MacOS Command Line - Create folder with files at once - macos

Is it possible to write a command that will create a new directory with name passed as argument 'MyFolder' (for example) and will create four files with the same name (as part):
MyFolder.js
MyFolder.css
MyFolder.test.js
README.md
(using mkdir / touch / echo ...)
Main problem - one line command


This one-liner function should do the work:
$ function mkdir_and_files() { mkdir "${1}"; touch ${1}/${1}.js; touch ${1}/${1}.css; touch ${1}/${1}.test.js; touch ${1}/README.md; }; mkdir_and_files "MyFolder" ;
$ ls -latrh MyFolder/
total 0
drwxrwxrwt 15 root wheel 480B Aug 19 18:58 ..
-rw-r--r-- 1 user wheel 0B Aug 19 18:58 MyFolder.js
-rw-r--r-- 1 user wheel 0B Aug 19 18:58 MyFolder.css
-rw-r--r-- 1 user wheel 0B Aug 19 18:58 MyFolder.test.js
-rw-r--r-- 1 user wheel 0B Aug 19 18:58 README.md
drwxr-xr-x 6 user wheel 192B Aug 19 18:58 .


Try this:
populate_dir() { mkdir "$1"; touch "$1/$1".{js,css,test.js} "$1/README.md"; }
populate_dir MyFolder

Related

bash console output print layout

I want to make my writing to the console output in a nice tidy human readable.
here is how it looks now:
====================== Sat Apr 16 12:57:17 EDT 2022 ======================
==========================================================================
====================== Leopard - Download from S3 ======================
==========================================================================
==========================================================================
====================== Leopard - Decompressing ======================
==========================================================================
total 1349872
drwxr-xr-x 2 root root 12288 Apr 16 12:57 .
drwxrwxrwt. 4 root root 102 Apr 16 12:57 ..
-rw-r--r-- 1 root root 185070885 Apr 16 12:03 asdasdasd.sql.gz
-rw-r--r-- 1 root root 40344632 Apr 16 12:03 asdasdas.sql.gz
-rw-r--r-- 1 root root 26631 Apr 16 12:03 asdad.sql.gz
-rw-r--r-- 1 root root 1679 Apr 16 12:03 asdasd.sql.gz
-rw-r--r-- 1 root root 1237 Apr 16 12:03 asd.sql.gz
-rw-r--r-- 1 root root 5241900 Apr 16 12:03 asdasd.sql.gz
-rw-r--r-- 1 root root 1144 Apr 16 12:03 asdasasd.sql.gz
-rw-r--r-- 1 root root 489312 Apr 16 12:03 asdasd.sql.gz
-rw-r--r-- 1 root root 1138 Apr 16 12:03 asdasdasd.sql.gz
==========================================================================
====================== NewYorkCity - Download from S3 ======================
==========================================================================
==========================================================================
====================== NewYorkCity - Unloading SSL Example ======================
==========================================================================
total 1349872
drwxr-xr-x 2 root root 12288 Apr 16 12:57 .
drwxrwxrwt. 4 root root 102 Apr 16 12:57 ..
-rw-r--r-- 1 root root 185070885 Apr 16 12:03 asdasdasd.sql.gz
-rw-r--r-- 1 root root 40344632 Apr 16 12:03 asdasdas.sql.gz
-rw-r--r-- 1 root root 26631 Apr 16 12:03 asdad.sql.gz
-rw-r--r-- 1 root root 1679 Apr 16 12:03 asdasd.sql.gz
-rw-r--r-- 1 root root 1237 Apr 16 12:03 asd.sql.gz
-rw-r--r-- 1 root root 5241900 Apr 16 12:03 asdasd.sql.gz
-rw-r--r-- 1 root root 1144 Apr 16 12:03 asdasasd.sql.gz
-rw-r--r-- 1 root root 489312 Apr 16 12:03 asdasd.sql.gz
-rw-r--r-- 1 root root 1138 Apr 16 12:03 asdasdasd.sql.gz
I want that all the === line will be in the same length, and the text always in the center with 1 space on each side
Will appreciate assistance here :)
UPDATE / EDIT:
The original script is something like that:
eecho () { echo ==========================================================================; }
echo_stage () {
START=1
END=11
for (( c=$START; c<=$END; c++ ))
do
printf == '-%.0s'
done
echo -n " " $1 " "
for (( c=$START; c<=$END; c++ ))
do
printf == '-%.0s'
done
echo
}
stage() {
eecho
echo_stage "$1" "$2"
eecho
}
print_date () { echo "======================" $(date) "======================"; }
reload_db() {
print_date
rm -rf /var/tmp/db
mkdir -p /var/tmp/db
stage "DB - Download from S3"
aws s3 sync s3://db-backup/latest/ /var/tmp/db --profile=papilon --quiet
stage "DB - Decompressing"
pigz -d /var/tmp/db/*
stage "DB - Restoring Data"
cd /var/tmp/db
stage "DB - Restoring Tables"
for i in `ls -1 *.sql | grep -v "_view.sql"`;do echo $i;mysql db < $i;done
stage "DB - Restoring Views"
for i in `ls -1 *.sql | grep "_view.sql"`;do echo $i;mysql db < $i;done
stage "DB - Clean up"
rm -rf /var/tmp/db
print_date
}
reload_db

This awk filter will size your === padding correctly, and align titles to the center, if you pipe your command output through it:
# cmd |
awk '
BEGIN {a[1] = "="}
NF>1 && $1~/^=+$/ && $NF~/^=+$/ {
sub(/^=+/, "")
sub(/=+$/, "")
title_len=length($0)
pad = ""
for (i=1; i<=(74-title_len)/2; ++i) {
pad=pad"="
}
$0 = pad $0 pad a[title_len%2]
}
1'
This doesn't wrap the ls -l output, only the titles. It assumes 74 is hardcoded as the length of the solid === lines (and doesn't change depending on terminal size). The array a is used to add an extra = when 74 - title_len is an odd number.
Example output:
====================== Sat Apr 16 12:57:17 EDT 2022 ======================
==========================================================================
====================== Leopard - Download from S3 ======================
==========================================================================
==========================================================================
======================= Leopard - Decompressing ========================
==========================================================================
total 1349872
drwxr-xr-x 2 root root 12288 Apr 16 12:57 .
drwxrwxrwt. 4 root root 102 Apr 16 12:57 ..
-rw-r--r-- 1 root root 185070885 Apr 16 12:03 asdasdasd.sql.gz
-rw-r--r-- 1 root root 40344632 Apr 16 12:03 asdasdas.sql.gz
-rw-r--r-- 1 root root 26631 Apr 16 12:03 asdad.sql.gz
-rw-r--r-- 1 root root 1679 Apr 16 12:03 asdasd.sql.gz
-rw-r--r-- 1 root root 1237 Apr 16 12:03 asd.sql.gz
-rw-r--r-- 1 root root 5241900 Apr 16 12:03 asdasd.sql.gz
-rw-r--r-- 1 root root 1144 Apr 16 12:03 asdasasd.sql.gz
-rw-r--r-- 1 root root 489312 Apr 16 12:03 asdasd.sql.gz
-rw-r--r-- 1 root root 1138 Apr 16 12:03 asdasdasd.sql.gz
==========================================================================
==================== NewYorkCity - Download from S3 ====================
==========================================================================
==========================================================================
================= NewYorkCity - Unloading SSL Example ==================
==========================================================================
total 1349872
drwxr-xr-x 2 root root 12288 Apr 16 12:57 .
drwxrwxrwt. 4 root root 102 Apr 16 12:57 ..
-rw-r--r-- 1 root root 185070885 Apr 16 12:03 asdasdasd.sql.gz
-rw-r--r-- 1 root root 40344632 Apr 16 12:03 asdasdas.sql.gz
-rw-r--r-- 1 root root 26631 Apr 16 12:03 asdad.sql.gz
-rw-r--r-- 1 root root 1679 Apr 16 12:03 asdasd.sql.gz
-rw-r--r-- 1 root root 1237 Apr 16 12:03 asd.sql.gz
-rw-r--r-- 1 root root 5241900 Apr 16 12:03 asdasd.sql.gz
-rw-r--r-- 1 root root 1144 Apr 16 12:03 asdasasd.sql.gz
-rw-r--r-- 1 root root 489312 Apr 16 12:03 asdasd.sql.gz
-rw-r--r-- 1 root root 1138 Apr 16 12:03 asdasdasd.sql.gz

Because you have now posted your script, I will add a new answer for pure bash.
title() {
local text pad
(( ${#1} > 70 )) && { echo "$1"; return; }
text=${1:+ }$1${1:+ }
pad=$( eval "printf %.1s ={1..$(( ( 74 - ${#text} ) / 2 ))}" )
echo "$pad$text$pad$( (( ${#text} % 2 )) && printf = )"
}
For title 'foo bar', this function prints foo bar (or any string up to 70 characters) with a space either side, centered and padded to 74 columns with =. If the string is longer than 70 characters it's too long to pad, so it's printed as is.
================================ foo bar =================================
With no argument, or an empty argument, it prints a solid line of 74 =:
==========================================================================
You can swap = for any single ASCII character.
You can swap 74 for any even number. Also for an odd number, if you change && printf to || printf in the last line. (also change the 70 to N - 4)
You can call title once for the date, or three times for the larger three line banners (see banner below).
Explanation:
${#text} is bash for "length of $text".
${1:+ } expands to a space, unless $1 is empty or unset. This allows us to add spaces to either end of the string, or exclude them for an empty string.
={1..10} expands to =1 =2 =3 ... =10, and printf %.1s prints the first character of each string. Combining these allows us to repeat a string (=) N times.
But we can't use a variable (or arithmetic) in {1..10} normally. So we need eval.
You probably heard eval is bad, and a security risk. That's often true, but here we are not passing any unknown data to eval (such as user input), and it's safe from code injection. (${#text} always expands to a single number)
So we make two bars, of length (74 - text-length) / 2, adding another = to the second bar if the text length is an odd number.
I also made a few changes to your script which you might consider. Apart from the date and titles, these have nothing to do with the padding. The title and banner functions will work on your old script.
title() {
local text pad
(( ${#1} > 70 )) && { echo "$1"; return; }
text="${1:+ }$1${1:+ }"
pad=$( eval "printf %.1s ={1..$(( ( 74 - ${#text} ) / 2 ))}" )
echo "$pad$text$pad$( (( ${#text} % 2 )) && printf = )"
}
banner() {
title
title "$1"
title
}
reload_db() {
local i
title "$(date)"
rm -rf /var/tmp/db || exit 1
mkdir -p /var/tmp/db || exit 1
banner 'DB - Download from S3'
aws s3 sync s3://db-backup/latest/ /var/tmp/db --profile=papilon --quiet
banner 'DB - Decompressing'
pigz -d /var/tmp/db/*
banner 'DB - Restoring Data'
cd /var/tmp/db || exit 1
banner 'DB - Restoring Tables'
GLOBIGNORE='*_view.sql'
for i in *.sql; do
echo "$i"
mysql db < "$i"
done
GLOBIGNORE=
banner 'DB - Restoring Views'
for i in *_view.sql; do
echo "$i"
mysql db < "$i"
done
banner 'DB - Clean up'
rm -rf /var/tmp/db
title "$(date)"
}
At the very least, you should exit early if cd, mkdir, or the first rm fail. Also, looping over an unquoted ls command sub is a bad idea. Instead you can use glob expansion (or find).
You could also concatenate the SQL scripts, but this only works if all the commands end with a semicolon (see Run multiple sql files in mysql batch):
big_title 'DB - Restoring Tables'
GLOBIGNORE='*_view.sql'
printf '%s\n' *.sql
cat *.sql | mysql db
GLOBIGNORE=
big_title 'DB - Restoring Views'
printf '%s\n' *_view.sql
cat *_view.sql | mysql db

Linux command du returns different size when the same content is, either an image mount to the file system, or under a directory of it

I have a qcow2 image which I have converted to raw format, and then mount to my file system:
# qemu-img convert -O raw initial-image.qcow2 raw-image.img
# kpartx -av raw-image.img
add map loop0p1 (253:1): 0 41940992 linear /dev/loop0 2048
# mount /dev/mapper/loop0p1 ~/myImage
# ls ~/myImage
bin boot dev etc home lib lib64 media mnt opt proc root run sbin srv sys tmp usr var
The size of ~/myImage mountpoint is checked with du command as follows:
# du -hx --max-depth=1 ~/myImage/
0 /root/myImage/dev
0 /root/myImage/proc
0 /root/myImage/run
0 /root/myImage/sys
36M /root/myImage/etc
40K /root/myImage/root
53M /root/myImage/var
12K /root/myImage/tmp
834M /root/myImage/usr
89M /root/myImage/boot
0 /root/myImage/home
0 /root/myImage/media
0 /root/myImage/mnt
0 /root/myImage/opt
0 /root/myImage/srv
1012M /root/myImage/
At this point I copied the contents of ~/myImage and pasted them inside ~/myImage-copy directory. Then I checked the size of the newly created directory. I expected the exact same size for each directory between ~/myImage and ~/myImage-copy, but it's not:
# cp -R myImage/ ~/myImage-copy
# du -hx --max-depth=1 ~/myImage-copy/
0 /root/myImage-copy/dev
0 /root/myImage-copy/proc
0 /root/myImage-copy/run
0 /root/myImage-copy/sys
36M /root/myImage-copy/etc
40K /root/myImage-copy/root
63M /root/myImage-copy/var
12K /root/myImage-copy/tmp
862M /root/myImage-copy/usr
89M /root/myImage-copy/boot
0 /root/myImage-copy/home
0 /root/myImage-copy/media
0 /root/myImage-copy/mnt
0 /root/myImage-copy/opt
0 /root/myImage-copy/srv
1.1G /root/myImage-copy/
From the paths above with different size, I chose /usr and I followed a branch of it until I conclude to an innermost directory which has different size, in order to inspect its files. Below is shown the size difference of an innermost directory:
# du -hx --max-depth=1 ~/myImage/usr/lib64/python2.7/json/
112K /root/myImage/usr/lib64/python2.7/json/
# du -hx --max-depth=1 ~/myImage-copy/usr/lib64/python2.7/json/
164K /root/myImage-copy/usr/lib64/python2.7/json/
However, by inspecting their file content, I can't see any difference related to their size. I don't know if the second column plays a role:
# ls -lah ~/myImage/usr/lib64/python2.7/json/
total 200K
drwxr-xr-x. 2 root root 280 Feb 3 11:17 .
drwxr-xr-x. 26 root root 20K Feb 3 11:17 ..
-rw-r--r--. 1 root root 14K Aug 13 2020 decoder.py
-rw-r--r--. 2 root root 12K Aug 13 2020 decoder.pyc
-rw-r--r--. 2 root root 12K Aug 13 2020 decoder.pyo
-rw-r--r--. 1 root root 17K Aug 13 2020 encoder.py
-rw-r--r--. 2 root root 14K Aug 13 2020 encoder.pyc
-rw-r--r--. 2 root root 14K Aug 13 2020 encoder.pyo
-rw-r--r--. 1 root root 15K Aug 13 2020 __init__.py
-rw-r--r--. 2 root root 14K Aug 13 2020 __init__.pyc
-rw-r--r--. 2 root root 14K Aug 13 2020 __init__.pyo
-rw-r--r--. 1 root root 2.3K Aug 13 2020 scanner.py
-rw-r--r--. 2 root root 2.2K Aug 13 2020 scanner.pyc
-rw-r--r--. 2 root root 2.2K Aug 13 2020 scanner.pyo
-rw-r--r--. 1 root root 997 Aug 13 2020 tool.py
-rw-r--r--. 2 root root 1.3K Aug 13 2020 tool.pyc
-rw-r--r--. 2 root root 1.3K Aug 13 2020 tool.pyo
# ls -lah ~/myImage-copy/usr/lib64/python2.7/json/
total 200K
drwxr-xr-x 2 root root 280 Mar 4 17:55 .
drwxr-xr-x 26 root root 20K Mar 4 17:55 ..
-rw-r--r-- 1 root root 14K Mar 4 17:55 decoder.py
-rw-r--r-- 1 root root 12K Mar 4 17:55 decoder.pyc
-rw-r--r-- 1 root root 12K Mar 4 17:55 decoder.pyo
-rw-r--r-- 1 root root 17K Mar 4 17:55 encoder.py
-rw-r--r-- 1 root root 14K Mar 4 17:55 encoder.pyc
-rw-r--r-- 1 root root 14K Mar 4 17:55 encoder.pyo
-rw-r--r-- 1 root root 15K Mar 4 17:55 __init__.py
-rw-r--r-- 1 root root 14K Mar 4 17:55 __init__.pyc
-rw-r--r-- 1 root root 14K Mar 4 17:55 __init__.pyo
-rw-r--r-- 1 root root 2.3K Mar 4 17:55 scanner.py
-rw-r--r-- 1 root root 2.2K Mar 4 17:55 scanner.pyc
-rw-r--r-- 1 root root 2.2K Mar 4 17:55 scanner.pyo
-rw-r--r-- 1 root root 997 Mar 4 17:55 tool.py
-rw-r--r-- 1 root root 1.3K Mar 4 17:55 tool.pyc
-rw-r--r-- 1 root root 1.3K Mar 4 17:55 tool.pyo
In addition, I checked the md5 hash of the files above as a view of their content. It seems there is no content differences between the same files:
# md5sum ~/myImage/usr/lib64/python2.7/json/*
598c681c82c582ca3f17950b4d5413c1 /root/myImage/usr/lib64/python2.7/json/decoder.py
939055a9fdfbbe6ab4d4babeb3ae63f5 /root/myImage/usr/lib64/python2.7/json/decoder.pyc
939055a9fdfbbe6ab4d4babeb3ae63f5 /root/myImage/usr/lib64/python2.7/json/decoder.pyo
007a9954ca6641b29564a0f0cb55096b /root/myImage/usr/lib64/python2.7/json/encoder.py
366d44efbfce1e5b4a3397b15f202765 /root/myImage/usr/lib64/python2.7/json/encoder.pyc
366d44efbfce1e5b4a3397b15f202765 /root/myImage/usr/lib64/python2.7/json/encoder.pyo
dd5db0c7fb7c531be4e14feebbdb52e8 /root/myImage/usr/lib64/python2.7/json/__init__.py
791c8dca2a86ce50ead04e918a17b508 /root/myImage/usr/lib64/python2.7/json/__init__.pyc
791c8dca2a86ce50ead04e918a17b508 /root/myImage/usr/lib64/python2.7/json/__init__.pyo
8d6660f10863f99ffdd9a95eeddd7b64 /root/myImage/usr/lib64/python2.7/json/scanner.py
59865f486b742aea959693c04cfce057 /root/myImage/usr/lib64/python2.7/json/scanner.pyc
59865f486b742aea959693c04cfce057 /root/myImage/usr/lib64/python2.7/json/scanner.pyo
ad879e2ba247d3d4a5cc71fe22db91d0 /root/myImage/usr/lib64/python2.7/json/tool.py
af6b5531a8bc6977bca14e8d34ba8f68 /root/myImage/usr/lib64/python2.7/json/tool.pyc
af6b5531a8bc6977bca14e8d34ba8f68 /root/myImage/usr/lib64/python2.7/json/tool.pyo
# md5sum ~/myImage-copy/usr/lib64/python2.7/json/*
598c681c82c582ca3f17950b4d5413c1 /root/myImage-copy/usr/lib64/python2.7/json/decoder.py
939055a9fdfbbe6ab4d4babeb3ae63f5 /root/myImage-copy/usr/lib64/python2.7/json/decoder.pyc
939055a9fdfbbe6ab4d4babeb3ae63f5 /root/myImage-copy/usr/lib64/python2.7/json/decoder.pyo
007a9954ca6641b29564a0f0cb55096b /root/myImage-copy/usr/lib64/python2.7/json/encoder.py
366d44efbfce1e5b4a3397b15f202765 /root/myImage-copy/usr/lib64/python2.7/json/encoder.pyc
366d44efbfce1e5b4a3397b15f202765 /root/myImage-copy/usr/lib64/python2.7/json/encoder.pyo
dd5db0c7fb7c531be4e14feebbdb52e8 /root/myImage-copy/usr/lib64/python2.7/json/__init__.py
791c8dca2a86ce50ead04e918a17b508 /root/myImage-copy/usr/lib64/python2.7/json/__init__.pyc
791c8dca2a86ce50ead04e918a17b508 /root/myImage-copy/usr/lib64/python2.7/json/__init__.pyo
8d6660f10863f99ffdd9a95eeddd7b64 /root/myImage-copy/usr/lib64/python2.7/json/scanner.py
59865f486b742aea959693c04cfce057 /root/myImage-copy/usr/lib64/python2.7/json/scanner.pyc
59865f486b742aea959693c04cfce057 /root/myImage-copy/usr/lib64/python2.7/json/scanner.pyo
ad879e2ba247d3d4a5cc71fe22db91d0 /root/myImage-copy/usr/lib64/python2.7/json/tool.py
af6b5531a8bc6977bca14e8d34ba8f68 /root/myImage-copy/usr/lib64/python2.7/json/tool.pyc
af6b5531a8bc6977bca14e8d34ba8f68 /root/myImage-copy/usr/lib64/python2.7/json/tool.pyo
So, what is the reason behind the size difference of the same content in du output?
My operating system is CentOS Linux release 7.9.2009.

Is there a way to remove the owner's read permissions on a file in macOS?

Is there any way to take away the owner's permission to read a file in macOS? I know there's no reason to do this but I have to for school and I can't find an answer anywhere. Removing my write permission works fine but when I try to remove my read permission it automatically give me my read and write permissions back. As you can see in the console when I use chmod -v -v (extra verbose) it shows the correct permissions it should be changed to but then when checking afterwards they havent changed into that...
thijs#Thijss-MacBook-Air-2 week6 % ls -l
total 16
-rw----r-- 1 thijs staff 12 Oct 11 21:10 greeting.txt
-rw-r--r-- 1 thijs staff 0 Oct 11 21:10 hello.txt
-rw------- 1 thijs staff 15 Oct 11 21:11 weather.txt
thijs#Thijss-MacBook-Air-2 week6 % chmod -v -v u-w weather.txt
weather.txt: 0100600 [-rw------- ] -> 0100400 [-r-------- ]
thijs#Thijss-MacBook-Air-2 week6 % ls -l
total 16
-rw----r-- 1 thijs staff 12 Oct 11 21:10 greeting.txt
-rw-r--r-- 1 thijs staff 0 Oct 11 21:10 hello.txt
-r-------- 1 thijs staff 15 Oct 11 21:11 weather.txt
thijs#Thijss-MacBook-Air-2 week6 % chmod -v -v u-r weather.txt
weather.txt: 0100400 [-r-------- ] -> 0100000 [---------- ]
thijs#Thijss-MacBook-Air-2 week6 % ls -l
total 16
-rw----r-- 1 thijs staff 12 Oct 11 21:10 greeting.txt
-rw-r--r-- 1 thijs staff 0 Oct 11 21:10 hello.txt
-rw------- 1 thijs staff 15 Oct 11 21:11 weather.txt

How to rename all directories on a terminal

I have a total of 31 directories. Every directory has a random name.
❯ ls -al
total 32
drwxr-xr-x 34 shinokada staff 1088 Dec 28 17:16 .
drwxr-xr-x 32 shinokada staff 1024 Dec 28 17:12 ..
-rw-r--r--# 1 shinokada staff 14340 Dec 28 17:16 .DS_Store
drwxr-xr-x 5 shinokada staff 160 Dec 28 17:10 05618066
drwxr-xr-x 5 shinokada staff 160 Dec 28 17:08 0fef2d20
drwxr-xr-x 5 shinokada staff 160 Dec 28 17:09 11ff096d
drwxr-xr-x 5 shinokada staff 160 Dec 28 17:09 1651ff1f
drwxr-xr-x 5 shinokada staff 160 Dec 28 17:09 2123b256
... and more
Now I'd like to rename them sample1 sample2 sample3 ...sample31.
How can I do it on a terminal(bash/zsh)?
Is there a quick way to do it rather than rename one by one?

This should do:
num=1; for dir in */ ; do mv "${dir}" "sample$num" ; ((num++)); done
I assume you don't want to rename the files, only directories inside your current working directory.

How to include a library in the path while compiling?

I'm reading this post about go and was trying to compile the source code found here
I downloaded the source code, compiled the first file with make and I can see the object is generated:
$pwd
/Users/oscarryz/code/go/rsc/rosetta/graph
$ls -ltR
total 136
-rw-r--r-- 1 oscarryz staff 61295 Sep 17 16:20 _go_.6
drwxr-xr-x 3 oscarryz staff 102 Sep 17 16:20 _obj
-rw-r--r-- 1 oscarryz staff 126 Sep 17 16:17 Makefile
-rw-r--r-- 1 oscarryz staff 2791 Sep 17 16:17 graph.go
./_obj:
total 0
drwxr-xr-x 3 oscarryz staff 102 Sep 17 16:20 rsc.googlecode.com
./_obj/rsc.googlecode.com:
total 0
drwxr-xr-x 3 oscarryz staff 102 Sep 17 16:20 hg
./_obj/rsc.googlecode.com/hg:
total 0
drwxr-xr-x 3 oscarryz staff 102 Sep 17 16:20 rosetta
./_obj/rsc.googlecode.com/hg/rosetta:
total 136
-rw-r--r-- 1 oscarryz staff 68486 Sep 17 16:20 graph.a
No my question is, how do I refer to that compiled code from the maze directory:
/Users/oscarryz/code/go/rsc/rosetta/maze/maze.go
Whose import declarations are:
import (
"bytes"
"fmt"
"rand"
"time"
"rsc.googlecode.com/hg/rosetta/graph"
)
And right now is failing to compile with the error message:
6g -o _go_.6 maze.go
maze.go:20: can't find import: rsc.googlecode.com/hg/rosetta/graph
make: *** [_go_.6] Error 1

Ok, I found it, wasn't that hard.
6g flags: -I DIR search for packages in DIR
I have to specify the -I option like this:
6g -I ../graph/_obj/ -o _go_.6 maze.go

Resources