Am trying to make a junit test to save data with JPA. Below is my entity class
#Entity
#Table(name="book")
public class test {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name="BOOK_REF_ID",nullable=false)
private int bookRefId;
#Column(name="BOOK_CODE",nullable=false)
private String bookCode;
#Column(name="BOOK_NAME",nullable=false)
private String bookDescription;
public int getBookRefId() {
return bookRefId;
}
public void setBookRefId(int bookRefId) {
this.bookRefId = bookRefId;
}
public String getBookCode() {
return bookCode;
}
public void setBookCode(String bookCode) {
this.bookCode = bookCode;
}
public String getBookDescription() {
return bookDescription;
}
public void setBookDescription(String bookDescription) {
this.bookDescription = bookDescription;
}
}
Service class is
public interface BookService()
{
public Book create(Book book);
}
Repository class is
public interface BookRepository extends
JpaRepository<Book,Integer>
{ }
Service Implementation class is
public BookServiceImpli implements BookService()
{
#Resource
BookRepository repository;
#Override
public Book create(Book book) {
// TODO Auto-generated method stub
return repository.save(book);
}
}
Now my test class is
#RunWith(SpringRunner.class)
#DataJpaTest
#SpringBootTest(classes= {JPAConfig.class})
#AutoConfigureTestDatabase(replace=Replace.NONE)
#TestPropertySource(
locations = "classpath:application.properties")
public class TestBook {
#Autowired
private BookService bookService ;
#Test
public void test() {
Book book = new Book();
book.setBookCode("abc");
book.setBookDescription("safd");
bookService.create(book);
}
Application properties contains password and database details and JPAConfig contain JPA configuration details such as entity scan database details. When am trying to run the test case am getting an error like
A component required a bean of type
'com.repository.sample.BookRepository' that could not be found.
I don't have main method in it.Am new to unit testing please anyone help me to solve the issue.
Related
I am quite new in Spring and I am facing an issue right now with testing:
I have the following Service:
#Service
public class MyService {
public Integer getKey() {
List<Integer> keys = getKeys(1);
if (keys.size() == 1) {
return keys.get(0);
}
throw new IllegalArgumentException("Error!");
}
... and a getKeys() method, which provides a list based ona rest call...
}
And I use this service class in antother class:
#NoArgsConstructor
public class MyOtherClass extends MyClass {
#Autowired
private MyService myService;
....
#Override public KeyValue<Object, Object> doSomething(Object key, Object value) {
if (conditionIsTrue(key, value)) {
MyObject obj = new MyObject();
myObject.setKey(keyService.getKey()); ----- here is always null the keyService
.....
} else {
return KeyValue.pair(null, null);
}
}
And I try to write a test but the MyService is always null..
#ActiveProfiles("my-test")
#SpringBootTest(classes = Application.class)
#Testcontainers
#Slf4j
public class MyTest extends TestContext {
#BeforeEach
void init(final TestInfo testInfo) {
....
}
#AfterEach
void deinit() {
....
}
#Test
public void myTest() {
....
}
How can I inject a mock MyService into the test container?
Thank you!
I have a spring boot REST API with a GET method that returns data available in a DB. I am attempting to write an integration test to test this API method. I have configured the test to use the H2 database. I am trying to add some mock data to the database before the test is executed and see if the API retrieves that data. Following is the code I have written so far.
#RunWith(SpringRunner.class)
#SpringBootTest
#AutoConfigureMockMvc
#TestPropertySource(locations = "classpath:application-test.properties")
public class MetaControllerTest {
#Autowired
private MockMvc mvc;
#Autowired
private ProvinceDAO provinceDAO;
#Transactional
#Before
public void addData () {
Province southern = getProvinceEntity("Southern", "දකුණ", "தென்");
provinceDAO.createEntity(southern);
System.out.println(provinceDAO.findAll(Province.class).size());
}
#Test
public void testGetProvinces() throws Exception {
MvcResult result = mvc.perform(get("/meta/provinces"))
.andExpect(status().isOk())
.andExpect(content().contentTypeCompatibleWith(MediaType.APPLICATION_JSON))
.andReturn();
System.out.println(result.getResponse().getContentAsString());
}
}
However, when I run this code, I am getting an error saying "org.springframework.dao.InvalidDataAccessApiUsageException: No transactional EntityManager available; nested exception is java.lang.IllegalStateException: No transactional EntityManager available"
I have also attempted using #MockBean instead of #Autowired to bind the provinceDAO. Even though this prevents the error, it does not persist the entity in the database.
How should I write my testcase to test my method here?
Update:
application-test.properties
spring.datasource.url = jdbc:h2:mem:test
spring.jpa.properties.hibernate.dialect = org.hibernate.dialect.H2Dialect
Entity -> Province.java
#Entity
#Table(name = "w4a_province")
public class Province {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "id")
private int id;
#Column(name = "province_name")
private String name;
#Column(name = "province_name_si")
private String nameSi;
#Column(name = "province_name_ta")
private String nameTa;
.
.
}
GenericDAO.java
#Repository
public class GenericDAO<T> implements IGenericDAO<T> {
#PersistenceContext
private EntityManager em;
#Override
public Session getCurrentSession() {
return this.em.unwrap(Session.class);
}
#Override
public T findByPrimaryKey(Class<T> clazz, Object primaryKey) {
return getCurrentSession().find(clazz, primaryKey);
}
#Override
public List<T> findAll(Class<T> clazz) {
DetachedCriteria criteria = DetachedCriteria.forClass(clazz);
return criteria.getExecutableCriteria(getCurrentSession()).list();
}
#Override
public T createEntity(T entity) {
getCurrentSession().save(entity);
return entity;
}
ProvinceDAOImpl.java
#Repository
public class ProvinceDAOImpl extends GenericDAO<Province> implements ProvinceDAO {
}
MetaController.java
#RestController
#PreAuthorize("permitAll()")
public class MetaController {
private final MetaService metaService;
#Autowired
public MetaController(MetaService metService) {
this.metaService = metService;
}
#GetMapping("/meta/provinces")
public ResponseEntity<List<ProvinceDTO>> getProvinces() {
if (logger.isDebugEnabled()) {
logger.debug("Retrieving list of provinces.");
}
List<ProvinceDTO> provinces = metaService.getProvinces();
return ResponseEntity.ok(provinces);
}
}
MetaServiceImpl.java
#Service
#Transactional
public class MetaServiceImpl implements MetaService {
private final ProvinceDAO provinceDAO;
#Autowired
public MetaServiceImpl(ProvinceDAO provnceDAO) {
this.provinceDAO = provnceDAO;
}
public List<ProvinceDTO> getProvinces() {
if (logger.isDebugEnabled()) {
logger.debug("Obtaining a list of provinces from database.");
}
List<Province> entities = provinceDAO.findAll(Province.class);
if (logger.isDebugEnabled()) {
logger.debug("Converting province entities to dtos.");
}
List<ProvinceDTO> dtos = new ArrayList<>();
for (int i = 0; i < entities.size(); i++) {
Province entity = entities.get(i);
if (LocaleContextHolder.getLocale().getLanguage().equals(
GlobalConstants.LanguageIdentifiers.SINHALA_LANGUAGE_TAG)) {
dtos.add(new ProvinceDTO(entity.getId(), entity.getNameSi()));
} else if (LocaleContextHolder.getLocale().getLanguage().equals(
GlobalConstants.LanguageIdentifiers.TAMIL_LANGUAGE_TAG)) {
dtos.add(new ProvinceDTO(entity.getId(), entity.getNameTa()));
} else {
dtos.add(new ProvinceDTO(entity.getId(), entity.getName()));
}
}
return dtos;
}
}
I managed to feed the database with the required data by placing a SQL script data-h2.sql with insert queries at the test/resources folder. This prevented the requirement to use an EntityManager or a DAO.
Furthermore, I added the following property to the application-test.properties file.
spring.datasource.platform=h2
In Order to test Rest Api You can try functional test as well as integration test.
You can prepare your own response formate as required and check whether the same is returned or else you can also verify whether the data from db is fine or not.Plz check the below example
#RunWith(SpringJUnit4ClassRunner.class)
#SpringBootTest(classes = FactsMain.class)
#WebAppConfiguration
public abstract class BaseTest {
protected MockMvc mvc;
#Autowired
WebApplicationContext webApplicationContext;
protected void setUp() {
mvc = MockMvcBuilders.webAppContextSetup(webApplicationContext).build();
}
protected String mapToJson(Object obj) throws JsonProcessingException {
ObjectMapper objectMapper = new ObjectMapper();
return objectMapper.writeValueAsString(obj);
}
protected <T> T mapFromJson(String json, Class<T> clazz)
throws JsonParseException, JsonMappingException, IOException {
ObjectMapper objectMapper = new ObjectMapper();
return objectMapper.readValue(json, clazz);
}
}
In First test case i am forming the response format and trying to return the same and then validating the same.Here i don't need the db data so i have kept service as mock instead of auto wired.And used ObjectMapper for converting json to java and then java obj to json from base Test class.
public class PersonalDetailsControllerTest extends BaseTest {
#MockBean
private IPersonalService service;
private static final String URI = "/api/personalDetails";
#Override
#Before
public void setUp() {
super.setUp();
}
#Test
public void testGet() throws Exception {
PersonalDetailsEntity entity = new PersonalDetailsEntity();
List<PersonalDetailsEntity> dataList = new ArrayList<PersonalDetailsEntity>();
FactsAdminResponse<PersonalDetailsEntity> dataResponse = new FactsAdminResponse<PersonalDetailsEntity>();
entity.setId(1);
entity.setName(“Anthony Holmes”);
entity.setAge(26);
entity.setCity(“Banglore”);
entity.setCountry(“India”);
dataList.add(entity);
dataResponse.setData(dataList);
Mockito.when(service.getBuildings()).thenReturn(dataList);
RequestBuilder requestBuilder = MockMvcRequestBuilders.get(URI)
.accept(MediaType.APPLICATION_JSON);
MvcResult mvcResult = mvc.perform(requestBuilder).andReturn();
MockHttpServletResponse response = mvcResult.getResponse();
String expectedJson = this.mapToJson(dataResponse);
String outputInJson = mvcResult.getResponse().getContentAsString();
assertEquals(HttpStatus.OK.value(), response.getStatus());
assertEquals(expectedJson, outputInJson);
}
}
In below case we are getting the actual data in json format as we are doing rest api call and then just validating the status apart from status you can also cross check the data
public class PersonalDetailsControllerTest extends BaseTest {
private static final String URI = "/api/personalDetails";
#Override
#Before
public void setUp() {
super.setUp();
}
#Test
public void getGet() throws Exception {
MvcResult mvcResult = mvc.perform(MockMvcRequestBuilders.get(URL)
.accept(MediaType.APPLICATION_JSON_VALUE)).andReturn();
int status = mvcResult.getResponse().getStatus();
assertEquals(200, status);
String content = mvcResult.getResponse().getContentAsString();
//you got the content in string format now you can also validate the data
}
I am new to Junits and Mockito, I am writing a Unit test class to test my service class CourseService.java which is calling findAll() method of CourseRepository.class which implements CrudRepository<Topics,Long>
Service Class
#Service
public class CourseService {
#Autowired
CourseRepository courseRepository;
public void setCourseRepository(CourseRepository courseRepository) {
this.courseRepository = courseRepository;
}
public Boolean getAllTopics() {
ArrayList<Topics> topicList=(ArrayList<Topics>) courseRepository.findAll();
if(topicList.isEmpty())
{
return false;
}
return true;
}
}
Repository class
public interface CourseRepository extends CrudRepository<Topics,Long>{
}
Domain class
#Entity
#Table(name="Book")
public class Topics {
#Id
#Column(name="Topicid")
private long topicId;
#Column(name="Topictitle",nullable=false)
private String topicTitle;
#Column(name="Topicauthor",nullable=false)
private String topicAuthor;
public long getTopicId() {
return topicId;
}
public void setTopicId(long topicId) {
this.topicId = topicId;
}
public String getTopicTitle() {
return topicTitle;
}
public void setTopicTitle(String topicTitle) {
this.topicTitle = topicTitle;
}
public String getTopicAuthor() {
return topicAuthor;
}
public void setTopicAuthor(String topicAuthor) {
this.topicAuthor = topicAuthor;
}
public Topics(long topicId, String topicTitle, String topicAuthor) {
super();
this.topicId = topicId;
this.topicTitle = topicTitle;
this.topicAuthor = topicAuthor;
}
}
Following is the Junit class I have written but courseRepository is getting initialized to NULL and hence I am getting NullPointerException.
public class CourseServiceTest {
#Mock
private CourseRepository courseRepository;
#InjectMocks
private CourseService courseService;
Topics topics;
#Mock
private Iterable<Topics> topicsList;
#Before
public void setUp() {
MockitoAnnotations.initMocks(CourseServiceTest.class);
}
#Test
public void test_Get_Topic_Details() {
List<Topics> topics = new ArrayList<Topics>();
Mockito.when(courseRepository.findAll()).thenReturn(topics);
boolean result=courseService.getAllTopics();
assertTrue(result);
}
}
Change the setUp() method to:
#Before
public void setUp() {
MockitoAnnotations.initMocks(this);
}
Probably you are dealing with some problem on the framework to make the mocked class be injected by the framework.
I recommend to use Constructor Injection, so you don't need to rely on the reflection and #Inject/#Mock annotations to make this work:
#Service
public class CourseService {
private final CourseRepository courseRepository;
// #Autowired annotation is optional when using constructor injection
CourseService (CourseRepository courseRepository) {
this.courseRepository = courseRepository;
}
// .... code
}
The test:
#Test
public void test_Get_Topic_Details() {
List<Topics> topics = new ArrayList<Topics>();
Mockito.when(courseRepository.findAll()).thenReturn(topics);
CourseService courseService = new CourseService(courseRepository);
boolean result = courseService.getAllTopics();
assertTrue(result);
}
In normal Spring, when we want to autowire an interface, we define it's implementation in Spring context file.
What about Spring boot?
how can we achieve this?
currently we only autowire classes that are not interfaces.
Another part of this question is about using a class in a Junit class inside a Spring boot project.
If we want to use a CalendarUtil for example, if we autowire CalendarUtil, it will throw a null pointer exception. What can we do in this case? I just initialized using "new" for now...
Use #Qualifier annotation is used to differentiate beans of the same interface
Take look at Spring Boot documentation
Also, to inject all beans of the same interface, just autowire List of interface
(The same way in Spring / Spring Boot / SpringBootTest)
Example below:
#SpringBootApplication
public class DemoApplication {
public static void main(String[] args) {
SpringApplication.run(DemoApplication.class, args);
}
public interface MyService {
void doWork();
}
#Service
#Qualifier("firstService")
public static class FirstServiceImpl implements MyService {
#Override
public void doWork() {
System.out.println("firstService work");
}
}
#Service
#Qualifier("secondService")
public static class SecondServiceImpl implements MyService {
#Override
public void doWork() {
System.out.println("secondService work");
}
}
#Component
public static class FirstManager {
private final MyService myService;
#Autowired // inject FirstServiceImpl
public FirstManager(#Qualifier("firstService") MyService myService) {
this.myService = myService;
}
#PostConstruct
public void startWork() {
System.out.println("firstManager start work");
myService.doWork();
}
}
#Component
public static class SecondManager {
private final List<MyService> myServices;
#Autowired // inject MyService all implementations
public SecondManager(List<MyService> myServices) {
this.myServices = myServices;
}
#PostConstruct
public void startWork() {
System.out.println("secondManager start work");
myServices.forEach(MyService::doWork);
}
}
}
For the second part of your question, take look at this useful answers first / second
You can also make it work by giving it the name of the implementation.
Eg:
#Autowired
MyService firstService;
#Autowired
MyService secondService;
Assume that you have a GreetingService
public interface GreetingService {
void doGreetings();
}
And you have 2 implementations HelloService
#Service
#Slf4j
public class HelloService implements GreetingService{
#Override
public void doGreetings() {
log.info("Hello world!");
}
}
and HiService
#Slf4j
#Service
public class HiService implements GreetingService{
#Override
public void doGreetings() {
log.info("Hi world!");
}
}
Then you have another interface, which is BusinessService to call some business
public interface BusinessService {
void doGreetings();
}
There are some ways to do that
#1. Use #Autowired
#Component
public class BusinessServiceImpl implements BusinessService{
#Autowired
private GreetingService hiService; // Spring automatically maps the name for you, if you don't want to change it.
#Autowired
private GreetingService helloService;
#Override
public void doGreetings() {
hiService.doGreetings();
helloService.doGreetings();
}
}
In case you need to change your implementation bean name, refer to other answers, by setting the name to your bean, for example #Service("myCustomName") and applying #Qualifier("myCustomName")
#2. You can also use constructor injection
#Component
public class BusinessServiceImpl implements BusinessService {
private final GreetingService hiService;
private final GreetingService helloService;
public BusinessServiceImpl(GreetingService hiService, GreetingService helloService) {
this.hiService = hiService;
this.helloService = helloService;
}
#Override
public void doGreetings() {
hiService.doGreetings();
helloService.doGreetings();
}
}
This can be
public BusinessServiceImpl(#Qualifier("hiService") GreetingService hiService, #Qualifier("helloService") GreetingService helloService)
But I am using Spring Boot 2.6.5 and
public BusinessServiceImpl(GreetingService hiService, GreetingService helloService)
is working fine, since Spring automatically get the names for us.
#3. You can also use Map for this
#Component
#RequiredArgsConstructor
public class BusinessServiceImpl implements BusinessService {
private final Map<String, GreetingService> servicesMap; // Spring automatically get the bean name as key
#Override
public void doGreetings() {
servicesMap.get("hiService").doGreetings();
servicesMap.get("helloService").doGreetings();
}
}
List also works fine if you run all the services. But there is a case that you want to get some specific implementation, you need to define a name for it or something like that. My reference is here
For this one, I use #RequiredArgsConstructor from Lombok.
As mentioned in the comments, by using the #Qualifier annotation, you can distinguish different implementations as described in the docs.
For testing, you can use also do the same. For example:
#RunWith(SpringRunner.class)
#SpringBootTest
public class MyClassTests {
#Autowired
private MyClass testClass;
#MockBean
#Qualifier("default")
private MyImplementation defaultImpl;
#Test
public void givenMultipleImpl_whenAutowiring_thenReturnDefaultImpl() {
// your test here....
}
}
There are 2 approaches when we have autowiring of an interface with multiple implementations:
Spring #Primary annotation
In short it tells to our Spring application whenever we try to autowire our interface to use that specific implementation which is marked with the #Primary annotation. It is like a default autowiring setting. It can be used only once per cluster of implementations of an interface. → #Primary Docs
Spring #Qualifier annotation
This Spring annotation is giving us more control to select the exact implementation wherever we define a reference to our interface choosing among its options. → #Qualifier Docs
For more details follow the links to their documentation.
public interface SomeInterfaces {
void send(String message);
String getType();
}
kafka-service
#Component
public class SomeInterfacesKafkaImpl implements SomeInterfaces {
private final String type = "kafka";
#Override
public void send(String message) {
System.out.println(message + "through Kafka");
}
#Override
public String getType() {
return this.type;
}
}
redis-service
#Component
public class SomeInterfacesRedisImpl implements SomeInterfaces {
private final String type = "redis";
#Override
public void send(String message) {
System.out.println(message + "through Redis");
}
#Override
public String getType() {
return this.type;
}
}
master
#Component
public class SomeInterfacesMaster {
private final Set<SomeInterfaces> someInterfaces;
public SomeInterfacesMaster(Set<SomeInterfaces> someInterfaces) {
this.someInterfaces = someInterfaces;
}
public void sendMaster(String type){
Optional<SomeInterfaces> service =
someInterfaces
.stream()
.filter(service ->
service.getType().equals(type)
)
.findFirst();
SomeInterfaces someService =
service
.orElseThrow(() -> new RuntimeException("There is not such way for sending messages."));
someService .send(" Hello. It is a letter to ....");
}
}
test
#SpringBootTest
public class MultiImplementation {
}
#TestInstance(TestInstance.Lifecycle.PER_CLASS)
class SomeInterfacesMasterTest extends MultiImplementation {
#Autowired
private SomeInterfacesMaster someInterfacesMaster;
#Test
void sendMaster() {
someInterfacesMaster.sendMaster("kafka");
}
}
Thus, according to the Open/Closed principle, we only need to add an implementation without breaking existing code.
#Component
public class SomeInterfacesRabbitImpl implements SomeInterfaces {
private final String type = "rabbit";
#Override
public void send(String message) {
System.out.println(message + "through Rabbit");
}
#Override
public String getType() {
return this.type;
}
}
test-v2
#TestInstance(TestInstance.Lifecycle.PER_CLASS)
class SomeInterfacesMasterTestV2 extends MultiImplementation {
#Autowired
private SomeInterfacesMaster someInterfacesMaster;
#Test
void sendMasterV2() {
someInterfacesMaster.sendMaster("rabbit");
}
}
If we have multiple implementations of the same interface, Spring needs to know which one it should be autowired into a class. Here is a simple example of validator for mobile number and email address of Employee:-
Employee Class:
public class Employee {
private String mobileNumber;
private String emailAddress;
...
/** Getters & Setters omitted **/
}
Interface EmployeeValidator:
public interface EmployeeValidator {
public Employee validate(Employee employee);
}
First implementation class for Mobile Number Validator:
#Component(value="EmployeeMobileValidator")
public class EmployeeMobileValidator implements EmployeeValidator {
#Override
public Employee validate(Employee employee) {
//Mobile number Validation logic goes here.
}
}
Second implementation class for Email address Validator:
#Component(value="EmployeeEmailValidator")
public class EmployeeEmailValidator implements EmployeeValidator {
#Override
public Employee validate(Employee employee) {
//Email address validation logic goes here.
}
}
We can now autowired these above validators individually into a class.
Employee Service Interface:
public interface EmployeeService {
public void handleEmployee(Employee employee);
}
Employee Service Implementation Class
#Service
public class EmployeeServiceImpl implements EmployeeService {
/** Autowire validators individually **/
#Autowired
#Qualifier("EmployeeMobileValidator") // Autowired using qualifier for mobile validator
private EmployeeValidator mobileValidator;
#Autowired
#Qualifier("EmployeeEmailValidator") // Autowired using qualifier for email valodator
private EmployeeValidator emailValidator;
#Override
public void handleEmployee(Employee employee) {
/**You can use just one instance if you need**/
employee = mobileValidator.validate(employee);
}
}
I've got an entity
#Entity
#Table(name = "books")
public class Book {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private Long id;
private String name;
#Column(name = "id", unique = true, nullable = false)
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
#Column(name = "name")
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
}
I initialize it like this
#PostConstruct
public void init() {
List<String> newFiles = this.listFiles();
newFiles.forEach(filename -> {
Book book = new Book();
book.setName(filename);
dbRepository.save(book);
});
}
If I set the result of save to an instance of Book, I can get the id and it is not null—so id is created fine.
I defined a repository
#RepositoryRestResource
public interface IBooksRepository extends CrudRepository<Book, Long> {
}
which I'd like to use to get and set data into the books table in the database.
When I try to access my repository rest using curl localhost:8080/books, I get this response
{
"_embedded":{
"books":[
{
"name":"simple-file.txt",
"_links":{
"self":{
"href":"http://localhost:8080/books/1"
},
"book":{
"href":"http://localhost:8080/books/1"
}
}
}
]
},
"_links":{
"self":{
"href":"http://localhost:8080/books"
},
"profile":{
"href":"http://localhost:8080/profile/books"
}
}
}
The books element returns name only. How can I make it return id too, on the same level as name?
Spring Data Rest hides the ID by default, in order to have it in the JSON you have to manually configure that for your entity. Depending on your spring version you can either provide your own configuration (old):
#Configuration
public class ExposeEntityIdRestConfiguration extends RepositoryRestMvcConfiguration {
#Override
protected void configureRepositoryRestConfiguration(RepositoryRestConfiguration config) {
config.exposeIdsFor(Book.class);
}
}
...or register a RepositoryRestConfigurer (current):
#Component
public class ExposeEntityIdRestMvcConfiguration extends RepositoryRestConfigurerAdapter {
#Override
public void configureRepositoryRestConfiguration(RepositoryRestConfiguration config) {
config.exposeIdsFor(Book.class);
}
}
See the Spring Data Rest documentation for more details.
The accepted answer overrides a deprecated method. Here's the updated version:
#Component
public class RestConfig implements RepositoryRestConfigurer {
#Override
public void configureRepositoryRestConfiguration(RepositoryRestConfiguration config, CorsRegistry cors) {
config.exposeIdsFor(Book.class);
}
}
An alternative approach is to implement RepositoryRestConfigurer in your #SpringBootApplication annotated class:
#SpringBootApplication
public class MyApplication implements RepositoryRestConfigurer {
public static void main(String[] args) {
SpringApplication.run(MyApplication.class, args);
}
#Override
public void configureRepositoryRestConfiguration(RepositoryRestConfiguration config, CorsRegistry cors) {
config.exposeIdsFor(Book.class);
}
}
There is now a static method RepositoryRestConfigurer.withConfig that does the same thing as above. See javadoc:
Convenience method to easily create simple {#link RepositoryRestConfigurer} instances that solely want to tweak the {#link RepositoryRestConfiguration}.
I found the usage in one of their integration tests
So the following approach would be more up to date as of now:
#Bean
public RepositoryRestConfigurer repositoryRestConfigurer()
{
return RepositoryRestConfigurer.withConfig(config -> {
config.exposeIdsFor(Book.class);
});
}
#Component
public class RestConfig implements RepositoryRestConfigurer {
#Override
public void configureRepositoryRestConfiguration(RepositoryRestConfiguration config) {
config.exposeIdsFor(Book.class);
//config.exposeIdsFor(Library.class);
}
}
This is a solution which works for all entities
#Autowired
private EntityManager entityManager;
#Bean
public RepositoryRestConfigurer repositoryRestConfigurer() {
return RepositoryRestConfigurer.withConfig(config -> config.exposeIdsFor(entityManager.getMetamodel().getEntities().stream().map(Type::getJavaType).toArray(Class[]::new)));
}
This is a good way to go.
#Projection(name = "customBook", types = { Book.class })
public interface CustomBook {
#Value("#{target.id}")
long getId();
}
credit: https://www.baeldung.com/spring-data-rest-projections-excerpts