I just got stuck creating routes with localization.
The language should be read from the URL:
domain/en/cars/
domain/fr/cars/
domain/en/cars/create
domain/fr/cars/edit
...
I use the resource method to create the routes:
Route::resource('cars','CarsController');
Similar to Route::get, how can I use placeholders in the URL to specify the language?
I don't want to start with changing all routes to "Route::get". Or is there a better way to implement localization?
Route resources declaration also allows you to specify routes placeholders the way you would in a get route declaration
Route::resource("/domain/{language}/cars", "CarsController");
and within your CarsController, use it as follows
class CarsController
{
public index ($language)
{
App::setLocale($language);
...
}
public show ($language, $id)
{ ... }
}
Or better still
class CarsController
{
public __construct ()
{
if ($currentRoute = Route::current()) {
$language = $currentRoute->getParameter('language');
App::setLocale($language);
}
// ...
}
public show ($language, $id)
{ ... }
public show ($language, $id)
{ ... }
}
Edit: Added the setting of locale. in both the constructor and in each Controller method
Related
I have following route group in my laravel 8.0 app:
Route::prefix('offline_transaction')->name('offline_transaction.')->group(function () {
Route::post('/approve/{transaction:uuid}', [OfflineTransactionController::class, 'approve'])
->name('approve');
Route::post('/reject/{transaction:uuid}', [OfflineTransactionController::class, 'reject'])
->name('reject');
});
And Transaction model is:
class Transaction extends Model implements CreditBlocker
{
//....
protected static function boot()
{
parent::boot();
static::addGlobalScope(new AuthUserScope());
}
//....
}
And this is my AuthUserScope:
class AuthUserScope implements Scope
{
private string $fieldName;
public function __construct($fieldName = 'user_id')
{
$this->fieldName = $fieldName;
}
public function apply(Builder $builder, Model $model)
{
$user = Auth::user();
if ($user) {
$builder->where($this->fieldName, $user->id);
}
}
}
Now the problem is when an admin wants to approve or reject a transaction, 404 Not found error will throws. How can I pass this?
Customizing The Resolution Logic
If you wish to define your own model binding resolution logic, you may
use the Route::bind method. The closure you pass to the bind
method will receive the value of the URI segment and should return the
instance of the class that should be injected into the route. Again,
this customization should take place in the boot method of your
application's RouteServiceProvider:
Solution
What you can do is change the parameter name(s) in your routes/web.php file for the specific route(s).
Route::prefix('offline_transaction')->name('offline_transaction.')->group(function () {
Route::post('/approve/{any_transaction}', [OfflineTransactionController::class, 'approve'])
->name('approve');
Route::post('/reject/{any_transaction}', [OfflineTransactionController::class, 'reject'])
->name('reject');
Note the any_transaction. Change that to whatever naming convention you find most convenient.
Then, in your app/Providers/RouteServiceProvider.php file, change your boot(...) method to something like this:
use App\Models\Transaction;
use Illuminate\Support\Facades\Route;
// ...
public function boot()
{
// ...
Route::bind('any_transaction', function($uuid) {
return Transaction::withoutGlobalScopes()->where('uuid', $uuid)->firstOrFail();
});
// ...
}
// ...
Then in your controller app/Http/Controllers/OfflineTransactionController.php file, access the injected model:
use App\Models\Transaction;
// ...
public function approve(Transaction $any_transaction) {
// ...
}
// ...
Credits: Using Route Model Binding without Global Scope #thomaskim
Addendum
If you would like to remove a specific global scope from the route model bound query, you may use
withoutGlobalScope(AuthUserScope::class) in the boot(...) method of the app/Providers/RouteServiceProvider.php file.
Another approach is that I can use Route::currentRouteNamed in AuthUserScope class as following, which I prefer to use instead of Route::bind:
<?php
namespace App\Scopes;
use Illuminate\Database\Eloquent\Builder;
use Illuminate\Database\Eloquent\Model;
use Illuminate\Database\Eloquent\Scope;
use Illuminate\Support\Facades\Auth;
use Illuminate\Support\Facades\Route;
class AuthUserScope implements Scope
{
private string $fieldName;
public function __construct($fieldName = 'user_id')
{
$this->fieldName = $fieldName;
}
public function apply(Builder $builder, Model $model)
{
$user = Auth::user();
if ($user && !Route::currentRouteNamed('admin.*')) {
$builder->where($this->fieldName, $user->id);
}
}
}
I have two controllers. StudentController and TeacherController. I have a variable $chat which I want to pass in all the views of StudentController and TeacherController. The $chat will contain different data for both these controllers.
I searched and found ways, but I am getting empty data. I am doing it like this.
<?php
namespace App\Http\Controllers;
use View;
class StudentController extends Controller {
public function __construct()
{
$this->middleware('auth')->except(['home']);
$this->middleware('access')->except(['home']);
$chats = studentChat();
View::share('chats', $chats);
}
So, here I am printing and it is returning an empty array, but when I use the same in a function the array contains data. What is wrong here? Can anyone please help?
What I tried:
public function boot()
{
View::composer('*', function ($view) {
$chats = Cache::remember('chats', 60, function () {
if(Auth::user()->user_type() == config('constant.student'))
{
return studentChat();
}
else
{
return teacherChat();
}
});
$view->with('chats', $chats);
});
}
If you use View::share your share data to ALL your view, if you need to add data to few different views you may do this:
Create blade file(chat.blade.php for your case), and put your variables:
<? $chats = studentChat(); ?>
Include this file to the begining of your views where your need this 'global' varables:
//begin of your blade file
#include('chat')
//some code
{{ $chat->channel }}
Sharing Data With All Views
Occasionally, you may need to share a piece of data with all views that are rendered by your application. You may do so using the view facade's share method. Typically, you should place calls to share within a service provider's boot method. You are free to add them to the AppServiceProvider or generate a separate service provider to house them:
<?php
namespace App\Providers;
use Illuminate\Support\Facades\View;
class AppServiceProvider extends ServiceProvider
{
public function boot()
{
$chats = studentChat();
View::share('chats', $chats);
}
public function register()
{
//
}
}
So, what I did was in the AppServiceProvider class, in the boot function I added this.
View::composer('*', function ($view) {
if(!\Auth::check())
{
return;
}
$userType = \Auth::user()->user_type ;
if($userType == config('constant.student'))
{
$chats = studentChat();
}
else if($userType == config('constant.teacher'))
{
$chats = teacherChat();
}
$view->with('chats', $chats);
});
You can pass data to the view Like.
return View::make('demo')->with('posts', $posts);
For more details visit article : Introduction to Routing in Laravel
write your query in boot method in appServiceProvider like,
View::composer('*', function ($view) {
$share_query = Cache::remember('share_query', 60,function () {
return App\User::all();
});
$view->with('share_query', $share_query);
});
Your final solution is ok, but not the cleanest possible.
Here is what i would do.
Define a class with a single function that contains your logic and return $chats, that way you will encapsulate your logic properly and keep your service provider boot method clean.
Then you have 2 options:
Inject your class in the boot() method of the service provider you use, then call its function and uses View::share. Should looks like :
public function boot(ChatResolver $chatResolver)
{
$chats = $chatResolver->getChats();
View::share(compact('chats));
}
If you only use $chats variable in a signe view or partial (like a part of layout), you can also inject the class you defined directly in the view.
Here is a link to Laravel doc regarding that.
In some cases it might be the easiest solution.
Tried looking for the answer to this everywhere but having no luck so far...
Basically I want my web route to use a slug for its URL, but I want to use ID for the API route. So...
http://myurl.com/chapter/my-chapter-slug
and
http://myurl.com/api/chapter/1234
Have tried various combinations of things in the getRouteKeyName method (if(Request::route()->named('myapiroute'), if(Request::isJson() etc...) but I think these might be being checked against the page it's running on, rather than the route I'm trying to generate?
I'm thinking maybe I need to extend the base model to have a separate one to use with my API maybe?
So I'd have...
class Chapter extends Model
{
public function getRouteKeyName()
{
return 'slug';
}
....
}
and then...
class ApiChapter extends Chapter
{
public function getRouteKeyName()
{
return 'id';
}
....
}
But not sure how I'd structure this in the most "Laravel" way? Or is there a better/tidier solution?
define your route for example like
Route::get('chapters/{chapter}','ChapterController#show'); // find by slug
Route::get('api/chapters/{chapter}','ApiChapterController#show'); // find by id
for web controller
class ChapterController extends Controller
{
public function show(Request $request,$slug)
{
$instance = Model::whereSlug($slug)->first();
}
}
for api
class ApiChapterController extends Controller
{
public function show(Request $request,$id)
{
$instance = Model::find($id);
}
}
You can define 2 different routes for that but unfortunatelly you will not be able to use model binding and you will have to look for the model like:
public function show(Request $request,$slug) {
$instance = Model::whereSlug($slug)->first();
}
as shown below: https://stackoverflow.com/a/48115385/6525417
I have to build an api.
It has one route. The client is sending a POST request with an XML.
Based on that xml, I have to decide witch controller#action to be called.
And I have a lot of controllers.
Unfortunately I can't modify the client side.
Do you have any suggestion how can i do that in a Laravel way?
For example
POST["body"] =
"...
<controller>content</controller>
<action>index</action>
..."
I want to call a ContentController::index()
Thx!
Thx for the reflection stuff. It is a big magic, worth the effort to look into it deeper.
I have no problem to parse the xml. So here is a simplier example
URL: /api/request/content/show
Routes.php
Route::get('api/request/{controller}/{action}', 'ApiController#request');
ApiController.php
class ApiController extends Controller
{
public function request($controller, $action)
{
//some error check
$controller = 'App\Http\Controllers\\' . ucfirst($controller) . 'Controller';
$params = "Put some params here";
$reflectionMethod = new \ReflectionMethod($controller, $action);
$reflectionMethod->invoke(new $controller, $params);
}
}
ContentController.php
class ContentController extends Controller
{
public function show($params)
{
dd($params);
}
}
And it is working!
Thx a lot!
A better option is to use App::call(); invoking controller with ReflectionMethod might not let you use response() inside your new forwarded controller and other laravel goodies.
Here is my try on this: /api/request/content/show
Routes web.php or api.php
use App\Http\Controllers\ApiController;
Route::get('api/request/{controller}/{action}', [ApiController::class, 'request']);
ApiController.php
class ApiController extends Controller
{
public function request($controller, $action)
{
//some error check
return App::call('App\Http\Controllers\\'.ucfirst($controller).'Controller#'.$action);
}
}
ContentController.php
use Illuminate\Http\Request;
class ContentController extends Controller
{
public function show(Request $request)
{
dd($request);
}
}
This will allow you more freedom.
I have a controller in Laravel 4, with a custom variable declared within it.
class SampleController extends BaseController{
public $customVariable;
}
Two questions: Is there any way I can call within a route filter:
The controller object where the filter is running at.
The custom variable from that specific controller ($customVariable).
Thanks in advance!
as per this post:
http://forums.laravel.io/viewtopic.php?pid=47380#p47380
You can only pass parameters to filters as strings.
//routes.php
Route::get('/', ['before' => 'auth.level:1', function()
{
return View::make('hello');
}]);
and
//filters.php
Route::filter('auth.level', function($level)
{
//$level is 1
});
In controllers, it would look more like this
public function __construct(){
$this->filter('before', 'someFilter:param1,param2');
}
EDIT:
Should this not suffice to your needs, you can allways define the filter inside the controller's constructor. If you need access to the current controller ($this) and it's custom fields and you have many different classes you want to have that in, you can put the filter in BaseController's constructor and extend it in all classes you need.
class SomeFancyController extends BaseController {
protected $customVariable
/**
* Instantiate a new SomeFancyController instance.
*/
public function __construct()
{
$ctrl = $this;
$this->beforeFilter(function() use ($ctrl)
{
//
// do something with $ctrl
// do something with $ctrl->customVariable;
});
}
}
EDIT 2 :
As per your new question I realised the above example had a small error - as I forgot the closure has local scope. So it's correct now I guess.
If you declare it as static in your controller, you can call it statically from outside the controller
Controller:
class SampleController extends BaseController
{
public static $customVariable = 'test';
}
Outside your controller
echo SampleController::$customVariable
use:
public function __construct()
{
$this->beforeFilter('auth', ['controller' => $this]);
}