How to append GUID to existing filenames and save to CSV - windows

Question

I currently have a CSV which contains 1 column that lists many file FullNames. (ie. "\\server\sub\folder\file.ext").
I am attempting to import this CSV, move the file to a separate location and append a GUID to the beginning of the filename in the new location (ie GUID_File.ext). I've been able to move the files, generate the GUID_ but haven't been able to store and reuse the existing filename.ext, it just gets cut off and the file ends up just being a GUID_. I just am not sure how to store the existing filename for reuse.
$Doc = Import-CSV C:\Temp\scripttest.csv
ForEach ($line in $Doc)
{
$FileBase = $Line.basename
$FileExt = $Line.extension
Copy-Item -path $line.File -Destination "\\Server\Folder\$((new-guid).guid.replace('-',''))_$($Filebase)$($FileExt)"
}
If possible, I'm going to also need to store and place all the new GUID_File.ext back into a CSV and store any errors to another file.

Answer 1

I currently have a CSV which contains 1 column that lists many file FullNames. (ie. "\server\sub\folder\file.ext").
This isn't a CSV. It's just a plaintext file with a list.
Here's how you can accomplish your goal, however:
foreach ($path in (Get-Content -Path C:\Temp\scripttest.csv))
{
$file = [System.IO.FileInfo]$path
$prefix = (New-Guid).Guid -replace '-'
Copy-Item -Path $file.FullName -Destination "\\Server\Folder\${prefix}_$file"
}
This will take your list, convert the item into a FileInfo type it can work with, and do the rest of your logic.

Answer 2

Based on:
$FileBase = $line.basename
$FileExt = $line.extension
it sounds like you mistakenly think that the $line instances representing the objects returned from Import-Csv C:\Temp\scripttest.csv are [System.IO.FileInfo] instances, but they're not:
What Import-Csv outputs are [pscustomobject] instances whose properties reflect the column values of the input CSV, and the values of these properties are invariably strings.
You must therefore use $line.<column1Name> to refer to the column containing the full filenames, where <column1Name> is the name defined for the column of interest in the header line (the 1st line) of the input CSV file.
If the CSV file has no header line, you can specify the column names by passing an array of column names to Import-Csv's -Header parameter, e.g.,
Import-Csv -Header Path, OtherCol1, OtherCol2, ... C:\Temp\scripttest.csv
I'll assume that the column of interest is named Path in the following solution:
$Doc = Import-Csv C:\Temp\scripttest.csv
ForEach ($rowObject in $Doc)
{
$fileName = Split-Path -Leaf $rowObject.Path
Copy-Item -Path $rowObject.Path `
-Destination "\\Server\Folder\$((new-guid).guid.replace('-',''))_$fileName"
}
Note how Split-Path -Leaf is used to extract the filename, including extension, from the full input path.

Answer 3

If I read your question carefully, you want to:
copy the files listed in the CSV file in the 'File' column.
the new files should have a GUID prepended to the filename
you need a new CSV file where the new filenames are stored for later reference
you want to track any errors and write those to a (log) file
Assuming you have an input CSV file looking something like this:
File,Author,MoreStuff
\\server\sub\folder\file.ext,Someone,Blah
\\server\sub\folder\file2.ext,Someone Else,Blah2
\\server\sub\folder\file3.ext,Same Someone,Blah3
Then below script does hopefully what you want.
It creates new filenames by prepending them with a GUID and copies the files in the CSV listed in column File to some destination path.
It outputs a new CSV file in the destination folder like this:
OriginalFile,NewFile
\\server\sub\folder\file.ext,\\anotherserver\sub\folder\38f7bec9e4c0443081b385277a9d253d_file.ext
\\server\sub\folder\file2.ext,\\anotherserver\sub\folder\d19546f7a3284ccb995e5ea27db2c034_file2.ext
\\server\sub\folder\file3.ext,\\anotherserver\sub\folder\edd6d35006ac46e294aaa25526ec5033_file3.ext
Any errors are listed in a log file (also in the destination folder).
$Destination = '\\Server\Folder'
$ResultsFile = Join-Path $Destination 'Copy_Results.csv'
$Logfile = Join-Path $Destination 'Copy_Errors.log'
$Doc = Import-CSV C:\Temp\scripttest.csv
# create an array to store the copy results in
$result = #()
# loop through the csv data using only the column called 'File'
ForEach ($fileName in $Doc.File) {
# check if the given file exists; if not then write to the errors log file
if (Test-Path -Path $fileName -PathType Leaf) {
$oldBaseName = Split-Path -Path $fileName.Path -Leaf
# or do $oldBaseName = [System.IO.Path]::GetFileName($fileName)
$newBaseName = "{0}_{1}" -f $((New-Guid).toString("N")), $oldBaseName
# (New-Guid).toString("N") returns the Guid without hyphens, same as (New-Guid).Guid.Replace('-','')
$destinationFile = Join-Path $Destination $newBaseName
try {
Copy-Item -Path $fileName -Destination $destinationFile -Force -ErrorAction Stop
# add an object to the results array to store the original filename and the full filename of the copy
$result += New-Object -TypeName PSObject -Property #{
'OriginalFile' = $fileName
'NewFile' = $destinationFile
}
}
catch {
Write-Error "Could not copy file to '$destinationFile'"
# write the error to the log file
Add-content $Logfile -Value "$((Get-Date).ToString("yyyy-MM-dd HH:mm:ss")) - ERROR: Could not copy file to '$destinationFile'"
}
}
else {
Write-Warning "File '$fileName' does not exist"
# write the error to the log file
Add-content $Logfile -Value "$((Get-Date).ToString("yyyy-MM-dd HH:mm:ss")) - WARNING: File '$fileName' does not exist"
}
}
# finally create a CSV with the results of this copy.
# the CSV will have two headers 'OriginalFile' and 'NewFile'
$result | Export-Csv -Path $ResultsFile -NoTypeInformation -Force

Answer 4

Thank you to everyone for the solutions. All of them worked and worked well. I chose Theo as the answer for the fact that his solution solved the error logging and stored all the new renamed files with GUID_File.ext new to the existing CSV info.
Thank you all.