Save the following code as testme.sh.
OPTS=$(getopt -o a:b:c -- "$#")
eval set -- "$OPTS"
while true; do
case "$1" in
-a )
echo "i am in a",$OPTIND
shift 2;;
-b )
echo "i am in b",$OPTIND
shift 2;;
-c )
echo "i am in c",$OPTIND
shift;;
-- )
shift;;
*)
break;;
esac
done
Run it with bash /tmp/testme.sh -a a1 -b b1 -c.
i am in a,1
i am in b,1
i am in c,1
Now wrap all content in testme.sh as a function.
testme(){
OPTS=$(getopt -o a:b:c -- "$#")
eval set -- "$OPTS"
while true; do
case "$1" in
-a )
echo "i am in a",$OPTIND
shift 2;;
-b )
echo "i am in b",$OPTIND
shift 2;;
-c )
echo "i am in c",$OPTIND
shift;;
-- )
shift;;
*)
break;;
esac
done
}
Run it with testme -a a1 -b b1 -c.
i am in a,
i am in b,
i am in c,
There are 2 issues confused me.
1.Why all $OPTINDs value is 1 when to run bash /tmp/testme.sh -a a1 -b b1 -c ?
2.Why no $OPTINDs value at all when to run testme -a a1 -b b1 -c ?
getopt is an external command and runs in a subprocess, so it can't modify the original shell's variables. Because of this, it can't set variables like OPTIND and OPTARG, the way the built-in command getopts does. It simply outputs a modified version of the argument list, which can be assigned to positional parameters with set.
So when you use getopt rather than getopts, $OPTIND is not updated. It's initialized to 1 when a shell script starts. Since your testme.sh script never does anything that updates the variable, you get 1 every time through the loop.
When I try your testme function, I also see 1 every time. If you're not seeing this, you must have reassigned OPTIND before running the function. Try:
OPTIND=123
testme -a a1 -b b1 -c
and you should see
i am in a,123
i am in b,123
i am in c,123
Related
I'm trying to make a getopt command such that when I pass the "-ab" parameter to a script,
that script will treat -ab as a single parameter.
#!/bin/sh
args=`getopt "ab":fc:d $*`
set -- $args
for i in $args
do
case "$i" in
-ab) shift;echo "You typed ab $1.";shift;;
-c) shift;echo "You typed a c $1";shift;;
esac
done
However, this does not seem to work. Can anyone offer any assistance?
getopt doesn't support what you are looking for. You can either use single-letter (-a) or long options (--long). Something like -ab is treated the same way as -a b: as option a with argument b. Note that long options are prefixed by two dashes.
i was struggling with this for long - then i got into reading about getopt and getopts
single char options and long options .
I had similar requirement where i needed to have number of multichar input arguments.
so , i came up with this - it worked in my case - hope this helps you
function show_help {
echo "usage: $BASH_SOURCE --input1 <input1> --input2 <input2> --input3 <input3>"
echo " --input1 - is input 1 ."
echo " --input2 - is input 2 ."
echo " --input3 - is input 3 ."
}
# Read command line options
ARGUMENT_LIST=(
"input1"
"input2"
"input3"
)
# read arguments
opts=$(getopt \
--longoptions "$(printf "%s:," "${ARGUMENT_LIST[#]}")" \
--name "$(basename "$0")" \
--options "" \
-- "$#"
)
echo $opts
eval set --$opts
while true; do
case "$1" in
h)
show_help
exit 0
;;
--input1)
shift
empId=$1
;;
--input2)
shift
fromDate=$1
;;
--input3)
shift
toDate=$1
;;
--)
shift
break
;;
esac
shift
done
Note - I have added help function as per my requirement, you can remove it if not needed
That's not the unix way, though some do it e.g. java -cp classpath.
Hack: instead of -ab arg, have -b arg and a dummy option -a.
That way, -ab arg does what you want. (-b arg will too; hopefully that's not a bug, but a shortcut feature...).
The only change is your line:
-ab) shift;echo "You typed ab $1.";shift;;
becomes
-b) shift;echo "You typed ab $1.";shift;;
GNU getopt have --alternative option
-a, --alternative
Allow long options to start with a single '-'.
Example:
#!/usr/bin/env bash
SOPT='a:b'
LOPT='ab:'
OPTS=$(getopt -q -a \
--options ${SOPT} \
--longoptions ${LOPT} \
--name "$(basename "$0")" \
-- "$#"
)
if [[ $? > 0 ]]; then
exit 2
fi
A=
B=false
AB=
eval set -- $OPTS
while [[ $# > 0 ]]; do
case ${1} in
-a) A=$2 && shift ;;
-b) B=true ;;
--ab) AB=$2 && shift ;;
--) ;;
*) ;;
esac
shift
done
printf "Params:\n A=%s\n B=%s\n AB=%s\n" "${A}" "${B}" "${AB}"
$ ./test.sh -a aaa -b -ab=test
Params:
A=aaa
B=true
AB=test
getopt supports long format. You can search SO for such examples.
See here, for example
Based on tutorials I found here and here getopt should provide me with information about errors using some combination of characters :?*.
But when I used this code:
#!/bin/bash
eval set -- "$(getopt -o hspna: --long help,server,project,name-prefix,action: -- "$#")"
while [ : ]; do
case "$1" in
-s | --server)
echo "Setting server"
shift
;;
-p | --project)
echo "Setting project"
shift
;;
-n | --name-prefix)
echo "Setting name prefix"
shift
;;
-a | --action)
echo "Setting action"
shift
;;
--)
shift
break
;;
-h | --help)
echo "Providing help 1"
exit
;;
:)
echo "Providing help 2"
exit
;;
?)
echo "Providing help 3"
exit
;;
*)
echo "Providing help 4"
exit
;;
esac
done
echo $#
echo "Configured"
exit
Then following command that was supposed to show an error gave me the following output:
$ ./debug.sh -a -s -b -- foo bar baz
getopt: invalid option -- 'b'
Setting action
Setting server
foo bar baz
Configured
I was expecting that:
Providing help 2 will appear due to -a missing a value
Providing help 3 will appear due to -b not being a valid parameter
Providing help 4 will appear due to overall errors
Configured should never appear since the previous 3 points have an exit
But none of the above was true.
Also when testing further even more things did not work as expected.
# Expecting error due to missing value for `-a` but instead everything worked fine
$ ./debug.sh -a -s
Setting action
Setting server
Configured
# This time I expected everything to work fine, since I provided `X` as value of `-a`, but error was shown.
$ ./debug.sh -aX
Setting action
Providing help 3
What am I doing wrong?
What am I doing wrong?
Util-linux getopt prints and handles errors.
if ! args="$(getopt \
-n your_command \
-o hspna: \
--long help,server,project,name-prefix,action: \
-- "$#"\
)"; then
exit 1
fi
eval "set -- $args"
...
$ ./util -a
your_command: option requires an argument -- 'a'
I was expecting that:
I do not understand why. There is no such documentation in getopt. No, getopt will not output ? nor :. You can handle your (as the author of the program) errors, like you forgot to handle the option in case that you have given to getopt - you handle that with *).
The ? is a glob that matches any character. Because you forgot a shift after esac before done, X remains in $1, which is one character and is matched by ?). You meant '?'). This should go into *) case, and you should print yourself an error message.
Example, subjective in my style that I use (many people do not like set -eu):
set -euo pipefail
args=$(getopt -o ab -- "$#")
eval "set -- $args"
aflag=0
while (($#)); do
case "$1" in
-a) afloag=1; ;;
--) shift; break;
*) echo "Och no, I forgot about -b, or some other error!" >&2; exit 1; ;;
easc
shift
done
In the following script:
#!/usr/bin/env bash
func_usage ()
{
cat <<EOF \
USAGE: ${0} \
EOF
}
## Defining_Version
version=1.0
## Defining_Input
options=$(getopt -o "t:" -l "h,help,v,version,taxonomy:" -a -- "$#")
eval set -- "$options"
while true;do
case $1 in
-h|--h|-help|--help)
func_usage
exit 0
;;
-v|--v|-version|--version)
echo $version
;;
-t|--t|-taxonomy|--taxonomy)
echo "Option t = $2 ";
Taxonomy_ID=$2
echo $Taxonomy_ID
shift
;;
--)
shift
break;;
esac
shift
done
## Defining Taxonomy Default Value (in case is not provided)
TaxonomyID=${Taxonomy_ID:=9606};
echo $TaxonomyID
exit 0
The commands:
./script.sh -v
./script.sh --v
./script.sh -version
./script.sh --version
Work as expected. But what I do not understand is why the commands:
./script.sh -ver
./script.sh --ver
work at all. An equivalent unexpected behavior is also observed for the commands:
./script.sh -tax 22
./script.sh --tax 22
I would be grateful to get an explanation and/or a way to correct this unexpected behavior.
Note that getopt is an external utility unrelated to Bash.
what I do not understand is why the commands: .. work at all.
Because getopt was designed to support it, there is no other explanation. From man getopt:
[...] Long options may be abbreviated, as long as the abbreviation is not ambiguous.
Unambiguous abbreviations of long options are converted to long options.
Based on the comments I have received, specially from #CharlesDuffy, I have modified my code to what I believe is a more robust and compatible version. Importantly, the code below addresses the pitfalls of the original code
#!/usr/bin/env bash
func_usage ()
{
cat <<EOF
USAGE: ${0}
EOF
## Defining_Version
version=1.0
## Defining_Input
while true;do
case $1 in
-h|--h|-help|--help|-\?|--\?)
func_usage
exit 0
;;
-v|--v|-version|--version)
echo $version
;;
-t|--t|-taxonomy|--taxonomy)
echo "Option t = $2 ";
Taxonomy_ID=$2
echo $Taxonomy_ID
shift
;;
--)
shift
break;;
-?*)
printf 'WARN: Unknown option (ignored): %s\n' "$1" >&2
;;
*)
break
esac
shift
done
TaxonomyID=${Taxonomy_ID:=9606};
echo $TaxonomyID
exit 0
The code above behaves as expected in that the commands:
./script -tax 22
Gives the warning:
WARN: Unknown option (ignored): -tax
9606
As expected
Is it possible to mix options (with getopts) and arguments ($1....$10)?
getopt (singular) can handle options and arguments intermixed, as well as short -s and long --long options and -- to end options processing.
See here how file1 and file2 are mixed with options and it separates them out:
$ args=(-ab opt file1 -c opt file2)
$ getopt -o ab:c: -- "${args[#]}"
-a -b 'opt' -c 'opt' -- 'file1' 'file2'
Typical usage looks like:
#!/bin/bash
options=$(getopt -o ab:c: -l alpha,bravo:,charlie: -- "$#") || exit
eval set -- "$options"
# Option variables.
alpha=0
bravo=
charlie=
# Parse each option until we hit `--`, which signals the end of options.
# Don't actually do anything yet; just save their values and check for errors.
while [[ $1 != -- ]]; do
case $1 in
-a|--alpha) alpha=1; shift 1;;
-b|--bravo) bravo=$2; shift 2;;
-c|--charlie) charlie=$2; shift 2;;
*) echo "bad option: $1" >&2; exit 1;;
esac
done
# Discard `--`.
shift
# Here's where you'd actually execute the options.
echo "alpha: $alpha"
echo "bravo: $bravo"
echo "charlie: $charlie"
# File names are available as $1, $2, etc., or in the "$#" array.
for file in "$#"; do
echo "file: $file"
done
I have a bash script myscript.sh.
I mean to call another script, command or builtin from within it, e.g., diff.
I mean to pass options to myscript.sh, some of which would be passed to diff when calling it.
The way I implemented this is by setting up an option string optstring via getopt, and then using
eval "diff ${optstring} ${file} ${TRG_DIR}/${filebase2}"
So far, it worked, but I do not know if this is prone to issues when passing arguments with wildcards, etc. At any rate, ...
Is there a better way to do it?
The way I set up optstring is
set -o errexit -o noclobber -o nounset -o pipefail
params="$(getopt -o qy --long brief,side-by-side,suppress-common-lines --name "$0" -- "$#")"
if [ $? != 0 ] ; then echo "Failed parsing options." >&2 ; exit 1 ; fi
echo params=$params
echo params=$#
eval set -- "$params"
optstring=""
# These variables are likely not needed
brief=false
sbs=false
scl=false
#while false ; do
while true ; do
case "$1" in
-q|--brief)
optstring=${optstring}" -q"
brief=true
echo "brief"
shift
;;
-y|--side-by-side)
optstring=${optstring}" -y"
sbs=true
echo "side-by-side"
shift
;;
--suppress-common-lines)
optstring=${optstring}" --suppress-common-lines"
scl=true
echo "suppress-common-lines"
shift
;;
--)
shift
break
;;
*)
echo "Not implemented: $1" >&2
exit 1
;;
esac
done
echo optstring=${optstring}
Use an array. Arrays can handle multi-word arguments with whitespace. Initialize a blank array with:
options=()
To append an option, do:
options+=(--suppress-common-lines)
Then finally you can get rid of the eval when you call diff and just call it normally. Make sure to quote all of the variable expansions in case they have whitespace:
diff "${options[#]}" "$file" "$TRG_DIR/$filebase2"