I have written a spring boot app with oracle db.
Below is my entiry class.
#Entity
public class SystemTypeLookup{
#Id
#GeneratedValue(generator = "UUID")
#GenericGenerator(name = "UUID", strategy = "org.hibernate.id.UUIDGenerator")
#Type(type = "uuid-char")
#Column(name = "ID", updatable = false, nullable = false)
protected UUID id;
#Column(name = "CODE")
private String code;
}
And in passing my own UUID as primary key value.
In oracle db ID is considered as RAW and the UUID stored in oracle is differently.
There is no - separation in oracle and all the UUID chars are in upper case.
When i try to find the entity using primary key it is not fetching the row with id. I'm always getting null.
#Resource(name = "coreRepository")
private ErpEntityRepository coreRepositoryBase;
SystemTypeLookup systemTypeLookup = coreRepositoryBase.findOne("WHERE o.id='"+id+"'", SystemTypeLookup.class);
when is pass 76c03cd9-3d96-40c5-8df9-aad8f2369453 as id value then the oracle will insert the id without '-' and all chars will be in upper case.
So how to solve this issue?
First of all you should use parameters in your query and second make sure that the id you are passing is of type UUID and not String.
Related
im working in spring boot project i want to map a property with serial (using my sequence) column in my table and this column is not the ID.
i found this solution :
#Column(name = "DEMANDE_NUMBER", insertable = false, updatable = false, columnDefinition = "serial")
private Integer demandeNumber;
(because #GeneratedValue persist null and doesn't use the sequence)
this solution works fine and the field is persisted in my DB and the value uses the sequence but when i get my object after saving using my repository the demandeNumber is null
Demande savedDemande= demandeRepository.save(demandeToSave);
//demandeObj .getDemandeNumber() return null
any suggestion to resolve this issue please ?
Thanks.
according to this answer How to use a sequence generator for a non ID field?
i added the following annotation on my property
#Generated(GenerationTime.INSERT)
#Column(name = "column_name", columnDefinition = "serial", updatable = false)
you should import the package from hibernate and not javax.persistence.
import org.hibernate.annotations.Generated;
import org.hibernate.annotations.GenerationTime;
i hope this can help other people in the future. note this solution is for spring data with postgresql.
i'm using Spring Boot 2.4.2 and Data module for JPA implementation.
Now, i'm using an Oracle View, mapped by this JPA Entity:
#Entity
#Immutable
#Table(name = "ORDER_EXPORT_V")
#ToString
#Data
#NoArgsConstructor
#EqualsAndHashCode(onlyExplicitlyIncluded = true)
public class OrderExportView implements Serializable {
private static final long serialVersionUID = -4417678438840201704L;
#Id
#Column(name = "ID", nullable = false)
#EqualsAndHashCode.Include
private Long id;
....
The view uses an UNION which allows me to obtain two different attributes of the same parent entity, so for one same parent entity (A) with this UNION I get the attribute B in row 1 and attribute C in row 2: this means that the rows will be different from each other.
If I run the query with an Oracle client, I get the result set I expect: same parent entity with 2 different rows containing the different attributes.
Now the issue: when I run the query with Spring Data (JPA), I get the wrong result set: two lines but duplicate.
In debug, I check the query that perform Spring Data and it's correct; if I run the same query, the result set is correct, but from Java/Spring Data not. Why??
Thanks for your support!
I got it! I was wrong in the ID field.
The two rows have the same parent id, which is not good for JPA, which instead expects a unique value for each line.
So, now I introduced a UUID field into the view:
sys_guid() AS uuid
and in JPA Entity:
#Id
#Column(name = "UUID", nullable = false)
#EqualsAndHashCode.Include
private UUID uuid;
#Column(name = "ID")
private Long id;
and now everything works fine, as the new field has a unique value for each row.
I am facing a wierd issue in my implementation where I am persisitng data to a PostgresSQL DB using Spring data JpaRepository
In my Entity class I have the below columns:
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Column(name = "id", unique = true, nullable = false)
private int id;
#Column(name = "field1", nullable = false, length = 16)
private String field1;
#Column(name = "field2", nullable = false, length = 16)
private String field2;
#Column(name = "field3", nullable = false, length = 16)
private String field3;
I initially avoided declaring the fields above as composite since there were many fields to be dealt with as composite keys. I thought the java code check would do the trick in all scenarios
So basically, I have to maintain the uniqueness of each row based on field1,field2 and field3. That was the basic requirement for which I had checks in my java code that if any entry exists in the DB for the combination of field1,field2 and field3 then I used to throw java exceptions
No two rows can have these values repeating. All was good until the application was tested under some errorneous business scenarios which would never happen in production but got run by mistake
Whats happening now is that if 2 requests are triggered at the exact same instance with the exact same 3 fields above (through a script) then they both enter into the Database since both get the entry check as false
Would declaring all of them as one composite key resolve the situation?
You should define the unique constraint in your database in addition of JPA constraint.
#Entity
#Table(uniqueConstraints={
#UniqueConstraint(columnNames = {"field1", "field2", "field3"})
})
public class MyEntity {
...
}
I'm trying to save this model to a database, and then retrieve what I just saved. Every field is retrieved except for the database generated UUID field.
#Entity
#Table(name = "usertoken")
public class UserToken implements Serializable
{
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Integer id;
#Column(name = "token", insertable = false, updatable = false, nullable = false)
private UUID token;
#ManyToOne(fetch = FetchType.EAGER)
#JoinColumn(name="usersid", nullable=false)
private User user;
#Column(name = "expiration", updatable = false, nullable = false)
private LocalDateTime expiration;
I save the token from within the service
token = tokenRepository.save(token);
which generates this SQL
Hibernate:
insert
into
usertoken
(expiration, usersid)
values
(?, ?)
The next statement gets the token
token = tokenRepository.findByUser(user);
I see the SQL select includes the token field
Hibernate:
select
usertoken0_.id as id1_8_,
usertoken0_.expiration as expirati2_8_,
usertoken0_.token as token3_8_,
usertoken0_.usersid as usersid4_8_
from
usertoken usertoken0_
where
usertoken0_.usersid=?
...but the returned object has every field populated BUT the token. The database does have a value in the token column.
I'm at a loss as to why it would populate every field but one.
Here's the table in question:
CREATE TABLE public.usertoken
(
id integer NOT NULL GENERATED ALWAYS AS IDENTITY ( INCREMENT 1 START 1 MINVALUE 1 MAXVALUE 2147483647 CACHE 1 ),
usersid integer NOT NULL,
token uuid NOT NULL DEFAULT uuid_generate_v1(),
expiration timestamp without time zone NOT NULL,
CONSTRAINT "usertoken_pkey" PRIMARY KEY (id)
)
I forgot to add that when I query later on the token is found and the UUID field is properly populated. So something weird with JPA caching? Are database DEFAULT column values ignored by hibernate after the insert?
tokenRepository.findByToken(UUID.fromString(userToken));
Hibernate:
select
usertoken0_.id as id1_8_,
usertoken0_.expiration as expirati2_8_,
usertoken0_.token as token3_8_,
usertoken0_.usersid as usersid4_8_
from
usertoken usertoken0_
where
usertoken0_.token=?
You have to signal hibernate that field is being generated by database. So add the following:
#org.hibernate.annotations.Generated(value = GenerationTime.INSERT)
#Column(name = "token", insertable = false,
updatable = false, nullable = false)
private UUID token;
You will also see hibernate issues a select just for that column after insert
I'm working on oracle database to manage a JPA entity with a String Primary key.
I cannot modify the type on the PK to a Long or int in the database, so i want to know how to configure the pk sequence in my JPA entity,
i've tried this :
#Id
#SequenceGenerator(name="SEQ_ID", sequenceName = "SEQ_ID" )
#GeneratedValue(strategy=GenerationType.SEQUENCE, generator="SEQ_ID")
#Column(name="SEQ_ID",unique=true, nullable = false,updatable = false)
private String id;
but when persisting a new entity i got the error : Unknown integral data type for ids : java.lang.String
someone can help me please ?
Try removing #GeneratedValue and #SequenceGenerator
Also, a remark, #Id will automatically set unique=true, nullable = false,updatable = false so you can remove them from #Column.
Otherwise, you can check this article for more details about creating a custom string generator https://vladmihalcea.com/how-to-implement-a-custom-string-based-sequence-identifier-generator-with-hibernate/