I need to calculate eigenvalues of a series of matrices and then save them in a separate file. My data has 5 columns and 10,000 rows. I use the following functions:
R<-NULL
A <- setwd("c:/location of the file on this computer")
for(i in 0:1){
X<-read.table(file="Example.prn", skip=i*5, nrow=5)
M <- as.matrix(X)
E=eigen(M, only.values = TRUE)
R<-rbind(R,E)}
print(E)
}
As an example I have used a data set with 10 rows and 5 columns. This gives me the following results:
$`values`
[1] 1.350000e+02+0.000e+00i -4.000000e+00+0.000e+00i 4.365884e-15+2.395e-15i 4.365884e-15-2.395e-15i
[5] 8.643810e-16+0.000e+00i
$vectors
NULL
$`values`
[1] 2.362320e+02+0.000000e+00i -4.960046e+01+1.258757e+01i -4.960046e+01-1.258757e+01i 9.689475e-01+0.000000e+00i
[5] 1.104994e-14+0.000000e+00i
$vectors
NULL
I have three questions and I would really appreciate any help:
I want to save the results in consecutive rows, such as:
Eigenvalue(1) Eigenvalue(3) Eigenvalue(5) Eigenvalue(7) Eigenvalue(9)
Eigenvalue(2) Eigenvalue(4) Eigenvalue(6) Eigenvalue(8) Eigenvalue(10)
any thoughts?
Also, I don't understand the eigenvalues in the output. They are not numbers. For example, one of them is 2.362320e+02+0.000000e+00i. My first though was that this is the sum of five determinants for a 5x5 matrix. However, "2.362320e+02+0.000000e+00i" seems to only have four numbers in it. Any thoughts? Doesn't eigen() function calculate the final values of eigenvalues?
how can I save my outcome on an Excel file? I have used the following codes
However, the result I get from the current codes are:
> class(R)
[1] "matrix"
> print(R)
values vectors
E Complex,5 NULL
E Complex,5 NULL
I think, you can easily get values by the following code:
R<-NULL
A <- setwd("c:/location of the file on this computer")
for(i in 0:1){
X<-read.table(file="Example.prn", skip=i*5, nrow=5)
M <- as.matrix(X)
E=eigen(M, only.values = TRUE)
R<-rbind(R,E$values)}
}
and then use the answer of this question, to save R into a file
Related
I performed an ANOVA and corrected it with Tukey's test, so I got several values of P.
Now I would like to build a Heatmap with these values and for that I need to create an matrix with the values of P to be able to make my Heat map
The first question would be how to fill a matrix with the anova p-values?
Then I made an ancova and obtained other p-values.
Now I would like to make a heatmap to compare these p-values between the anova and the ancova.
Can someone help me ?
I will exemplify
anova_model <- aov( X ~ groups , data = T1)
postHocs <- glht(anova_model, linfct = mcp(groups = "Tukey"))
summary(postHocs)
This anova gave me several values of P(!)
ancova_model <- aov( X ~ groups + age , data = T1)
postHocs <- glht(ancova_model, lymphct = mcp(groups = "Tukey"))
summary(postHocs)
This ancova gave me several other values of P(!)
I would now like to create a Heat map to compare these P values. To see for example when age interferes a lot or not. I believe that before the ideal is to create a matrix before but I'm actually kind of lost.
Could someone help me?
Thank you very much
I had a look at this post to compute the correlation matrix given an input table.
My issue is that my columns are not consistently aligned.
For instance:
([]date:.z.d+til 100;a:100?10f;b:(10#0n),90?1f;c:(90?1f),(10#0n))
date a b c
---------------------------------------------
2019.11.18 6.018138 0.1357346
2019.11.19 2.365495 0.9805366
2019.11.20 0.5136894 0.2821858
2019.11.21 9.013581 0.4946025
2019.11.22 1.0842 0.967023
2019.11.23 4.543989 0.6901084
2019.11.24 4.597627 0.6303566
2019.11.25 2.18889 0.01415349
2019.11.26 3.050233 0.2783062
2019.11.27 5.259109 0.6675121
2019.11.28 5.175593 0.1684333 0.3706485
2019.11.29 5.14162 0.5885103 0.4183277
I don't want to remove all the rows containing null values before computing the correlation matrix, as I have many columns and the intersection of all the dates could be the empty set.
Instead, I would like to apply n*(n-1)\2 operations to populate the correlation matrix that I would construct myself, by taking the joint series of a and b, and putting the result in my correlation matrix C at C[1,2] and C[2,1].
I insist on the n*(n-1)\2 operations as the answers in the post I mentioned above seem to do n*n operations (my n is roughly equal to 700).
This might get you something close to what you're looking for:
q)m:(1_cols t)!();
q){x{m::m,'key[x]!1f,value(1_x)cor\:y;1_x}/x}1_flip t
q)m^flip m
| a b c
-| ----------------------------------
a| 1 0.01418217 0.04938382
b| 0.01418217 1 -0.06297328
c| 0.04938382 -0.06297328 1
Uses only 3 cor operations.
so this is what I'm trying to do, and I'm not sure how cause I'm new to python. I've searched for a few options and I'm not sure why this doesn't work.
So I have 6 different nodes, in maya, called aiSwitch. I need to generate random different numbers from 0 to 6 and input that value in the aiSiwtch*.index.
In short the result should be
aiSwitch1.index = (random number from 0 to 5)
aiSwitch2.index = (another random number from 0 to 5 different than the one before)
And so on unil aiSwitch6.index
I tried the following:
import maya.cmds as mc
import random
allswtich = mc.ls('aiSwitch*')
for i in allswitch:
print i
S = range(0,6)
print S
shuffle = random.sample(S, len(S))
print shuffle
for w in shuffle:
print w
mc.setAttr(i + '.index', w)
This is the result I get from the prints:
aiSwitch1 <-- from print i
[0,1,2,3,4,5] <--- from print S
[2,3,5,4,0,1] <--- from print Shuffle (random.sample results)
2
3
5
4
0
1 <--- from print w, every separated item in the random.sample list.
Now, this happens for every aiSwitch, cause it's in a loop of course. And the random numbers are always a different list cause it happens every time the loop runs.
So where is the problem then?
aiSwitch1.index = 1
And all the other aiSwitch*.index always take only the last item in the list but the time I get to do the setAttr. It seems to be that w is retaining the last value of the for loop. I don't quite understand how to
Get a random value from 0 to 5
Input that value in aiSwitch1.index
Get another random value from 0 to 6 different to the one before
Input that value in aiSwitch2.index
Repeat until aiSwitch5.index.
I did get it to work with the following form:
allSwitch = mc.ls('aiSwitch')
for i in allSwitch:
mc.setAttr(i + '.index', random.uniform(0,5))
This gave a random number from 0 to 5 to all aiSwitch*.index, but some of them repeat. I think this works cause the value is being generated every time the loop runs, hence setting the attribute with a random number. But the numbers repeat and I was trying to avoid that. I also tried a shuffle but failed to get any values from it.
My main mistake seems to be that I'm generating a list and sampling it, but I'm failing to assign every different item from that list to different aiSwitch*.index nodes. And I'm running out of ideas for this.
Any clues would be greatly appreciated.
Thanks.
Jonathan.
Here is a somewhat Pythonic way: shuffle the list of indices, then iterate over it using zip (which is useful for iterating over structures in parallel, which is what you need to do here):
import random
index = list(range(6))
random.shuffle(index)
allSwitch = mc.ls('aiSwitch*')
for i,j in zip(allSwitch,index):
mc.setAttr(i + '.index', j)
I want to do a simple task but somehow I'm unable to do it. Assume that I have one column like:
a
z
e
r
t
How can I create a new column with the same value twice with the following result:
a
a
z
z
e
e
r
r
t
t
I've already tried to double my column and do something like :
=TRANSPOSE(SPLIT(JOIN(";",A:A,B:B),";"))
but it creates:
a
z
e
r
t
a
z
e
r
t
I get inspired by this answer so far.
Try this:
=SORT({A1:A5;A1:A5})
Here we use:
sort
{} to combine data
Accounting your comment, then you may use this formula:
=QUERY(SORT(ArrayFormula({row(A1:A5),A1:A5;row(A1:A5),A1:A5})),"select Col2")
The idea is to use additional column of data with number of row, then sort by row, then query to get only values.
And join→split method will do the same:
=TRANSPOSE(SPLIT(JOIN(",",ARRAYFORMULA(CONCAT(A1:A5&",",A1:A5))),","))
Here we use range only two times, so this is easier to use. Also see Concat + ArrayFormula sample.
Few hundreds rows is nothing :)
I created index from 1 to n, then pasted it twice and sorted by index. But it's obviously fancier to do it with a formula :)
Assuming Your list is in column A and (for now) the times of repeat are in C1 (can be changed to a number in the formula), then something simple like this will do (starting in B1):
=INDEX(A:A,(INT(ROW()-1)/$C$1)+1)
Simply copy down as you need it (will give just 0 after the last item). No sorting. No array. No sheets/excel problems. No heavy calculations.
I have a function toWords which converts a integer into a word
e.g. toWords(500, tableWords) gives fivehundred
I have an array of numbers h = (1..999).to_a, and I want to go through this array and convert each number into a word and store it in a new array. My current attempt to do this is:
h = (1..999).to_a
Lh = h.each do |i| toWords(i, tableWords) end
However, the contents of Lh is simply the integers from 1 to 999 and not the output of my toWords function. How do I do this? I'm thinking of something along the lines of sapply in R.
Even better is if my new array Lh can have two columns, the first column containing the integers in number format, and the second column would be the corresponding number in words.
Thank you!
To get your two columns, you can do the following
(1..999).map {|x| [x, toWords(x, tableWords)]}
As per Cicada's comment, the answer is:
Lh = h.map{|x| toWords(x, tableWords)}