IEnumerable Model from view to Controller is NULL [duplicate] - ajax

Question

This question already has answers here:
Post an HTML Table to ADO.NET DataTable
(2 answers)
Closed 4 years ago.
I am trying to return table values of my view back to the controller to save on db but I keep getting null. I can post the values without problem and bind them to the view.
I cannot understand why, I am using a server side view model.
Is there any way to perform this?
View:
#model IEnumerable<MultiEdit.Models.TableViewModel>
#using (Ajax.BeginForm("Save", "UUTs", new AjaxOptions
{
HttpMethod = "Post",
}, new { id = "tableForm" }))
{
#Html.AntiForgeryToken()
<div class="row" style="padding-top:10px;">
<div class="col-lg-12">
<table class="table table-bordered table-striped ">
<thead>
<tr>
<th>
#Html.DisplayNameFor(model => model.IsChassis)
</th>
<th>
#Html.DisplayNameFor(model => model.Justification)
</th>
</tr>
</thead>
<tbody id="tblMultiEdit">
#foreach(var item in Model)
{
<tr>
<td>
#Html.CheckBoxFor(modelItem => item.CheckIsChassis)
</td>
<td>
#Html.EditorFor(modelItem => item.Justification)
</td>
</tr>
}
</tbody>
</table>
</div>
</div>
}
Controller:
public void Save(IEnumerable<TableViewModel> vm)
{
DoSomething();
}

Answer 1

You need to iterate through your collection with a for loop and index qualifier. Something like the below. The syntax is not exact but you should be able to see what I mean.
#for(var index = 0; index <= Model.Count - 1; index++)
{
<tr>
<td>
#Html.CheckBoxFor(modelItem => Model[index].CheckIsChassis)
</td>
<td>
#Html.EditorFor(modelItem => Model[index].Justification)
</td>
</tr>
}
This is required so the index can be used to create the unique id's of the Enumerable items and aids model binding
Hope that helps

Answer 2

I resolved it by using IList insead of IEnumerable.
View:
#model IList<MultiEdit.Models.TableViewModel>
#Html.CheckBoxFor(modelItem => modelItem[index].CheckIsChassis, new { #class = "form-control" })
Controller:
public void Save(IList<TableViewModel> vm)
{
var x = vm;
}