it can evaluate each day (holiday or non-holiday); then we get a running count of non-holiday days, and use the sixth one.
SQLFiddle here
AFAIK, You can use CASE alternative to DECODE in Oracle
CASE [ expression ]
WHEN condition_1 THEN result_1
WHEN condition_2 THEN result_2
...
WHEN condition_n THEN result_n
ELSE result
END
Finally i found the optimal solution.Thanks for ur response guys. SELECT dt FROM
(SELECT dt FROM (SELECT TO_DATE('15-AUG-2013','dd-mon-yyyy')+LEVEL dt FROM DUAL
CONNECT BY LEVEL < 30)
WHERE
(SELECT COUNT (*) FROM mst_holiday WHERE holidaydate = dt) = 0 )
where rownum=1