Set up custom time to allow NSLocalNotif xcode - xcode

See sample code as follows - unable to use custom time here. Why is this not possible giving a result:
NSDate *dt1 = [NSDate date]; //2018-07-26 08:31:22 +0000
NSString *datestr = [NSString stringWithFormat:#"%#", [NSDate date]];//2018-07-26 10:42:09 +0001
NSString *cutstring = 09:00 PM;

I would just create date with NSDateComponents where you can set year, month, hour, minute etc. Refer https://nshipster.com/nsdatecomponents/
Extracting Components From Dates
NSDateComponents can be initialized and manipulated manually, but most often, they’re extracted from a specified date, using NSCalendar -components:fromDate::
Swift
Objective-C
let calendar = NSCalendar.currentCalendar()
let date = NSDate()
let components = calendar.components([.Month, .Day], fromDate: date)
The components parameter is a bitmask of the date component values to retrieve, with many to choose from:
Swift
Objective-C
NSCalendarUnit.Era
NSCalendarUnit.Year
NSCalendarUnit.Month
NSCalendarUnit.Day
NSCalendarUnit.Hour
NSCalendarUnit.Minute
NSCalendarUnit.Second
NSCalendarUnit.Weekday
NSCalendarUnit.WeekdayOrdinal
NSCalendarUnit.Quarter
NSCalendarUnit.WeekOfMonth
NSCalendarUnit.WeekOfYear
NSCalendarUnit.YearForWeekOfYear
NSCalendarUnit.Calendar
NSCalendarUnit.TimeZone
Since it would be expensive to compute all of the possible values, specify only the components that will be used in subsequent calculations (joining with |, the bitwise OR operator).

Related

How to get parse objects newer then a week

I need to get objects from parse that not older then a week.
i was trying it with
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:#"EEEE, MMMM d yyyy"];
NSDate *date = [object createdAt];
[dateFormatter stringFromDate:date]
Your code is a long way from working and shows some basic misunderstandings. I think you really need to go and learn about Objective-C and Cocoa/UIKit before you jump into Parse. However:
Parse has an automatic column called createdAt on all objects. You should use that.
I'm not sure about your definition of "a week ago" but to get a date exactly one week ago to the second use:
NSDate* date = [NSDate dateWithTimeIntervalSinceNow:-60*60*24*7];
There are more complex ways of doing this if you mean "midnight one week ago" or something like that but I'll leave this as is for the sake of clarity.
Pass this date to a PFQuery using the built in createdAt column:
PFQuery* q = [PFQuery queryWithClassName:[MyClass parseClassName]];
[q whereKey:#"createdAt" greaterThan:date];
Then issue the find:
[q findObjectsInBackgroundWithBlock:^(NSArray *objects, NSError *error) {
// here objects will contain your PFObject subclasses from the server
}];

Convert UTC to local time with NSDateFormatter

I am getting the following string from a server in my iOS app:
20140621-061250
How can I convert it to the local time?
How can I define my date formatter? Is this correct?
dateFormatter.dateFormat = #"YYYYMMd-HHmmss";
The question doesn't specify the nature of what you mean by converting, exactly, but the first thing you should do, regardless of the final goal, is to correctly parse the server response using a properly configured NSDateFormatter. This requires specification of the correct format string, and the time zone must be explicitly set on the formatter or it will infer it from the local time, which would be incorrect in most cases.
Specify The Format String
Let's look at the input string provided:
20140621-061250
This uses four digits for the year, two digits (with a zero-padding) for the month, and two digits (presumably, these will be zero-padded as well) for the day. This is followed by a -, then two digits to represent the hour, 2 digits for the minute, and 2 digits for the second.
Referring to the Unicode date format standards, we can derive the format string in the following way. The four digits representing the calendar year will be replaced with yyyy in the format string. Use MM for the month, and dd for the day. Next would come the literal -. For the hours, I assume that it will be in 24 hour format as otherwise this response is ambiguous, so we use HH. Minutes are then mm and seconds ss. Concatenating the format specifiers yields the following format string, which we will use in the next step:
yyyyMMdd-HHmmss
In our program, this would look like:
NSString *dateFormat = #"yyyyMMdd-HHmmss";
Configure the input date formatter
The time format above does not specify a time zone, but because you have been provided the specification for the server response that it represents the UTC time, we can code this into our application. So, we instantiate an NSDateFormatter, set the correct time zone, and set the date format:
NSTimeZone *inputTimeZone = [NSTimeZone timeZoneWithAbbreviation:#"UTC"];
NSDateFormatter *inputDateFormatter = [[NSDateFormatter alloc] init];
[inputDateFormatter setTimeZone:inputTimeZone];
[inputDateFormatter setDateFormat:dateFormat];
Convert the input string to an NSDate
For demonstration purposes, we hard-code the string you received from the server response; you would replace this definition of inputString with the one you get from the server:
NSString *inputString = #"20140621-061250";
NSDate *date = [inputDateFormatter dateFromString:inputString];
At this point, we have the necessary object to do any further conversions or calculations - an NSDate which represents the time communicated by the server. Remember, an NSDate is just a time stamp - it has no relation to a time zone whatsoever, which only plays a role when converting to and from string representations of the date, or representations of a calendrical date via NSDateComponents.
Next steps
The question doesn't clearly specify what type of conversion is needed, so we'll see an example of formatting the date to display in the same format as the server response (although, I can't think of a likely use case for this particular bit of code, to be honest). The steps are quite similar - we specify a format string, a time zone, configure a date formatter, and then generate a string (in the specified format) from the date:
NSTimeZone *outputTimeZone = [NSTimeZone localTimeZone];
NSDateFormatter *outputDateFormatter = [[NSDateFormatter alloc] init];
[outputDateFormatter setTimeZone:outputTimeZone];
[outputDateFormatter setDateFormat:dateFormat];
NSString *outputString = [outputDateFormatter stringFromDate:date];
Since I'm in UTC-06:00, printing outputString gives the following:
20140621-001250
It's likely you'll instead want to use setDateStyle: and setTimeStyle: instead of a format string if you're displaying this date to the user, or use an NSCalendar to get an NSDateComponents instance to do arithmetic or calculations on the date. An example for displaying a verbose date string to the user:
NSTimeZone *outputTimeZone = [NSTimeZone localTimeZone];
NSDateFormatter *outputDateFormatter = [[NSDateFormatter alloc] init];
[outputDateFormatter setTimeZone:outputTimeZone];
[outputDateFormatter setDateStyle:NSDateFormatterFullStyle];
[outputDateFormatter setTimeStyle:NSDateFormatterFullStyle];
NSString *outputString = [outputDateFormatter stringFromDate:date];
Printing outputString here gives us the following:
Saturday, June 21, 2014 at 12:12:50 AM Mountain Daylight Time
Note that setting the time zone appropriately will handle transitions over daylight savings time. Changing the input string to "20141121-061250" with the formatter style code above gives us the following date to display (Note that Mountain Standard Time is UTC-7):
Thursday, November 20, 2014 at 11:12:50 PM Mountain Standard Time
Summary
Any time you get date input in a string form representing a calendar date and time, your first step is to convert it using an NSDateFormatter configured for the input's format, time zone, and possibly locale and calendar, depending on the source of the input and your requirements. This will yield an NSDate which is an unambiguous representation of a moment in time. Following the creation of that NSDate, one can format it, style it, or convert it to date components as needed for your application requirements.
To get your string into a NSDate, you would use a NSDateFormatter like this:
NSString *myDateAsAStringValue = #"20140621-061250"
NSDateFormatter *df = [[NSDateFormatter alloc] init];
[df setDateFormat:#"yyyyMMdd-HHmmss"];
NSDate *myDate = [df dateFromString: myDateAsAStringValue];
You may want to read this post about working with Date and Time
EDIT:
To parse it as UTC you have to add the line:
[df setTimeZone:[NSTimeZone timeZoneWithAbbreviation:#"UTC"]];
Also, when you print it with NSLog, if you are using the same NSDateFormatter, you will get the input string as output (since you apply the inverse of the parsing function).
Here is the full code, for parsing and for getting the output with a standard format:
//The input
NSString *myDateAsAStringValue = #"20140621-061250";
//create the formatter for parsing
NSDateFormatter *df = [[NSDateFormatter alloc] init];
[df setTimeZone:[NSTimeZone timeZoneWithAbbreviation:#"UTC"]];
[df setDateFormat:#"yyyyMMdd-HHmmss"];
//parsing the string and converting it to NSDate
NSDate *myDate = [df dateFromString: myDateAsAStringValue];
//create the formatter for the output
NSDateFormatter *out_df = [[NSDateFormatter alloc] init];
[out_df setDateFormat:#"yyyy-MM-dd'T'HH:mm:ssz"];
//output the date
NSLog(#"the date is %#",[out_df stringFromDate:myDate]);
One possible solution in Swift using NSDate extension (maybe it could help future viewers of this question):
import UIKit
// For your personal information: NSDate() initializer
// always returns a date in UTC, no matter the time zone specified.
extension NSDate {
// Convert UTC (or GMT) to local time
func toLocalTime() -> NSDate {
let timezone: NSTimeZone = NSTimeZone.localTimeZone()
let seconds: NSTimeInterval = NSTimeInterval(timezone.secondsFromGMTForDate(self))
return NSDate(timeInterval: seconds, sinceDate: self)
}
// Convert local time to UTC (or GMT)
func toGlobalTime() -> NSDate {
let timezone: NSTimeZone = NSTimeZone.localTimeZone()
let seconds: NSTimeInterval = -NSTimeInterval(timezone.secondsFromGMTForDate(self))
return NSDate(timeInterval: seconds, sinceDate: self)
}
}

cocoa : assign nstimeInterval value to nsdate?

I want to assign nstimeInterval value to nsdate.
NSDate *startTime=[NSDate date] ;
NSDate *endTime=[NSDate date] ;
NSTimeInterval difference=[endTime
timeIntervalSinceDate:startTime];
startTime=difference; This gives me an error.
how can i assign my difference result of nsTimeInterval type to nsdate?
thanks in Advance
You need to understand that NSTimeInterval is the difference between two dates. What you're trying to do is like telling the program to:
Set the date to 2 days.
When what you want to do is tell the program to:
Set the date to last monday plus 2 days.
Therefore you need to use one of these family of NSDate methods:
+ dateWithTimeIntervalSinceNow:
+ dateWithTimeInterval:sinceDate:
+ dateWithTimeIntervalSinceReferenceDate:
+ dateWithTimeIntervalSince1970:
– initWithTimeIntervalSinceNow:
– initWithTimeInterval:sinceDate:
– initWithTimeIntervalSinceReferenceDate:
– initWithTimeIntervalSince1970:
Where you create the NSDate with some reference date plus/minus the NSTimeInterval; note that NSDate objects are immutable so there are no methods to change the date represented by the object using NSTimeInterval values.
See the NSDate Class Reference for more details.
To correct your code, this is how you'd do it:
NSDate *startTime=[NSDate date] ;
NSDate *endTime=[NSDate date] ;
NSTimeInterval difference=[endTime timeIntervalSinceDate:startTime];
NSDate *newTime = [NSDate dateWithTimeInterval:difference sinceDate:startDate];

UIDatePicker Not storing time in core data

I am using a UIDatepicker with only "Time", I save the time in a NSDate object type, however when I try to store the Object in core data I get an error saying its not a NSDate type...
tt = [pickerTime date];
[myObject setValue:tt forKey:#"time"];
Thanks,
Hey, a see a mistake here:
tt = [pickerTime date];
tt's type is either an NSDate, or... You have to declare what tt is:
NSDate *tt = [pickerTime date];
Make sure that your using a date field in IB.

Calculate time difference in Cocoa

I have got two timevalues in the format: %H%M%S (E.G.161500)
These values are text-based integers.
Is there a simple function in Cocoa that calculates the difference between these two integers using a 60 seconds and minutes scale?
So if
time 1 = 161500
time 2 = 171500
timedifference = 003000
NSDateFormatter *dateFormatter = [[[NSDateFormatter alloc] init] autorelease];
[dateFormatter setDateFormat:#"HHmmss"];
NSDate *date1 = [dateFormatter dateFromString:#"161500"];
NSDate *date2 = [dateFormatter dateFromString:#"171500"];
NSTimeInterval diff = [date2 timeIntervalSinceDate:date1]; // diff = 3600.0
The class for manipulating dates is NSDate. The method for getting time intervals is -timeIntervalSinceDate:. The result is a NSTimeInterval value, which is a double representing the interval in seconds.
You can create a NSDate object from a NSString with +dateWithString:, provided that your date is formatted as 2001-03-24 10:45:32 +0600.
try this code.
- (NSTimeInterval)intervalBetweenDate:(NSDate *)dt1 andDate:(NSDate *)dt2 {
NSTimeInterval interval = [dt2 timeIntervalSinceDate:dt1];
NSLog(#"%f",interval);
return interval;
}
I would create an NSFormatter subclass to parse time values in that format from input data (you can put one on a text field to automatically convert user input, or use it to parse from a data source in code). Have it return the combined number of seconds as an NSTimeInterval (double representing seconds) wrapped in an NSNumber. From there it's easy to subtract the difference, and display it using the same NSFormatter class you created. In both parsing and displaying values, you're the one responsible to write code converting from seconds to hours:minutes:seconds or whatever format you like. You could also convert these values to an NSDate like mouviciel mentioned, if it makes sense for your application. Just keep in mind you're always going to be storing the time difference from a reference date, usually Jan 1st 1970 (NSDate has methods to do this for you).

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