Handling error thrown by resource controller's method - laravel

Question

I' working with Laravel 5.6 and i've decided to create a resource controller to handle one of my models. Right know im trying to destroy a record from the database like this:
public function destroy(Role $role)
{
$role->delete();
return response([
'alert' => [
'type' => 'success',
'title' => 'Role destroyed!'
]
], 200);
}
It works just fine as longs as the $role exists. My problem is that i want to handle the response myself in the case that $role does not exist to do something like this:
return response([
'alert' => [
'type' => 'ups!',
'title' => 'There is no role with the provided id!'
]
], 400);
But instead, i'm getting a error like this:
"No query results for model [App\\Models\\Role]."
And that is something I don't want.
Thanks in advance!

Answer 1

The "No query results for model [App\\Models\\Role]." is the standard response message for a ModelNotFound exception in Laravel.
The best way to change the response for an exception like this is to use the exception handler's render function to respond with whatever message you want.
For example you could do
if ($e instanceof ModelNotFoundException) {
$response['type'] = "ups!;
$response['message'] = "Could not find what you're looking for";
$response['status'] = Response::HTTP_NOT_FOUND
}
return response()->json(['alert' => $response], $response['status']);
The alternative is to ensure that the ModelNotFound exception does not get thrown (So use ->find() rather than ->findOrFail() when querying the model)
and then using the abort helper like so if no results are returned:
abort(400, 'Role not found');
or
return response(['alert' => [
'type' => 'ups!',
'title' => 'There is no role with the provided id!']
],400);