I am new to golang and migrating from php to golang.
I am trying to do something like below stuff, where I want field name age to get assigned from variable test. Is this possible in golang?
In php, we have provision like $$test, looking something similar in golang as well.
package main
import "fmt"
// This `person` struct type has `name` and `age` fields.
type person struct {
name string
age int
}
func main() {
var test = "age"
fmt.Println(person{name: "Alice",test: 30})
}
This is just sample code replicating my use case.
You have three options, in rough order of preference:
1) An if/switch statement:
var p = &person{}
if key == "age" {
p.age = value
}
2) Use a map instead of a struct:
var p = map[string]interface{}
p[key] = value
3) Use reflection. See this question for details, but generally you should avoid reflection. It's slow, and non-idiomatic, and it only works with exported fields (your example uses un-exported fields, so as written, is not a candidate for reflection anyway).
Related
I have a function which takes an interface, like this:
func method(data interface{})
.. because I need to process different structs which have common fields/methods. In this function I use data tens or hundreds of times, in different places. It's really unpleasant to add switch a.(type) { case .. case .. all the time.
Is there a way to create a variable with just one switch with needed type and then just use this variable everywhere later? Something like:
var a .... // something here
switch data.(type) {
case *Struct1:
a = data.(*Struct1)
case *Struct2:
a = data.(*Struct2)
}
// Continue with 'a' only
a.Param = 15
fmt.Println(a.String())
Go is a statically typed language, the type of a must be known at compile time. And since Go does not support generics yet, you can't do what you want.
Try to come up with some other solution, e.g. abstract away the things you want to do with a into an interface, and have the concrete types implement that interface. Then a can be a variable of this interface type, and you can call methods of it.
If you can achieve this, actually you can even change the parameter of the data type to this interface, and no type assertion or type switch is needed.
Alternatively you could use reflection to access common fields (either for get or set) identified by their name, but reflection provides no compile-time guarantee, and it's usually less efficient. For an example how to do that, see this question: Assert interface to its type
You can't do what you ask for in your question directly, go is statically typed, so you can't have one variable that can hold different types, and still access that variable as if it is typed.
If you're only working on the common struct fields in your method, you are perhaps better off gathering all the common variables in its own struct, illustrated below as the commons struct and have your method take that type as an argument
package main
import (
"fmt"
)
type commons struct {
name string
age int
}
type structA struct {
commons
other_stuff int
}
type structB struct {
commons
foo string
}
func method(c* commons) {
fmt.Println(c)
c.age +=1
}
func main() {
a := structA{commons{"foo", 44}, 1}
b := structB{commons{"bar", 33}, "test"}
method(&a.commons)
method(&b.commons)
fmt.Println(a)
}
Go playground
I can't figure out what is your real goal but if the "method" you want to write handles common fields from similar structures, and you cannot fix original structures using Type Embedding, as #nos said above, then you can try to make another structure for method-internal use:
var v Vehicle // with common fields
switch data.(type) {
case *Car:
v.Handle = data.(*Car).Handle // or CircleHandle
case *Motorcycle:
v.Handle = data.(*Motorcycle).Handle // or BarHandle
}
v.Degree = 15
v.Speed = 50
v.Direction = "left"
v.Style = "rough"
/// so many things on `v`...
steering(v)
I think it is not a good approach but sometimes... :-)
I have a function which takes an interface, like this:
func method(data interface{})
.. because I need to process different structs which have common fields/methods. In this function I use data tens or hundreds of times, in different places. It's really unpleasant to add switch a.(type) { case .. case .. all the time.
Is there a way to create a variable with just one switch with needed type and then just use this variable everywhere later? Something like:
var a .... // something here
switch data.(type) {
case *Struct1:
a = data.(*Struct1)
case *Struct2:
a = data.(*Struct2)
}
// Continue with 'a' only
a.Param = 15
fmt.Println(a.String())
Go is a statically typed language, the type of a must be known at compile time. And since Go does not support generics yet, you can't do what you want.
Try to come up with some other solution, e.g. abstract away the things you want to do with a into an interface, and have the concrete types implement that interface. Then a can be a variable of this interface type, and you can call methods of it.
If you can achieve this, actually you can even change the parameter of the data type to this interface, and no type assertion or type switch is needed.
Alternatively you could use reflection to access common fields (either for get or set) identified by their name, but reflection provides no compile-time guarantee, and it's usually less efficient. For an example how to do that, see this question: Assert interface to its type
You can't do what you ask for in your question directly, go is statically typed, so you can't have one variable that can hold different types, and still access that variable as if it is typed.
If you're only working on the common struct fields in your method, you are perhaps better off gathering all the common variables in its own struct, illustrated below as the commons struct and have your method take that type as an argument
package main
import (
"fmt"
)
type commons struct {
name string
age int
}
type structA struct {
commons
other_stuff int
}
type structB struct {
commons
foo string
}
func method(c* commons) {
fmt.Println(c)
c.age +=1
}
func main() {
a := structA{commons{"foo", 44}, 1}
b := structB{commons{"bar", 33}, "test"}
method(&a.commons)
method(&b.commons)
fmt.Println(a)
}
Go playground
I can't figure out what is your real goal but if the "method" you want to write handles common fields from similar structures, and you cannot fix original structures using Type Embedding, as #nos said above, then you can try to make another structure for method-internal use:
var v Vehicle // with common fields
switch data.(type) {
case *Car:
v.Handle = data.(*Car).Handle // or CircleHandle
case *Motorcycle:
v.Handle = data.(*Motorcycle).Handle // or BarHandle
}
v.Degree = 15
v.Speed = 50
v.Direction = "left"
v.Style = "rough"
/// so many things on `v`...
steering(v)
I think it is not a good approach but sometimes... :-)
I really want a way to print the string representation of a field name in go. It has several use cases, but here is an example:
lets say I have a struct
type Test struct {
Field string `bson:"Field" json:"field"`
OtherField int `bson:"OtherField" json:"otherField"`
}
and, for example, I want to do a mongo find:
collection.Find(bson.M{"OtherField": someValue})
I don't like that I have to put the string "OtherField" in there. It seems brittle and easy to either misstype or have the struct change and then my query fails without me knowing it.
Is there any way to get the string "OtherField" without having to either declare a const or something like that? I know I can use reflection to a get a list of field names from a struct, but I'd really like to do something along the lines of
fieldName := nameOf(Test{}.OtherField)
collection.Find(bson.M{fieldName: someValue})
is there any way to do this in Go?? C# 6 has the built in nameof, but digging through reflection I can't find any way to do this in Go.
I don't really think there is. You may be able to load a set of types via reflection and generate a set of constants for the field names. So:
type Test struct {
Field string `bson:"Field" json:"field"`
OtherField int `bson:"OtherField" json:"otherField"`
}
Could generate something like:
var TestFields = struct{
Field string
OtherField string
}{"Field","OtherField"}
and you could use TestFields.Field as a constant.
Unfortunately, I don't know of any existing tool that does anything like that. Would be fairly simple to do, and wire up to go generate though.
EDIT:
How I'd generate it:
Make a package that accepts an array of reflect.Type or interface{} and spits out a code file.
Make a generate.go somewhere in my repo with main function:
func main(){
var text = mygenerator.Gen(Test{}, OtherStruct{}, ...)
// write text to constants.go or something
}
Add //go:generate go run scripts/generate.go to my main app and run go generate
Here is a function that will return a []string with the struct field names. I think it comes in the order they are defined.
WARNING: Reordering the fields in the struct definition will change the order in which they appear
https://play.golang.org/p/dNATzNn47S
package main
import (
"fmt"
"strings"
"regexp"
)
type Test struct {
Field string `bson:"Field" json:"field"`
OtherField int `bson:"OtherField" json:"otherField"`
}
func main() {
fields, err := GetFieldNames(Test{})
if err != nil {
fmt.Println(err)
return
}
fmt.Println(fields)
}
func GetFieldNames(i interface{}) ([]string, error) {
// regular expression to find the unquoted json
reg := regexp.MustCompile(`(\s*?{\s*?|\s*?,\s*?)(['"])?(?P<Field>[a-zA-Z0-9]+)(['"])?:`)
// print struct in almost json form (fields unquoted)
raw := fmt.Sprintf("%#v", i)
// remove the struct name so string begins with "{"
fjs := raw[strings.Index(raw,"{"):]
// find and grab submatch 3
matches := reg.FindAllStringSubmatch(fjs,-1)
// collect
fields := []string{}
for _, v := range matches {
if len(v) >= 3 && v[3] != "" {
fields = append(fields, v[3])
}
}
return fields, nil
}
I am trying to create a function that takes a []byte and an interface{} (standing for the struct) and returns an interface{} as the struct type passed into the func.
Something like this:
package main
import (
"encoding/json"
)
func UnmarshalFromJSONArray(sms []byte,tt string) (interface{}) {
var ts = new(tt)
err := json.Unmarshal(sms,&ts)
if(err != nil) {
fmt.Println(err)
}
return sms
}
So that method would run something like this:
// let's say a struct has the following definition:
type MyStructType struct {
Id int
Name string
Desc string
}
// we can some how get its fully qualified class name (this may require reflection?) or pass it into the UnMarshal method direction some how.
mst := "package.MyStructType",
// and then assume a byte array ba that has JSON format for
ba := []byte(`{"Id":"3","Name":"Jack","Desc":"the man"}`)
stct := UnmarshalFromJSONArray(ba,mst)
MyStructureType out := stct
// leaving "stct" being the unmarshalled byte array which can be used like any other struct of type "MyStructureType"
The key being that I never need to know what the fields of MyStructureType are before unmarshalling. All I need are the name of the struct and some way to instance one and then populate it with JSON byte array data that matches its fields. Hopefully that is possible (it is trivial in java using reflection). So I want to basically unmarshal an anonymous struct type by it's name without needing to know what fields it has.
Any suggestions?
The short answer is that this is impossible. There is no string to type translator in Go. You can make a map of strings to reflect.Type's, but you would need to know the possible options ahead of time or you need to provide the caller with a way to register types (perhaps in init).
Assuming you have found a way to resolve the string to its reflect.Type, you can simply call reflect.New(typ).Interface() to get the pointer you need to pass to json.Unmarshal().
The best answer is to avoid trying this all together. Writing idiomatic Java in Go isn't really possible. If I knew more about your problem, I could give you a more idiomatic Go solution.
My problem is like this: I have a MyMail package which provides a function SendMail(MyMail.Mail) to other packages. MyMail uses the package LowLevelMail and its function Send(LowLevelMail.Mail) to actually send Mails. MyMail.Mail and LowLevelMail.Mail are identical in the sense that they define the "same struct" (i.e. equally named and typed fields).
SendMail(m MyMail.Mail) has to convert m to LowLevelMail.Mail before using Send(LowLevelMail.Mail. newmail := LowLevelMail.Mail(m) won't work. But this could be possible as the compiler should be able to see that the fields of the two structs are identical. Maybe it's not a good idea to support this because of not exported fields.
1) Can I somehow assign m to newmail without doing it all by hand (and without losing all type safety?)? The by hand method would cause some pain (the struct does not solely consist of simple types which can be assigned to the other struct's).
2) Is there a better solution to the whole problem (i.e. "I don't want to use other packages' types in my API because I don't want my packages' clients to depend on a foreign API. This foreign API may change or I might decide at some point to not use it any more.").
Update: I missed an important point: LowLevelMail.Mail has a field of type LowLevelMail.Address which also is "redefined" in MyMail as MyMail.Address.
This works :
type T1 struct {
a int
b string
}
type T2 struct {
a int
b string
}
func main() {
t1 := T1{2, "test"}
t2 := T2(t1)
fmt.Println(t2)
}
Isn't it what you're looking for ?
If your question is about how to do this when T1 and T2 are in different packages and don't export their fields, well, allowing this would simply nullify the privacy of those fields so of course that's not possible.
Your problem seems to be something like this:
package lowlevelmail
type Mail struct { P int; p int}
func Send(m Mail) { }
and
package mymail
import "lowlevelmail"
type Mail lowlevelmail.Mail
func Send(m Mail) { lowlevelmail.Send(lowlevelmail.Mail(m)) }
and
package main
import "mymail"
func main() {var m mymail.Mail; mymail.Send(m)}