Bash script programming - bash

Question

I want to keep printing in a while loop(this occurs every second , i.e. sleeps for one second) and keep asking for a user input in a separate while loop, however if one indefinite runs , it doesn't go to the other for loop and if we run one in background and one in foreground still it doesnt helps, I am programming in bash script
#!/bin/bash
memusageStatus=false
diskspace=false
processStatus=false
menuStatus=true
function printMenu {
while [ true ]
do
if $menuStatus ; then
printf "\na) Show/Hide Memory Usage Information \nb) Show/Hide Disk Space Information \nc) Show/Hide Process Information\no) Show/Hide List of options \nq) Exit\n"
fi
sleep 1
tput cup 0 0 ;
tput ed
done
}
function disMenu {
while [ true ]
do
read ab
echo ab
case $ab in
'a') if $memusageStatus ; then
# free -k
memusageStatus=false;
else
memusageStatus=true;
fi
;;
'b') if $diskspace ; then
diskspace=false
else
diskspace=true;
fi
# df -h
;;
'c') if $processStatus ; then
processStatus=false
else
processStatus=true;
fi
;; #ps u
'o') echo "you pressed o"
if $menuStatus ; then
menuStatus=false;
else
menuStatus=true;
fi ;;
'q') exit 0;;
esac
done
}
printMenu &
disMenu
exit 0

Answer 1

You can try to use a read -t 1 in only one loop instead of a sleep 1.
But maybe with a longer read time.
Something like:
while [ true ]
do
echo "Show your Menu"
read -t 5 ab
case $ab in
'q') exit;;
esac
done