In GNU Make you can export a variable for a target:
foo: export X=42
foo:
echo $$X
# Call several more commands that use $X.
Is there a way to do this in portable POSIX Make? So far, I've found two ways. The first is to basically merge all commands into one:
foo:
export X=42; \
echo $$X; \
# Call several more commands that use $X.
This is bad because now everything is bundled together. The second is to call $(MAKE):
foo:
$(MAKE) foo_ X=42
foo_:
echo $$X
# Call several more commands that use $X.
But this has an extra call to make again. Is there a better way?
The simplest solution is probably to set the variable on the command line by invoking make with:
make X=42
This way:
The make X variable is defined and set to 42, even if it is set to another value in the Makefile.
The shell environment variable X is defined and set to 42 for all recipes.
If you cannot use this (for instance because it is make that computes the value) the recursive make solution is probably the best option:
ifeq ($(X),)
X := <some-make-magic>
all:
$(MAKE) X=$(X) all
else
all:
<recipe-that-uses-X-environment-variable>
endif
Related
Is there a way to make use of exported variables in shell function without the need for sub-make?
Take the following example.
FOO := BAR
.EXPORT_ALL_VARIABLES:
.PHONY: buzz
buzz:
$(info buzz)
$(error finish)
.PHONY: fizz
fizz: $(if $(shell echo $$FOO),buzz,)
$(info fizz)
$(MAKE) fizz
If I run the fizz target like so I get the following output.
$ make fizz
fizz
make fizz
make[1]: Entering directory '/home/jshbrntt/test'
buzz
Makefile:8: *** finish. Stop.
make[1]: Leaving directory '/home/jshbrntt/test'
make: *** [Makefile:13: fizz] Error 2
As you can see only the second run of make fizz had the shell function expanded and cause the buzz target to also run.
Is there a way to make use of exported variables in shell function without the need for sub-make?
No.
Remember always that GNU make functions such as $(shell) are evaluated while the makefile is being parsed, not when make runs recipes (refer to section 3.7 of the manual), regardless of where in the makefile the $(shell) invocation appears. make determines which variables are exported based on its own environment and the combination of all rules and export / unexport directives in the makefile, potentially including rules and / or directives generated via $(shell) and other functions. In this way it ensures that it is consistent about the environment used to execute recipes.
Although it is conceivable that make would expose expose intermediate forms of its export list to the $(shell) function (and its documentation doesn't clearly specify whether it does so), as a practical matter it would be surprising for it to do so, and your experiment shows that it does not do. And although the manual does not explicitly speak directly to the question, it should be noted that its documentation of export, etc. is in a section entitled Communicating Variables to a Sub-make.
Personally, I recommend avoiding $(shell) (and $(wildcard)) altogether. If you do use $(shell) then I recommend reserving such use to outside recipes. Inside recipes, use shell code directly. This is clearer, certainly in terms of makefile semantics (what is evaluated when), but often in terms of the actual code, too. For your particular example, that might look like so:
FOO := BAR
.EXPORT_ALL_VARIABLES:
.PHONY: fizz
fizz:
#echo fizz
#if test -n "$$FOO"; then echo FOO found; else echo FOO missing; make fizz; fi
In all current versions of GNU make, exported variables are not sent to the shell function. There are some very nasty recursive behaviors that can happen (what if you write export BAR = $(shell echo $$FOO) ???)
In the next release of GNU make, make variables will be exported to the shell function.
However, there's never any good reason to use shell in a recipe. The recipe is running in a shell, so you can just write the commands that you want directly. So if your example is accurate in that you want to use this facility in a recipe, just take out the shell invocation:
.PHONY: fizz
fizz:
#echo fizz
#test -n $$FOO && echo FOO found || echo FOO missing
how to create local variable in a Makefile recipe in which only it is assignable and also just used there only ?
The recipe is executed by the shell, usually line by line. So you'll have to use your shell definition of variables, use escape if your shell uses $ for variables, and use escapes so that the recipe is logically one line. For instance on Unix, you can do:
target: <dependencies>
v=42 ; \
echo $$v
You can use so-called target-specific variables:
foo: bar = 1
foo:
#echo $(bar)
Or, if they are not flexible enough for you, consider using eval.
eval creates/manipulates global variables, so to avoid name collisions, I'd use a prefix for the variables you create with it:
foo:
$(eval _local_bar = 1)
#echo $(_local_bar)
When I run
export PATH := mypath
$(error $(shell echo "$${PATH}"))
it seems my PATH isn't changed on the call to shell.
Why is this and how do I actually change the PATH for shell calls?
Is this with GNU make? There is a long-standing GNU make feature request to honor exported variables with $(shell …). This is not specific to PATH at all, it affects (or does not affect) all export variables.
According to the GNU make sources, this is tricky to implement:
/* Using a target environment for 'shell' loses in cases like:
export var = $(shell echo foobie)
bad := $(var)
because target_environment hits a loop trying to expand $(var) to put it
in the environment. This is even more confusing when 'var' was not
explicitly exported, but just appeared in the calling environment.
See Savannah bug #10593.
envp = target_environment (NULL);
*/
The solution is simple: never ever use $(shell) or export.
Environment variables should be part of the recipe that needs them.
For $(shell) invocations that are supposed to fill a makefile variable you can use instead.
it also has the advantage to be more flexible, because you can fill more than one variable with one recipe
you can also define proper dependencies, whereas $(shell) is always executed, either when the makefile is parsed or the recursively expanded variable gets expanded.
you get build errors and recipes are logged, whereas $(shell) can make the DevOp engineers life a living h...
PATH := mypath
Makefile.variables:
#PATH=$(PATH) echo "This my path '$${PATH}'"
echo >$# "MY_DYNAMIC_CONTENT := abcd"
include Makefile.variables
$(info MY_DYNAMIC_CONTENT '$(MY_DYNAMIC_CONTENT)')
Example run:
$ make
MY_DYNAMIC_CONTENT ''
This my path 'mypath'
echo >Makefile.variables "MY_DYNAMIC_CONTENT := abcd"
MY_DYNAMIC_CONTENT 'abcd'
make: 'Makefile.variables' is up to date.
Note: This question was originally posted as a rant by a now-deleted user, but there was a valid question behind the rant; this is my attempt to provide an answer.
Given the Makefile:
ifeq "$(MAKELEVEL)" "0"
# Override the command-line specification of "foo".
override foo=replaced
export foo
all::
#echo outer: foo is "$(foo)"
#$(MAKE)
else
# Variable 'foo' was "exported" from the top-level Makefile.
all::
#echo inner: foo is "$(foo)"
endif
The expectation is that export foo will cause make to export the value defined in the override declaration. But it doesn't:
$ make -s foo=original
outer: foo is replaced
inner: foo is original
The expectation is probably reasonable, but it turns out that this is not the way Gnu make works. It could well be that the make documentation could be improved to clarify the process, but the hints all seem to be there.
How variables get their values
A variable can be set by the programmer in three ways:
On the command line with a var=value command-line argument
Explicitly in the make file
From the environment
The above list is the normal priority order; the first definition found in the list "wins". However, you can use the override directive to swap the priorities of the first two methods. (You can also use the -e flag to make to swap the priorities of the last two methods. The -e flag is required by Posix, but its use is discouraged and it does not interact will with override.)
How variables are passed to sub-makes
make is very similar to a shell in that the environment is used to pass variable values. If a variable is marked as exported, then its value is placed into the environment for any processes initiated by make, including sub-makes. As with the shell, a variable is marked as exported if its definition came from the environment or if it is explicitly marked as exported with the export directive. Variables are also exported if they were set on the command line.
However, there is another mechanism by which variables on the command-line are passed to subprocesses: the MAKEFLAGS exported variable.. MAKEFLAGS contains (most) command-line options as well as all of the command-line variable overrides. If make finds MAKEFLAGS in the environment, it merges the settings in that variable with the ones actually specified on its command line. That means that command-line variable settings in a make will also take priority in a sub-make.
Since command-line variable settings are passed through the MAKEFLAGS variable, they are not subject to any changes in the makefile. A makefile can unexport or override a variable set on the command-line, but that will only affect the value (or presence) of the variable in the environment; it does not remove or change the value from MAKEFLAGS.
Resolution
So if the intent is to override (or modify) a command-line variable both in the make itself and in the environment of sub-makes, it is necessary to use both an override and an explicit modification of MAKEFLAGS. (As explained in the make manual, MAKEFLAGS is actually recursively composed using the MAKEOVERRIDES variable, so we actually modify that variable.)
ifeq "$(MAKELEVEL)" "0"
# Override the command-line specification of "foo".
override foo=replaced
MAKEOVERRIDES += foo=replaced
all::
#echo outer: foo is "$(foo)"
#$(MAKE) -s
else
# Variable 'foo' was "exported" from the top-level Makefile.
all::
#echo inner: foo is "$(foo)"
endif
And now we get the expected result:
$ make -s foo=original
outer: foo is replaced
inner: foo is replaced
Real-life application: dealing with whitespace
The primary intention of overrides is to allow the makefile to append words to a variable possibly provided on the command line. The example provided in the gnu make manual is insisting that CFLAGS always includes the -g flag, even if it were specified on the make command line:
override CFLAGS += -g
Passing the append through to a sub-make needs a little caution; in particular, the obvious:
MAKEOVERRIDES += CFLAGS=$(CFLAGS) # Don't do this
won't work because the whitespace inside the CFLAGS variable will not be escaped when it is added to MAKEFLAGS; the result will be that MAKEFLAGS will look something like this:
-- CFLAGS=-O3 CFLAGS=-O3 -g
instead of the desired
-- CFLAGS=-O3 CFLAGS=-O3\ -g
If the value assigned to CFLAGS on the command line included whitespace, the whitespace is escaped in MAKEFLAGS. The particular escaping mechanism used is not documented, and Posix only requires that there be some mechanism; apparently, Gnu make uses backslash. It would be possible to manually backslash escape the whitespace, resulting in something like this:
# Don't do this either
MAKEOVERRIDES += CFLAGS=$(subst $(space),\ ,$(CFLAGS))
(The definition and use of space is based on an example in the gnu make manual.)
But it is actually easier to just use an append assignment in MAKEOVERRIDES, which is undocumented but appears to work. It works on the command line, too.
override CFLAGS+=-g
MAKEOVERRIDES += CFLAGS+=-g
Important Note as of make v4.1: A bit of testing revealed that the above stanza will only work if CFLAGS (or some other variable) is actually set on the command-line. I reported this bug as Savannah issue 46013, with a very simple fix in the bug report. In the meantime, if you really want to do this, use the following workaround:
override CFLAGS+=-g
MAKEOVERRIDES += CFLAGS+=-g
# This line is necessary in case there were no command-line overrides.
# In effect, it produces a command-line override, although that value
# will not be passed on to sub-makes.
MAKEFLAGS += dummy=dummy
Update May 19, 2019: Today I was informed that a fix for the bug referenced above has been committed, so it should be fixed in the next gmake release.
First of all, I want to point out that your suggestion to add to MAKEOVERRIDES, is dangerous!
And SHOULD NEVER BE DONE!!
You simply turn a recursive variable into a simple one, you will always get false results, if recursive expansion is done.
I can not believe that you got up-voted for this clearly wrong "suggestion".
And note this:
You can not even fix it with a quoted assignment, like MAKEOVERRIDES += foo=$$(bar)!!!
But, let me return to the main point of your post.
And, with which, I couldn't disagree more.
One simple example would be, if you run the very same makefile, that you have:
This one is copied verbatim, from your post:
ifeq "$(MAKELEVEL)" "0"
# Override the command-line specification of "foo".
override foo=replaced
export foo
all::
#echo outer: foo is "$(foo)"
#$(MAKE) -s
else
# Variable 'foo' was "exported" from the top-level Makefile.
all::
#echo inner: foo is "$(foo)"
endif
And running in any modern version, 4.0 and up:
# Sub-make does NOT get the value from the root-Make's command-line.
# Instead, it "inherits" the value from the root-Make's definition in the Makefile.
$ make -s foo=original -e
outer: foo is replaced
inner: foo is replaced
Now, given your assertion above:
However, there is another mechanism by which variables on the command-line are passed to subprocesses: the [MAKEFLAGS exported variable.][3]. MAKEFLAGS contains (most) command-line options as well as all of the command-line variable overrides. If make finds MAKEFLAGS in the environment, it merges the settings in that variable with the ones actually specified on its command line. That means that command-line variable settings in a make will also take priority in a sub-make.
Since command-line variable settings are passed through the MAKEFLAGS variable, they are not subject to any changes in the makefile. A makefile can unexport or override a variable set on the command-line, but that will only affect the value (or presence) of the variable in the environment; it does not remove or change the value from MAKEFLAGS.
You should get:
outer: foo is replaced
inner: foo is original
In other words, we should get for the sub-make, the value defined on the command-line (original)!
Because, you said yourself:
A makefile can't unexport or override a variable set on the command-line.
So, here, when we empower the environment over the makefile, which means that the makefile has less "power" in the total scheme of things. Right?
Sure, for such a case, you assertion will hold even stronger.
Can I pass variables to a GNU Makefile as command line arguments? In other words, I want to pass some arguments which will eventually become variables in the Makefile.
You have several options to set up variables from outside your makefile:
From environment - each environment variable is transformed into a makefile variable with the same name and value.
You may also want to set -e option (aka --environments-override) on, and your environment variables will override assignments made into makefile (unless these assignments themselves use the override directive . However, it's not recommended, and it's much better and flexible to use ?= assignment (the conditional variable assignment operator, it only has an effect if the variable is not yet defined):
FOO?=default_value_if_not_set_in_environment
Note that certain variables are not inherited from environment:
MAKE is gotten from name of the script
SHELL is either set within a makefile, or defaults to /bin/sh (rationale: commands are specified within the makefile, and they're shell-specific).
From command line - make can take variable assignments as part of his command line, mingled with targets:
make target FOO=bar
But then all assignments to FOO variable within the makefile will be ignored unless you use the override directive in assignment. (The effect is the same as with -e option for environment variables).
Exporting from the parent Make - if you call Make from a Makefile, you usually shouldn't explicitly write variable assignments like this:
# Don't do this!
target:
$(MAKE) -C target CC=$(CC) CFLAGS=$(CFLAGS)
Instead, better solution might be to export these variables. Exporting a variable makes it into the environment of every shell invocation, and Make calls from these commands pick these environment variable as specified above.
# Do like this
CFLAGS=-g
export CFLAGS
target:
$(MAKE) -C target
You can also export all variables by using export without arguments.
The simplest way is:
make foo=bar target
Then in your makefile you can refer to $(foo). Note that this won't propagate to sub-makes automatically.
If you are using sub-makes, see this article: Communicating Variables to a Sub-make
Say you have a makefile like this:
action:
echo argument is $(argument)
You would then call it make action argument=something
From the manual:
Variables in make can come from the environment in which make is run. Every environment variable that make sees when it starts up is transformed into a make variable with the same name and value. However, an explicit assignment in the makefile, or with a command argument, overrides the environment.
So you can do (from bash):
FOOBAR=1 make
resulting in a variable FOOBAR in your Makefile.
It seems command args overwrite environment variable.
Makefile:
send:
echo $(MESSAGE1) $(MESSAGE2)
Example run:
$ MESSAGE1=YES MESSAGE2=NG make send MESSAGE2=OK
echo YES OK
YES OK
There's another option not cited here which is included in the GNU Make book by Stallman and McGrath (see http://www.chemie.fu-berlin.de/chemnet/use/info/make/make_7.html). It provides the example:
archive.a: ...
ifneq (,$(findstring t,$(MAKEFLAGS)))
+touch archive.a
+ranlib -t archive.a
else
ranlib archive.a
endif
It involves verifying if a given parameter appears in MAKEFLAGS. For example .. suppose that you're studying about threads in c++11 and you've divided your study across multiple files (class01, ... , classNM) and you want to: compile then all and run individually or compile one at a time and run it if a flag is specified (-r, for instance). So, you could come up with the following Makefile:
CXX=clang++-3.5
CXXFLAGS = -Wall -Werror -std=c++11
LDLIBS = -lpthread
SOURCES = class01 class02 class03
%: %.cxx
$(CXX) $(CXXFLAGS) -o $#.out $^ $(LDLIBS)
ifneq (,$(findstring r, $(MAKEFLAGS)))
./$#.out
endif
all: $(SOURCES)
.PHONY: clean
clean:
find . -name "*.out" -delete
Having that, you'd:
build and run a file w/ make -r class02;
build all w/ make or make all;
build and run all w/ make -r (suppose that all of them contain some certain kind of assert stuff and you just want to test them all)
If you make a file called Makefile and add a variable like this $(unittest)
then you will be able to use this variable inside the Makefile even with wildcards
example :
make unittest=*
I use BOOST_TEST and by giving a wildcard to parameter --run_test=$(unittest)
then I will be able to use regular expression to filter out the test I want my Makefile
to run
export ROOT_DIR=<path/value>
Then use the variable, $(ROOT_DIR) in the Makefile.