Good Day Masters,
Can anyone help me how to convert this SQL Query into Code Igniter format (model).
SELECT firstName, FLOOR(DATEDIFF(CURRENT_DATE, birthDate)/365.25) as age FROM residents_tbl WHERE FLOOR(DATEDIFF(CURRENT_DATE, birthDate)/365.25) >= 18
I don't know how to write it on WHERE clause.
$query = $this->db->select('*');
$query = $this->db->from('residents_tbl');
**$query = $this->db->where('isHead', '1');**
$query = $this->db->order_by('lastName', 'ASC');
$query = $this->db->get('', 15, $this->uri->segment(3));
if ($query->num_rows() > 0) {
return $query->result();
}
TIA.
This is a simplified version with chaining. I just changed the type of 1 from string to number which might caused the problem.
$query = $this->db
->where('isHead', 1)
->get('residents_tbl')
->order_by('lastName', 'ASC');
Related
I'm trying to convert a query to CodeIgniter's query builder.
Original version:
$query = $this->db->query('SELECT tb.*,b.`property` FROM `email_template_blocks` as tb inner join email_blocks as b on tb.`block_id`=b.`id` where tb.template_id=' . $id);
if ($query->num_rows() < 1) {
return null;
}
return $query->result_array();
Query builder version:
$this->db->select('*');
$this->db->from('email_template_blocks');
$this->db->join('email_blocks', 'email_template_blocks.block_id = email_blocks.id', 'inner');
$this->db->where('email_template_blocks.template_id', $id);
$query = $this->db->get();
//$query = $this->db->query('SELECT tb.*,b.`property` FROM `email_template_blocks` as tb inner join email_blocks as b on tb.`block_id`=b.`id` where tb.template_id=' . $id);
if ($query->num_rows() < 1) {
return null;
}
return $query->result_array();
The query builder version returns no results (no error messages either and I have db debug on). I'm fairly certain I'm doing something wrong, but I find the CI documentation on joins lacking. How can I fix this?
I'd also like to know how to select all of the items from the email_template_blocks table and just join the property column of the email_blocks table.
Email template blocks table:
table schema
Email blocks table:
table schema
So this code is a combination of 3 table joined, now i want to filter the query where only the request that a user can have is his/her own request and not from other user.. the problem is in where clause i have duplicated.
$this->db->order_by('loanrequest.ApplicationNo', 'DESC');
$query = $this->db->get('loanrequest','loanapplication','user');
$this->db->join('loanapplication','loanrequest.ApplicationNo = loanapplication.ApplicationNo');
$this->db->join('user', 'user.userId = loanapplication.userId');
$this->db->where('loanapplication.userId', $this->session->userdata('userId'));
$this->db->where('loanapplication.ApplicationNo', 'loanrequest.ApplicationNo');
return $query->result_array();
I can not get what you have done in your join query but Here is how I do join in my CodeIgniter model.
You don't need to put this in where condition:
$this->db->where('loanapplication.ApplicationNo', 'loanrequest.ApplicationNo');
Because you have already done that in the join query.
$query = $this->db->select('*')
->from('loanapplication')
->join('loanrequest', 'loanrequest.ApplicationNo = loanapplication.ApplicationNo', 'left')
->join('user', 'user.userId = loanapplication.userId', 'left')
->where_in('loanapplication.userId',$this->session->userdata('userId'))
->order_by('loanrequest.ApplicationNo', 'DESC')
->get();
return $query->result_array();
I will recommend you should use $this->db->last_query() because it gives you a better idea about your query.
$query = $this->db->select('*')
->from('loanapplication')
->join('loanrequest', 'loanrequest.ApplicationNo = loanapplication.ApplicationNo', 'left')
->join('user', 'user.userId = loanapplication.userId', 'left')
->where_in('loanapplication.userId',$this->session->userdata('userId'))
->order_by('loanrequest.ApplicationNo', 'DESC');
$result = $query->get();
echo $this->db->last_query();exit; //use this to print your query so that you can get the actual issue
if ($result->num_rows() > 0) {
return $result->result_array();
} else
return '';
I am using codeigniter 3.1.0 and I am trying to get the total SUM of two columns from different tables
If my user_id = 1 it should return the total sum of 421 but returns 431 It is adding the votes from other users on my reply table
Question Using Active Record How can I make sure the SUM is getting the correct amount for the users id.
Model Function
public function thread_reputation($user_id) {
$this->db->select('SUM(reply.votes + thread.votes) AS reputation');
$this->db->from('thread', 'left');
$this->db->join('reply', 'reply.user_id = thread.user_id', 'left');
$this->db->where('thread.user_id', $user_id);
$this->db->where('reply.user_id', $user_id);
$query = $this->db->get();
if ($query->num_rows() > 0) {
return $query->row();
} else {
return 0;
}
}
Controller section where i echo it
$thread_reputation = $this->thread_analytics_model->thread_reputation('1');
echo $thread_reputation->reputation;
Thread Table
Reply Table
Change your query with this
$query = $this->db->query("SELECT SUM(A.votes) as reputation from
(
SELECT reply.votes FROM reply where reply.user_id = $user_id
UNION ALL
SELECT thread.votes FROM thread where thread.user_id = $user_id
)AS A");
Tested and properly working
Check Screenshot:-
Query using ACTIVE REOCRD
$this->db->select("SUM(A.votes) as reputation");
$this->db->from("(
SELECT reply.votes FROM reply where reply.user_id = $user_id
UNION ALL
SELECT thread.votes FROM thread where thread.user_id = $user_id) AS A");
$query = $this->db->get();
Another Solution using $this->db->get_compiled_select();
public function reputation($user_id) {
$this->db->select('thread.votes');
$this->db->from('thread');
$this->db->where('thread.user_id =' . $user_id);
$thread_query = $this->db->get_compiled_select();
$this->db->select('reply.votes');
$this->db->from('reply');
$this->db->where('reply.user_id ='. $user_id);
$reply_query = $this->db->get_compiled_select();
$query = $this->db->query("SELECT SUM(total.votes) as reputation from ($reply_query UNION ALL $thread_query) as total");
if ($query->num_rows() > 0) {
return $query->row();
} else {
return 0;
}
}
When you will use left join, it will return matched column & all other unmatched column from left table. Use inner join & check your result.
$data is an array which contain user post data for fetch record from orders table
$data=array('customer_id'=>$this->input->post('custId'),'paided'=>2);
$this->db->select('*');
$this->db->from('orders');
$this->db->where($data);
$this->db->get();
$data = array(
'customer_id' => $this->input->post('custId')],
'paided' => 2
);
$this->db->select('*');
$this->db->from('orders');
$this->db->where($data);
$this->db->get();
try this :
public function function_name (){
$data = array (
'customer_id' => $this->input->post('custId'),
'paided' => 2
);
$this->db->select('*');
$this->db->from('ordere');
$this->db->where($data);
$query = $this->db->get();
return $query->result_array();
}
You have done all good just need to put result() if you get multiple row or row() if you get one row
$data=array('customer_id'=>$this->input->post('custId'),'paided'=>2);
$this->db->select('*');
$this->db->from('orders');
$this->db->where($data);
$result= $this->db->get()->result(); //added result()
print_r($result);
as simple use
$custId = $_post['custId'];
$query = $this->db->query("SELECT * FROM orders WHERE customer_id= '$custId' AND paided='2'");
$result = $query->result_array();
return $result;//result will be array
This is the plus of using framework, you don't need to write that much of code,
$where = array('customer_id' => $this->input->post('custId'),'paided'=>2)
$result = $this->db->get_where('orders', $where);
and for fetching them, use $result->row() for single record retrieval.
If you want all records, use $result->result()
Here is documentation link, if you want to learn more.
What You should need to be Correct And Why
$data=array('customer_id'=>$this->input->post('custId'),'paided'=>2);
$this->db->select('*'); // by defaul select all so no need to pass *
$this->db->from('orders');
$this->db->where($data);
$this->db->get(); // this will not return data this is just return object
So Your Code Should be
$data=array('customer_id'=>$this->input->post('custId'),'paided'=>2);
$this->db->select(); // by defaul select all so no need to pass *
$this->db->from('orders');
$this->db->where($data);
$query = $this->db->get();
$data = $query->result_array();
// or You can
$data= $this->db->get()->result_array();
here result_array() return pure array where you can also use result()
this will return array of object
login(id, name, role,user_id)
teacher(teacher_id)
I need to check role is 2.
$this->db->select('*');
$this->db->from('teacher');
$this->db->where('teacher_branch_id',$this->session->userdata('branch_id'));
$this->db->join('login','teacher.teacher_id = login.login_user_id');
$query = $this->db->get();
Just add a where condition like this: $this->db->where('login.role', 2);
$this->db->select('*');
$this->db->from('teacher');
$this->db->join('login', 'teacher.teacher_id = login.login_user_id');
$this->db->where('teacher_branch_id', $this->session->userdata('branch_id'));
$this->db->where('login.role', 2);
$query = $this->db->get();