Save multiple inputs Laravel 5.6 - laravel

Question

I'm trying to save a data to my database coming from 2 inputs which has multiple values. The scenario is that after a product has been saved, data will be save to my another table with columns 'product_id','price','size'. How ever when I tried to run my code, only the first value is saved in the column 'size', the data in 'price' are fine.
<input name="fix_size[]">
<input name="fix_price[]">
foreach($request->fix_price as $prc){
$cprice = new ContainerPrice;
$cprice->product_id = $id;
$cprice->price = $prc;
foreach($request->fix_size as $size){
$cprice->size = $size;
}
$cprice->save();
}

Answer 1

Remember, fix_size and fix_price are arrays.
You have to get the respective pairs of each fix_size and fix_price. So you have to monitor the index in the loop.
This is one of the possible solution in your problem:
$fix_sizes = $request->fix_size;
foreach($request->fix_price as $i => $prc){
$cprice = new ContainerPrice;
$cprice->product_id = $id;
$cprice->price = $prc;
$cprice->size = $fix_sizes[$i];
$cprice->save();
}
I may suggest to you to master the basic principles of programming and learn to debug codes by yourself.

Answer 2

Try this
foreach($request->fix_price as $prc){
foreach($request->fixed_size as $size){
$cprice = new ContainerPrice;
$cprice->product_id = $id;
$cprice->price = $prc;
$cprice->size = $size;
$cprice->save();
}
}

Answer 3

You could try this:
foreach($request->fix_price as $key => $prc) {
$cprice = new ContainerPrice;
$cprice->product_id = $id;
$cprice->price = $prc;
$cprice->size = $request->input('size')[$key];
$cprice->save();
}
The problem you had is because you loop over all elements inside the main loop and keeping only the last element. In other words, in the foreach loop, you are constantly overriding the $cprice->size property with the last you find.
Now with this code you access the "size" which has the same index as your "price".